Not Creating Tables in Hibernate JPA - spring

I am creating Spring (Version 4.0.6) , Hibernate(Version 4.3.6) CRUD application.
I tried giving both <prop key="hibernate.hbm2ddl.auto">create</prop> and <property name="generateDdl" value="true" />. But the tables did not get created.
All entities has #Entity and #Table(name) annotation from javax.persistence.
Here comes my applicationContext.xml. http://textuploader.com/5pjw8
Here comes one of my Entity
http://textuploader.com/5pjyk
Where I have gone wrong and why it is not creating tables for me?
How do I troubleshoot the issue?

You don't seem to have defined a datasource bean, i.e. an actual database to connect to, is this in another file?

Related

Setup JPA Console in Intellij using Spring

I'm trying to get the JPA console working in Intellij. I have added JPA to the project under facets. However, IDE is asking for a persistence.xml. I'm using Annotated Spring and don't have any direct mapping files. Anyone configured this before, and can help me? Thanks
Further information:
Without adding JavaEE stuff - I don't need this.
File->Project Structure - Under modules: add JPA to a single module. Do not add persistence.xml or orm.xml
Under facets: Add JPA. Leave XML config blank. Leave JPA Provider blank
View -> Tool windows -> Persistence
You will see the module name and the EntityManager as configured under your SpringContext.xml. On my system I have these properties referenced in this SpringContext.xml
# jdbc.X
jdbc.driverClassName=org.postgresql.Driver
jdbc.url=jdbc:postgresql:///someThing
jdbc.user=postgres
jdbc.pass=postgres
# hibernate.X
hibernate.dialect=org.hibernate.dialect.PostgreSQL9Dialect
hibernate.show_sql=false
hibernate.hbm2ddl.auto=create
I then select in my Persistence window (in which I can now see all entities) - click console button. Select JPA console. This will get me the error outlined here {yes, I'm using Postgres}
https://intellij-support.jetbrains.com/hc/en-us/community/posts/206186929-JPA-Console-without-persistence-xml
Note the two "TTs-" PostgreSQL9Dialectt
Further further information:
Wierd. If I move the dialect into the actual xml config
<property name="jpaProperties">
<props>
<prop key="hibernate.hbm2ddl.auto">${hibernate.hbm2ddl.auto}</prop>
<prop key="hibernate.dialect">org.hibernate.dialect.PostgreSQL9Dialect</prop>
<!--<prop key="hibernate.enable_lazy_load_no_trans">true</prop>-->
</props>
</property>
[2017-01-04 13:03:46] java.lang.IllegalStateException: Transaction already active
at org.hibernate.engine.transaction.internal.TransactionImpl.begin(TransactionImpl.java:52)
at com.intellij.jpa.remote.impl.RemoteQueryImpl$1.getResultList(RemoteQueryImpl.java:92)
at com.intellij.jpa.remote.impl.QueryResultImpl.ensureInitialized(QueryResultImpl.java:113)
at com.intellij.jpa.remote.impl.QueryResultImpl.getColumnInfos(QueryResultImpl.java:30)
at com.intellij.jpa.remote.impl.RemoteQueryResultImpl.getColumnInfos(RemoteQueryResultImpl.java:79)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)

persistence.xml in a Spring application

I'm used to have persistence.xml in my projects in which I define the provider to use (hibernate in most cases).
However, I'm starting a new project in which it is mandatory to use Spring framework. I've seen some blogs describing the integration of Hibernate in Spring and I've understood that I should declare a session factory in spring's beans descriptor org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean
All the examples I've seen don't mention the use of persistence.xml, persistence context, entity manager...
I'm not sure I understand this point, I always thought that Hibernate is just a provider of JPA unless the factory declared in application-context.xml is doing something in background. If it is the case, I would like to understand how it is working..
thanks in advance...
AnnotationSessionFactoryBean is Factory bean implemented by Spring to create Hibernate Session Factory and shared to Spring's Application Context.if you are planning to use Direct Hibernate ( in case you dont need persistent.xml / per-cont.xml / entityManager) you can provide the properties in AnnotationSession FactoryBean. and can be injected in Any DAO.
How ever if you are planing to wire through JPA. Then you need ( persistent and persistent-context and entity Manager). In order to do that you required three steps
1. declare / configure Spring's JPA Adapter to create EntityManager instance for you
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
Inside JPA Bean declaration provide details about your database and who is ORM provider such as ( hibernate /toplink / ....) in your case Hibernate
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true" />
<property name="generateDdl" value="false" />
<property name="databasePlatform" value="org.hibernate.dialect.Oracle9Dialect"/>
</bean>
</property>
then Provide information about your persistent entity details in persistent.xml or some way
<property name="persistenceXmlLocation" value="classpath:persistence.xml" />
if you have any specific JPA properties then
<property name="jpaProperties">
<props>
<!-- <prop key="hibernate.cache.provider_class">
org.hibernate.cache.EhCacheProvider
</prop>
-->
<prop key="hibernate.format_sql">false</prop>
<prop key="hibernate.use_sql_comments">false</prop>
</props>
</property>
Bottom line, Spring provies adapters to directly to Hibernate ( in that case your dont need Jpa files such as persistent.xml and so but you need hibernate related files like hbm files) or adapters to the JPA ( in that case you have provide details about who is JPA vendor and instrut spring how to connect to the JPA vendor).
Hope the above clarifies.

