So I am tryng to create a comment form and a comment view within a post view.
Basically i have a post view from my blog, and i want to show a comments form and a comment section on each.
I have the views all prepared, and so far i have my form displayed at the bottom of my post view.
What i am looking to do is add my comments view to the post view above the form.
Comment Controller
// GET: /Comments/_AllComments - Partial view
public ViewResult _AllComments(int postid)
{
TempData["PostId"] = postid;
return View("_AllComments");
}
Post Detail View
#model MyProject.Models.Post
//MARKUP OMITTED
//Comments Partial View
#Html.Partial("_AllComments", new Invest.Models.Comment())
//Comments Form Partial View
#Html.Partial("_Comment_Form", new Invest.Models.Comment())
Partial View - All Comments
#model IEnumerable<MyProject.Models.Comment>
//MARKUP OMITTED
The error that i get is:
The model item passed into the dictionary is of type 'MyProject.Models.Comment', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[MyProject.Models.Comment]'.
Could someone tell me how I get round this?. I have tried changing the partial to Html.RenderPartial which didnt work either.
If you look closely you will see that your partial view needs a collection and you are passing a single object.
To solve this you can change the line with partial to like below:
//Comments Partial View
#Html.Partial("_AllComments", new List<Invest.Models.Comment>(){ new Invest.Models.Comment()})
Note: Using Html.Partial won't make a call to Action _AllComments, if you want to use the result of that action (the partial view), Html.Action or Html.RenderAction are used to do that.
Related
i am new in mvc. now learning. i was searching various technique to load partial view in mvc and i got good one in stackoverflow. here it is.
If you want to load the partial view directly inside the main view you could use the Html.Action helper:
#Html.Action("Load", "Home")
or if you don't want to go through the Load action use the HtmlPartial hepler:
#Html.Partial("_LoadView")
If you want to use Ajax.ActionLink, replace your Html.ActionLink with:
#Ajax.ActionLink(
"load partial view",
"Load",
"Home",
new AjaxOptions { UpdateTargetId = "result" }
)
and of course you need to include a holder in your page where the partial will be displayed:
<div id="result"></div>
Also don't forget to include:
<script src="#Url.Content("~/Scripts/jquery.unobtrusive-ajax.js")" type="text/javascript"></script>
in your main view in order to enable Ajax.* helpers. And make sure that unobtrusive javascript is enabled in your web.config (it should be by default):
<add key="UnobtrusiveJavaScriptEnabled" value="true" />
after going through the above code one confusion occur. help require. my confusion as below.
#Html.Action("Load", "Home")
#Html.Partial("_LoadView")
i know the use of #Html.Partial("_LoadView") but do not understand how #Html.Action("Load", "Home") will work ?
can anyone show me couple of example to show the various usage of
#Html.Action("Load", "Home")
and how it is different from #Html.Partial("_LoadView")
thanks
Html.Partial
Renders the partial view as an HTML-encoded string.
This method result can be stored in a variable, since it returns string type value.
Simple to use and no need to create any action.
Partial method is useful used when the displaying data in the partial view is already in the corresponding view model.For example : In a blog to show comments of an article, we would like to use RenderPartial method since an article information with comments are already populated in the view model.
#Html.Partial("_Comments")
Html.Action
Renders the partial view as an HtmlString .
For this method, we need to create a child action for the rendering the partial view.
This method result can be stored in a variable, since it returns string type value.
Action method is useful when the displaying data in the partial view is independent from corresponding view model.For example : In a blog to show category list on each and every page, we would like to use Action method since the list of category is populated by the different model.
#{Html.Action("Category","Home");}
#Html.Action("Load", "Home")
Will execute the "Load" ActionResult in your "HomeController".
This Action may return any of these (ref: MSDN):
ContentResult
EmptyResult
FileResult
HttpUnauthorizedResult
JavaScriptResult
JsonResult
RedirectResult
RedirectToRouteResult
ViewResultBase
While
#Html.Partial("_LoadView")
Will insert your partial view "_LoadView" into your current view.
If you're familiar with web forms, think of your partial views as .ascx (user controls).
Edit:
Example of usage of #Html.Action():
Say you have this view:
<p>Here is my name: #Html.Action("Name")</p>
And this is my controller (As you see, I use the overload of Html.Action() that implicit uses the controller you're routed to):
public class FooController : Controller
{
//
// GET: /Foo/
public ActionResult Index()
{
return View();
}
// GET: /Foo/Name
public ActionResult Name()
{
return Content("Annish");
}
}
My MVC page has a Parent view that show the Parish page. Every Parish has multiple Churches and Every Church has its Own mass times. Parish page has Churches as Partial View but I want to use Church ID to render another Parital view of Mass times (Stored Procidure). How can use the ID of a partial view and create anothe partial view. I had been banging my head but unable to get this resolved.
render the Partial view in Side the Div tag. Then use the div ID and Clone the div to create a another partial view.
See below code sample.
<Div id="SomeId">
//Render your partial view here.
</Div>
Clone the Div and create as many partial view u need.
I finally got it working... I was now able to get the Partial view work...
