Adding backreferenced value to its replacement - ruby

I am trying to add a number from a backreference to another number, but I seem to get only concatenation:
textStr = "<testsuite errors=\"0\" tests=\"4\" time=\"4.867\" failures=\"0\" name=\"TestRateUs\">"
new_str = textStr.gsub(/(testsuite errors=\"0\" tests=\")(\d+)(\" time)/, '\1\2+4\3')
# => "<testsuite errors=\"0\" tests=\"4+4\" time=\"4.867\" failures=\"0\" name=\"TestRateUs\">"
I tried also using to_i on the backreferenced value, but I can't get the extracted value to add. Do I need to do something to the value to make it addable?

If you are manipulating XML, I'd suggest using some specific library for that. In this answer, I just want to show how to perform operations on the submatches.
You can sum up the values inside a block:
textStr="<testsuite errors=\"0\" tests=\"4\" time=\"4.867\" failures=\"0\" name=\"TestRateUs\">"
new_str = textStr.gsub(/(testsuite errors=\"0\" tests=\")(\d+)(\" time)/) do
Regexp.last_match[1] + (Regexp.last_match[2].to_i + 4).to_s + Regexp.last_match[3]
end
puts new_str
See IDEONE demo
If we use {|m|...} we won't be able to access captured texts since m is equal to Regexp.last_match[0].to_s.

Related

Sort an array depending on given set of characters within each element

I have an array made of a number of elements read from a .txt file. Each element is long and has a lot of information, for instance:
20201102066000000000000000000000000020052IC04008409Z8000000000030546676591AFIP
All the lines are already part of the array lines_array, but I need to sort them out depending on the content of the 36° character until the 51°, which in the example provided above would be:
20052IC04008409Z
I was already able to catch the patterns from each of the elements in the array:
lines_array = File.readlines(complete_filename)
pattern = nil
lines_array.each do |line|
pattern = line[36] + line[37] + line[38] + line[39] + line[40] + line[41] + line[42] + line[43] +
line[44] + line[45] + line[46] + line[47] + line[48] + line[49] + line[50] + line[51]
end
What I need to do now is to be able to sort alphabetically all the elements of the array (with the long elements) based on the content of the variable variable pattern. I tried with methods sort and sort_by but I wasn't able to pass my variable pattern as a parameter. For example, a correct order of three given elements would be:
20201102066000000000000000000000000020001IC04180127X8000000000030546676591AFIP
20201104066000000000000000000000000020001IC04182757T8000000000030546676591AFIP
20201102066000000000000000000000000020001IC05020641D8000000000030546676591AFIP
Any help?
Firstly, there are easier and cleaner ways to extract the substring you're after, you could use String#[] or String#slice:
# These do the same thing, use whichever reads better to you.
pattern = line[36, 16]
pattern = line.slice(36, 16)
pattern = line[36..51]
pattern = line.slice(36..51)
Then you can Enumerable#sort_by on that slice by using a block with sort_by:
sorted = lines_array.sort_by { |str| str[36, 16] }

How do I regex-match an unknown number of repeating elements?

