Good Day! Can the Column Header Color can be changed in Odoo?
Many Thanks
Good Day I found some solutions to my problem Just create a css file and JavaScript get class name of your Field..
Create first a JavaScript
Example:
openerp.your_module_name= function (instance) {
instance.web.list.columns.add('field.your_field_name', 'instance.your_module_name.your_field_name');
instance.your_module_name.your_field_name = instance.web.list.Column.extend({
_format: function (row_data, options) {
res = this._super.apply(this, arguments);
var amount = parseFloat(res);
return "<font color='#0000CD'>"+amount.toFixed(2)+"</font>";
}
});};
This Javascript I only Found it some Forums this code is to change the font color of some columns.
To Change the Column Header is to Call the your_field_name define in JavaScript and Just create a CSS File
CSS
Example:
.openerp .oe_list_your_field_name{
background-color: #FF3333;}
Hope to help with this code :D
Related
I want to change group of CSS items in jqGrid. Documentation is saying
Of course if we want to change not only one CSS item from a group, but two or more we can use jQuery extend to do this:
var my_col_definition = {
icon_move : 'ui-icon-arrow-1',
icon_menu : "ui-icon-pencil"
}
$.extend( $.jgrid.styleUI.jQueryUI.colmenu , my_col_definition );
And this is working partially. But I want to override all icons in my Bootstrap with next code:
$.extend($.jgrid.styleUI.Bootstrap, {
common: {
icon_base: "fa"
},
inlinedit: {
icon_edit_nav: "fa-edit"
},
navigator: {
icon_edit_nav: "fa-edit"
},
// ...
});
and my grid stops working and does not respond to any commands. There are no errors in console.
Do anybody know how to fix the problem in an elegant way and do not override every group separately?
It is unknown which versions of Guriddo jqGrid and Bootstrap are used.
I see you try to use the fontAwesome.
With the last release you can use fontAwesome with ths following settings:
<script>
$.jgrid.defaults.styleUI = 'Bootstrap4';
$.jgrid.defaults.iconSet = "fontAwesome";
</script>
And point to the needed css files as described in this documentation
You can change the icons the way you do in your code without problems - I have tested this and it works.
In any case, please prepare a simple demo which reproduces the problem, so that we can look into it.
How can I change the color of the currency in my kendo numeric textbox in jquery? I used the standard code in creating a numeric textbox in kendo.
$("#currency").kendoNumericTextBox({
format: "c",
});
For example I have $12.00 as value in my input element.
I just want to change the color of the $. Not the 12.00.
How can I achieve this?
Apply css for "k-formatted-value" class textbox i.e. Currency value
Try something like this..
var widget = $("#numeric").kendoNumericTextBox().data("kendoNumericTextBox");
widget.wrapper.find("input.k-formatted-value").css("color", "red");
Refer this link to achieve
http://docs.telerik.com/kendo-ui/controls/editors/numerictextbox/how-to/change-text-color
Updated:
We can do some tricks to change currency format colour change.
I did for normal textbox.
Refer JSfiddle.
For your requirement try something like this.
steps:
1. Create one span element
Create onchange event for the input
$("#salary").kendoNumericTextBox({
change: onChange,
});
Define the style change functionalities.
function onChange() {
ChangeColorFormat($('.k-formatted-value'));
}
function ChangeColorFormat(inp) {
inp.style.color = 'transparent';
var span = document.getElementById('back');
span.innerHTML = inp.value.substr(0, 1) +
"" +
inp.value.substr(1, 1) +
"" +
inp.value.substr(2);
}
Found the solution. Because its kendo, it was simply setting a ClientTemplate before loading it.
I read all the posts regarding freezing column. But still I am unable solve my problem.
When I called setFrozenColumns my column has frozen but along with another column header is added to the grid. So the column headers one more than the columns. How to resolve this. Here is my over view of code.
makeJqueryGridInstance(grid, gridSettings);
window.prepareSortableColumns(grid);
makefrozenColumns(grid);
function makeFrozenColumn( grid )
{
var colmodel = grid.jqGrid('getGridParam', 'colModel');
if (colmodel[0].name === 'cb')
{
grid.jqGrid('setColProp', colmodel[0].name, { frozen: true });
grid.jqGrid('setFrozenColumns');
fixPositionsOfFrozenDivs.call(grid[0]);
}
}
function prepareSortableColumns(grid)
{
var gridSettings = grid.data('settings');
var gridId = gridSettings.gridId;
var columnHeaders = $("#" + "gview_" + gridId.replace("#", "")).find(".ui-jqgrid-htable > thead > tr > th");
var colModel = grid[0].p.colModel;
$.each(columnHeaders, function (index, columnHeader)
{
if (colModel[index].sortable == false)
{
$(columnHeader).find("div").removeClass("ui-jqgrid-sortable");
}
});
}
For the first time, it is working fine and the column has frozen.
