I have been trying to find something related but couldn't.
I have an issue that i need to produce an availability percentage of something. I have a table that includes events that are happening, which i managed to count them by the day they are happening, but i am finding issues to count the total number of working hours in a quarter or a year.
when each day of the week has a different weight.
Basically my question is: can i do it without making a table with all dates in that month/year?
An example of the data:
ID DATE duration Environment
1 23/10/15 25 a
2 15/01/15 50 b
3 01/01/15 43 c
8 05/06/14 7 b
It can work for me by a calculated field or just a general query to get the information.
sorry I don't really understand the question but if you want to generate dates using connect by level is an easy way to do it (you could also use the model clause or recursive with) I did it here for just 10 days but you get the idea. I put in your dates as t1 and generated a list of dates (t) and then did a left outer join to put them together.
WITH t AS
(SELECT to_date('01-01-2015', 'mm-dd-yyyy') + level - 1 AS dt,
NULL AS duration
FROM dual
CONNECT BY level < = 10
),
t1 AS
(
SELECT to_date('10/01/15', 'dd-mm-yy') as dt, 50 as duration FROM dual
UNION ALL
SELECT to_date('01/01/15', 'dd-mm-yy'), 43 FROM dual
UNION ALL
SELECT to_date('06/01/15', 'dd-mm-yy'), 43 FROM dual
)
SELECT t.dt,
NVL(NVL(t1.duration, t.duration),0) duration
FROM t,
t1
WHERE t.dt = t1.dt(+)
ORDER BY dt
results
DT Duration
01-JAN-15 43
02-JAN-15 0
03-JAN-15 0
04-JAN-15 0
05-JAN-15 0
06-JAN-15 43
07-JAN-15 0
08-JAN-15 0
09-JAN-15 0
10-JAN-15 50
This was my intention, and the full answer below.
WITH t AS
(SELECT to_date('01-01-2015', 'mm-dd-yyyy') + level - 1 AS dt
FROM dual
CONNECT BY level < =365
),
t1 as
(
SELECT dt,
CASE
WHEN (to_char(TO_DATE( t.dt,'YYYY-MM-DD HH24:MI:SS'),'DY') in ('MON', 'TUE', 'WED', 'THU', 'FRI'))
THEN 14*60
WHEN (to_char(TO_DATE( t.dt,'YYYY-MM-DD HH24:MI:SS'),'DY') in ('SAT'))
THEN 8*60
WHEN (to_char(TO_DATE( t.dt,'YYYY-MM-DD HH24:MI:SS'),'DY') in ('SUN'))
THEN 10*60
ELSE 0 END duration ,
to_char(t.dt,'Q') as quarter
FROM t
)
select to_char(t1.dt,'yyyy'), to_char(t1.dt,'Q'),sum(t1.duration)
from t1
group by
to_char(t1.dt,'yyyy'), to_char(t1.dt,'Q');
Related
I have a very big table 'DATES_EVENTS' (20 T) that looks like this:
ID DATE
1 '2022-04-01'
1 '2022-03-02'
1 '2022-03-01'
2 '2022-05-01'
3 '2021-12-01'
3 '2021-11-11'
3 '2020-11-11'
3 '2020-10-01'
I want per each row to get all past dates (per user) limited to up to 6 months.
My desired table:
ID DATE DATE_list
1 '2022-04-01' ['2022-04-01','2022-03-02','2022-03-01']
1 '2022-03-02' ['2022-03-02','2022-03-01']
1 '2022-03-01' ['2022-03-01']
2 '2022-05-01' ['2022-05-01']
3 '2021-12-01' ['2021-12-01','2021-11-11']
3 '2021-11-11' ['2021-11-11']
3 '2020-11-11' ['2020-11-11','2020-10-01']
3 '2020-10-01' ['2020-10-01']
I have a solution for all dates not limited:
SELECT
ID, DATE, ARRAY_AGG(DATE) OVER (PARTITION BY ID ORDER BY DATE) as DATE_list
FROM
DATES_EVENTS
But for a limited up to 6 months I don't have an efficient solution:
SELECT
distinct A.ID, A.DATE, ARRAY_AGG(B.DATE) OVER (PARTITION BY B.ID ORDER BY B.DATE) as DATE_list
FROM
DATES_EVENTS A
INNER JOIN
DATES_EVENTS B
ON
A.ID=B.ID
AND B.DATE BETWEEN DATE_SUB(A.DATE, INTERVAL 180 DAY) AND A.DATE
** ruffly a solution
Anyone know of a good and efficient way to do what I need?
