Number of string value occurrences for distinct another column value - ruby

Question

I have a model Counter which returns the following records:
name.....flowers.....counter
vino.....rose.........1
vino.....lily.........1
gaya.....rose.........1
rosi.....lily.........1
vino.....lily.........1
rosi.....rose.........1
rosi.....rose.........1
I want to display in the table like:
name | Rose | Lily |
---------------------
Vino | 1 | 2 |
---------------------
Gaya | 1 | 0 |
---------------------
Rosi | 2 | 1 |
I want to display the count of flowers for each distinct name. I have tried the following and wondering how can I do it elegantly?
def counter_results
#counter_results= {}
Counter.each do |name|
rose = Counter.where(flower: 'rose').count
lily= Counter.where(flower: 'lily').count
#counter_results['name'] = name
#counter_results['rose_count'] = rose
#counter_results['lily_count'] = lily
end
return #counter_results
end
which I don't get the hash values.

Answer 1

This will give you slightly different output, but I think it is probably closer to what you want than what you showed.
You can use the query:
Counter.group([:name, :flowers]).sum(:counter)
To get a result set that looks like:
{ ["vino", "rose"] => 1, ["vino", "lily"] => 2, ["gaya", "rose"] => 1, ["gaya", "lily"] => 0, ... }
And you can do something like this to generate your hash:
def counter_results
#counter_results = {}
Counter.group([:name, :flowers]).sum(:counter).each do |k, v|
#counter_results[k.join("_")] = v
end
#counter_results
end
The resulting hash would look like this:
{
"vino_rose" => 1,
"vino_lily" => 2,
"gaya_rose" => 1,
"gaya_lily" => 0,
...
}
Somebody else may have a better way to do it, but seems like that should get you pretty close.