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For debugging purposes, I want to alter a rake test so as not to end a saved file with a newline.
I don't know ruby. How do I do this? (file.print doesn't seem to work.)
Not clear what you are doing, but since you tried file.print, it looks like you have access to what is to be printed. Let's say this is string. My guess is that string already has a newline character. Then do:
file.print(string.chomp)
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it should be compiled and started only x times and then not anymore, should also be not hackable. for example no use of lock file.
maybe a use-counter in the binary?
im expecting suggestions to my problem here.
For this must use destructur.
Destroyed variables after scope and must nul
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add=+
echo "$((1{$add}2))"
If I write 1+2 it outputs 3, but when I store the + sign in a variable called "add" and then use it in place of + operator, it just outputs it as if it was a string. How can I use the variable and still make it output 3?
As far as I can see, the code is wrong and should not print anything but an error.
What you should do is write the variable as ${add}, not {$add}.
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"Galaxy".match(/(al)*/)
It seems that <<>>Galaxy is the match, where <<>> = matching part. Why is the R.E working? Perhaps because of \b?
RE:
Sorry, it's my fault to post unclear question.
Exactly, i want to know the reason that why the empty space is matched with (al)*.
Finally i could understand by you-all favor :)
The regex /(al)*/ allows it to match nothing at all, which is what it does. It starts at the beginning of the string, matches "nothing" and returns. If you expected it to match the al in Galaxy then you would need to use /(al)+/ to avoid empty matches.
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I want to verify the numbers after a given decimal. Values above 10 should be considered as invalid. I would need a regex command to verify. For example:
Input: Expected response
0.005: valid
1.003: not valid
1.04: valid
I tried the following regex, but it doesn't give me the expected result.
/\d{0,1}\d{0,3}/
If I understand your question correctly
^(0\.\d{3}|[1-9]\.\d{2}|10\.00)$
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I am in a search of one regular expression which validates the following string format "1,a|2,b|3,c".
Also I want to parse this string and extract out the numbers and characters.
Can any one has any idea on what could be the best regular expression.
Thanks
Try this expression: http://regex101.com/r/qI7kW9
/(\d),([a-z])(?:\||$)/gi
The first capturing group will hold the digit, the second will hold the letter. If there will be more than one character that you want to capture, use this:
/(\d+),([a-z]+)(?:\||$)/gi