I observed some applications create a geometric structure apparently by just having a set of touch points. Like this example:
I wonder which algorithms can possibly help me to recreate such geometric structures?
UPDATE
In 3D printing, sometimes a support structure is needed:
The need for support is due to collapse of some 3D object regions, i.e. overhangs, while printing. Support structure is supposed to connect overhangs either to print floor or to 3D object itself. The geometric structure shown in the screenshot above is actually a sample support structure.
I am not a specialist in that matter and I may be missing important issues. So here is what I would naively do.
The triangles having a external normal pointing downward will reveal the overhangs. When projected vertically and merged by common edges, they define polygonal regions of the base plane. You first have to build those projected polygons, find their intersections, and order the intersections by Z. (You might also want to consider the facing polygons to take the surface thickness into account).
Now for every intersection polygon, you draw verticals to the one just below. The projections of the verticals might be sampled from a regular grid or elsehow, to tune the density. You might also consider sampling those pillars from the basement continuously to the upper surface, possibly stopping some of them earlier.
The key ingredient in this procedure is a good polygon intersection algorithm.
I have a challenging problem to solve. The Figure shows green lines, that are derived from an image and the red lines are the edges derived from another image. Both the images are taken from the same camera, so the intrinsic parameters are same. Only, the exterior parameters are different, i.e. there is a slight rotation and translation while taking the 2nd image. As it can be seen in the figure, the two sets of lines are pretty close. My task is to find correspondence between the edges derived from the 1st image and the edges derived from the second image.
I have gone through a few sources, that mention taking corresponding the nearest line segment, by calculating Euclidean distances between the endpoints of an edge of image 1 to the edges of image 2. However, this method is not acceptable for my case, as there are edges in image 1, near to other edges in image 2 that are not corresponding, and this will lead to a huge number of mismatches.
After a bit of more research, few more sources referred to Hausdorff distance. I believe that this could really be a solution to my problem and the paper
"Rucklidge, William J. "Efficiently locating objects using the
Hausdorff distance." International Journal of Computer Vision 24.3
(1997): 251-270."
seemed to be really interesting.
If, I got it correct the paper formulated a function for calculating translation of model edges to image edges. However, while implementation in MATLAB, I'm completely lost, where to begin. I will be much obliged if I can be directed to a pseudocode of the same algorithm or MATLAB implementation of the same.
Additionally, I am aware of
"Apply Hausdorff distance to tile image classification" link
and
"Hausdorff regression"
However, still, I'm unsure how to minimise Hausdorff distance.
Note1: Computational cost is not of concern now, but faster algorithm is preferred
Note2: I am open to other algorithms and methods to solve this as long as there is a pseudocode available or an open implementation.
Have you considered MATLAB's image registration tools?
With imregister(https://www.mathworks.com/help/images/ref/imregister.html), you can just insert both images, 1 as reference, one as "moving" and it will register them together using an affine transform. The function call is just
[optimizer, metric] = imregconfig('monomodal');
output_registered = imregister(moving,fixed,'affine',optimizer,metric);
For better visualization, use the RegistrationEstimator command to open up a gui in which you can import the 2 images and play around with it to register your images. From there you can export code for future images.
Furthermore if you wish to account for non-rigid transforms there is imregdemons(https://www.mathworks.com/help/images/ref/imregdemons.html) which works much the same way.
You can compute the Hausdorff distance using Matlab's bwdist function. You would compute the distance transform of one image, evaluate it at the edge points of the other, and take the maximum value. (You can also take the sum instead, in which case it is called the chamfer distance.) For this problem you'll probably want the symmetric Hausdorff distance, so you would do the computation in both directions.
Both Hausdorff and chamfer distance measure the match quality of a particular alignment. To find the best registration you'll need to try multiple alignment transformations and evaluate them all looking for the best one. As suggested in another answer, you may find it easier to use registration existing tools than to write your own.
I want to write a program to draw a picture which covers a plane with tiled irregular quadrangles, just like this one:
However, I don't know the relevant algorithms, for example, in which order should I draw the edges?
Could someone point a direction for me?
Apologies, in my previous answer, I misunderstood the question.
Here is one stab at an algorithm (not necessarily the most optimal way, but a way). All you need is the ability to render a polygon and a basic rotation.
If you don't want the labels to be flipped, draw them separately (the labels can be stored in the vertices, e.g., and rotated with the polygon points, but drawn upright as text).
Edit
I received a question about the "start with an arbitrary polygon" step. I didn't communicate that step very clearly, as I actually intended to merely suggest an arbitrary polygon from the provided diagram, and not any arbitrary polygon in the world.
However, this should work at least for arbitrary quads, including concave ones, like so:
I'm afraid I lack the proper background to provide a proof as to why this works, however. Perhaps more mathematically-savvy people can help there with the proof.