I'm trying to write a Ruby script that replaces all rem values in a CSS file with their px equivalents. This would be an example CSS file:
body{font-size:1.6rem;margin:4rem 7rem;}
The MatchData I'd like to get would be:
# Match 1 Match 2
# 1. font-size 1. margin
# 2. 1.6 2. 4
# 3. 7
However I'm entirely clueless as to how to get multiple and different MatchData results. The RegEx that got me closest is this (you can also take a look at it at Rubular):
/([^}{;]+):\s*([0-9.]+?)rem(?=\s*;|\s*})/i
This will match single instances of value declarations (so it will properly return the desired Match 1 result), but entirely disregards multiples.
I also tried something along the lines of ([0-9.]+?rem\s*)+, but that didn't return the desired result either, and doesn't feel like I'm on the right track, as it won't return multiple result data sets.
EDIT After the suggestions in the answers, I ended up solving the problem like this:
# search for any declarations that contain rem unit values and modify blockwise
#output.gsub!(/([^ }{;]+):\s*([^}{;]*[0-9.]rem+[^;]*)(?=\s*;|\s*})/i) do |match|
# search for any single rem value
string = match.gsub(/([0-9.]+)rem/i) do |value|
# convert the rem value to px by multiplying by 10 (this is not universal!)
value = sprintf('%g', Regexp.last_match[1].to_f * 10).to_s + 'px'
end
string += ';' + match # append the original match result to the replacement
match = string # overwrite the matched result
end
You can't capture a dynamic number of match groups (at least not in ruby).
Instead you could do either one of the following:
Capture the whole value and split on space
Use multilevel matching to capture first the whole key/value pair and secondly match the value. You can use blocks on the match method in ruby.
This regex will do the job for your example :
([^}{;]+):(?:([0-9\.]+?)rem\s?)?(?:([0-9\.]+?)rem\s?)
But whith this you can't match something like : margin:4rem 7rem 9rem
This is what I've been able to do: DEMO
Regex: (?<={|;)([^:}]+)(?::)([^A-Za-z]+)
And this is what my result looks like:
# Match 1 Match 2
# 1. font-size 1. margin
# 2. 1.6 2. 4
As #koffeinfrei says, dynamic capture isn't possible in Ruby. Would be smarter to capture the whole string and remove spaces.
str = 'body{font-size:1.6rem;margin:4rem 7rem;}'
str.scan(/(?<=[{; ]).+?(?=[;}])/)
.map { |e| e.match /(?<prop>.+):(?<value>.+)/ }
#⇒ [
# [0] #<MatchData "font-size:1.6rem" prop:"font-size" value:"1.6rem">,
# [1] #<MatchData "margin:4rem 7rem" prop:"margin" value:"4rem 7rem">
# ]
The latter match might be easily adapted to return whatever you want, value.split(/\s+/) will return all the values, \d+ instead of .+ will match digits only etc.

RegEx to remove new line characters and replace with comma

I scraped a website using Nokogiri and after using xpath I was left with the following string (which is a few td's pushed into one string).
"Total First Downs\n\t\t\t\t\t\t\t\t359\n\t\t\t\t\t\t\t\t274\n\t\t\t\t\t\t\t"
My goal is to make this into an array that looks like the following(it will be a nested array):
["Total First Downs", "359", "274"]
The issue is creating a regex equation that removes the escaped characters, subs in one "," but does not sub in a "," after the last set of integers. If the comma after the last set of integers is necessary, I could use #compact to get rid of the nil that occurs in the array. If you need the code on how I scraped the website here it is: (please note i saved the webpage for testing in order for my ip address to not get burned during the trial phase)
f = File.open('page')
doc = Nokogiri::HTML:(f)
f.close
number = doc.xpath('//tr[#class="tbdy1"]').count
stats = Array.new(number) {Array.new}
i = 0
doc.xpath('//tr[#class="tbdy1"]').each do |tr|
stats[i] << tr.text
i += 1
end
Thanks for your help
I don't fully understand your problem, but the result can be easily achieved with this:
"Total First Downs\n\t\t\t\t\t\t\t\t359\n\t\t\t\t\t\t\t\t274\n\t\t\t\t\t\t\t"
.split(/[\n\t]+/)
# => ["Total First Downs", "359", "274"]
Try with gsub
"Total First Downs\n\t\t\t\t\t\t\t\t359\n\t\t\t\t\t\t\t\t274\n\t\t\t\t\t\t\t".gsub("/[\n\t]+/",",")

Incrementing numeric parameter in a URL parameter string?

