#!/bin/bash
# slightly malformed input data
input_start=2014-11-1
input_end=2016-01-1
# After this, startdate and enddate will be valid ISO 8601 dates,
# or the script will have aborted when it encountered unparseable data
# such as input_end=abcd
startdate=$(date -I -d "$input_start") || exit -1
enddate=$(date -I -d "$input_end") || exit -1
m="$startdate"
while [ "$m" != "$enddate" ]; do
echo $m
m=$(date -I -d "$m + 1 month")
done
"Script is running fine but when I want to change the While loop condition i.e '<=' 'less then or equal to' its giving error even I tried using "-le".What I want to do here is startdate <= enddate in while loop. Can anyone suggest what needs to done to overcome this issue.
Same Code
-le is for numeric data. 2014-11-01 is not a number. Use < or >. (You need to escape them as \< or \>. Or use [[ instead of [.)
effectively, change
while [ "$m" != "$enddate" ]; do
to
until [ "$m" \> "$enddate" ]; do
or
until [ "$m" '>' "$enddate" ]; do
or
until [[ "$m" > "$enddate" ]]; do
Alternately, use seconds since epoch instead of ISO8601 format.
while [ "$(date -d "$m" +%s)" -le "$(date -d "$enddate" +%s)" ]; do
With dateutils' datetest this is simple:
$ datetest 2014-11-1 --le 2016-01-1 ; echo $?
0
$ datetest 2014-11-1 --gt 2016-01-1 ; echo $?
1
Then again, what you want is simply done by dateseq, which also happens to be a tool of the dateutils suite.
$ dateseq 2014-11-1 +1mo 2016-01-1
2014-11-01
2014-12-01
2015-01-01
2015-02-01
2015-03-01
2015-04-01
2015-05-01
2015-06-01
2015-07-01
2015-08-01
2015-09-01
2015-10-01
2015-11-01
2015-12-01
2016-01-01
Disclaimer: I am the author of the package.
I have code that prints dates incorrectly
condition=`date -d "20150209" +%a`
start_date=`date -d -7day"20150209" +%Y%m%d`
end_date=`date -d -1day"20150209" +%Y%m%d`
if [ "$condition" = "Mon" ]
then
while [ "$start_date" != "$end_date" ]
do
Date+=$start_date,
start_date=$(date -d +1day"$start_date" +%Y%m%d)
done
echo "$Date"
fi
I am expecting output as
20150203,20150204,20150205,20150206,20150207,20150208
I am unable to figure out what is wrong.
I was missing the last element in the date range.
here is the solution.
condition=`date -d "20150209" +%a`
start_date=`date -d -7day"20150209" +%Y%m%d`
end_date=`date -d -1day"20150209" +%Y%m%d`
while [ "$start_date" != "$end_date" ]
do
Date+=$start_date,
start_date=$(date -d +1day"$start_date" +%Y%m%d)
done
echo "$Date$end_date"
if someone has a better solution please let me know.
Hi I have a csv file with dates like this which I want to parse with bash and check against todays date.
12-Jan-2015
Checking only day and month works good
DAT=$(date '+%d %b %Y')
DAY=${DAT:0:2}
MON=$(echo ${DAT:3:3} | awk '{print toupper("$0");}')
YEAR=${DAT:6:5}
while IFS=",-" read name day month year
do
day=$(printf "%02d\n" "$day")
month=$(echo "$month" | awk '{print toupper($0);}')
year=$(printf "%04d\n" "$year")
if [ "$day" -eq "$DAY" ] && [ "$month" = "$MON" ]; then
echo "$name";
fi
done < $SNAPDB > $SNAPTMPDB
but when I try to also check the year
if [ "$day" -eq "$DAY" ] && [ "$month" = "$MON" ] && [ "$year" -eq "$YEAR" ]; then
Script ends with an error: line 119: 2015: command not found
I´ve by now tried several writings like [[ … ]] -a and so on. but nothing did work.
Thanks for help!
