$account_types = $this->members_model->getAllAccountTypes();
$result_set = array();
foreach($account_types as $account_type){
$result_set[$account_type->db_name] = array(
'subscribed' => $this->members_model->getAllSubscribedMembers($account_type->id),
'unsubscribed' => $this->members_model->getAllUnsubscribedMembers($account_type->id)
);
}
echo json_encode($result_set);
return;
i have these line of code which return me Trying to get property of non-object on foreach($account_types as $account_type)
Change your code with following it will solved your problem :-
$result_set = array();
$account_types = json_decode(json_encode($account_types), true);
foreach($account_types as $account_type){
$result_set[$account_type->db_name] = array(
'subscribed' => $this->members_model->getAllSubscribedMembers($account_type->id),
'unsubscribed' => $this->members_model->getAllUnsubscribedMembers($account_type->id)
);
}
Always take care of your query results in the model:
This could be possible that the query returns null so you better test the result first:
if ($query->num_rows() > 0)
{
foreach ($query->result() as $row)
{
echo $row->title;
echo $row->name;
echo $row->body;
}
}
You can also pass a string to result() which represents a class to instantiate for each result object. More Information
Related
Here is my model:
public function count_diabetic(){
$query = $this->db->query("Select count(diabetic) as count_diabetic from member where diabetic is not NULL");
return $query->result_array();
}
public function count_hypertensive(){
$query = $this->db->query("Select count(hypertensive) as count_hypertensive from member where hypertensive is not NULL");
return $query->result();
}
here is my controller:
public function home(){
$this->load->model('Jsv_model');
$data = array(
'count_diabetic' => $this->Jsv_model->count_diabetic(),
'count_hypertensive' => $this->Jsv_model->count_hypertensive()
);
$this->session->set_userdata($data);
$this->load->view('home');
}
Here is my view with in php tag:
echo $this->session->userdata('count_diabetic');
But Here it shows error that array to string conversion error..
please help me
Inside count_diabetic() you should change $query->result_array()
into
$query->row()->count_diabetic,
it would return number of count only not array.
Do it to count_hypertensive() too.
In PHP, you can display arrays by using the print_r function instead of echo.
For example, you have to change your code to:
print_r($this->session->userdata['count_diabetic']);
You are doing it wrong in this line.
echo $this->session->userdata('count_diabetic');
What should you do?
// To Set a Data in Session
$session_data = array(
'count_diabetic' => $this->Jsv_model->count_diabetic(),
'count_hypertensive' => $this->Jsv_model->count_hypertensive()
);
$this->session->set_userdata('user_data', $session_data);
// To get the session data
$session_data = $this->session->userdata('user_data');
$user_name = $session_data['username'];
$count_diabetic = $session_data['count_diabetic'];
$count_hypertensive = $session_data['count_hypertensive'];
i'm trying to generates pdfs in loop against member id, but every time i got only the first one, i addedd code in foreach so it runs multiple times, but it gives me only one pdf.please someone help me.
public function pdf($ids){
$k = 0;
foreach ($ids as $key => $id) {
$data[$k]['academics'] = $this->Utility_model->get_all_from_table_where('member_academics', array('member_id' => $id));
$data[$k]['member_employment'] = $this->Utility_model->get_all_from_table_where('member_employment', array('member_id' => $id));
$data[$k]['member_data'] = $this->Utility_model->get_all_from_table_where('members',array('member_id' => $id));
$data[$k]['disclosure'] = $this->Utility_model->get_all_from_table('generalsettings',array('key'=>'disclosure'));
$data[$k]['enrollment_fee'] = $this->Utility_model->get_all_from_table('member_invoices',array('user_id' => $id,'paymentFor'=>'Enrollment Fee'));
$data[$k]['enrollment_fee']['payment'] = $this->Utility_model->get_all_from_table('member_payments',array('invoice_id'=>$data[$k]['enrollment_fee']['id']));
$j=0;
if (!empty($data[$k]['member_data'])) {
foreach ($data[$k]['member_data'] as $member) {
$data[$k]['member_data'][$j]['term'] = $this->Utility_model->get_all_from_table('term', array('term_id' => $member['term_id']));
$data[$k]['member_data'][$j]['degree'] = $this->Utility_model->get_all_from_table('degree', array('degree_id' => $member['degree_id']));
$data[$k]['member_data'][$j]['year'] = $this->Utility_model->get_all_from_table('year', array('year_id' => $member['year_id']));
$data[$k]['member_data'][$j]['address'] = $this->Utility_model->get_all_from_table('member_addresses', array('id' => $member['address_id']));
$j++;
}
}
$this->load->view('admin/reports_management/applications_pdf/pdf_output',$data[$k],false);
$html = $this->output->get_output();
$this->load->library('dompdf_gen');
$this->dompdf->load_html($html);
$this->dompdf->render();
$this->dompdf->stream($k."file".".pdf");
$k++;
}
// echo "<pre>";
// print_r($data);
// die;
}
As long as you only request the page once you cannot get the controller method to output more than one file. You could either try to instead make a multiple page PDF or you need to change how the controller is called, and call it multiple times.
