maven-assembly-plugin include *.properties at root level of zip - maven

I'm trying to get maven to include my *.properties files when it zips up my artifacts. They are located inside src/main/resources. I tried adding the fileSet element to my assembly file, but the resources are not being included in the zip. I saw this question which seems to indicate that adding fileSet should work.
plugins.xml:
<?xml version="1.0"?>
<assembly>
<id>release</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>${project.build.directory}</directory>
<outputDirectory>/</outputDirectory>
<includes>
<include>*.properties</include>
</includes>
</fileSet>
</fileSets>
<dependencySets>
<dependencySet>
<outputDirectory>/</outputDirectory>
<useProjectArtifact>true</useProjectArtifact>
<useTransitiveFiltering>true</useTransitiveFiltering>
</dependencySet>
</dependencySets>
</assembly>

The properties that you want to include inside your ZIP are located in the src/main/resources source directory of your project. So the <fileSet> element should point to this directory.
${project.build.directory} is Maven current build directory, which is by default target. You could also point to the temporary directory where Maven copies all resources during the build but it is preferable to stick with the permanent data where possible.
As such, you just need to change your <fileSet> element with:
<directory>src/main/resources</directory>

Related

Maven assembly plugin: include file without taking its path folders

I'm using maven-assembly-plugin to include files from a dependency ZIP (also generated with assembly plugin) into a final release ZIP file.
The issue is that I want to select which files from the dependency to get, but not copying the folder path where those files are. Just the files.
For example:
<assembly>
<formats>
<format>zip</format>
<format>dir</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<dependencySets>
<dependencySet>
<includes>
<include>package:artifactId:zip:*</include>
</includes>
<outputDirectory>sql/update/01.00.00_to_01.01.00</outputDirectory>
<unpack>true</unpack>
<unpackOptions>
<includes>
<include>oracle/update/1_alter_schema.sql</include>
<include>oracle/update/2_insert_data.sql</include>
</includes>
</unpackOptions>
<useProjectArtifact>false</useProjectArtifact>
<useTransitiveDependencies>false</useTransitiveDependencies>
</dependencySet>
</dependencySet>
</assembly>
This copies the required files like this:
sql/update/01.00.00_to_01.01.00/oracle/update/1_alter_schema.sql
sql/update/01.00.00_to_01.01.00/oracle/update/2_insert_data.sql
I would like to copy just the files without the original oracle/update/ folder, resulting in this folder structure:
sql/update/01.00.00_to_01.01.00/1_alter_schema.sql
sql/update/01.00.00_to_01.01.00/2_insert_data.sql
The dependency ZIP contains many files used by different projects, therefore the structure to differentiate oracle from sql-server files makes sense there, but for this distribution I don't need those folders, just the files.
Does somebody knows if this is possible with maven-assembly-plugin?
Many thanks in advance!
From the documentation of maven-assembly-plugin (maven-assembly-plugin) I can see that the <fileSets> tag does not provide us with the option of changing the path of an included resource. Instead we can use the <file> tag which gives us this flexibility.
For example, the below configuration will include file1.jar and run.bat in the root folder of the extracted zip file, skipping their original paths.
<assembly>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<files>
<file>
<source>target/file1.jar</source>
<destName>file1.jar</destName>
</file>
<file>
<source>src/main/resources/run.bat</source>
<destName>run.bat</destName>
</file>
</files>
</assembly>
It should work by splitting the dependency unzipping and the file assembly.
Configure the dependency-plugin to unpack the desired dependency before performing the assembly work:
<plugin>
<artifactId>maven-dependency-plugin</artifactId>
<configuration>
<includeArtifactIds>project-sql</includeArtifactIds>
<outputDirectory>${project.build.directory}/extract</outputDirectory>
<includes>oracle/update/1_alter_schema.sql,oracle/update/2_insert_data.sql</includes>
</configuration>
<executions>
<execution>
<id>unpack-sql</id>
<phase>prepare-package</phase>
<goals><goal>unpack-dependencies</goal></goals>
</execution>
</executions>
</plugin>
Then, in your assembly-distribution.xml, just assemble from the sub-directory:
<?xml version="1.0" encoding="UTF-8"?>
<assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>distribution-${project.version}</id>
<formats>
<format>zip</format>
<format>dir</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>${project.build.directory}/extract/oracle/update</directory>
<outputDirectory>sql/update/01.00.00_to_01.01.00</outputDirectory>
</fileSet>
</fileSets>
</assembly>
I had the same problem, using dependencies plugin dumped a lot of other files, which I am sure it can be improved. But I think I found a simpler and better solution.
All you need to do is add another <fileSet>. The fileSet has the relative source path and an output directory. The value of your outputDirectory determines the path in the resulting zip. It is as simple as that. Hope this helps someone out there, fighting with producing lambda zips for AWS (rolling my eyes)
Here is my assembly.xml BEFORE(HAS PROBLEM) that I was struggling with:
<assembly>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory></directory>
<outputDirectory/>
<includes>
<include>lib/**.*</include>
<include>${basedir}/target/classes/com/abc/test.LambdaTest.*</include>
</includes>
</fileSet>
</fileSets>
</assembly>
The above produces zip with directory target, but here is an improved and FIXED (CORRECT) which does not have the path "target" in zip.
<assembly>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory></directory>
<outputDirectory/>
<includes>
<include>lib/**.*</include>
</includes>
</fileSet>
<fileSet>
<directory>${basedir}/target/classes</directory>
<outputDirectory/>
<includes>
<include>com/abc/test.LambdaTest.*</include>
</includes>
</fileSet>
</fileSets>
</assembly>
Pay attention to the value of <directory> in both fileSets, which provides a relative path which is not used to when files are added to the zip