I think one way to tackle the proof is to first start with the notion that all tiled edges are manifold -- this is a given considering that we're generating a neighboring polygon at every edge in order to generate the tiled result. Then we might be able to prove that every 2-valence boundary vertex is going to become a 4-valence vertex as a result of this operation (since each of its two edges are going to become manifold, and that introduces two new vertex edges into the mix -- this seems like the hardest part to prove to me). Last step might be to prove that the sum of the angles at each 4-valence vertex will always add up to 360 degrees.
I have a set of 3d points that approximate a surface. Each point, however, are subject to some error. Furthermore, the set of points contain a lot more points than is actually needed to represent the underlying surface.
What I am looking for is an algorithm to create a new (much smaller) set of points representing a simplified, smoother version of the surface (pardon for not having a better definition than "simplified, smoother"). The underlying surface is not a mathematical one so I'm not hoping to fit the data set to some mathematical function.
Instead of dealing with it as a point cloud, I would recommend triangulating a mesh using Delaunay triangulation: http://en.wikipedia.org/wiki/Delaunay_triangulation
Then decimate the mesh. You can research decimation algorithms, but you can get pretty good quick and dirty results with an algorithm that just merges adjacent tris that have similar normals.
I think you are looking for 'Level of detail' algorithms.
A simple one to implement is to break your volume (surface) into some number of sub-volumes. From the points in each sub-volume, choose a representative point (such as the one closest to center, or the closest to the average, or the average etc). use these points to redraw your surface.
You can tweak the number of sub-volumes to increase/decrease detail on the fly.
I'd approach this by looking for vertices (points) that contribute little to the curvature of the surface. Find all the sides emerging from each vertex and take the dot products of pairs (?) of them. The points representing very shallow "hills" will subtend huge angles (near 180 degrees) and have small dot products.
Those vertices with the smallest numbers would then be candidates for removal. The vertices around them will then form a plane.
Or something like that.
Google for Hugues Hoppe and his "surface reconstruction" work.
Surface reconstruction is used to find a meshed surface to fit the point cloud; however, this method yields lots of triangles. You can then apply mesh a reduction technique to reduce the polygon count in a way to minimize error. As an example, you can look at OpenMesh's decimation methods.
OpenMesh
Hugues Hoppe
There exist several different techniques for point-based surface model simplification, including:
clustering;
particle simulation;
iterative simplification.
See the survey:
M. Pauly, M. Gross, and L. P. Kobbelt. Efficient simplification of point-
sampled surfaces. In Proceedings of the conference on Visualization’02,
pages 163–170, Washington, DC, 2002. IEEE.
unless you parametrise your surface in some way i'm not sure how you can decide which points carry similar information (and can thus be thrown away).
i guess you can choose a bunch of points at random to get rid of, but that doesn't sound like what you want to do.
maybe points near each other (for some definition of 'near') can be considered to contain similar information, and so reduced to single representatives for each such group.
could you give some more details?
It's simpler to simplify a point cloud without the constraints of mesh triangles and indices.
smoothing and simplification are different tasks though. To simplify the cloud you should first get rid of noise artefacts by making a profile of the kind of noise that you have, it's frequency and directional caracteristics and do a noise profile compared type reduction. good normal vectors are helfpul for that.
here is a document about 5-6 simplifications using delauney, voronoi, and k nearest neighbour maths:
http://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.10.9640&rep=rep1&type=pdf
A later version from 2008:
http://www.wseas.us/e-library/transactions/research/2008/30-705.pdf
here is a recent c++ version:
https://github.com/tudelft3d/masbcpp/blob/master/src/simplify.cpp
I've been working on a visualization project for 2-dimensional continuous data. It's the kind of thing you could use to study elevation data or temperature patterns on a 2D map. At its core, it's really a way of flattening 3-dimensions into two-dimensions-plus-color. In my particular field of study, I'm not actually working with geographical elevation data, but it's a good metaphor, so I'll stick with it throughout this post.
Anyhow, at this point, I have a "continuous color" renderer that I'm very pleased with:
The gradient is the standard color-wheel, where red pixels indicate coordinates with high values, and violet pixels indicate low values.
The underlying data structure uses some very clever (if I do say so myself) interpolation algorithms to enable arbitrarily deep zooming into the details of the map.
At this point, I want to draw some topographical contour lines (using quadratic bezier curves), but I haven't been able to find any good literature describing efficient algorithms for finding those curves.
To give you an idea for what I'm thinking about, here's a poor-man's implementation (where the renderer just uses a black RGB value whenever it encounters a pixel that intersects a contour line):
There are several problems with this approach, though:
Areas of the graph with a steeper slope result in thinner (and often broken) topo lines. Ideally, all topo lines should be continuous.
