shell script to add leading zeros in middle of file name - shell

I have files with names like "words_transfer1_morewords.txt". I would like to ensure that the number after "transfer" is five digits, as in "words_transfer00001_morewords.txt". How would I do this with a ksh script? Thanks.

This will work in any Bourne-type/POSIX shell as long as your words and morewords don't contain numbers:
file=words_transfer1_morewords.txt
prefix=${file%%[0-9]*} # words_transfer
suffix=${file##*[0-9]} # _morewords.txt
num=${file#$prefix} # 1_morewords.txt
num=${num%$suffix} # 1
file=$(printf "%s%05d%s" "$prefix" "$num" "$suffix")
echo "$file"

Use ksh's regular expression matching operation to break the filename down into separate parts, them put them back together again after formatting the number.
pre="[^[:digit:]]+" # What to match before the number
num="[[:digit:]]+" # The number to match
post=".*" # What to match after the number
[[ $file =~ ($pre)($num)($post) ]]
new_file=$(printf "%s%05d%s\n" "${.sh.match[#]:1:3}")
Following a successful match with =~, the special array parameter .sh.match contains the full match in element 0, and each capture group in order starting with element 1.

Related

Extract value for a key in a key/pair string

I have key value pairs in a string like this:
key1 = "value1"
key2 = "value2"
key3 = "value3"
In a bash script, I need to extract the value of one of the keys like for key2, I should get value2, not in quote.
My bash script needs to work in both Redhat and Ubuntu Linux hosts.
What would be the easiest and most reliable way of doing this?
I tried something like this simplified script:
pattern='key2\s*=\s*\"(.*?)\".*$'
if [[ "$content" =~ $pattern ]]
then
key2="${BASH_REMATCH[1]}"
echo "key2: $key2"
else
echo 'not found'
fi
But it does not work consistently.
Any better/easier/more reliable way of doing this?
To separate the key and value from your $content variable, you can use:
[[ $content =~ (^[^ ]+)[[:blank:]]*=[[:blank:]]*[[:punct:]](.*)[[:punct:]]$ ]]
That will properly populate the BASH_REMATCH array with both values where your key is in BASH_REMATCH[1] and the value in BASH_REMATCH[2].
Explanation
In bash the [[...]] treats what appears on the right side of =~ as an extended regular expression and matched according to man 3 regex. See man 1 bash under the section heading for [[ expression ]] (4th paragraph). Sub-expressions in parenthesis (..) are saved in the array variable BASH_REMATCH with BASH_REMATCH[0] containing the entire portion of the string (your $content) and each remaining elements containing the sub-expressions enclosed in (..) in the order the parenthesis appear in the regex.
The Regular Expression (^[^ ]+)[[:blank:]]*=[[:blank:]]*[[:punct:]](.*)[[:punct:]]$ is explained as:
(^[^ ]+) - '^' anchored at the beginning of the line, [^ ]+ match one or more characters that are not a space. Since this sub-expression is enclosed in (..) it will be saved as BASH_REMATCH[1], followed by;
[[:blank:]]* - zero or more whitespace characters, followed by;
= - an equal sign, followed by;
[[:blank:]]* - zero or more whitespace characters, followed by;
[[:punct:]] - a punctuation character (matching the '"', which avoids caveats associated with using quotes within the regex), followed by the sub-expression;
(.*) - zero or more characters (the rest of the characters), and since it is a sub-expression in (..) it the characters will be stored in BASH_REMATCH[2], followed by;
[[:punct:]] - a punctuation character (matching the '"' ... ditto), at the;
$ - end of line anchor.
So if you match what your key and value input lines separated by an = sign, it will separate the key and value into the array BASH_REMATCH as you wanted.
Bash supports BRE only and you cannot use \s and .*?.
As an alternative, please try:
while IFS= read -r content; do
# pattern='key2\s*=\s*\"(.*)\".*$'
pattern='key2[[:blank:]]*=[[:blank:]]*"([^"]*)"'
if [[ $content =~ $pattern ]]
then
key2="${BASH_REMATCH[1]}"
echo "key2: $key2"
(( found++ ))
fi
done < input-file.txt
if (( found == 0 )); then
echo "not found"
fi
What you start talking about key-value pairs, it is best to use an associative array:
declare -A map
Now looking at your lines, they look like key = "value" where we assume that:
value is always encapsulated by double quotes, but also could contain a quote
an unknown number of white spaces is before and/or after the equal sign.
So assuming we have a variable line which contains key = "value", the following operations will extract that value:
key="${line%%=*}"; key="${key// /}"
value="${line#*=}"; value="${value#*\042}"; value="${value%\042*}"
IFS=" \t=" read -r value _ <<<"$line"
This allows us now to have something like:
declare -A map
while read -r line; do
key="${line%%=*}"; key="${key// /}"
value="${line#*=}"; value="${value#*\042}"; value="${value%\042*}"
map["$key"]="$value"
done <inputfile
With awk:
awk -v key="key2" '$1 == key { gsub("\"","",$3);print $3 }' <<< "$string"
Reading the output of the variable called string, pass the required key in as a variable called key and then if the first space delimited field is equal to the key, remove the quotes from the third field with the gsub function and print.
Ok, after spending so many hours, this is how I solved the problem:
If you don't know where your script will run and what type of file (win/mac/linux) are you reading:
Try to avoid non-greedy macth in linux bash instead of tweaking diffrent switches.
don't trus end of line match $ when you might get data from windows or mac
This post solved my problem: Non greedy text matching and extrapolating in bash
This pattern works for me in may linux environments and all type of end of lines:
pattern='key2\s*=\s*"([^"]*)"'
The value is in BASH_REMATCH[1]

