I have collection like this:
child{length:3, models:array[3], _byId:Object}
I wanna sort models array, I use lodash like this:
var array_of_objects = new ListCollection();
var data = _.sortByOrder(array_of_objects.models, ['id'], ['asc']);
And I get result only:
[child, child, child]
How to sort models arrays with keep length and the Object.
If you want to order the original collection, set collection.comparator to 'id' and then call collection.sort().
To order the models without affecting the collection do: _.sortBy(collection.models, 'id')
Note that these will order the Models, not native js arrays. If your looking to operate on a raw collection of arrays, get a copy of the collection with var models = JSON.parse(collection.toJSON()) and then follow the instructions for _.sortBy.
Related
My question is similar to this question Adding new property to Eloquent Collection, but I need some further explanation.
In many occasions it would be really useful to be able to construct your own collections and use Laravel collection methods. The docs only explain how to make a simple collection of nameless items (a 1 dimensional data set), but I'm interested in 2 dimensional data sets.
For example when you use Laravel validator, it takes your named array of inputs and spits out a Illuminate\Support\ValidatedInput object, which is a collection. Then you can access your properties as properties in any object and also use collection methods such as only() or except().
$safe = $request->safe(); //returns a Illuminate\Support\ValidatedInput collection
//$safe = $request->validate(); //returns an associative array
echo $safe->my_prop;
Model::create( $safe->only(['prop1', 'prop2']) );
My objective is to transform an associative array such as:
$a = [
'prop1' => 'val1',
'prop2' => 3656,
'prop3' => ['stuff', 'more']
];
Into a collection that can be used like the Illuminate\Support\ValidatedInput object.
PS I'm currently using arrays and array functions (like array_intersect_key() as a substitute to ->only()), but would rather use collections.
Using
$c = collect( $a );
you cannot access the properties of $c like $c->prop, you still need to use $c['prop']. Which is confusing, given that many objects in laravel are both objects (which allow $object->property) AND collections.
I thought the data which is from DB::get() is Array.
However , the console says it is not array.
$fruitList = Food::where('id' => 300)->get(['id']);
shuffle($fruitList);
ErrorException: shuffle() expects parameter 1 to be array, object given in file
The return value of get() is not an array. it's Laravel array collection you can convert it to an array or use shuffle of array collection:
$fruitList = Food::where('id' => 300)->get(['id'])->toArray();
shuffle($fruitList);
with array collection:
$fruitList = Food::where('id' => 300)->get(['id'])->shuffle();
Just like #A.seddighi mentioned, using get() or all() gives you a collection. It may seem like an array when you output it using return or print but it is different.
Collections can be filtered, queried and so on. e.g
$fruitList->has('price')
etc.
To get an array simply called the toArray() method on it, you may also use flatMap(), mapWithKeys() etc. Make sure you follow the documentation that is suitable for your version of laravel.
I have some properties and i want to get the object for each property, currently, I am using the eloquent in the foreach loop like this as shown in the image that will describe the best..
but it is really not a good approach because if I have 100 published property I will making 100 calls to the DB... and that is not correct?
I need a suggestion and a proper solution to this query?
Thanks in advance
Before foreach you can get all the RentalProperty items from db like this:
$allRentalProperties = RentalProperty::all();
and in foreach loop you can get those items without connecting database like this:
$propertyObj = $allRenatalProperties -> where('id', $property['id']) -> first();
Also, you can use array shorthand.
$newArray = [];
it's much simple and readable.
You can do array pluck before loop:
$propertyIds = Arr::pluck($published_properties, 'id');
Then you can make a whereIn query to get only those data which are in $published_properties object
$propertyObj = RentalProperty::whereIn('id', $propertyIds);
Then you can access that object with id if you change array key with record id.
I have a ManyToMany relationship between AdInterest and AdInterestGroup models, with a belongsToMany() method in each model so I can use dynamic properties:
AdInterest->groups
AdInterestGroup->interests
I can find all the "interests" in a single group like this:
$interests = AdInterestGroup::find(1)->interests->pluck('foo');
What I need is a merged, deduplicated array of the related 'foo' field from multiple groups.
I imagine I can deduplicate with ->unique(), but first, as you'd expect, this:
AdInterestGroup::whereIn('id',[1,2])->interests->get();
throws:
Property [interests] does not exist on the Eloquent builder instance.
The advice seems to be to use eager loading via with():
AdInterestGroup::with('interests')->whereIn('id',[1,2])->get();
Firstly, as you'd expect that's giving me an array of two values though (one for each ID).
Also, if I try and pluck('foo') again, it's looking in the wrong database table: from the AdInterestGroup table, rather than the relationship (AdInterest).
Is there a nice, neat Collection method / pipeline I can use to combine the data and get access to the relationship fields?
Use pluck() and flatten():
$groups = AdInterestGroup::with('interests')->whereIn('id', [1, 2])->get();
$interests = $groups->pluck('interests')->flatten();
$foos = $interests->pluck('foo')->unique();
Using Laravel 5.3, I have a model with the following function
public function myData() {
return $this->hasMany(MyData::class);
}
and in my collection I have the following
$my_data = MyModel->myData()->get();
All good so far. If I return $my_data I get an eloquent collection with three items.
What I need now though is to create a duplicate of that collection but containing only three of the fields.
I have tried several different things, each of which return an error. The following is the closest I have got, but this returns an empty array - I assume because the fields are located one level deeper than the collection object.
$new_collection = $my_data->only(['field_1', 'field_2', 'field_3']);
What would be the correct way to create a new collection containing all three items, each with only the three selected fields?
Thanks for your help
You could use map:
$slimmed_down = $collection->map(function ($item, $key) {
return [
'field_1' => $item->field_1,
'field_2' => $item->field_2,
'field_3' => $item->field_3
];
});
This will return a new Collection with just the values you want. As far as I know there isn't any other method that does what you want, so iterating over every item and selecting the fields this way is one of the few solutions.
The advantage of using map instead of a standard foreach loop is that when you use map it returns a new instance of Collection.
Edit:
After some thoughts and research about this, the problem you'll have created is that the all the values in the Collection aren't instances of anything anymore. If you don't mind this effect, an even prettier and faster way would be to do this:
$slimmed_down = $collection->toArray()->only(['field_1', 'field_2', 'field_3']);
This basically has the same result.
Using Laravel 9, I just had the same issue :
$my_data->only(['field_1', 'field_2', 'field_3']);
returning an empty array.
I solved it with :
$my_data->map->only(['field_1', 'field_2', 'field_3']);