laravel join fake table - laravel

Question

I'm using datatables with server side processing in a Laravel project. My status column is integer, which is then formatted
->editColumn('status', function($orders) use ($statuses) {
return $statuses[$orders->status];
})
But this approach prevents status column from being used in search.
Is sthere a way to join query with fake table? Smth like this
->join('fake_status_table', 'production_orders.status', '=', 'fake_status_table.id')
Drafting two solutions
Solution #1
$orders= DB::table('production_orders')
->select(DB::raw("DECODE (status_id, 1, 'No started',
2, 'Running',
3, 'Done',
4, 'Defect')"))
solution #2
//create tamporary table
$status_table = DB::insert( DB::raw( "CREATE TEMPORARY TABLE statuses") );
$orders = \DB::table('production_requests')
// join it with drawing table
->join('statuses', 'production_requests.status', '=', 'statuses.id')
// Generate result
$result = Datatables::of($orders)->make(true);
// KILL TEMPORARY TABLE
$dropTable = DB::unprepared( DB::raw( "DROP TEMPORARY TABLE statuses" ) );
// RETURN RESULT
return $result;

Answer 1

Views is nothing but a temporary table..
But it was copy of the table itself.. You shall create a view according to your need.. If you want to have the view of your entire table .. then
CREATE VIEW test.v AS SELECT * FROM t;
Or even
CREATE VIEW v AS SELECT qty, price, qty*price AS value FROM t;
Then you shall return some data from the controller and construct the coloumn as we do usual in the datatables
Like this
Jquery :
$(document).ready(function() {
$('#example').DataTable();
} );
And then foreach for the table !!
Hope this helps you