Areas of the graph with a flatter slope result in wider topo lines (and often entire regions of blackness, especially at the outer perimeter of the rendering region).
So I'm looking at a vector-drawing approach for getting those nice, perfect 1-pixel-thick curves. The basic structure of the algorithm will have to include these steps:
At each discrete elevation where I want to draw a topo line, find a set of coordinates where the elevation at that coordinate is extremely close (given an arbitrary epsilon value) to the desired elevation.
Eliminate redundant points. For example, if three points are in a perfectly-straight line, then the center point is redundant, since it can be eliminated without changing the shape of the curve. Likewise, with bezier curves, it is often possible to eliminate cetain anchor points by adjusting the position of adjacent control points.
Assemble the remaining points into a sequence, such that each segment between two points approximates an elevation-neutral trajectory, and such that no two line segments ever cross paths. Each point-sequence must either create a closed polygon, or must intersect the bounding box of the rendering region.
For each vertex, find a pair of control points such that the resultant curve exhibits a minimum error, with respect to the redundant points eliminated in step #2.
Ensure that all features of the topography visible at the current rendering scale are represented by appropriate topo lines. For example, if the data contains a spike with high altitude, but with extremely small diameter, the topo lines should still be drawn. Vertical features should only be ignored if their feature diameter is smaller than the overall rendering granularity of the image.
But even under those constraints, I can still think of several different heuristics for finding the lines:
Find the high-point within the rendering bounding-box. From that high point, travel downhill along several different trajectories. Any time the traversal line crossest an elevation threshold, add that point to an elevation-specific bucket. When the traversal path reaches a local minimum, change course and travel uphill.
Perform a high-resolution traversal along the rectangular bounding-box of the rendering region. At each elevation threshold (and at inflection points, wherever the slope reverses direction), add those points to an elevation-specific bucket. After finishing the boundary traversal, start tracing inward from the boundary points in those buckets.
Scan the entire rendering region, taking an elevation measurement at a sparse regular interval. For each measurement, use it's proximity to an elevation threshold as a mechanism to decide whether or not to take an interpolated measurement of its neighbors. Using this technique would provide better guarantees of coverage across the whole rendering region, but it'd be difficult to assemble the resultant points into a sensible order for constructing paths.
So, those are some of my thoughts...
Before diving deep into an implementation, I wanted to see whether anyone else on StackOverflow has experience with this sort of problem and could provide pointers for an accurate and efficient implementation.
Edit:
I'm especially interested in the "Gradient" suggestion made by ellisbben. And my core data structure (ignoring some of the optimizing interpolation shortcuts) can be represented as the summation of a set of 2D gaussian functions, which is totally differentiable.
I suppose I'll need a data structure to represent a three-dimensional slope, and a function for calculating that slope vector for at arbitrary point. Off the top of my head, I don't know how to do that (though it seems like it ought to be easy), but if you have a link explaining the math, I'd be much obliged!
UPDATE:
Thanks to the excellent contributions by ellisbben and Azim, I can now calculate the contour angle for any arbitrary point in the field. Drawing the real topo lines will follow shortly!
Here are updated renderings, with and without the ghetto raster-based topo-renderer that I've been using. Each image includes a thousand random sample points, represented by red dots. The angle-of-contour at that point is represented by a white line. In certain cases, no slope could be measured at the given point (based on the granularity of interpolation), so the red dot occurs without a corresponding angle-of-contour line.
Enjoy!
(NOTE: These renderings use a different surface topography than the previous renderings -- since I randomly generate the data structures on each iteration, while I'm prototyping -- but the core rendering method is the same, so I'm sure you get the idea.)
Here's a fun fact: over on the right-hand-side of these renderings, you'll see a bunch of weird contour lines at perfect horizontal and vertical angles. These are artifacts of the interpolation process, which uses a grid of interpolators to reduce the number of computations (by about 500%) necessary to perform the core rendering operations. All of those weird contour lines occur on the boundary between two interpolator grid cells.
Luckily, those artifacts don't actually matter. Although the artifacts are detectable during slope calculation, the final renderer won't notice them, since it operates at a different bit depth.
UPDATE AGAIN:
Aaaaaaaand, as one final indulgence before I go to sleep, here's another pair of renderings, one in the old-school "continuous color" style, and one with 20,000 gradient samples. In this set of renderings, I've eliminated the red dot for point-samples, since it unnecessarily clutters the image.
Here, you can really see those interpolation artifacts that I referred to earlier, thanks to the grid-structure of the interpolator collection. I should emphasize that those artifacts will be completely invisible on the final contour rendering (since the difference in magnitude between any two adjacent interpolator cells is less than the bit depth of the rendered image).
