Sort the Items with Stored Procedure - sorting

Question

So I have following example from my database:
"John" "1"
"Diva" "1"
"Christ" "2"
"Azzam" "2"
"Sunny" "3"
"Daniel" "3"
"Alex" "4"
"Mike" "4"
Two Names can have same NameID. Now I want to sort in such a way that when I pass the parameter "NameID" it will show Name related to that Id at first and the other Name close to that ID respectively. Example If I pass the parameter "3" to Stored Procedure the result should be:
"Sunny" "3"
"Daniel" "3"
"Alex" "4"
"Mike" "4"
"Christ" "2"
"Azzam" "2"
"John" "1"
"Diva" "1"
What I did till now?
Select * From Database
Order by NameID
I couldn't go further than that.

Answer 1

Use a CTE or subquery to assign a weight to the matching NameIDs. Then use that weight so those names appear first in the result set.
Here's an example from SQL Server, but the basic idea can be used in almost any SQL dialect:
SET NOCOUNT ON;
DECLARE #name_id_parameter INT = 3;
DECLARE #names TABLE
(
[name] NVARCHAR(MAX) NOT NULL,
[name_id] INT NOT NULL
);
INSERT INTO #names
(
[name],
[name_id]
)
VALUES
('John', 1),
('Diva', 1),
('Christ', 2),
('Azzam', 2),
('Sunny', 3),
('Daniel', 3),
('Alex', 4),
('Mike', 4);
/* Solution #1: Using a common table expression (CTE) */
WITH cte([name], [name_id], [sort_weight])
AS
(
/* Assign a higher "weight" to the [name_id]s that match
#name_id_parameter, so those [name_id]s will appear
first in the final result set. */
SELECT
[name],
[name_id],
CASE
WHEN [name_id] = #name_id_parameter THEN 1
ELSE 0
END
FROM
#names
)
SELECT
[name],
[name_id]
FROM
cte
ORDER BY
[sort_weight] DESC, [name_id] DESC
/* Solution #2: Using a subquery */
SELECT
S.[name],
S.[name_id]
FROM
/* Assign a higher "weight" to the [name_id]s that match
#name_id_parameter, so those [name_id]s will appear
first in the final result set. */
(SELECT
[name],
[name_id],
[sort_weight] =
CASE
WHEN [name_id] = #name_id_parameter THEN 1
ELSE 0
END
FROM
#names) AS S
ORDER BY
S.[sort_weight] DESC, S.[name_id] DESC

Answer 2

DECLARE #ID AS NVARCHAR(50)
SET #ID = '3';
SELECT *
FROM ( SELECT TOP(100)
[Name] ,
[NameID]
FROM [Test].[dbo].[Table_1]
WHERE NameID = #ID
ORDER BY NameID DESC
) a
UNION ALL
SELECT *
FROM ( SELECT TOP(100)
[Name] ,
[NameID]
FROM [Test].[dbo].[Table_1]
WHERE NameID #ID
ORDER BY NameID DESC
) b

Answer 3

Here is I think what you want:
DECLARE #t TABLE ( name VARCHAR(20), id INT )
INSERT INTO #t
VALUES ( 'John', '1' ),
( 'Diva', '1' ),
( 'Christ', '2' ),
( 'Azzam', '2' ),
( 'Sunny', '3' ),
( 'Daniel', '3' ),
( 'Alex', '4' ),
( 'Mike', '4' )
declare #id int = 3
SELECT * FROM #t
ORDER BY ABS(#id - id), #id - id, name
Output:
name id
Daniel 3
Sunny 3
Alex 4
Mike 4
Azzam 2
Christ 2
Diva 1
John 1