Given String: approximateLastUseTime: '2019-10-15T16:56:07.082500Z', I need to extract everything after the T and before the Z (after the colon)

Given String:->
approximateLastUseTime: '2019-10-15T16:56:07.082500Z'
I need to extract everything after the T and before the Z (after the colon)
With bash, you can use substring operator, or prefix/suffix
T=2019-10-15T16:56:07.082500Z
# Using substring
echo ${T:11:15}
# Using prefix/suffix
T1=${T#*T}
T1=${T1%Z*}
echo "$T1"

Basic string manipulation from filenames in bash

I have a some file names in bash that I have acquired with
$ ones=$(find SRR*pass*1*.fq)
$ echo $ones
SRR6301033_pass_1_trimmed.fq
SRR6301034_pass_1_trimmed.fq
SRR6301037_pass_1_trimmed.fq
...
I then converted into an array so I can iterate over this list and perform some operations with filenames:
# convert to array
$ ones=(${ones// / })
and the iteration:
for i in $ones;
do
fle=$(basename $i)
out=$(echo $fle | grep -Po '(SRR\d*)')
echo "quants/$out.quant"
done
which produces:
quants/SRR6301033
SRR6301034
...
...
SRR6301220
SRR6301221.quant
However I want this:
quants/SRR6301033.quant
quants/SRR6301034.quant
...
...
quants/SRR6301220.quant
quants/SRR6301221.quant
Could somebody explain why what I'm doing doesn't work and how to correct it?
Why do you want this be done this complicated? You can get rid of all the unnecessary roundabouts and just use a for loop and built-in parameter expansion techniques to get this done.
# Initialize an empty indexed array
array=()
# Start a loop over files ending with '.fq' and if there are no such files
# the *.fq would be un-expanded and checking it against '-f' would fail and
# in-turn would cause the loop to break out
for file in *.fq; do
[ -f "$file" ] || continue
# Get the part of filename after the last '/' ( same as basename )
bName="${file##*/}"
# Remove the part after '.' (removing extension)
woExt="${bName%%.*}"
# In the resulting string, remove the part after first '_'
onlyFir="${woExt%%_*}"
# Append the result to the array, prefixing/suffixing strings 'quant'
array+=( quants/"$onlyFir".quant )
done
Now print the array to see the result
for entry in "${array[#]}"; do
printf '%s\n' "$entry"
done
Ways your attempt could fail
With ones=$(find SRR*pass*1*.fq) you are storing the results in a variable and not in an array. A variable has no way to distinguish if the contents are a list or a single string separated by spaces
With echo $ones i.e. an unquoted expansion, the string content is subject to word splitting. You might not see a difference as long as you have filenames with spaces, having one might let you interpret parts of the filename as different files
The part ${ones// / } makes no-sense in converting the string to an array as the attempt to use an unquoted variable $ones itself would be erroneous
for i in $ones; would be error prone for the said reasons above, the filenames with spaces could be interpreted as separated files instead of one.