Use -a for 'and' and -o for 'or'. From the documentation: http://tldp.org/LDP/Bash-Beginners-Guide/html/sect_07_01.html (look specifically at Table 7-2)
Updated from comments:
Use double brackets and parentheses:
if ( [[ "$day" -eq "$DAY" ]] && [[ "$month" = "$MON" ]] && [[ "$year" -eq "$YEAR" ]] ); then`
I have to create a Shell Script wherein one of the parameters will be the date in the format dd/mm/yyyy. My question is, how can I check if the Date passed as parameter really follows this Date Format? I tried to use the grep command as below:
if echo "$1" | grep -q '^[0-3][0-9]/[0-1][0-9]/[0-9]\{4\}$'
but it didn't give the correct format because the day for example can be 33, 34, (...), that is not really the correct format. Anyone know something that can really check if the date passed really follows the format dd/mm/yyyy ?
Use date
date "+%d/%m/%Y" -d "09/99/2013" > /dev/null 2>&1
is_valid=$?
The date string must be in "MM/DD/YYYY" format.
If you do not get 0 then date is in invalid format.
The simplest solution, that still works perfectly, is the following :
if [[ $1 =~ ^[0-9]{4}-[0-9]{2}-[0-9]{2}$ ]] && date -d "$1" >/dev/null 2>&1
...
It consists in combining 2 checks :
the first part checks that $1 is of this format : NNNN-NN-NN
the second part checks that it is a valid date
You need the two checks because :
if you don't do the first check, date will exit with code 0 even if your variable is a valid date in another format
if you don't do the second check, then you can end up with a 0 even for variables such as 2016-13-45
This function expects 2 strings,a format string, a date string
The format string uses the codes from the date command but does not include the '+'
The function returns 0 if the provided date matches the given format, otherwise it returns 1
Code (my_script.sh)
#!/bin/bash
datecheck() {
local format="$1" d="$2"
[[ "$(date "+$format" -d "$d" 2>/dev/null)" == "$d" ]]
}
date_test="$1"
echo $date_test
if datecheck "%d %b %Y" "$date_test"; then
echo OK
else
echo KO
fi
Output
$ ./my_script.sh "05 Apr 2020"
05 Apr 2020
OK
$ ./my_script.sh "foo bar"
foo bar
KO
First, check the form of the input using the regex. Then use awk to switch to mm/dd/yyyy and use date to validate. You can use the following expression in your if statement:
echo "$1" | egrep -q '^[0-3][0-9]/[0-1][0-9]/[0-9]{4}$' && date -d "$(echo "$1" | awk 'BEGIN{FS=OFS="/"}{print $2"/"$1"/"$3}')" >/dev/null 2>&1
Simplest way for dd/mm/yyyy exactly in Bash is:
if [[ $1 == [0-3][0-9]/[0-1][0-9]/[0-9][0-9][0-9][0-9] ]]
Or
if [[ $1 =~ ^[0-3][0-9]/[0-1][0-9]/[0-9]{4}$ ]]
How about using awk:
echo "31/12/1999" | awk -F '/' '{ print ($1 <= 31 && $2 <= 12 && match($3, /^[1-9][1-9][1-9][1-9]$/)) ? "good" : "bad" }'
It prints "good" if its valid date else prints "bad"
#! /bin/bash
isDateInvalid()
{
DATE="${1}"
# Autorized separator char ['space', '/', '.', '_', '-']
SEPAR="([ \/._-])?"
# Date format day[01..31], month[01,03,05,07,08,10,12], year[1900..2099]
DATE_1="((([123][0]|[012][1-9])|3[1])${SEPAR}(0[13578]|1[02])${SEPAR}(19|20)[0-9][0-9])"
# Date format day[01..30], month[04,06,09,11], year[1900..2099]
DATE_2="(([123][0]|[012][1-9])${SEPAR}(0[469]|11)${SEPAR}(19|20)[0-9][0-9])"
# Date format day[01..28], month[02], year[1900..2099]
DATE_3="(([12][0]|[01][1-9]|2[1-8])${SEPAR}02${SEPAR}(19|20)[0-9][0-9])"
# Date format day[29], month[02], year[1904..2096]
DATE_4="(29${SEPAR}02${SEPAR}(19|20(0[48]|[2468][048]|[13579][26])))"
# Match the date in the Regex
if ! [[ "${DATE}" =~ "^(${DATE_1}|${DATE_2}|${DATE_3}|${DATE_4})$" ]]
then
echo -e "ERROR - '${DATE}' invalid!"