Multi-tenant webapp using Spring MVC and Hibernate 4.2.0.Final

I have developed a small webapp using and SpringMVC(3.1.3.RELEASE) and Hibernate 4.2.0.Final.
I'm trying to convert it to be a multi-tenant application.
Similar topics have been covered in other threads, but I couldn't find a definitive solution to my problem.
What I am trying to achieve is to design a web app which is able to:
Read a datasource configuration at startup (an XML file containing multiple datasource definitions, which is placed outside the WAR file and it's not the application-context or hibernate configuration file)
Create a session factory for each one of them (considering that each datasource is a database with a different schema).
How can i set my session factory scope as session? ( OR Can i reuse the same session factory ?) .
Example:
Url for client a - URL: http://project.com/a/login.html
Url for client b - URL: http://project.com/b/login.html
If client "a" make request,read the datasource configuration file and Create a session factory using that XML file for the client "a".
This same process will be repeating if the client "b" will send a request.
What I am looking, how to implement datasource creation upon customer subscription without editing the Spring configuration file. It needs to be automated.
Here is my code ,that i have done so far.
Please anyone tell me,What modifications i need to be made?
Please give an answer with some example code..I am quite new in spring and hibernate world.
Spring.xml
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
destroy-method="close" p:driverClassName="${jdbc.driverClassName}"
p:url="${jdbc.databaseurl}"
p:username="${jdbc.username}" p:password="${jdbc.password}" />
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="configLocation">
<value>classpath:hibernate.cfg.xml</value>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">${jdbc.dialect}</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="transactionManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
JDBC.properties File
jdbc.driverClassName=com.mysql.jdbc.Driver
jdbc.dialect=org.hibernate.dialect.MySQLDialect
jdbc.databaseurl=jdbc:mysql://localhost:3306/Logistics
jdbc.username=root
jdbc.password=rot#pspl#12
hibernate.cfg.xml File
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<mapping class="pepper.logis.organizations.model.Organizaions" />
<mapping class="pepper.logis.assets.model.Assets" />
</session-factory>
</hibernate-configuration>
Thanks,
First create a table for Tenant with tenant_id and associate it with all users.Now, you can fetch this details while the user logs in and set it in session.
We are using AbstractRoutingDataSource to switch DataSource for every request on Spring Boot. I think it is Hot Swapable targets/datasource mentioned by #bhantol above.
It solves our problems but I don't think it is sound solution. I guess JNDI could be a better one than AbstractRoutingDataSource.
Wondering what you ended up with.
Here are some ideas for you.
Option 1) Single Application Instance.
It is somewhat ambitious to to this using what you are actually trying to achieve.
The gist is to simply deploy the same exact application with different context root on the same JVM. You can still tune the JVM as a whole like you would have if you had a truely multi-tenant application. But this comes at the expense of duplication of classes, contexts, local caching, start up times etc.
But as of today the Spring Framework 4.0 does not provide much of an multi-tenancy support (other than Hot Swapable targets/datasource) etc. I am looking for a good framework but it may be a wash to move away from Spring at this time for me.
Option 2) Multiple deployments of same application (more practical as of today)
Just have your same exact application deploy to the same application server JVM instance or even different.
If you use the same instance you may now need to bootstrap your app to pickup a DataSource based on what the instance should serve e.g. client=a property would be enough to pickup a **a**DataSource" or **b**DataSource I myself ended up going this approach.
If you have a different application server instance you could just configure a different JNDI path and treat things generically. No need for client="a" property because you have liberty to define your datasource differently with the same name.

