I'm working on the following query and cant figure out the final piece of it. I need my query to give me a result set between the previous business and the previous business day minus (-) 28 days. (e.g. date range between 10/28/2015 and 10/28/2015 -28) The query that I wrote so far is only giving me the -28th day (09/30/2015) and NOT a range in between the previous business day and the previous business day -28. My research shows a couple of different ways of doing it and so far none have worked for me.
SELECT SMBL, SUM(NET_FLOWS/1000000.00)
FROM HISTORY
WHERE DATE - 28 = DATE AND DATE = TO_DATE('10282015','MMDDYYYY')
AND SYMBOL IN ('AAA','BBB')
GROUP BY SMBL
First off, date ranges are easy using BETWEEN, so you do the quick solution:
WHERE DATE BETWEEN (SYSDATE-28) and (SYSDATE-1)
Then you realize your dates have time components, so to include all of yesterday and all of day-28 you need to:
WHERE DATE >= TRUNC(SYSDATE)-28
AND DATE < TRUNC(SYSDATE)
Then I look at your rule "previous BUSINESS day" and ask - what are your business days? On a Monday to go up to the previous Friday? Or Saturday? Or are you a 7-day-a-week business? How about statutory holidays? And is it 28 CALENDAR days back? Or 28 BUSINESS days?
Ahh business rules. The devil is always in those details....
Related
I am trying to find the same day of week from last month if today's date is Wednesday Oct 2nd 2019. I need to retrieve Wednesday Sept 4th 2019.
I am using Carbon and have tried subDays(30) and subMonth(1) but that obviously doesn't return the same week day.
SalesLogs::loadByDate(Carbon::now()->subMonth(1));
This code works as expected, however I am unable to work out how to make it find the same day of the week based on the prior month.
It's not super clear what you are trying to do, but I will take a shot at it. What about if you subtract a month, and then go to the next matching weekday?
$weekday = now()->dayOfWeek;
SalesLogs::loadByDate(now()->subMonth(1)->next($weekday));
Note: you can take advantage of Laravel's handy now() helper function, which is equal to Carbon::now(), but saves you from having to import Carbon.
Does that get you what you need?
I have a report that takes sales data from a few tables. I want to add a field that will divide the total sales for the given month by the total number of business days in that same month. Is there a way I can calculate that in an expression? Do I need to create a new table in the database specifically for months and their number of business days? How should I go about this?
Thank you
Intuitively, I would say that you need a simple function and a table.
The table is to host the exceptions like Independence day, labor day, etc.
The function will get two parameters: Month and Year (I'm not providing any sample code since you haven't specified which language you are using).
It will then build a date as yyyy-mm-01 (meaning, first day of the month). If will then loop from 2 to 31 and:
Create a new date by adding the index of the loop to the initial date,
Check if the resulting date is still within the month,
Check if it is a working or not working day (e.g. Sunday),
Check if it is found within the table of exceptions.
If the created date passes all the above tests, you add 1 to the counter.
Though it might look complex, it is not and it will provide you the correct answer regardless of the month (e.g. Feb.) and the year (leap or not).
I have to work with data retrieved and grouped on a weekly basis (ISO week) and my DB is structured on a daily basis (field: DATE). I need to write down a code which is rolling, so that given the current date, it calculate the week and the retrieve data in the previous 3 weeks, too.
So I write in the WHERE clauses:
TO_DATE(TO_CHAR(DATE, 'YYYYWW')) BETWEEN TO_DATE(TO_CHAR(TO_DATE(running_date, 'YYYYMMDD'), 'YYYYWW'), 'YYYYWW')-3 AND TO_DATE(TO_CHAR(TO_DATE(running_date, 'YYYYMMDD'), 'YYYYWW'), 'YYYYWW')
It doesn't seems to work though.
Any suggestions on how to handle the problem?
Thanks a lot!
You have to subtract 21 days when you want to recive the previous 3 weeks. If you subtract 3 then you recive only the last three days.
You need to use 'IW', not 'WW' as the format mask for ISO week. From the Oracle docs:
IW = Week of year (1-52 or 1-53) based on the ISO standard.
WW = Week of year (1-53) where week 1 starts on the first day of the year and
continues to the seventh day of the year.
I'm writing an app that relies on the calendar and calendar events to display data to the user.
I need to be able to let the user select the beginning of his/her 'fiscal' year in settings, which will be the 1st of any of the 12 months. This is an app for military users, and any given unit's fiscal year can begin on whatever month their unit (base) decides.
The data I'm displaying to the user needs to be divided into 'fiscal' quarters according to the user's setting of the beginning of the fiscal year, not calendar year.
I'm not having problems retrieving, editing or deleting the events, I can't figure out how to change the beginning of the year to anything besides Jan 1st.
I found NSDateCategoryForReporting on GitHub, that seems like it's exactly what I need, but how do I tell it that the year begins on the 1st of x month?
iOS doesn't natively support this, so you'll have to find a plugin to do this or write your own. Your best bet is to write a class that performs the date conversions using the standard NSDate, NSCalendar, etc.
For instance, you could store what day the user specifies as their starting fiscal year. Then you can calculate the number of days difference between that and January 1st, and just shift dates based on that.
I have a query that needs to return the "week of year" of a date field but the customer of the query uses a non-standard first day of the week so TO_CHAR with 'IW' isn't returning the expected result. In this case the first day of the week is Saturday and Friday is the seventh day of the week.
With T-SQL I'd use DATEPART and SET DATEFIRST.
What is the Oracle equivalent? The Oracle answers I've found in the google all talk about setting the NLS_TERRITORY like so ALTER SESSION SET NLS_TERRITORY = 'UNITED KINGDOM'; but I'm not seeing where I can pick an arbitrary day (other than perhaps finding a territory that uses Saturday).
IW works with a Monday - Sunday week, so this should get you what you are looking for. Basically, get the week according to the day 2 days from now:
to_char(your_date + 2, 'IW')
Oracle's default week format calculates the week number from the first day of the year instead of the first day of the week.
So if a year starts on 01-jan-2009 and the first day is on Wednesday, the week No. 1 will be from 01-jan-2009 to 08-jan-2009 (wednesday to tuesday).
You can use the "iw" format (and a little tweak) if you need the week range to start from sunday through saturday. http://download-uk.oracle.com/docs/cd/B14117_01/server.101/b10749/ch9sql.htm#CIHGFJEI
Try this code below. I basically use the "IW" format and add a condition to get the week number to start from a given date.. say...01-jul-2008.
select target_date,
to_char(target_date+1,'iw') week_sun_thru_saturday,
to_number(to_char(target_date+1,'iw')) -
to_number(to_char( to_date('10-jul-2008','dd-mon-yyyy')+1,'iw')) week_from_01_jul_2008
from t;
Remember..This code will not give week number 1 from jul1st to jul-07 .unless of course 01-jul-2008 is a sunday ;)