Laravel Modeling join three Table in single line - laravel

Question

i have 3 table/Model such as Users, CurrentCurrency and CurrencyType, in CurrentCurrency 2 column are relation with CurrencyType and Users, as user_id and currency_id
i can use this code to fetch CurrentCurrency user :
$all_records = CurrentCurrency::with('user')->orderBy('id', 'DESC')->paginate(50);
this code return all records with users, now i want to create simple related with CurrencyType by Modeling, unfortunately for this table i get null
CurrentCurrency :
class CurrentCurrency extends Model
{
protected $table = 'current_currency';
protected $fillable = ['currency_id', 'current_money', 'user_id'];
/**
* #return \Illuminate\Database\Eloquent\Relations\BelongsTo
*/
public function user()
{
return $this->belongsTo('App\User');
}
public function currency_type()
{
return $this->belongsTo('App\CurrencyType');
}
}
CurrencyType:
class CurrencyType extends Model
{
protected $table = 'currency_type';
protected $fillable = ['currency_type', 'currency_symbol', 'user_id'];
public function user()
{
return $this->belongsTo('App\User');
}
public function currency()
{
return $this->hasMany('App\current_currency');
}
}
User:
class User extends Model implements AuthenticatableContract,
AuthorizableContract,
CanResetPasswordContract
{
use Authenticatable, Authorizable, CanResetPassword;
/**
* The database table used by the model.
*
* #var string
*/
protected $table = 'users';
/**
* The attributes that are mass assignable.
*
* #var array
*/
protected $fillable = ['name', 'email', 'password'];
/**
* The attributes excluded from the model's JSON form.
*
* #var array
*/
protected $hidden = ['password', 'remember_token'];
/**
* #param $value
*/
public function setPasswordAttribute($value)
{
$this->attributes['password'] = Hash::make($value);
}
/**
* #return \Illuminate\Database\Eloquent\Relations\HasMany
*/
public function currentCurrency()
{
return $this->belongsToMany('User', 'CurrentCurrency', 'user_id', 'currency_id');
}
/**
* #return \Illuminate\Database\Eloquent\Relations\HasMany
*/
public function currencyType()
{
return $this->hasMany('App\CurrencyType');
}
}
By this code i can get user information:
$all_records = CurrentCurrency::with(['user', 'currency_type'])->orderBy('id', 'DESC')->paginate(50);
foreach ($all_records as $key => $contents) {
echo $contents->user;
}
But i can not get currency_type, thats return null
RESULT:
{"id":3,"current_money":"333","user_id":1,
"created_at":"\u0622\u0630\u0631 20\u060c 1394",
"updated_at":"\u0622\u0630\u0631 20\u060c 1394",
"currency_id":1,"user":{"id":1,"name":"\u0645\u0647\u062f\u06cc",
"family":"\u067e\u06cc\u0634\u06af\u0648\u06cc","username":"mahdi","token":"",
"email":"pishguy#gmail.com",
"image_file_name":"","mobile_number":"09373036569",
"status":1,"created_at":"\u0622\u0630\u0631 20\u060c 1394",
"updated_at":"\u0622\u0630\u0631 20\u060c 1394"},
"currency_type":null}

Answer 1

You have to update the relation in CurrentCurrency as below:
return $this->belongsTo('App\CurrencyType','currency_id', 'id');
// where currency_id is foreign_key and id is otherKey referring to id of currency_type table
Also update your query to select user with CurrencyType as below :
$all_records = CurrentCurrency::with(array('user','currencyType'))->orderBy('id', 'DESC')->paginate(50);
http://laravel.com/docs/5.1/eloquent-relationships#updating-belongs-to-relationships

Answer 2

In file CurrencyType
return $this->hasMany('App\current_currency');
should be
return $this->hasMany('App\CurrentCurrency');