My text file contains:
/**
*
**/
I want to replace the second line with text.txt so that it looks something like:
/**
* text.txt
**/
I tried the following sed command but it rendered the text file empty.
sed -n 2p -i -e "/^ \*/ s/ \*/ \* text.txt/" example.txt
Please let me know what I need to do to get the desired result.
sed -i -e "2s/$/ test.txt/" example.txt
if you want to do the replacement in line 2, specifically.
To add that to the line after /**
sed '/^\/\*\*/ {n; s/$/ text.txt/;}' example.txt
To replace the second line (independently on its content), use
sed -i -e '2c\ * test.txt' example.txt
2 addresses the second line, c\ replaces it with the rest of the argument
(\ is needed otherwise the space is omitted).
Related
i have 2 file.
analizeddata.txt:
A001->A002->A003->A004
A001->A005->A007
A022->A033
[...]
and
matrix.txt:
A001|Scott
A002|Bob
A003|Mark
A004|Jane
A005|Elion
A007|Brooke
A022|Meggie
A023|Tif
[..]
How i can replace in analizeddata.txt, or obtain a new file, with the second column of matrix.txt?
The expected output file will be as:
Scott->Bob->Mark->Jane
Scott->Elion->Brooke
Meggie->Tif
[...]
Thanks
Just use sed to replace the string what you want.
sed 's/|/\//g' matrix.txt will generate the replace pattern likes A001/Scott which will be used as regexp/replacement of the second sed s/regexp/replacement/ command.
sed -i option will update directly analizeddata.txt file, back up it before exec this command.
for replace_mode in $(sed 's/|/\//g' matrix.txt); do sed -i 's/'$replace_mode'/g' analizeddata.txt; done
Suggesting awk script:
awk -F"|" 'FNR==NR{arr[$1]=$2;next}{for(i in arr)gsub(i,arr[i])}1' matrix.txt analizeddata.txt
with provided sample data, results:
Scott->Bob->Mark->Jane
Scott->Elion->Brooke
Meggie->A033
Hello I'm sort of new to scripting and have the following problem
I need to replace 20069.1216.0
HintPath..\packages\String.20069.1216.0\lib\net\Thoo.Tkc.dll/HintPath
This works fine at replacing 20069.1216.0 with whatever is provided in $2
`xargs sed -i 's/String.20.........0/String.'"${2}"'/g'`
I need a way for sed to search for **"String.*\lib\net\"**where anything in between **String.** and **\lib...** is wildcard
This what i have tried
sed -i 's/String.*\/String.'"${2}"'/g'
sed -i 's/String.*\\/String.'"${2}"'/g'
sed -i 's/String.\(.*\)\\/String.'"${2}"'/g'
I'll assume that you call sed inside a function.
So try this code:
#!/bin/bash
replace() {
echo 'HintPath..\packages\String.20069.1216.0\lib\net\Thoo.Tkc.dll/HintPath' |\
sed "s/String\.[0-9.]*/String\.${2}/"
}
replace dont_care filename
If your path may contain --SNAPSHOT this solution should work for you:
#!/bin/bash
replace() {
echo 'HintPath..\packages\String.20069.1216.0--SNAPSHOT\lib\net\Thoo.Tkc.dll/HintPath' |\
sed "s/String[0-9.]*\(--SNAPSHOT\)\{0,1\}/String\.${2}/"
}
replace dont_care filename
I am trying to remove the last space of a file.txt which contains many rows.
I just need to remove "only the last space" after the third column/each line.
My file looks like this:
3 180 120
3 123 145
6 234 0
4 122 12
I have been trying with the following script but it does not work, so far. Somebody can help me, please?
#!/bin/bash
var="val1 val2 val3 "
var="${var%"${var##*[![:space:]]}"}"
echo "===$var===" <Antart_csv1_copy.txt> trimmed.txt
You can use sed:
sed -i -e 's/ $//g' filename.txt
-i will make the command inplace (change the original file)
-e 's/ $//g' will take regular expression <space><endline> and change it to nothing. Modifier g makes it for all lines in the file
You can try it first without -i and redirect output:
sed -e 's/ $//g' filename.txt > trimmed.txt
Another solution removing all trailing spaces from each line :
while read line; do echo "${line%%*( )}" >> trimmed.txt; done < Antart_csv1_copy.txt
I have many files named a, b, c and so on. These files contain line like this:-
11.077-105.882
-22.134-302.321
-1.011-201.254
I want to add a space when - sign come in mid of line. I want my output file look like this:-
11.077 -105.882
-22.134 -302.321
-1.011 -201.254
I have tried this command:-
cat a |sed 's/-/ -/g' >out.txt
But it do not give desired result
Require (and capture) a character before each - to replace:
$ sed 's/\(.\)-/\1 -/g' < tmp.txt
11.077 -105.882
-22.134 -302.321
-1.011 -201.254
This will only match a - that is not line-initial, and will include the preceding character in the replacement text.
You could combine 2 sed commands:
$ sed 's/-/ -/g' a | sed 's/^ //'
11.077 -105.882
-22.134 -302.321
-1.011 -201.254
Or, in a single line solution add whitespaces only before - that come after a digit:
$ sed 's,\([0-9]\)-,\1 -,' a
11.077 -105.882
-22.134 -302.321
-1.011 -201.254
I am trying to get a substring between &DEST= and the next & or a line break.
For example :
MYREQUESTISTO8764GETTHIS&DEST=SFO&ORIG=6546
In this I need to extract "SFO"
MYREQUESTISTO8764GETTHIS&DEST=SANFRANSISCO&ORIG=6546
In this I need to extract "SANFRANSISCO"
MYREQUESTISTO8764GETTHISWITH&DEST=SANJOSE
In this I need to extract "SANJOSE"
I am reading a file line by line, and I need to update the text after &DEST= and put it back in the file. The modification of the text is to mask the dest value with X character.
