This question already has answers here:
bash script order of execution
(2 answers)
Closed 7 years ago.
I was just wondering, in a bash script, if I have a command on one line to say rsync a large file (~10GB) then the next command on the next line is meant to rename then move that same file, will the script know to wait for the rsync to complete before attempting the rename and move?
Is there a flag or something I can put on each line to make it wait before executing the next command?
Sorry if this seems like a total noob question, but alas I am a noob!
Thanks in advance for any info!
All commands are executed in sequence, so, a command will wait for the previous command to complete. Only when you add a & to the end of a command will it run in the background, and thus not wait for completion before executing the next.
Related
This question already has answers here:
How can I debug a Bash script? [closed]
(12 answers)
Closed 2 years ago.
I'm not sure I address this problem correctly, but I've search and search over the net and found nothing, yet.
I'm writing a bash script and I want to see what the script is really doing when being executed, like a log of all the commands, one by one, what are executed - this way, I'll be able to see why my script is falling.
Note : I've post similar question in the past, someone told me I run my bash script with sh -xe script.sh but it doesn't give me enough information to debug properly.
Please advise. Thanks!
Adding set -x at the beginning of the script displays, in the terminal, all the commands sent by the script as the terminal received it. It was exactly what I needed and it working perfectly.
This question already has answers here:
How to create batch file in Windows using "start" with a path and command with spaces
(7 answers)
Closed 2 years ago.
So normally I have several *.bat files to automate some things in my computer.
But I'm kinda stuck in this call...
cd "C:\Users\user\AppData\Local\Programs\program2Execute"
start program has spaces.exe
I don't get the app executed, instead I get a cmd window with the cd command result, nothing else. I tried to quote "program has spaces.exe" but it doesn't get executed I get the window duplicated instead.
Apologize if this is kinda dumb to ask, but I have spent quite time looking for the answer.
Thanks in advance.
If you use the start command:
start "" "a program with spaces.exe"
start will use the first double quoted string as the title and the 2nd as the command.
Or don't use start:
"a program with spaces.exe"
This question already has answers here:
How do I run a shell script without using "sh" or "bash" commands?
(13 answers)
How to enable a system-wide function for users including sudo?
(2 answers)
Closed 3 years ago.
I have a bash script called climb.sh. When I execute it I write
./climb.sh 1
while inside the directory in which the script is located. However, I want to do the same thing wherever I am, and across all shell sessions by simply calling
climb 1
Also, climb.sh takes an numeric argument and calls "cd ../" that many times. In order for the program to work, it has to run alongside the current process, not within some child process.
How to achieve all this?
Thanks
This question already has answers here:
Loop background job
(3 answers)
Closed 4 years ago.
Is it possible to run a command in a for loop without waiting for that command ended, while keeping going to the next iteration?
Because I have to send multi-files at the same time asap via many ssh connections, therefore I couldn't wait until the command ended one by one.
Maybe is it related to something like 'xterm' or 'gnome-terminal'?
Yes, you can execute the command in background by adding & at its end.
So the syntax looks like programName [arguments] & (at least for bourne compatible shells)
This question already has answers here:
What does "program &" mean on the command line?
(2 answers)
Closed 5 years ago.
Recently I am learning how to write bash script.
I noticed that in other's code, there is a line calling a function like this:
restartApp ${array[app]} $num &
I know the first two are variables that passing to the function, but I really don't understand what is the last symbol & here?
If you end the line with & the process starts in the background. This means you can continue to use the shell and do not have to wait on the output.