Bon appetit!!
The gradient is a mathematical operator that may help you.
If you can turn your interpolation into a differentiable function, the gradient of the height will always point in the direction of steepest ascent. All curves of equal height are perpendicular to the gradient of height evaluated at that point.
Your idea about starting from the highest point is sensible, but might miss features if there is more than one local maximum.
I'd suggest
pick height values at which you will draw lines
create a bunch of points on a fine, regularly spaced grid, then walk each point in small steps in the gradient direction towards the nearest height at which you want to draw a line
create curves by stepping each point perpendicular to the gradient; eliminate excess points by killing a point when another curve comes too close to it-- but to avoid destroying the center of hourglass like figures, you might need to check the angle between the oriented vector perpendicular to the gradient for both of the points. (When I say oriented, I mean make sure that the angle between the gradient and the perpendicular value you calculate is always 90 degrees in the same direction.)
In response to your comment to #erickson and to answer the point about calculating the gradient of your function. Instead of calculating the derivatives of your 300 term function you could do a numeric differentiation as follows.
Given a point [x,y] in your image you could calculate the gradient (direction of steepest decent)
g={ ( f(x+dx,y)-f(x-dx,y) )/(2*dx),
{ ( f(x,y+dy)-f(x,y-dy) )/(2*dy)
where dx and dy could be the spacing in your grid. The contour line will run perpendicular to the gradient. So, to get the contour direction, c, we can multiply g=[v,w] by matrix, A=[0 -1, 1 0] giving
c = [-w,v]
Alternately, there is the marching squares algorithm which seems appropriate to your problem, although you may want to smooth the results if you use a coarse grid.
The topo curves you want to draw are isosurfaces of a scalar field over 2 dimensions. For isosurfaces in 3 dimensions, there is the marching cubes algorithm.
I've wanted something like this myself, but haven't found a vector-based solution.
A raster-based solution isn't that bad, though, especially if your data is raster-based. If your data is vector-based too (in other words, you have a 3D model of your surface), you should be able to do some real math to find the intersection curves with horizontal planes at varying elevations.
For a raster-based approach, I look at each pair of neighboring pixels. If one is above a contour level, and one is below, obviously a contour line runs between them. The trick I used to anti-alias the contour line is to mix the contour line color into both pixels, proportional to their closeness to the idealized contour line.
Maybe some examples will help. Suppose that the current pixel is at an "elevation" of 12 ft, a neighbor is at an elevation of 8 ft, and contour lines are every 10 ft. Then, there is a contour line half way between; paint the current pixel with the contour line color at 50% opacity. Another pixel is at 11 feet and has a neighbor at 6 feet. Color the current pixel at 80% opacity.
alpha = (contour - neighbor) / (current - neighbor)
Unfortunately, I don't have the code handy, and there might have been a bit more to it (I vaguely recall looking at diagonal neighbors too, and adjusting by sqrt(2) / 2). I hope this enough to give you the gist.
It occurred to me that what you're trying to do would be pretty easy to do in MATLAB, using the contour function. Doing things like making low-density approximations to your contours can probably be done with some fairly simple post-processing of the contours.
Fortunately, GNU Octave, a MATLAB clone, has implementations of the various contour plotting functions. You could look at that code for an algorithm and implementation that's almost certainly mathematically sound. Or, you might just be able to offload the processing to Octave. Check out the page on interfacing with other languages to see if that would be easier.
Disclosure: I haven't used Octave very much, and I haven't actually tested it's contour plotting. However, from my experience with MATLAB, I can say that it will give you almost everything you're asking for in just a few lines of code, provided you get your data into MATLAB.
Also, congratulations on making a very VanGough-esque slopefield plot.
I always check places like http://mathworld.wolfram.com before going to deep on my own :)
Maybe their curves section would help? Or maybe the entry on maps.
compare what you have rendered with a real-world topo map - they look identical to me! i wouldn't change a thing...
Write the data out as an HGT file (very simple digital elevation data format used by USGS) and use the free and open-source gdal_contour tool to create contours. That works very well for terrestrial maps, the constraint being that the data points are signed 16-bit numbers, which fits the earthly range of heights in metres very well, but may not be enough for your data, which I assume not to be a map of actual terrain - although you do mention terrain maps.
I recommend the CONREC approach:
Create an empty line segment list
Split your data into regular grid squares
For each grid square, split the square into 4 component triangles:
For each triangle, handle the cases (a through j):
If a line segment crosses one of the cases:
Calculate its endpoints
Store the line segment in the list
Draw each line segment in the line segment list
If the lines are too jagged, use a smaller grid. If the lines are smooth enough and the algorithm is taking too long, use a larger grid.