Hibernate doesn't seem to be scanning for #Entity #Table

I've got two Spring Hibernate modules that I'm trying to combine. They have separate application contexts. In one hibernate uses xml mapping files while in the second module annotations are used to map the hibernate db tables.
Both modules seem to be scanned ok (service beans seem to be injected ok) except for the hibernate table scanning in the second table. One table occurs twice -- once in the xml mapping files and once in annotations but in different java packages with separated package scanning.
When I try to access the second module's table class in a hibernate select I get:
MappingException: Unknown entity: msg.entity: message
I tried substituting another annotated table entity in the hibernate query to check where the problem was mapping to the same table but I get the same MappingException so it seems like the problem is that hibernate is just not picking up any #Entity #Table annotations in the second module. But I tested this module on it's own and all the annotations did get picked up ok.
Could it be that the hibernate session factory is somehow being carried over from the calling module and masking the second module's session factory and its associated list of entities? Yet I'm not in a transaction in the calling method.
<context:component-scan base-package="msg"/>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSourceJmsMod"/>
<property name="packagesToScan" value="msg.entity"/>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</prop>
<prop key="hibernate.show_sql">true</prop>
<prop key="hibernate.format_sql">true</prop>
<prop key="javax.persistence.validation.mode">none</prop>
</props>
</property>
</bean>
Thanks for any help

Using Spring Transactions in MyBatis API

We have developed a data persistence framework using Mybatis. The framework uses plain MyBatis APIs. (We were prohibited from using any mybatis-spring, do not ask… why?)
Now we have to integrate this persistence framework with another framework developed by other teams. This other framework heavily uses spring transactions for everything. Our persistent framework DAOs will be used by this framework within its own API ….that means the spring managed transactions will be propagated to MyBatis DAO. It is expected that our MyBatis based persistence framework should participate in spring managed transactions without any issues.
There are two options for us to make this work
(1)Change our persistent framework to use mybatis-spring module. Change DAOs to use mappers directly injected using spring and spring’s SqlSessionFactoryBean. I did build a small example simulating both the frameworks and everything works without any issue. The problem is with this approach that it requires changing almost all the DAOs to use spring injected mapper, extensively test the framework again. We simply do not have time available due to delivery timeline.
(2)Use mybatis-spring, define SqlSeeionFactory using spring – set the datasource and transaction manager used by other framework. Something like
<bean id="smpDataSource" class="oracle.jdbc.pool.OracleDataSource" destroy-method="close">
<property name="connectionCachingEnabled" value="true" />
<property name="URL"> <value>${db.thin.url}</value></property>
<property name="user"> <value>${db.user}</value></property>
<property name="password"><value>${db.password}</value>
</property>
</bean>
<bean id="dbTransactionManager" class="org.springframework.jdbc.datasource.DataSourceTransactionManager">
<property name="dataSource" ref="smpDataSource" />
</bean>
<bean id="sqlSessionFactory" class="org.mybatis.spring.SqlSessionFactoryBean">
<property name="dataSource" ref="smpDataSource" />
<property name="typeAliasesPackage" value="spike.smp51.domain" />
<property name="mapperLocations" value="classpath*:spike/smp51/mappers/*.xml" </bean>
Then in applicataion code MyBatis DAO gets the sqlseesionfactory from spring like
public static SqlSessionFactory getSqlSessionFactory() throws Exception
{
DefaultSqlSessionFactory sessionFactory = (DefaultSqlSessionFactory)ctx.getBean("sqlSessionFactory");
return sessionFactory;
}
All DAOs already use SqlSeesionFactory to open and close sessions. Just replace that mybatis created sqlseeionfactory with spring created sqlseeionfactory. That way we will have only few lines of changes.
This approach is outlined here
http://mybatis.github.io/spring/using-api.html
The mybatis documentation warns about this approach – specifically that it will not participate in spring transactions.
When I tried the 2nd approach, our framework was able to participate in spring transactions. This is strange. Is the MyBatis documentation incorrect then? I did verify it extensively by creating various transaction boundaries using spring transactions + AOP . MyBatis DAOs are able to participate in spring managed transactions every time. Since this second approach will save us 90% of the development time – we really like to use it – but worried since MyBatis warns following this approach. Has anyone tried this approach? Any feedback is greatly appreciated.
Did you have any return on that ?
I'm wondering if in the doc they're talking about org.apache.ibatis.session.SqlSessionFactory from Mybatis-api while the SqlSessionFactory you're using is from the mybatis-spring lib : org.mybatis.spring.SqlSessionFactoryBean

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