I'm trying to use the sort command to sort integers in string separated by a space. For example 8 6 5 7 9 56 -20 - 10. I receive the string on the standard output. I tried all of these but nothing works :
sort -t' '
sort -t ' '
sort -t " "
sort -t" "
sort -t=" "
echo "8 6 5 7 9 56 -20 - 10" | tr ' ' '\n' | sort -n
Sort can only sort lines.
You can first read string into an array with space as delimiter then use sort with process substitution:
s='8 6 5 7 9 56 -20 - 10'
read -ra arr <<< "$s"
sort -n <(printf "%s\n" "${arr[#]}")
Output:
-20
-10
5
6
7
8
9
56
To store output in string again:
read -r str < <(sort -n <(printf "%s\n" "${arr[#]}") | tr '\n' ' ')
And check output:
declare -p str
declare -- str="-20 -10 5 6 7 8 9 56"
Related
I have a file txt
for example:
11 23 4 9
5 2 17 25
and the output that I want is:
2 4 5 9
11 17 23 25
Sort the numbers in the file with sort -un:
tr ' ' '\n' < file.txt | sort -un | tr '\n' ' '
$ tr -s ' ' '\n' <file | sort -n | paste -d ' ' - - - -
2 4 5 9
11 17 23 25
tr changes all spaces into newlines and removes excess newlines from the input. This create a stream of numbers, one number per line, which is then sorted numerically and pasted into four space-separate columns.
this gawk codes will work for the dynamic number of columns:
awk '{for(x=1;x<=NF;x++)a[++i]=$x}
END{asort(a,b)
for(x=1;x<=i;x++)printf "%s%s",b[x],x%NF==0?RS:FS,b[x]}' file
Im stuck on some homework. The requirements of the assignment are to accept an input file and perform some statistics on the values. The user may specify whether to calculate the statistics by row or by value. The shell script must be pure bash script so I can't use awk, sed, perl, python etc.
sample input:
1 1 1 1 1 1 1
39 43 4 3225 5 2 2
6 57 8 9 7 3 4
3 36 8 9 14 4 3
3 4 2 1 4 5 5
6 4 4814 7 7 6 6
I can't figure out how to sort and process the data by column. My code for processing the rows works fine.
# CODE FOR ROWS
while read -r line
echo $(printf "%d\n" $line | sort -n) | tr ' ' \\t > sorted.txt
....
#I perform the stats calculations
# for row line by working with the temp file sorted.txt
done
How could I process this data by column? I've never worked with shell script so I've been staring at this for hours.
If you wanted to analyze by columns you'll need the cols value first (number of columns). head -n 1 gives you the first row, and NF counts the number of fields, giving us the number of columns.
cols=$(head -n 1 test.txt | awk '{print NF}');
Then you can use cut with the '\t' delimiter to grab every column from input.txt, and run it through sort -n, as you did in your original post.
$ for i in `seq 2 $((cols+1))`; do cut -f$i -d$'\t' input.txt; done | sort -n > output.txt
For rows, you can use the shell built-in printf with the format modifier %dfor integers. The sort command works on lines of input, so we replace spaces ' ' with newlines \n using the tr command:
$ cat input.txt | while read line; do echo $(printf "%d\n" $line); done | tr ' ' '\n' | sort -n > output.txt
Now take the output file to gather our statistics:
Min: cat output.txt | head -n 1
Max: cat output.txt | tail -n 1
Sum: (courtesy of Dimitre Radoulov): cat output.txt | paste -sd+ - | bc
Mean: (courtesy of porges): cat output.txt | awk '{ $total += $2 } END { print $total/NR }'
Median: (courtesy of maxschlepzig): cat output.txt | awk ' { a[i++]=$1; } END { print a[int(i/2)]; }'
Histogram: cat output.txt | uniq -c
8 1
3 2
4 3
6 4
3 5
4 6
3 7
2 8
2 9
1 14
1 36
1 39
1 43
1 57
1 3225
1 4814
I have 5 variables and each variables contains five values.I want to print five lines with the five values from five variables one by one
For example
$a=1 2 3 4 5
$b=4 2 3 4 5
$c=8 9 7 6 5
$d= 8 7 6 5 4
$e=5 6 7 3 3
I want to print five lines in this format
My options was a=1,b=4,c=8,d=8and e=5
My options was a=2,b=2,c=9,d=7 and e=6
and so on upto five values.