else
echo "${DATE} is valid"
fi
}
echo
echo "Exp 1: "`isDateInvalid '12/13/3000'`
echo "Exp 2: "`isDateInvalid '12/11/2014'`
echo "Exp 3: "`isDateInvalid '12 01 2000'`
echo "Exp 4: "`isDateInvalid '28-02-2014'`
echo "Exp 5: "`isDateInvalid '12_02_2002'`
echo "Exp 6: "`isDateInvalid '12.10.2099'`
echo "Exp 7: "`isDateInvalid '31/11/2000'`
Here's a function to do some data validation this:
# Script expecting a Date parameter in MM-DD-YYYY format as input
verifyInputDate(){
echo ${date} | grep '^[0-9][0-9]-[0-9][0-9]-[0-9][0-9][0-9][0-9]$'
if [ $? -eq 0 ]; then
echo "Date is valid"
else
echo "Date is not valid"
fi
}
`X="2016-04-21" then check for the below value being 1 or 0.
cal echo $x | cut -c 6-7 echo $x | cut -c 1-4 2>/dev/null | grep -c echo $x | cut -c 9-10
If the value is 1, then it's valid, else it's not valid.
Though the solution (if [[ $1 =~ ^[0-9]{4}-[0-9]{2}-[0-9]{2}$ ]] && date -d "$1" >/dev/null 2>&1) of #https://stackoverflow.com/users/2873507/vic-seedoubleyew is best one at least for linux, but it gives error as we can not directly compare/match regex in if statement. We should put the regex in a variable and then we should compare/match that variable in if statement. Moreover second part of if condition does not return a boolean value so this part will also cause error.
So I have done slight modification in the above formula and this modification can also be customized further for various other formats or combination of them.
DATEVALUE=2019-11-12
REGEX='^[0-9]{4}-[0-9]{2}-[0-9]{2}$'
if [[ $DATEVALUE =~ $REGEX ]] ; then
date -d $DATEVALUE
if [ $? -eq 0 ] ; then
echo "RIGHT DATE"
else
echo "WRONG DATE"
fi
else
echo "WRONG FORMAT"
fi
I would like to give an extended answer for a slightly different format, but this can easily be changed to the dd/mm/YY format with the answers already given; it's tested on busybox (posix shell)
This is one of the first hits for web searches similar to "busybox posix shell script date" and "test format" or "validate" etc, so here my solution for busybox (tested with 1.29.3, 1.23.1)
#!/bin/sh
##########
#
# check if date valid in busybox
# tested in busybox 1.29.3, 1.23.1
#
# call with:
# $0 <yyyymmdd>
#
##########
mydate=$1
if echo $mydate | grep -qE '20[0-9][0-9](0[1-9]|1[0-2])([012][0-9]|3[01])'; then
printf 'may be valid\n'
date +%Y%m%d -d $mydate -D %Y%m%d > /dev/null 2>&1
is_valid=$?
if [ $is_valid -ne 0 ]; then
printf 'not valid\n'
return 1
else
mytestdate=$(date +%Y%m%d -d $mydate -D %Y%m%d)
if [ $mydate -ne $mytestdate ]; then
printf 'not valid, results in "%s"\n' "$mytestdate"
return 1
else
printf 'valid\n'
fi
fi
else
printf 'not valid (must be: <yyyymmdd>)\n'
return 1
fi
as in busybox (1.29.3 & 1.23.1) you have responds like:
lxsys:~# date +%Y%m%d -d 20110229 -D "%Y%m%d"
20110301
I had the need to validate the date in some better way but i wanted to rely mostly on the system itself
so with
mytestdate=$(date +%Y%m%d -d $mydate -D %Y%m%d)
if [ $mydate -ne $mytestdate ]; then
...
fi
there is a second test - do we have a difference between the wanted or given format (input, $mydate) and the system interpretation (output, $mytestdate) of it ... if it's not the same, discard the date
I wrote this bash script to validate date. I can accept mont as alphanumeric.