See this answer for some input about making multiple page PDF: How to create several pages with dompdf
http error occured while calling data from model using function
model
public function getProductCombo() {
$q = $this->db->get_where('products', array('type' => 'combo'));
if ($q->num_rows() > 0) {
foreach (($q->result()) as $row) {
$data[] = $row;
}
return $data;
}
}
controller
function sets() {
$this->sma->checkPermissions();
$this->load->helper('security');
$this->data['error'] = (validation_errors() ? validation_errors() :
$this->session->flashdata('error'));
// problem in this line also
$this->data['showcombo'] = $this->load->sales_model->getComboProduct();
$bc = array(array('link' => base_url(),
'page' => lang('home')),
array('link' => site_url('sales'),
'page' => lang('products')),
array('link' => '#', 'page' => "sets")
);
$meta = array('page_title' => "Add Sets", 'bc' => $bc);
$this->page_construct('sales/sets', $meta, $this->data);
}
First of all, No need to include the curly braces for $q->result
foreach ($q->result as $row)
{
$data[] = $row;
}
No need to use validation_errors in your php file.You can directly load your form page.Use validation_errors() in view page.
In your Controller, do this
if ($this->form_validation->run() == FALSE)
{
$this->load->view('myform');
}
Then in your formpage you can echo
<?php echo validation_errors(); ?>
change this line to
$this->data['showcombo'] = $this->load->sales_model->getComboProduct();
this
$this->data['showcombo'] = $this->load->sales_model->getProductCombo();
Because your
model name is
public function getProductCombo()
{
}
Firstly you load model in controller. And then called function, which you have defined in model..
$this->load->model('sales_model','sales'); // sales is alias name of model name
$this->data['showcombo'] = $this->sales->getComboProduct();
Im trying to get joins to work when selecting a single row. here is my code:
model:
function view($id) {
$this->db->select('c.name
,c.phone
,c.active
,c.website
,c.date_acquired
,con.firstName');
$this->db->from('company c');
$this->db->join('contacts con','c.primary_contact = con.id','left');
$this->db->where('id', $id);
$query = $this->db->get();
return $query->row_array();
controller:
public function view($id)
{
$this->load->model('Company_model');
$data['data']= $this->Company_model->view($id);
$this->load->view('templates/header');
$this->load->view('company/view', $data);
$this->load->view('templates/footer');
}
the error im getting is:
Fatal error: Call to a member function row_array() on a non-object in
/home/techf/public_html/application/models/company_model.php on line
35
and line 35 in the above code is:
$query = $this->db->get()
is this not correct when dealing with joins and a row array?
