Keep X amount of files in folder, forfiles - windows

Question

I would like to keep the X latest files from a folder and delete the rest. Is this possible with FORFILES? If it's not I can fallback to another solution I seen here. Thanks for help.
I did this but it takes by dates: EDIT
forfiles /p [path] /s /d -5 /c "cmd /c echo #file"
(echo file for testing purpose)

Answer 1

#ECHO OFF
SETLOCAL
SET "targetdir=U:\destdir"
SET /a retain=10
FOR /f "skip=%retain%delims=" %%a IN (
'dir /b /a-d /o-d "%targetdir%\*" '
) DO ECHO (DEL "%targetdir%\%%a"
GOTO :EOF
You would need to change the setting of targetdir to suit your circumstances. Equally, this procedure targets all files - change the filemask to suit.
The required DEL commands are merely ECHOed for testing purposes. After you've verified that the commands are correct, change ECHO(DEL to DEL to actually delete the files.
method is to simply execute a dir in basic form without directories, sorted in reverse-date order.
Skip the first 10 entries, and delete the rest.

Answer 2

With forfiles I see no chance to accomplish your task of returning the newest (most recent) number of files.
So my idea for this approach is this:
to use dir /B /A:-D /T:C /O:-D to retrieve a bare list (/B) of files (no directories, /A:-D), sorted by creation date (/T:C; if you want to use the last modification date, simply remove the /T:C portion) in decending order (/O:-D), meaning newest items first;
to put over a for /F "eol=| delims=" loop to gather and parse the dir output line by line, meaning file by file, not excluding file names beginning with ; (eol=|, | is illegal for file names) and not splitting file names containing white-spaces like SPACE or TAB (delims=);
to establish a variable that constitutes a counter, incremented per each loop iteration;
to place an if condition inside of the loop to check if the counter reached the desired limit number and in case it is fulfilled, to break the for /F loop by goto;
Here is the related code:
#echo off
setlocal EnableExtensions DisableDelayedExpansion
rem Define global constants here:
set "TARGETPATH=\path\to\files\*.*"
set /A "TOTAL=10"
set /A "COUNT=0"
for /F "eol=| delims=" %%F in ('
dir /B /A:-D /T:C /O:-D "%TARGETPATH%"
') do (
echo(%%F
set /A COUNT+=1
setlocal EnableDelayedExpansion
if !COUNT! GEQ %TOTAL% (
endlocal
goto :NEXT
) else (
endlocal
)
)
:NEXT
endlocal
exit /B
I toggled the delayed variable expansion within the for /F loop to avoid trouble in case file names contain exclamation marks !, which would get lost in the line echo(%%F in case it is on.
Update
The following code accomplishes the original task of your question, namely to delete files in a given directory but to keep the most recent number of files:
#echo off
setlocal EnableExtensions DisableDelayedExpansion
rem Define global constants here:
set "TARGETPATH=\path\to\files\*.*"
set /A "TOTAL=10"
set "SKIPOPT=" & if %TOTAL% GTR 0 set "SKIPOPT=skip=%TOTAL% "
for /F "%SKIPOPT%eol=| delims=" %%F in ('
dir /B /A:-D /T:C /O:-D "%TARGETPATH%"
') do (
del /P "%%F"
)
endlocal
exit /B
Since for /F supports a skip= to skip the given number of lines, and so files in our situation, let us make use of it. It is given indirectly here via variable SKIPOPT, which holds the entire option string like skip=10 (given that TOTAL is set to 10). The if %TOTAL% GTR 0 query is implemented for the script not to fail in case TOTAL is 0, because for /F does not accept the option skip=0.
The /P switch at the del command lets appear a prompt Delete (Y/N)? for testing purposes. If you do not want any prompts, simply remove it.