Stored Procedure inside the controller:
public ActionResult Timing(int id)
{
var massTimings = db.masTimings(id);
return PartialView(massTimings);
}
My View inside Locations Partial View:
#Html.Action("Timing",new {id = item.LocationID})
I currently have a _layout.cshtml used by every page of my website.
I need to put a form on each page displayed as a popin.
So, i created a new PartialView (the content of my form) with its corresponding ViewModel and called it in _layout.cshtml.
However, i have a model conflict between ViewModels of pages using the layout and the ViewModel used by the new form (since we can't have directly two models for the same view).
The model item passed into the dictionary is of type 'XXX', but this
dictionary requires a model item of type 'YYY'.
How can we include a form in _layout without this conflict ?
The following has worked for me with a sidebar on every page.
Create a controller for your partial view
In that controller, create a method for the view you want to return, and be sure to use the [ChildActionOnly] filter
public class PartialController : Controller
{
[ChildActionOnly]
public PartialViewResult Alerts()
{
return PartialView("Alerts", messages);
}
}
In your _layout view, you'll have the following:
#Html.Action("Alerts", "Partial")
(instead of #Html.RenderPartial or #Html.Partial)
It sounds like you already have what you need for the view.
I have not used this with a form, but it should work similarly. Hope this helps.
I am wondering about a couple variations of forms and partial forms. The submit is on the parent page and I have varied what I pass to the partial view. I have a parent view with a related HomeViewModel (which has public properties Name and public Person Employee {get;set;}
1.) Scenario 1: The main view has something like the following
#model MasterDetailSample.Models.HomeViewModel
#using (Html.BeginForm()) {
<div>
#{Html.RenderPartial("_PersonView", #Model);}
</div>
<input type="submit" value="Save" />
}
In this scenario I am passing to the partial view _PersonView the entire HomeViewModel. Within _PersonView partial view I have to reference a property of the HomeViewModel i.e. Person object via #model.Employee.Name (in this scenario the submit is on the parent form (not within the partial view))
When I hit submit on the form (POST) in the controller i have to access the property of Employee "Name" via the following model.Employee.Name
This seems to work however notice the following variation scenario 2 (where I only pass to the partial the Employee object)
2.) Scenario 2
In this scenario I only want to send the Employee object to the partial view. Again the begin form and submit is on the parent form.
So from the parent form i have
#{Html.RenderPartial("_MasterView", #Model.Employee);}
and so within the partial view i reference the Name property of the Person object via #Employee.Name Now when I submit the form within the controller the Employee object is not available from the auto model binder. I can access the properties via formcollection but not from the model parameter
i.e.
[HttpPost]
public ActionResult Index(ModelViewModel model) {
**//model.Employee is null!**
return View();
}
Why? (is model.Employee null) I would like my partial view to only accept an object of type Person however after submitting from the parent page, the Employee property is null. On the partial view I am using the following on the #model line
#model MasterDetailSample.Models.Person
I would like the partial to only need a Person object to be sent to it, but I would like the submit on the main form. If i do it this way I can re-use the partial view in a few situations however IF i must send HomeViewModel i have significantly limited how I can use this partial view. So, again, I only want to use Person as the model with the partial view but I need to be able to access the properties when submitted from the parent view.
Can this be done? If yes how?
thx
You have a couple of options:
1) One I recommend -> Dont use partial views, instead use EditorFor and create an editor template for Person. With partial views the context is whatever model you pass into the view, this is why your example (1) works and (2) not. However with editor templates the parent context is taken into consideration with the html helpers and will generate the correct input names. Have a look at Darin Dimitrov's answer to a similar question.
2) Use your second example as is, but change the post action to look something like this:
[HttpPost]
public ActionResult Index(ModelViewModel model) {
TryUpdateModel(model.Employee);
**//model.Employee should now be filled!**
return View();
}
3) Use custom html helpers that accepts prefix for input, see this answer I posted a while back for example code. You could then use this inside your partial view.
In my asp.net mvc3 application i have created two partial views for two different action that is,
partialviewresult setcomment and
partialviewresult getcomment
i have created partial view using create a strongly type view and different scaffold template
for _setcomment i am using create template and for _getcomment i am using List template.
Now i want to call both _setcomment and _getcomment partial view in one view.
in my view file .cshtml
_setcomment -
#model <NAMESPACE>.<MODELNAME>
<some code>
_getcomment -
#model IEnumerable<<NAMESPACE>.<MODELNAME>>
<some code>
how can i call diiferent partial view in one view?
any suggestions?
There are different ways to do it.
If you already have the model class data in the Main view you can use like
In the main view call
#Html.Partial("PartialViewName1",model1)
#Html.Partial("PartialViewName1",model2)
If you do not have the model class data in the mail view then you can call the action on the controller and from there return the partial view.
#Html.Action("Controller","Action1")
#Html.Action("Controller","Action2")
In the Controller class
PartialResult Action1()
{
model = new ModelClass();
return PartialView(model);
}
Hope this helps.
The answer to your question is to use the following within a single view:
#{ Html.RenderAction("ActionName", "ControlerName"); }
#{ Html.RenderAction("ActionName2", "ControlerName2"); }
This would do what you are trying to achieve, however, I think there is a problem with design. What are you trying to achieve?