I got confused in using the loops.Can anyone help me to provide loops in script to obtain the following output.
a="1 2 3 4 5"
b="4 2 3 4 5"
c="8 9 7 6 5"
d="8 7 6 5 4"
e="5 6 7 3 3"
for i in $(seq 1 5); do
echo -e "My options was \c"
echo -e "a=$(echo $a | cut -f$i -d' ')\c"
echo -e "b=$(echo $b | cut -f$i -d' ')\c"
echo -e "c=$(echo $c | cut -f$i -d' ')\c"
echo -e "d=$(echo $d | cut -f$i -d' ') and \c"
echo -e "e=$(echo $e | cut -f$i -d' ')"
done
Using this awk command with a bash loop:
for i in {1..5}; do
awk '{printf "My options was a=%d, b=%d, c=%d, d=%d and e=%d\n", $1, $2, $3, $4, $5}' <<< $(awk '{print $'$i'}' <(echo -e "$a\n$b\n$c\n$d\n$e") | tr $'\n' ' '); done
Output:
$ a='1 2 3 4 5'
$ b='4 2 3 4 5'
$ c='8 9 7 6 5'
$ d='8 7 6 5 4'
$ e='5 6 7 3 3'
$ for i in {1..5}; do
awk '{printf "My options was a=%d, b=%d, c=%d, d=%d and e=%d\n", $1, $2, $3, $4, $5}' <<< $(awk '{print $'$i'}' <(echo -e "$a\n$b\n$c\n$d\n$e") | tr $'\n' ' '); done
My options was a=1, b=4, c=8, d=8 and e=5
My options was a=2, b=2, c=9, d=7 and e=6
My options was a=3, b=3, c=7, d=6 and e=7
My options was a=4, b=4, c=6, d=5 and e=3
My options was a=5, b=5, c=5, d=4 and e=3
If you transpose the matrix, this is really simple, portable, and idiomatic.
while read -r a b c d e; do
: stuff with "$a", "$b", etc
done <<____
1 4 8 8 5
2 2 9 7 6
3 3 7 6 7
4 4 6 5 3
5 5 5 4 3
____
Notice how the first column enumerates the a values, the second, the bs, etc.
I am trying to merge 2 files in one single.
FILE1
2015-09-30T13:30:57+01:00 6 1
2015-09-30T13:30:58+01:00 6 1
2015-09-30T13:30:59+01:00 6 1
2015-09-30T13:31:00+01:00 6 1
2015-09-30T13:31:01+01:00 6 1
2015-09-30T13:31:02+01:00 6 1
2015-09-30T13:31:04+01:00 6 1
FILE2
2015-09-30T13:16:19+01:00 4
2015-09-30T13:16:20+01:00 7
2015-09-30T13:16:21+01:00 7
2015-09-30T13:16:22+01:00 8
2015-09-30T13:16:23+01:00 8
2015-09-30T13:16:24+01:00 7
2015-09-30T13:16:25+01:00 2
2015-09-30T13:16:26+01:00 4
2015-09-30T13:16:27+01:00 1
2015-09-30T13:30:58+01:00 1
The result that I am trying to get is to add the column 2 from FILE2 being added to FILE1 as fourth columns as the time match:
2015-09-30T13:30:57+01:00 6 1 4
2015-09-30T13:16:23+01:00 8 3 1
Thank you for your help,
Al.
Use cut to find the first column and nested while loop to compare the firsts columns:
#!/usr/bin/bash
printf "" > FILE3
while read line1; do
file1_first_col=$(printf "${line1}" | cut -f1 -d' ')
printf "${line1}" >> FILE3
while read line2; do
file2_first_col=$(printf "${line2}"| cut -f1 -d' ')
if [[ "${file1_first_col}" == "${file2_first_col}" ]]; then
file2_second_col=$(printf "${line2}" | cut -f2 -d' ')
printf " ${file2_second_col}" >> FILE3
fi
done < FILE2
printf "\n" >> FILE3
done < FILE1
Then print the result to a file called FILE3.
NOTE that for large files this may be very slow.
I have a file/string containing the following:
[1-9]
[11-12]
[10-15]
I then want to expand that to become this:
1 2 3 4 5 6 7 8 9
11 12
10 11 12 13 14 15
I know how to do it in a very long way (first capture the two numbers and then expand them using a for loop).
I would like to know if there is a faster/smarter way of achieve the same.
One way:(Pure bash solution)
while IFS=- read l1 l2
do
eval echo ${l1/[/{}".."${l2/]/}}
done < file
There are several solutions.
Solution 1:
sed 's/^/echo /; s/[[]/{/; s/]/}/; s/-/../' | bash
Example:
$ cat 1.txt | sed 's/^/echo /; s/[[]/{/; s/]/}/; s/-/../' | bash
1 2 3 4 5 6 7 8 9
11 12
10 11 12 13 14 15
Solution 2:
tr '[]-' ' ' | sed "s/^/seq -s' '/" | bash
Example:
$ cat 1.txt | tr '[]-' ' ' | sed "s/^/seq -s' '/" | bash
1 2 3 4 5 6 7 8 9
11 12
10 11 12 13 14 15
If you're confident that your input all matches that pattern:
while read a; do
seq -s' ' $(echo "$a" | tr '[]-' ' ')
done
Add error checking as appropriate.
Here's a one-liner:
cat lines | sed -E -e 's/\[|]//g' -e 's/-/ /g' | xargs -n 2 seq -s ' ' -t '\n'
As in:
$ cat <<EOF | sed -E -e 's/\[|]//g' -e 's/-/ /g' | xargs -n 2 seq -s ' ' -t '\n'
> [1-9]
> [11-12]
> [10-15]
> EOF
1 2 3 4 5 6 7 8 9
11 12
10 11 12 13 14 15