Consider below approach
select id, date, array(
select day
from t.date_list day
where day <= date
order by day desc
) as date_list
from (
select *, array_agg(date) over win as date_list
from dates_events
window win as (
partition by id
order by extract(year from date) * 12 + extract(month from date)
range between 5 preceding and current row
)
) t
if applied to sample data in your question - output is
In case if (as I noticed in your question) 180 days is appropriate substitution for 6 months for you - you can use below simpler version
select *, array_agg(date) over win as date_list
from dates_events
window win as (
partition by id
order by unix_date(date)
range between current row and 179 following
)
I write a Query to fetch a data for 10 days from the table. If there is no data for 10 days, then i need to fetch for 50 days.But i don't know how to modify my query to fetch data for 90 days.
Query:
Select ep.NAME||'|'||s.id||'|'||s.SUBMISSION_DATE||'|'||E.VALUE
from SUMMARY_EXT e, summary s, enterprise ep
where e.id = id and e.name_res_key = 'Plan'
and s.id in (select id from summary where
trunc(start_date) > trunc(sysdate) -10 and service_name ='Dplan')
I want to modify my query as if there is a data for 10 days then it should fetch for 10 days. If there is no data then it should fetch for 90days.
Analytic functions can help return rows based on the existence of other rows. First, use CASE expressions to categorize the rows into 10 day, 50 day, or 90 day buckets. Then use analytic functions to count the number of rows in each group. Finally, select only from the relevant groups depending on those counts.
For example:
-- Return 10 days, 50 days, or 90 days of data.
--
--#3: Only return certain rows depending on the counts.
select id, start_date
from
(
--#2: Count the number of rows in each category.
select id, start_date, is_lt_10, is_lt_50, is_lt_90
,sum(is_lt_10) over () total_lt_10
,sum(is_lt_50) over () total_lt_50
,sum(is_lt_90) over () total_lt_90
from
(
--#1: Put each row into a date category.
select
id, start_date,
case when trunc(start_date) > trunc(sysdate) - 10 then 1 else 0 end is_lt_10,
case when trunc(start_date) > trunc(sysdate) - 50 then 1 else 0 end is_lt_50,
case when trunc(start_date) > trunc(sysdate) - 90 then 1 else 0 end is_lt_90
from summary
where start_date > trunc(sysdate) - 90
)
)
where
(is_lt_10 = 1 and total_lt_10 > 0) or
(is_lt_50 = 1 and total_lt_10 = 0 and total_lt_50 > 0) or
(is_lt_90 = 1 and total_lt_50 = 0 and total_lt_90 > 0);
The below views can help simulate date ranges. For complicated queries like this, it's helpful to start as simple as possible, and add all the other joins and columns later.
--Data for 10 days only.
create or replace view summary as
select 1 id, sysdate start_date from dual union all
select 2 id, sysdate-49 start_date from dual union all
select 3 id, sysdate-89 start_date from dual union all
select 4 id, sysdate-99 start_date from dual;
--Data for 50 days only.
create or replace view summary as
select 2 id, sysdate-49 start_date from dual union all
select 3 id, sysdate-89 start_date from dual union all
select 4 id, sysdate-99 start_date from dual;
--Data for 90 days only.
create or replace view summary as
select 3 id, sysdate-89 start_date from dual union all
select 4 id, sysdate-99 start_date from dual;
I group my table by months
SELECT TO_CHAR (created, 'YYYY-MM') AS operation, COUNT (id)
FROM user_info
WHERE created IS NOT NULL
GROUP BY ROLLUP (TO_CHAR (created, 'YYYY-MM'))
2015-04 1
2015-06 10
2015-08 22
2015-09 8
2015-10 13
2015-12 5
2016-01 25
2016-02 37
2016-03 24
2016-04 1
2016-05 1
2016-06 2
2016-08 2
2016-09 7
2016-10 103
2016-11 5
2016-12 2
2017-04 14
2017-05 2
284
But the records don't cover all the months.
I would like the output to include all the months, with the missing ones displayed in the output with a default value:
2017-01 ...
2017-02 ...
2017-03 ZERO
2017-04 ZERO
2017-05 ...
Oracle has a good array of date manipulation functions. The two pertinent ones for this problem are
MONTHS_BETWEEN() which calculates the number of months between two dates
ADD_MONTHS() which increments a date by the given number of months
We can combine these functions to generate a table of all the months spanned by your table's records. Then we use an outer join to conditionally join records from USER_INFO to that calendar. When no records match count(id) will be zero.
with cte as (
select max(trunc(created, 'MM')) as max_dt
, min(trunc(created, 'MM')) as min_dt
from user_info
)
, cal as (
select add_months(min_dt, (level-1)) as mth
from cte
connect by level <= months_between(max_dt, min_dt) + 1
)
select to_char(cal.mth, 'YYYY-MM') as operation
, count(id)
from cal
left outer join user_info
on trunc(user_info.created, 'mm') = cal.mth
group by rollup (cal.mth)
order by 1
/
The question I need to answer is this "What is the maximum number of page requests we have ever received in a 60 minute period?"
I have a table that looks similar to this:
date_page_requested date;
page varchar(80);
I'm looking for the MAX count of rows in any 60 minute timeslice.