I've had a look round and can't find what I need on Stack Overflow, and was wondering if someone had a simple solution.
I want to find a parameter within a URL and increment its value, so, as an example:
?kws=&pstc=&cty=&prvnm=1
I want to be able to locate the prvnm parameter no matter where it is in the string and increment its value by 1.
I know I could split the parameters into an array, find the key, increment it and write it back but that seems rather long winded and wondered if someone else had any ideas!
require "uri"
url = "http://example.com/?kws=&pstc=&cty=&prvnm=1"
def new_url(url)
uri = URI.parse(url)
hsh = Hash[URI.decode_www_form(uri.query)]
hsh['prvnm'] = hsh['prvnm'].next
uri.query = URI.encode_www_form(hsh).to_s
uri.to_s
end
new_url(url) # => "http://example.com/?kws=&pstc=&cty=&prvnm=2"
There are already four answers, so I had to come up with something a little different:
s = "?kws=&pstc=&cty=&prvnm=1"
head, sep, tail = s.partition(/(?<=[?&]prvnm=)\d+/)
head + (sep.to_i + 1).to_s + tail # => "?kws=&pstc=&cty=&prvnm=2"
'String#partition' returns an array of three strings [head, sep, tail], such that head + sep + tail => s, where separator is partition's argument, which can be a string or a regex.
We want the separator to be the digits following &prvnm=. We therefore use a regex with \d+ preceeded by the aforementioned string which we want to treat as having zero length, so it will not be included in the separator. That calls for a "positive look-behind": (?<=&prvnm=). \d+ is "greedy", so it take all consequetive digits.
For the given value of s, head, sep, tail = s.partition(/(?<=&prvnm=)(\d+)/)
=> ["?kws=&pstc=&cty=&prvnm=", "1", ""].
Edit: my thanks to #quetzalcoatl for pointing out that I needed to change (?<=&prvnm=) in my regex to what I have now, as what I had would fail when ?prvnm= was at the beginning of the string.
split the string by `&`
then iterate over the parts
then split each part by `=` and inspect the results
when found `prvnm`, parse the integer and increment it
then join the bits by '='
then join the parts by '&'
Or, use regex like:
/[?&]prvnm=\d+/
and parse the result and then do a replacement.
Or, get some URL-parsing library..
Try something like this:
params = "?kws=&pstc=&cty=&prvnm=1"
num = params.scan(/prvnm=(\d)/)[0].join.to_i
puts num + 1
Use:
require 'uri'
Then:
parsed-url= URI.parse( ur full url)
r = CGI.parse(parsed_url.query)
r is now a hash of all your query parameters.
You can easily access it by using:
r["prsvn"].to_i + 1

How do I convert a Ruby string with brackets to an array?

I would like to convert the following string into an array/nested array:
str = "[[this, is],[a, nested],[array]]"
newarray = # this is what I need help with!
newarray.inspect # => [['this','is'],['a','nested'],['array']]
You'll get what you want with YAML.
But there is a little problem with your string. YAML expects that there's a space behind the comma. So we need this
str = "[[this, is], [a, nested], [array]]"
Code:
require 'yaml'
str = "[[this, is],[a, nested],[array]]"
### transform your string in a valid YAML-String
str.gsub!(/(\,)(\S)/, "\\1 \\2")
YAML::load(str)
# => [["this", "is"], ["a", "nested"], ["array"]]
You could also treat it as almost-JSON. If the strings really are only letters, like in your example, then this will work:
JSON.parse(yourarray.gsub(/([a-z]+)/,'"\1"'))
If they could have arbitrary characters (other than [ ] , ), you'd need a little more:
JSON.parse("[[this, is],[a, nested],[array]]".gsub(/, /,",").gsub(/([^\[\]\,]+)/,'"\1"'))
For a laugh:
ary = eval("[[this, is],[a, nested],[array]]".gsub(/(\w+?)/, "'\\1'") )
=> [["this", "is"], ["a", "nested"], ["array"]]
Disclaimer: You definitely shouldn't do this as eval is a terrible idea, but it is fast and has the useful side effect of throwing an exception if your nested arrays aren't valid
Looks like a basic parsing task. Generally the approach you are going to want to take is to create a recursive function with the following general algorithm
base case (input doesn't begin with '[') return the input
recursive case:
split the input on ',' (you will need to find commas only at this level)
for each sub string call this method again with the sub string
return array containing the results from this recursive method
The only slighlty tricky part here is splitting the input on a single ','. You could write a separate function for this that would scan through the string and keep a count of the openbrackets - closedbrakets seen so far. Then only split on commas when the count is equal to zero.
Make a recursive function that takes the string and an integer offset, and "reads" out an array. That is, have it return an array or string (that it has read) and an integer offset pointing after the array. For example:
s = "[[this, is],[a, nested],[array]]"
yourFunc(s, 1) # returns ['this', 'is'] and 11.
yourFunc(s, 2) # returns 'this' and 6.
Then you can call it with another function that provides an offset of 0, and makes sure that the finishing offset is the length of the string.

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