But second time when the call made to prepareSortableColumns(grid), the columnHeader having one more than colModel (I debugged through devTools). So I am getting error for that particular columnHeader sortable is undefined.
Can anybody help me with this. Thanks in advance.
The code of prepareSortableColumns seems be wrong. Its not oriented on dives added in case of usage of frozen columns (see the answer for more details and use Developer Tools to examine the structure of the grids). You can try to use grid[0].grid.headers array instead of selecting columnHeaders in the way like you do this.
Additionally it's in general wrong to remove ui-jqgrid-sortable class. The meaning of the class will be frequently misunderstood because of the name. Non-sortable columns have to have the class too. What you need to do instead is to set CSS style cursor: default on the headers. See the old answer for the corresponding code example.
var currentDialog = CKEDITOR.dialog.getCurrent();
currentDialog._.editor.insertHtml("<customTag myAttr='var'></customTag>");
Throws an error, TypeError: Cannot read property 'isBlock' of undefined
If I try .insertHtml("<span>hello</span>") it works just fine.
How can I change ckeditor to allow me to specify my own custom html tags via .insertHtml()? I'd love to just change it to be something like <span class='custom'... or something like that, but I'm having to deal with legacy CMS articles. Using latest ckeditor. Thanks.
You need to modify CKEDITOR.dtd object so editor will know this tag and correctly parse HTML and process DOM:
CKEDITOR.dtd.customtag = { em:1 }; // List of tag names it can contain.
CKEDITOR.dtd.$block.customtag = 1; // Choose $block or $inline.
CKEDITOR.dtd.body.customtag = 1; // Body may contain customtag.
You need to allow for this tag and its styles/attrs/classes in Advanced Content Filter:
editor.filter.allow( 'customtag[myattr]', 'myfeature' );
Unfortunately, due to some caching, in certain situations you cannot modify DTD object after CKEditor is loaded - you need to modify it when it is created. So to do that:
Clone the CKEditor repository or CKEditor presets repository.
Modify core/dtd.js code.
And build your minified package following instructions in README.md - the only requirements are Java (sorry - Google Closure Compiler :P) and Bash.
PS. That error should not be thrown when unknown element is inserted, so I reported http://dev.ckeditor.com/ticket/10339 and to solve this inconvenience http://dev.ckeditor.com/ticket/10340.
I worked around this issue with a combination of createFromHtml() and insertElement()
CKEDITOR.replace('summary', { ... });
var editor = CKEDITOR.instances.summary;
editor.on('key', function(ev) {
if (ev.data.keyCode == 9) { // TAB
var tabHtml = '<span style="white-space:pre"> </span>';
var tabElement = CKEDITOR.dom.element.createFromHtml(tabHtml, editor.document);
editor.insertElement(tabElement);
}
}
I have rendered a grid that way:
myGrid = new Slick.Grid("#grid", myDataView, myColumns, myOptions);
myDataView.beginUpdate();
myDataView.setItems(myDataset);
myDataView.endUpdate();
it is ok.
Now i need to change css class name in certain column. I do:
myGrid.onSort.subscribe(function(e, args) {
args.sortCol.headerCssClass = 'newClassName';
});
What i need to do now to see changes in DOM?
I found this solution:
myGrid.onSort.subscribe(function(e, args) {
args.sortCol.headerCssClass = 'newClassName';
var columns = myGrid.getColumns();
myGrid.setColumns(columns);
});
Is this solution most elegant? Is there a proper method?
Are you trying to change the style of the "sorted-by" header column. If this is indeed the case, why don't you modify the slick-header-column-sorted CSS selector?
For instance, the following rule would bold the title of the "sorted-by" header column:
.slick-header-column-sorted
{
font-weight: bold;
}