So, SFO should be replaced with XXX.
SANJOSE should be replaced with XXXXXXX.
Output :
MYREQUESTISTO8764GETTHIS&DEST=XXX&ORIG=6546
MYREQUESTISTO8764GETTHIS&DEST=XXXXXXXXXXXX&ORIG=6546
MYREQUESTISTO8764GETTHISWITH&DEST=XXXXXXX
Please let me know how to achieve this in script (Preferably shell or bash script).
Thanks.
$ cat file
MYREQUESTISTO8764GETTHIS&DEST=SFO&ORIG=6546
MYREQUESTISTO8764GETTHIS&DEST=PORTORICA
MYREQUESTISTO8764GETTHIS&DEST=SANFRANSISCO&ORIG=6546
MYREQUESTISTO8764GETTHISWITH&DEST=SANJOSE
$ sed -E 's/^.*&DEST=([^&]*)[&]*.*$/\1/' file
SFO
PORTORICA
SANFRANSISCO
SANJOSE
should do it
Replacing airports with an equal number of Xs
Let's consider this test file:
$ cat file
MYREQUESTISTO8764GETTHIS&DEST=SFO&ORIG=6546
MYREQUESTISTO8764GETTHIS&DEST=SANFRANSISCO&ORIG=6546
MYREQUESTISTO8764GETTHISWITH&DEST=SANJOSE
To replace the strings after &DEST= with an equal length of X and using GNU sed:
$ sed -E ':a; s/(&DEST=X*)[^X&]/\1X/; ta' file
MYREQUESTISTO8764GETTHIS&DEST=XXX&ORIG=6546
MYREQUESTISTO8764GETTHIS&DEST=XXXXXXXXXXXX&ORIG=6546
MYREQUESTISTO8764GETTHISWITH&DEST=XXXXXXX
To replace the file in-place:
sed -i -E ':a; s/(&DEST=X*)[^X&]/\1X/; ta' file
The above was tested with GNU sed. For BSD (OSX) sed, try:
sed -Ee :a -e 's/(&DEST=X*)[^X&]/\1X/' -e ta file
Or, to change in-place with BSD(OSX) sed, try:
sed -i '' -Ee :a -e 's/(&DEST=X*)[^X&]/\1X/' -e ta file
If there is some reason why it is important to use the shell to read the file line-by-line:
while IFS= read -r line
do
echo "$line" | sed -Ee :a -e 's/(&DEST=X*)[^X&]/\1X/' -e ta
done <file
How it works
Let's consider this code:
search_str="&DEST="
newfile=chart.txt
sed -E ':a; s/('"$search_str"'X*)[^X&]/\1X/; ta' "$newfile"
-E
This tells sed to use Extended Regular Expressions (ERE). This has the advantage of requiring fewer backslashes to escape things.
:a
This creates a label a.
s/('"$search_str"'X*)[^X&]/\1X/
This looks for $search_str followed by any number of X followed by any character that is not X or &. Because of the parens, everything except that last character is saved into group 1. This string is replaced by group 1, denoted \1 and an X.
ta
In sed, t is a test command. If the substitution was made (meaning that some character needed to be replaced by X), then the test evaluates to true and, in that case, ta tells sed to jump to label a.
This test-and-jump causes the substitution to be repeated as many times as necessary.
Replacing multiple tags with one sed command
$ name='DEST|ORIG'; sed -E ':a; s/(&('"$name"')=X*)[^X&]/\1X/; ta' file
MYREQUESTISTO8764GETTHIS&DEST=XXX&ORIG=XXXX
MYREQUESTISTO8764GETTHIS&DEST=XXXXXXXXXXXX&ORIG=XXXX
MYREQUESTISTO8764GETTHISWITH&DEST=XXXXXXX
Answer for original question
Using shell
$ s='MYREQUESTISTO8764GETTHIS&DEST=SFO&ORIG=6546'
$ s=${s#*&DEST=}
$ echo ${s%%&*}
SFO
How it works:
${s#*&DEST=} is prefix removal. This removes all text up to and including the first occurrence of &DEST=.
${s%%&*} is suffix removal_. It removes all text from the first & to the end of the string.
Using awk
$ echo 'MYREQUESTISTO8764GETTHIS&DEST=SFO&ORIG=6546' | awk -F'[=\n]' '$1=="DEST"{print $2}' RS='&'
SFO
How it works:
-F'[=\n]'
This tells awk to treat either an equal sign or a newline as the field separator
$1=="DEST"{print $2}
If the first field is DEST, then print the second field.
RS='&'
This sets the record separator to &.
With GNU bash:
while IFS= read -r line; do
[[ $line =~ (.*&DEST=)(.*)((&.*|$)) ]] && echo "${BASH_REMATCH[1]}fooooo${BASH_REMATCH[3]}"
done < file
Output:
MYREQUESTISTO8764GETTHIS&DEST=fooooo&ORIG=6546
MYREQUESTISTO8764GETTHIS&DEST=fooooo&ORIG=6546
MYREQUESTISTO8764GETTHISWITH&DEST=fooooo
Replace the characters between &DEST and & (or EOL) with x's:
awk -F'&DEST=' '{
printf("%s&DEST=", $1);
xlen=index($2,"&");
if ( xlen == 0) xlen=length($2)+1;
for (i=0;i<xlen;i++) printf("%s", "X");
endstr=substr($2,xlen);
printf("%s\n", endstr);
}' file