#!/bin/bash
function isDateValid {
DATE=$1
if [[ $DATE =~ ^[0-9]{1,2}-[0-9a-zA-Z]{1,3}-[0-9]{4}$ ]]; then
echo "Date $DATE is a number!"
day=`echo $DATE | cut -d'-' -f1`
month=`echo $DATE | cut -d'-' -f2`
year=`echo $DATE | cut -d'-' -f3`
if [ "$month" == "01" ] || [ "$month" == "1" ]; then
month="Jan"
elif [ "$month" == "02" ] || [ "$month" == "2" ]; then
month="Feb"
elif [ "$month" == "03" ] || [ "$month" == "3" ]; then
month="Mar"
elif [ "$month" == "04" ] || [ "$month" == "4" ]; then
month="Apr"
elif [ "$month" == "05" ] || [ "$month" == "5" ]; then
month="May"
elif [ "$month" == "06" ] || [ "$month" == "6" ]; then
month="Jun"
elif [ "$month" == "07" ] || [ "$month" == "7" ]; then
month="Jul"
elif [ "$month" == "08" ] || [ "$month" == "8" ]; then
month="Aug"
elif [ "$month" == "09" ] || [ "$month" == "9" ]; then
month="Sep"
elif [ "$month" == "10" ]; then
month="Oct"
elif [ "$month" == "11" ]; then
month="Nov"
elif [ "$month" == "12" ]; then
month="Dec"
fi
ymd=$year"-"$month"-"$day
echo "ymd: "$ymd
dmy=$(echo "$ymd" | awk -F- '{ OFS=FS; print $3,$2,$1 }')
echo "dmy: "$dmy
if date --date "$dmy" >/dev/null 2>&1; then
echo "OK"
return 0
else
echo "NOK"
return 1
fi
else
echo "Date $DATE is not a number"
return 1
fi
}
if isDateValid "15-15-2014"; then
echo "date is valid =)"
else
echo "bad format date"
fi
echo "==================="
if isDateValid "15-12-2014"; then
echo "date is valid =)"
else
echo "bad format date"
fi
echo "==================="
if isDateValid "15-Dec-2014"; then
echo "date is valid =)"
else
echo "bad format date"
fi
echo "==================="
if isDateValid "1-May-2014"; then
echo "date is valid =)"
else
echo "bad format date"
fi
echo "==================="
if isDateValid "1-1-2014"; then
echo "date is valid =)"
else
echo "bad format date"
fi
echo "==================="
if isDateValid "12-12-2014"; then
echo "date is valid =)"
else
echo "bad format date"
fi
Blockquote
DATE = "$*"
[[ "${DATE}" != #(((([123][0]|[012][1-9])|3[1])?([ \/._-])(0[13578]|1[02])?([ \/._-])(19|20)[0-9][0-9])|(([123][0]|[012][1-9])?([ \/._-])\
(0[469]|11)?([ \/._-])(19|20)[0-9][0-9])|(([12][0]|[01][1-9]|2[1-8])?([ \/._-])02?([ \/._-])(19|20)[0-9][0-9])|(29?([ \/._-])02?([ \/._-])\
(19|20(0[48]|[2468][048]|[13579][26])))) ]] && echo error || echo good)
I am trying to compare dates in the while loop of a shell script. The shell script will be controlled by 2 conditions, like the following:
while [ $currentDate -le $currentDateMonthEnd -a $currentDate -le $toDate ]; do
...
done
The above is my current code, which complains of "integer expression expected". I have also tried using && and AND, which also do not work and complains of mismatching braces.
Could someone please provide the syntax to make the above comparison?
dc ()
{
[ $(date +%s -d "$1") $2 $(date +%s -d "$3") ]
}
while dc "$currentDate" -le "$currentDateMonthEnd" && dc "$currentDate" -le "$toDate"
do
# ...
done
following code works for me,
#! /bin/bash
toDate=`echo 2014/03/30 | tr -d "/"`
currentDate=`date +"%Y/%m/%d" | tr -d "/"`
currentDateMonthEnd=`date +%Y/%m/%d -d "-$(date +%d) days +1 month" | tr -d "/"`
while [[ $currentDate -le $currentDateMonthEnd ]] && [[ $currentDate -le $toDate ]]
do
...
done
#! /bin/sh
while [ $currentDate -le $currentDateMonthEnd ] && [ $currentDate -le $toDate ]
do
...
done