**
edit 1
**:
Here is my controller:
public function view($id)
{
$this->load->model('Company_model');
$data = $this->Company_model->view($id)->row();
$this->load->view('templates/header');
$this->load->view('company/view', $data);
$this->load->view('templates/footer');
}
and my model:
function view($id) {
$this->db->select('*');
$this->db->from('company');
$this->db->join('contacts con','c.primary_contact = con.id','left');
$this->db->where('id', $id);
return $this->db->get('company');
}
but now im am getting error:
Fatal error: Call to a member function row() on a non-object in
/home/techf/public_html/application/controllers/company.php on line 21
Here you go model code
public function get_joins($table,$value,$joins,$where,$order_by,$order)
{
$this->db->select($value);
if (is_array($joins) && count($joins) > 0)
{
foreach($joins as $k => $v)
{
$this->db->join($v['table'], $v['condition'], $v['jointype']);
}
}
$this->db->order_by($order_by,$order);
$this->db->where($where);
return $this->db->get($table);
}
and in your controller aceess it like
$value=('restaurantorders.*,restaurant.Name,restaurant.CurrencyId,currency.*,orderpaymentdetail.Gateway ');
$joins = array
(
array
(
'table' => 'tk_restaurant',
'condition' => 'restaurant.Id = restaurantorders.RestaurantId',
'jointype' => 'inner'
),
array
(
'table' => 'tk_currency',
'condition' => 'restaurant.CurrencyId = currency.Id',
'jointype' => 'inner'
),
array
(
'table' => 'tk_orderpaymentdetail',
'condition' => 'restaurantorders.Id = orderpaymentdetail.OrderId',
'jointype' => 'inner'
),
);
$data['order_detail'] = $this->general_model->get_joins($data['tbl'],$value,$joins,array('OrderStatus'=>'Confirm','restaurantorders.Id'=>$orderid),'restaurantorders.Id','desc')->row();
note that on the model i test first if num_rows() is greater than 1 before sending on the row and if not return false.
Note that on my this->db->get i removed the name of the table, because you already added it on the from method.
$this->db->select('*')
->from('company c');
->join('contacts con','c.primary_contact = con.id','left');
->where('id', $id);
$query = $this->db->get();
return $query->num_rows() >= 1 ? $query->row() : FALSE;
on your COntroller
on on the data variable you forgot to add a key, this will be used when you access the variable/object on you're view, example is $data['contacts']
public function view($id)
{
$this->load->model('Company_model');
$data['contacts'] = $this->Company_model->view($id);
$this->load->view('templates/header');
$this->load->view('company/view', $data);
$this->load->view('templates/footer');
}
on your VIEWS
access the contacts key that you assigned earlier on you're controller.
<?
if(!empty($contacts))
{
print_r($contacts);
}else{
echo 'No data';
}
?>
to show the structure of your query on a standard MySQL query
you could comment out the return on you're model and add this snippets of code just after the $this->db->get() method.
echo $this->db->last_query();
die();
This will echo out what query was made, and you can run it on phpmyadmin and compare if the values returned are right.
can you try it like this maybe?
model: (i'm not sure in which table is id and in which primary_contact, so change that if i made a mistake)
function view($id) {
$this->db->join('contacts','company.primary_contact = contacts.id','left')
->where('id', $id);
$query = $this->db->get('company');
return $query->row();
}
in controller call it like this:
$data['result'] = $this->company_model->view($id);
then access object in view:
<?=$result->id?> (etc.)
here's my problem:
Codeigniter's doc says this :
<?php
$array = array('name' => $name, 'title' => $title, 'status' => $status);
$this->db->where($array);
// Produces: WHERE name = 'Joe' AND title = 'boss' AND status = 'active'
?>
I just want to pass conditions to my where clause from controller to model so :
Controller
<?php
$condition = array('id' => $id_user)
$data['info_user'] = $this->user_model->get_user($condition);
?>
Model
public function get_user($condition)
{
$q = $this
->db
->where($condition)
->get('users');
if($q->num_rows > 0)
{
return $q->row();
}
}
This return : SELECT * FROM (users) WHERE 3 IS NULL
But when I put my array directly in the model ($
There is no need to pass an array and I'm not even positive that it can be done the way you're trying to do it. Just pass the value itself to the model as below. Answer edited to show multiple variables.
Controller:
$data['info_user'] = $this->user_model->get_user($id_user,$user_login);
Model:
public function get_user($id_user,$user_login)
{
$q = $this
->db
->where('id_user',$id_user)
->or_where('user_login',$user_login);
->get('users');
if($q->num_rows == 1)
{
return $q->row();
}
}
As a side note when you want a single result from your database, as in retrieving a user ALWAYS check for a single result and not > 0. You want to ensure you're only getting one user back.