I thought analytic functions might get me there but so far I'm drawing a blank.
I would love a pointer in the right direction.
You have some options in the answer that will work, here is one that uses Oracle's "Windowing Functions with Logical Offset" feature instead of joins or correlated subqueries.
First the test table:
Wrote file afiedt.buf
1 create table t pctfree 0 nologging as
2 select date '2011-09-15' + level / (24 * 4) as date_page_requested
3 from dual
4* connect by level <= (24 * 4)
SQL> /
Table created.
SQL> insert into t values (to_date('2011-09-15 11:11:11', 'YYYY-MM-DD HH24:Mi:SS'));
1 row created.
SQL> commit;
Commit complete.
T now contains a row every quarter hour for a day with one additional row at 11:11:11 AM. The query preceeds in three steps. Step 1 is to, for every row, get the number of rows that come within the next hour after the time of the row:
1 with x as (select date_page_requested
2 , count(*) over (order by date_page_requested
3 range between current row
4 and interval '1' hour following) as hour_count
5 from t)
Then assign the ordering by hour_count:
6 , y as (select date_page_requested
7 , hour_count
8 , row_number() over (order by hour_count desc, date_page_requested asc) as rn
9 from x)
And finally select the earliest row that has the greatest number of following rows.
10 select to_char(date_page_requested, 'YYYY-MM-DD HH24:Mi:SS')
11 , hour_count
12 from y
13* where rn = 1
If multiple 60 minute windows tie in hour count, the above will only give you the first window.
This should give you what you need, the first row returned should have
the hour with the highest number of pages.
select number_of_pages
,hour_requested
from (select to_char(date_page_requested,'dd/mm/yyyy hh') hour_requested
,count(*) number_of_pages
from pages
group by to_char(date_page_requested,'dd/mm/yyyy hh')) p
order by number_of_pages
How about something like this?
SELECT TOP 1
ranges.date_start,
COUNT(data.page) AS Tally
FROM (SELECT DISTINCT
date_page_requested AS date_start,
DATEADD(HOUR,1,date_page_requested) AS date_end
FROM #Table) ranges
JOIN #Table data
ON data.date_page_requested >= ranges.date_start
AND data.date_page_requested < ranges.date_end
GROUP BY ranges.date_start
ORDER BY Tally DESC
For PostgreSQL, I'd first probably write something like this for a "window" aligned on the minute. You don't need OLAP windowing functions for this.
select w.ts,
date_trunc('minute', w.ts) as hour_start,
date_trunc('minute', w.ts) + interval '1' hour as hour_end,
(select count(*)
from weblog
where ts between date_trunc('minute', w.ts) and
(date_trunc('minute', w.ts) + interval '1' hour) ) as num_pages
from weblog w
group by ts, hour_start, hour_end
order by num_pages desc
Oracle also has a trunc() function, but I'm not sure of the format. I'll either look it up in a minute, or leave to see a friend's burlesque show.
WITH ranges AS
( SELECT
date_page_requested AS StartDate,
date_page_requested + (1/24) AS EndDate,
ROWNUMBER() OVER(ORDER BY date_page_requested) AS RowNo
FROM
#Table
)
SELECT
a.StartDate AS StartDate,
MAX(b.RowNo) - a.RowNo + 1 AS Tally
FROM
ranges a
JOIN
ranges b
ON a.StartDate <= b.StartDate
AND b.StartDate < a.EndDate
GROUP BY a.StartDate
, a.RowNo
ORDER BY Tally DESC
or:
WITH ranges AS
( SELECT
date_page_requested AS StartDate,
date_page_requested + (1/24) AS EndDate,
ROWNUMBER() OVER(ORDER BY date_page_requested) AS RowNo
FROM
#Table
)
SELECT
a.StartDate AS StartDate,
( SELECT MIN(b.RowNo) - a.RowNo
FROM ranges b
WHERE b.StartDate > a.EndDate
) AS Tally
FROM
ranges a
ORDER BY Tally DESC
below mentioned qry only am using to filter the data in time basis. am having a little bit doubt in that. for e.g. for 01AM i ll get the 8 records but it should have 7 records. bcoz
2 columns repeated. if i use count seperately it ll give write ans. can u plz help me..
SELECT TRUNC(createdon,'hh'), SUM(CASE WHEN hh=1 THEN 1 ELSE 0) h1,
SUM(CASE WHEN hh=2 THEN 1 ELSE 0) h2 .....
FROM TABLle1,
(SELECT 1 AS hh FROM dual
UNION
SELECT 2 AS hh FROM dual
UNION
SELECT 3 AS hh FROM dual
....
) hours
WHERE LABSTATUS=1 AND CREATEDON >=TO_DATE('01/07/2010 10','DD/MM/YYYY hh') AND
TRUNC(createdon,'hh')= hours.hh
GROUP BY TRUNC(createdon,'hh')
You might want to use HH24 instead of HH.