Maven: add non-JAR dependency

I'am using the maven-assembly-plugin to create a tar.gz archive. Now I need to include files in that archive. These are just a bunch of plain old text files and are a dependency at runtime, not at compile or (unit) test time.
I thought about adding a maven dependency on that but these files are not stored in a maven repository but in a simple remove folder. To make it even worse, this folder is password protected. I could, in a pre-build-step, download these password-protected files into a local folder. But then there is still the problem of using those files in the assembly. Also, this is extra work I want to avoid.
Is there any way to do that?
If you can download those files, workaround password. Maybe this will help.
Create mod assembly project where you put something like that:
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.3"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.3 http://maven.apache.org/xsd/assembly-1.1.3.xsd">
<id>${artifact.version}</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<dependencySets>
<dependencySet>
<useProjectArtifact>false</useProjectArtifact>
<useTransitiveDependencies>true</useTransitiveDependencies>
<unpack>false</unpack>
<excludes>
<exclude>${project.groupId}:*:*</exclude>
</excludes>
<outputFileNameMapping>project${timestamp}_code-${artifact.name}.${artifact.extension}</outputFileNameMapping>
</dependencySet>
</dependencySets>
<fileSets>
<fileSet>
<includes>
<include>readme.txt</include> <!-- here's that plain file -->
</includes>
</fileSet>
</fileSets>
You can include those files in fileSets.
http://maven.apache.org/plugins/maven-assembly-plugin/examples/single/filtering-some-distribution-files.html for more info

Maven assembly: placing project jar in bin folder

We have a deploy.xml file which is referenced in by the maven-assembly-plugin section in the pom.xml.
When mvn package -DskipTests -Pdeploy is run from the command line, it creates a zip, within which all the dependency jars are placed in the lib folder. It also puts the project jar itself (with the code and configuration specific to our application) into the lib.
We would like the project jar to be placed in the bin folder. (Have been told that that is the standard, though not sure if that is true). How do we modify our configuration to do that?
This is the relevant configuration we have in deploy.xml right now:
<assembly>
<fileSets>
<fileSet>
<directory>bin</directory>
<outputDirectory>bin</outputDirectory>
</fileSet>
</fileSets>
...
<dependencySets>
<dependencySet>
<outputDirectory>lib</outputDirectory>
<includes>
<include>*:*</include>
</includes>
</dependencySet>
</dependencySets>
</assembly>
Thanks
You need two dependency sets, one including the project artifact, the other including your dependencies:
<dependencySets>
<dependencySet>
<outputDirectory>lib</outputDirectory>
<useProjectArtifact>false</useProjectArtifact>
</dependencySet>
<dependencySet>
<outputDirectory>bin</outputDirectory>
<includes>
<include>${yourgroupid}:${yourartifactid}:jar</include>
</includes>
<useProjectArtifact>true</useProjectArtifact>
</dependencySet>
</dependencySets>

Create maven uberjar without including an internal pom file

I have a maven build setup but it has been requested that I make one change to the uberjar and that is to not include the pom file, because it messes up my clients subsequent build that uses my uberjar as a dependancy. I know this is not the way to do this but my client cannot access my central repo because of security issues. So the uberjar was settled on as a deployment method. Now the question is this: Is there a way to not include the pom file in the creation of a jar via maven?
Thanks,
Blair
I assume you are using the maven-assembly-plugin to build your uberjar and using an assembly descriptor. What you want to do is instruct the assembly plugin (via the assembly descriptor) to exclude any files named "pom.xml". For example:
<assembly>
<id>bin</id>
<formats>
<format>jar</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>target/classes</directory>
<outputDirectory>/</outputDirectory>
</fileSet>
</fileSets>
<dependencySets>
<dependencySet>
<outputDirectory>/</outputDirectory>
<unpack>true</unpack>
<unpackOptions>
<excludes>
<exclude>**/pom.xml</exclude>
</excludes>
</unpackOptions>
<scope>runtime</scope>
<useProjectArtifact>false</useProjectArtifact>
</dependencySet>
</dependencySets>
</assembly>
The key here is the "unpackOptions" section and the exclusion contained therein.
Hope that helps, if so please remember to mark my answer as correct so I get the reputation points.

Deploy Akka java microkernel with maven

I am trying my hands on JCranky's tutorials about distributing akka microkernel with maven and tbt start scripts click. from the descriptor.xml file I suppose there are four directories to be created by the assembly pluggin.
below is the descriptor.xml file
<id>akka</id>
<formats>
<format>zip</format>
</formats>
<fileSets>
<fileSet>
<directory>${project.build.directory}</directory>
<outputDirectory>/deploy</outputDirectory>
<includes>
<include>*.jar</include>
</includes>
</fileSet>
</fileSets>
<dependencySets>
<dependencySet>
<outputDirectory>/lib</outputDirectory>
</dependencySet>
</dependencySets>
<files>
<file>
<source>src/main/start</source>
<outputDirectory>/bin</outputDirectory>
</file>
<file>
<source>src/main/resources/application.conf</source>
<outputDirectory>/config</outputDirectory>
</file>
</files>
</assembly>
The following directories are created in the zip folder. that is the lib, config and bin directories. Reading from the descriptor.xml file , looks like the deploy directory has to be created. don't know if I am missing something. Will be very happy for a clarification.
You have the wrong directory in the fileset.
Change to:
<directory>${project.build.directory}</directory>
It cannot find any files in the place you stated. Thus no files were copied and the deploy directory didn't have to be created.

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