batch replace spaces between quotes in file and then remove all quotes - windows

Question

I want create a batch to replace spaces with a + sign if the space is in between quotes. Then I want to remove the quotes from a text file. How can I accomplish this?
So I want to change a line like this:
2016-01-11 14:45:09 Server 127.0.0.1 GET /global/images/logo_small.jpg - 80 - 173.252.120.117 "facebookexternalhit/1.1 (+http://www.facebook.com/externalhit_uatext.php)" "-" www.vietnam.ttu.edu 200 200 200 1868 0
To this line.
2016-01-11 14:45:09 Server 127.0.0.1 GET /global/images/logo_small.jpg - 80 - 173.252.120.117 facebookexternalhit/1.1+(+http://www.facebook.com/externalhit_uatext.php) - www.vietnam.ttu.edu 200 200 200 1868 0
Thanks

Answer 1

You could use JREPL.BAT to arrive at a very concise and efficient solution. JREPL is a pure script based (JScript/batch) regular expression text processing utility that runs on any version of Windows from XP onward.
jrepl "\q| " "q=!q;''|q?'+':' '" /j /x /t "|" /jbegln "q=false" /f test.txt /o -
For this solution I use the /T option, which is very similar to the unix tr utility, or the sed y command.
I define two search terms, the first for a quote (The \X option enables the \q escape sequence), and the second for a space.
The /J option treats replacement strings as JScript. The first replacement string for the quote toggles a "q" variable TRUE or FALSE, and replaces the quote with an empty string. The second replacement string conditionally replaces the space with a plus or space, depending on the state of the "q" variable.
The /JBEGLN option initializes the "q" variable to FALSE at the beginning of each line.
The /F option specifies the input file, and the /O - option specifies that the output overwrites the original file.

Answer 2

#ECHO OFF
SETLOCAL
SET "sourcedir=U:\sourcedir"
SET "filename1=%sourcedir%\q34732271.txt"
FOR /f "usebackqdelims=" %%a IN ("%filename1%") DO ECHO %%a&SET "line="&CALL :process %%a
GOTO :EOF
:process
SET "addition=%~1"
IF not DEFINED addition ECHO %line:~1%&GOTO :eof
IF "%~1"==%1 (
REM quoted
SET "line=%line% %addition: =+%"
) ELSE (
SET "line=%line% %addition%"
)
shift
GOTO process
You would need to change the setting of sourcedir to suit your circumstances.
I used a file named q34732271.txt containing your data for my testing.
The echo %%a shows your one line of data on the screen and the echo within the :process routine shows that line processed.
Batch is not an ideal language to process strings as it exhibits sensitivity to many symbols. This process should work provided you are happy to have space-strings compressed and the source string does not contain , ;,tab % or any other symbol that cmd treats specially.

Answer 3

Here is a pure batch-file solution that walks through the characters in each line in file line.txt, replaces all SPACEs in between a pair of quotation marks "" by + signs and stores the result in text_new.txt. The input string may contain any characters, even special ones:
#echo off
setlocal EnableExtensions DisableDelayedExpansion
rem Define global constants here:
set "INFILE=line.txt"
set "OUTFILE=line_new.txt"
set "SEARCH= "
set "REPLACE=+"
set "KEEPQUOTES="
set "QUOTE="""
set "QUOTE=%QUOTE:~,1%"
set "QFLAG="
> "%OUTFILE%" (
for /F usebackq^ delims^=^ eol^= %%L in ("%INFILE%") do (
set "LINE=%%L"
call :SUB LINE
)
)
endlocal
exit /B
:SUB
setlocal EnableDelayedExpansion
set "LINE=!%1!"
set "LINENEW="
set /A "POS=0"
:LOOP
set "CHAR=!LINE:~%POS%,1!"
set /A "POS+=1"
if not defined CHAR (
echo(!LINENEW!
endlocal
exit /B
)
if "!CHAR!"=="!QUOTE!" (
if defined QFLAG (
set "QFLAG="
) else (
set "QFLAG=Quoted"
)
if defined KEEPQUOTES (
set "LINENEW=!LINENEW!!CHAR!"
)
) else if defined QFLAG (
if "!CHAR!"=="!SEARCH!" (
set "LINENEW=!LINENEW!!REPLACE!"
) else (
set "LINENEW=!LINENEW!!CHAR!"
)
) else (
set "LINENEW=!LINENEW!!CHAR!"
)
goto :LOOP