I have a file called worker.dat, and in that file, a list of information is stored as variables "Income","Promotion", "Age" etc.
And I want to read that information from the file and print on the screen.
So I used
Open App.Path & "worker.DAT" For Input As #1
and using the Print method, printed the information.
However for the sake of emphasis, I want to print some information in a bigger size and in different font etc.
So I wrote this.
Printer.FontSize = 16
Printer.Print "Income = "; Income
However this didn't work. Does anyone how to fix this problem?
Set the size on the font object:
Dim pt As Long
With Printer.Font
pt = .Size
Printer.Print "default text"
.Size = 16
Printer.Print "larger text"
.Size = pt
.Bold = True
Printer.Print "bold ";
.Bold = False
Printer.Print "in default size"
Printer.EndDoc
End With
Related
In a RichTextBox, when sending EM_LINEINDEX to get the index of the first character of a line, the index will be affected by soft line breaks. Consider the following text box:
Calling SendMessage hWnd, EM_LINEINDEX, 1, 0 will result in 25, while I would expect it to return 45 (line 1 should be "this is another line" not "and continues here").
Is there a way to get the real first char index of the second line using WinAPI calls?
This is from a working program. I play with right margin.
Sub mnuWordWrap_Click()
'On Error Resume Next
If txtNote.RightMargin = 0 Then
txtNote.RightMargin = &HFFFE&
mnuWordWrap.Checked = False
Else
txtNote.RightMargin = 0
mnuWordWrap.Checked = True
End If
txtNote.SetFocus
txtNote_SelChange
End Sub
In another program I do this, though this is Vista's RTF window (not a control so not the old ANSI version of RTF as in VB6)
If mnuViewWordWrap.Checked = True Then
Ret = SendMessageByVal(gRtfHwnd, EM_SETTARGETDEVICE, GetDC(gRtfHwnd), -1800)
If Ret = 0 Then ReportError "Form Resize", "Set Target Device"
Else
Ret = SendMessageByVal(gRtfHwnd, EM_SETTARGETDEVICE, GetDC(gRtfHwnd), 4000000)
If Ret = 0 Then ReportError "Form Resize", "Set Target Device"
End If
I'm getting a error message in a VB6 .exe file running on Windows XP.
I compile and "make it" on Windows 7/8, but always get an Overflow error message when it executes this two lines on XP:
sUrl = "C:\Arquivos de Programas\Internet Explorer\IEXPLORE.EXE http://example.com/WebForms/send.aspx?id=" & intCodID & "&type=500&usr=" & intCodUser
openWeb = Shell(sUrl, vbMaximizedFocus)
sUrl is a String and OpenWeb is actually a Integer, but I already declared it as Double and as nothing (just Dim OpenWeb) and still get the overflow error.
UPDATE
Didn't managed to find out what was happening there, but another solution for calling IE:
Dim IE
sUrl = "http://www.google.com/"
Set IE = CreateObject("InternetExplorer.Application")
IE.Visible = True
IE.Navigate sUrl
While the VB6 documentation says Shell() returns a Variant Double... that appears to be obsolete information left over from manuals for earler versions of VB. Instead if you check the typelib info (i.e. look in the IDE's Object Browser) it actually returns a Double type result value.
As far as I can tell Shell() is a wrapper around a call to the WinExec() function.
The returned values are:
0 The system is out of memory or resources.
ERROR_BAD_FORMAT = 11 The .exe file is invalid.
ERROR_FILE_NOT_FOUND = 2 The specified file was not found.
ERROR_PATH_NOT_FOUND = 3 The specified path was not found.
or a Process ID
Also contrary to the documentation, Shell() turns those error values into exceptions ("File not found", "Invalid procedure call or argument," etc.). So if the call succeeds you always get back a PID value.
In all cases this is a DWORD. So it always fits in a Double without the possibility of an overflow. If you are seeing an overflow there is something else going wrong in your code.
