Two wherehas in a Laravel Eloquent query - laravel

Question

I have the following query, simplified below.
$property = Property::whereHas('features', function ($q1) use ($features) {
$q1->where(function ($sub) use ($features) {
$sub->whereIn('features.FeatureID', $features);
});
$q1->groupBy('PropertyID');
$q1->having('count(*)', '=', count($features));
})
->whereHas('Week', function ($q) use ($nights) {
$q->where(function ($sub) use ($nights) {
$sub->whereIn('priceAvailDate', $nights);
});
$q->groupBy('PropertyID');
$q->having('count(*)', '=', count($nights));
})
->get();
If I take one whereHas out, I get the expected collection returned. If I take the other out I get the expected result.It is when they are together I have nothing returned. I assume it is down to having two count(*). I know I have data where both whereHas is true.
SQL output is
select * from `tblproperties` where (select count(*) from `features` inner
join `propertyfeatures` on `features`.`featureid` =
`propertyfeatures`.`FeatureID` where `propertyfeatures`.`PropertyID` =
`tblproperties`.`PropertyID` and (`features`.`FeatureID` in (?)) group by
`PropertyID` having `count(*)` = ?) >= 1 and (select count(*) from
`tblpriceavail` where `tblpriceavail`.`propertyID` = `tblproperties`.`PropertyID`
and (`priceAvailDate` in (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)) group by
`PropertyID` having `count(*)` = ?) >= 1
Fixed, although not 100% sure why. Using havingRaw instead of having worked.
i.e. changing the $q->having('count(*)', '=', count($nights));
to $q->havingRaw('count(*) = ' . count($nights));