Build a variable made with 2 sub-stings of another variable in bash

Here is a script I use:
for dir in $(find . -type d -name "single_copy_busco_sequences"); do
sppname=$(dirname $(dirname $(dirname $dir))| sed 's#./##g');
for file in ${dir}/*.faa; do name=$(basename $file); cp $file /Users/admin/Documents/busco_aa/${sppname}_${name}; sed -i '' 's#>#>'${sppname}'|#g' /Users/admin/Documents/busco_aa/${sppname}_${name}; cut -f 1 -d ":" /Users/admin/Documents/busco_aa/${sppname}_${name} > /Users/admin/Documents/busco_aa/${sppname}_${name}.1;
done;
done
The sppname variable is something like Gender_species
do you know how could I add a line in my script to creat a new variable called abbrev which transformes Gender_species into Genspe, the 3 first letters cat with the 3 first letters after _
exemples:
Homo_sapiens gives Homsap
Canis_lupus gives Canlup
etc
Thank for your help :)
You can achieve this using a regular expression with sed:
echo "Homo_sapiens" | sed -e s'/^\(...\).*_\(...\).*/\1\2/'
Homsap
start, get 3 chars (to keep in \1), anything, _, anything, get 3 chars (to keep in \2), anything
Replace echo "Homo_sapiens" by your $dir thing
PS: will fail if you have less than 3 chars in one word
You can do it all with bash built-in parameter expansions. Specifically, string indexes and substring removal.
$ a=Homo_sapiens; prefix=${a:0:3}; a=${a#*_}; postfix=${a:0:3}; echo $prefix$postfix
Homsap
$ a=Canis_lupus; prefix=${a:0:3}; a=${a#*_}; postfix=${a:0:3}; echo $prefix$postfix
Canlup
Using bash built-ins is always more efficient than spawning separate subshell(s) to invoke utilities to accomplish the same thing.
Explanation
Your string index form (bash only) allows you to index characters from within a string, e.g.
* ${parameter:offset:length} ## indexes are zero based, ${a:0:2} is 1st 2 chars
Where parameter is simply the variable name holding the string.
(you can index from the end of a string by using a negative offset preceded by a space or enclosed in parenthesis, e.g. a=12345; echo ${a: -3:2} outputs "34")
prefix=${a:0:3} ## save the first 3 characters in prefix
a=${a#*_} ## remove the front of the string through '_' (see below)
postfix=${a:0:3} ## save the first 3 characters after '_'
Your substring removal forms (POSIX) are:
${parameter#word} trim to 1st occurrence of word from parameter from left
${parameter##word} trim to last occurrence of word from parameter from left
and
${parameter%word} trim to 1st occurrence of word from parameter from right
${parameter%%word} trim to last occurrence of word from parameter from right
(word can contain globbing to expand to a pattern as well)
a=${a#*_} ## trim from left up to (and including) the first '_'
See bash(1) - Linux manual page for full details.

Split filename and get the element between first and last occurrence of underscore

I am trying to split many folder names in a for loop and extract the element between first and last underscore of filename. Filenames can look like ENCSR000AMA_HepG2_CTCF or ENCSR000ALA_endothelial_cell_of_umbilical_vein_CTCF.
My problem is that folder names differ form each other in the total number of underscores, so I cannot use something like:
IN=$d
folderIN=(${IN//_/ })
tf_name=${folderIN[-1]%/*} #get last element which is the TF name
cell_line=${folderIN[-2]%/*}; #get second last element which is the cell line
dataset_name=${folderIN[0]%/*}; #get first element which is the dataset name
cell_line can be one or more words separated by underscore but it's allways between 1st and last underscore.
Any help?
Just do this in a two step bash parameter expansion ONLY because bash does not support nested parameter expansion unlike zsh or other shells.
"${string%_*}" to strip the everything after the last occurrence of '_' and "${tempString#*_}" to strip everything from beginning to first occurrence of '_'
string="ENCSR000ALA_endothelial_cell_of_umbilical_vein_CTCF"
tempString="${string%_*}"
printf "%s\n" "${tempString#*_}"
endothelial_cell_of_umbilical_vein
Another example,
string="ENCSR000AMA_HepG2_CTCF"
tempString="${string%_*}"
printf "%s\n" "${tempString#*_}"
HepG2
You can modify this logic to apply on each of the file-names in your folder.
Could use regex.
extract_words() {
[[ "$1" =~ ^([^_]+)_(.*)_([^_]+)$ ]] && echo "${BASH_REMATCH[2]}"
}
while read -r from_line
do
extracted=$(extract_words "$from_line")
echo "$from_line" "[$extracted]"
done < list_of_filenames.txt
EDIT: I moved the "extraction" into an alone bash function for reuse and easy modification for more complex cases, like:
extract_words() {
perl -lnE 'say $2 if /^([^_]+)_(.*)_([^_]+)$/' <<< "$1"
}

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