Sadly a Double isn't particularly useful here, though it can at least hold the entire range of values. But you'd normally want to carefully convert it to a Long value:
Option Explicit
Function DDoubleToDLong(ByVal DDouble As Double) As Long
'Some functions like the intrinsic Shell() return a Double
'to get around the lack of a UI4 type (DWORD, i.e. unsigned
'Long) in VB. Of course this isn't clean to pass to API
'calls, making it sort of worthless so we need to do a type
'conversion such as this:
If DDouble > 2147483647# Then
DDoubleToDLong = CLng(DDouble - 2147483648#) Or &H80000000
Else
DDoubleToDLong = CLng(DDouble)
End If
End Function
Private Sub Form_Load()
Dim DD As Double
Dim DL As Long
AutoRedraw = True
Font.Name = "Courier New" 'Or other handy monospaced font.
Font.Size = 12#
DD = 0#: DL = DDoubleToDLong(DD): Print DD, DL, Hex$(DL)
DD = 1#: DL = DDoubleToDLong(DD): Print DD, DL, Hex$(DL)
DD = 2147483647#: DL = DDoubleToDLong(DD): Print DD, DL, Hex$(DL)
DD = 2147483648#: DL = DDoubleToDLong(DD): Print DD, DL, Hex$(DL)
DD = 4294967295#: DL = DDoubleToDLong(DD): Print DD, DL, Hex$(DL)
End Sub
Integer is worthless since overflows will be common. Long without the conversion could cause overflows now and then. String is just silly.
You also need to quote the values for the EXE and its arguments property, as in:
Option Explicit
Function DDoubleToDLong(ByVal DDouble As Double) As Long
If DDouble > 2147483647# Then
DDoubleToDLong = CLng(DDouble - 2147483648#) Or &H80000000
Else
DDoubleToDLong = CLng(DDouble)
End If
End Function
Private Sub Form_Load()
Dim sUrl As String
Dim PID As Long
sUrl = """C:\Arquivos de Programas\Internet Explorer\IEXPLORE.EXE"" " _
& """http://example.com/WebForms/send.aspx?id=" _
& intCodID _
& "&type=500&usr=" _
& intCodUser _
& """"
PID = DDoubleToDLong(Shell(sUrl, vbMaximizedFocus))
End Sub
Even this isn't quite "right" since exception handling should be added. And both intCodID and intCodUser may require "cleansing" (UrlEncoding) depending on what types they are and what values they really have. These might be Integers based on the names, with you relying on implicit String coercion? If so they might be Ok.
BTW, as we see above special folder names get localized. For that matter the system drive might not even be C:\ at all! So such paths should never be hard-coded but instead be built up based on values returned from calls to Shell32 to look up the special folder.
An integer can only be a whole number. No decimals.
You say it's declared as an integer therefore you cannot assign 1. anything, and you certainly can't assign anything like that to a number variable as it's not a valid number anyway as it has two decimal points.
You need to declare it as string.
Looking at my server, i see filenames, that theur characters have been messed up.
Example: ôøùú-ô÷åãé-1.mp3
should should be Hebrew letters.
While the files can be read in a browser and FTP, they cannot be read always - for example, in an online audio player, or VBScript FSO (File system object)
is there something that can be done to change the charset or something, so that i can read and then rename these files?
Thanks!
solved, using this link: http://pastebin.com/yXRWDggY
function convertChar(letter)
lat = array("à","á","â","ã","ä","å","æ","ç","è","é","ê","ë","ì","í","î","ï","ð","ñ","ò","ó","ô","õ","ö","÷","ø","ù","ú", " " )
heb = array("א","ב","ג","ד","ה","ו","ז","ח","ט","י","ך","כ","ל","ם","מ","ן","נ","ס","ע","ף","פ","ץ","צ","ק","ר","ש","ת", " ")
inarray = false
for ii = 0 to ubound(heb)
if letter = heb(ii) then
convertChar = lat(ii)
inarray = true
exit for
end if
next
if inarray = false then convertChar = letter
end function
I would like to get a working code to simply remove from a text line a specific part that always begins with "(" and finish with ")".
Sample text : Hello, how are you (it is a question)
I want to remove this part: "(it is a question)" to only keep this message "Hello, how are you"
Lost...
Thanks
One way using Regular Expressions;
input = "Hello, how are you (it is a question)"
dim re: set re = new regexp
with re
.pattern = "\(.*\)\s?" '//anything between () and if present 1 following whitespace
.global = true
input = re.Replace(input, "")
end with
msgbox input
If the part to be removed is always at the end of the string, string operations would work as well:
msg = "Hello, how are you (it is a question)"
pos = InStr(msg, "(")
If pos > 0 Then WScript.Echo Trim(Left(msg, pos-1))
If the sentence always ends with the ( ) section, use the split function:
line = "Hello, how are you (it is a question)"
splitter = split(line,"(") 'splitting the line into 2 sections, using ( as the divider
endStr = splitter(0) 'first section is index 0
MsgBox endStr 'Hello, how are you
If it is in the middle of the sentence, use the split function twice:
line = "Hello, how are you (it is a question) and further on"
splitter = split(line,"(")
strFirst = splitter(0) 'Hello, how are you
splitter1 = split(line,")")
strSecond = splitter1(UBound(Splitter1)) 'and further on
MsgBox strFirst & strSecond 'Hello, how are you and further on
If there is only one instance of "( )" then you could use a '1' in place of the UBound.
Multiple instances I would split the sentence and then break down each section containing the "( )" and concatenate the final sentence.
How to strip ALL HTML tags using MSHTML Parser in VB6?
This is adapted from Code over at CodeGuru. Many Many thanks to the original author:
http://www.codeguru.com/vb/vb_internet/html/article.php/c4815
Check the original source if you need to download your HTML from the web. E.g.:
Set objDocument = objMSHTML.createDocumentFromUrl("http://google.com", vbNullString)
I don't need to download the HTML stub from the web - I already had my stub in memory. So the original source didn't quite apply to me. My main goal is just to have a qualified DOM Parser strip the HTML from the User generated content for me. Some would say, "Why not just use some RegEx to strip the HTML?" Good luck with that!
Add a reference to: Microsoft HTML Object Library
This is the same HTML Parser that runs Internet Explorer (IE) - Let the heckling begin. Well, Heckle away...
Here's the code I used:
Dim objDocument As MSHTML.HTMLDocument
Set objDocument = New MSHTML.HTMLDocument
'NOTE: txtSource is an instance of a simple TextBox object
objDocument.body.innerHTML = "<p>Hello World!</p> <p>Hello Jason!</p> <br/>Hello Bob!"
txtSource.Text = objDocument.body.innerText
The resulting text in txtSource.Text is my User's Content stripped of all HTML. Clean and maintainable - No Cthulhu Way for me.
One way:
Function strip(html As String) As String
With CreateObject("htmlfile")
.Open
.write html
.Close
strip = .body.outerText
End With
End Function
For
?strip("<strong>hello <i>wor<u>ld</u>!</strong><foo> 1234")
hello world! 1234
Public Function ParseHtml(ByVal str As String) As String
Dim Ret As String, TagOpenend As Boolean, TagClosed As Boolean
Dim n As Long, sChar As String
For n = 1 To Len(str)
sChar = Mid(str, n, 1)
Select Case sChar
Case "<"
TagOpenend = True
Case ">"
TagClosed = True
TagOpenend = False
Case Else
If TagOpenend = False Then
Ret = Ret & sChar
End If
End Select
Next
ParseHtml = Ret
End Function
This is a simple function i mafe for my own use.
use Debug window
?ParseHtml( "< div >test< /div >" )
test
I hope this will help without using external libraries