I am basically trying to make a animation of vertical bars across the screen which should be equally spaced and continue until some key is pressed etc.. in the processing.org tool for animation.
I was able to get a kind of animation, but with hard coded values and had to write the same code again and again to generate the animation of bars for the whole frame/screen. I need to make it generic, so that changing the screen width or the size of the bars would not make me change the whole code but just the variables which control the parameters. Below is my code. I have written the code for three vertical bars but that needs to be done for the whole screen..
int a;
int i;
int j;
void setup() {
size(640, 360);
a = width/2;
i = 0;
}
void draw() {
background(51);
//need to avoid these repetitions each time for each bar
rect(a , 0, 25, width);
a = a - 1;
if (a < 0) {
a = width;
}
rect(i= a+50, 0, 25, width);
i = i - 1;
if (i < 0) {
i = width + a;
}
rect(j = i + 50, 0, 25, width);
j = j - 1;
if (a < 0) {
j = width + i;
}
}
It sounds like you're looking for an array.
An array is like a variable, only it can hold multiple values in its indexes. You can then use a for loop to iterate over the array and do stuff based on the values in the array.
Here's an example that uses an array to keep track of the line positions:
float[] linePositions = new float[10];
float lineWidth = 25;
float lineSpacing = 25;
float lineSpeed = 1;
void setup() {
size(640, 360);
for (int i = 0; i < linePositions.length; i++) {
linePositions[i] = width/2 + (lineWidth+lineSpacing)*i;
}
}
void draw() {
background(51);
//loop through the lines
for (int i = 0; i < linePositions.length; i++) {
//draw the line
rect(linePositions[i], 0, lineWidth, width);
//move the line
linePositions[i] -= lineSpeed;
//wrap the line
if ( linePositions[i] < 0) {
linePositions[i] = width;
}
}
}
More info on arrays can be found in the Processing reference.
Related
I need some help with a code for an exam in my university.
What I'm trying to do here is a visual representation of a speech between two people. So the code starts when you press "L" and then works a bit like walkie talkie so when the other person speaks need to push "A", when the word goes back to the first person he needs to press "L" again and so on.
I like the result of the code so far but my professor told me to try something and I'm not able to do it.
He would like to see the coloured lines covering all the screen in vertical and not just a portion of it and when they reach the end of the screen on the right split in two so that the first row that just got created becomes half of the screen and the new one creating in the other half. When the second row finishes and the third row is created the screen must split in 3 and so on.
I tried to achieve this but I messed up the code so I will post here the last version of it working.
I hope you can help in any way, all kind of suggestion are appreciated, thank you!
import processing.sound.*;
AudioIn input;
Amplitude amp;
int y;
int x;
int incY = 141;
color bg = color(255, 0);
color high;
color low;
color mid;
void setup() {
size(1440, 846);
background(bg);
pixelDensity(displayDensity());
input = new AudioIn(this, 0);
input.start();
amp = new Amplitude(this);
amp.input(input);
}
void draw() {
textSize(40);
fill(0);
float volume = amp.analyze();
int lncolor = int(map(volume, 0, 0.05, 0, 3));
noFill();
strokeCap(SQUARE);
//strokeWeight(10);
if (lncolor==0) {
stroke(bg);
}
if (lncolor==1) {
stroke(low);
}
if (lncolor==2) {
stroke(mid);
}
if (lncolor==3) {
stroke(high);
}
if (key == 'a') {
x++;
if (x==width) {
x = 0;
y = y + incY;
}
line(x, y, x, y+incY);
high=color(72, 16, 255);
low= color(179, 155, 255);
mid = lerpColor(low, high, .5);
}
if (key == 'l') {
x++;
if (x==width) {
x = 0;
y = y + incY;
}
line(x, y, x, y+incY);
high=color(255, 128, 16);
low= color(255, 203, 156);
mid = lerpColor(low, high, .5);
}
}
The following code won't solve all of your problems, but does show how to keep splitting the screen into proportionate rectangles based on the number of times the graph exceeds the width of the screen. The advancing green bar at the top is where your current signal would be plotted. I'll leave it to you to figure out how to get all the old signal into its respective rectangle. I was unable to run the code that you posted; error message was "Audio Input not configured in start() method". All that I saw was a blank screen.
int x = 0;
int counter = 1;
void rectGrid(int t, int w, int h) {
int top;
for (int k = 0; k < counter; k++) {
top = t + k*h;
stroke(0);
strokeWeight(1);
fill(random(255));
rect( 0, top, w, h);
}
}
void setup() {
size(400, 400);
background(209);
}
void draw() {
fill(0, 255, 0);
rect(0, 0, x++, height/counter);
if (x == width) {
counter++;
println("count = ", counter + " : " + "height = ", height/counter);
x = 0;
background(209);
rectGrid(0, width, height/counter);
}
}
i have modified the code for the animation of vertical lines which was given by . In the recent code I need to change the value between the two arrays of lines which are generated by the code and also make the disappearing of lines gradual. All the lines leaving or coming should have the same spacing between them. Below is the code.
//float[] linePositions = new float[10];
ArrayList<Integer> linePositions = new ArrayList<Integer>();
int lineWidth = 50;
int lineSpacing = 25;
int lineSpeed = 1;
int totalwidth;
int pixelperframe = 0;
int arraySize = 0;
void setup() {
size(640, 360);
println("Setup");
totalwidth = lineWidth+lineSpacing;
for (int i = 0; i < width; i=i +totalwidth) {
//Float value = 0 + (lineWidth+lineSpacing)*i;
linePositions.add(i);
}
arraySize = linePositions.size();
}
Boolean drawn = false;
void draw() {
println("Draw");
background(51);
//loop through the lines
//println("before Draw ka forloop"+linePositions.size());\
pixelperframe = ((lineSpeed - 10) > 1) ? (lineSpeed-10) : 1;
for (int i = 0; i < arraySize; i++) {
//println("Draw ka forloop");
rect(linePositions.get(i), 0, lineWidth, width);
int newPosition = linePositions.get(i) - pixelperframe ;
linePositions.set(i, newPosition);
//linePositions[i] -= lineSpeed;
//wrap the line
if ( linePositions.get(i) < 0) {
println("Wrapping the line");
linePositions.set(i, width);
// drawn = true;
}
}
//int temp = (width - linePositions.get(arraySize - 1)) - totalwidth;
//println(temp);
}
For the spacing between the lines to always be the same, you have to make sure that the total line spacing adds up to the total width of your screen. Right now each line takes up 75 pixels (50 for the line itself and 25 for the space after it), but your width is 640. That will always leave you with extra space, which will mess up your spacing after the lines start over.
So the easiest thing to do is to simply make your window a multiple of the line spacing. Let's go with 600, which is enough room for exactly 8 lines.
However, since you want your lines to slide off the screen, you actually need 9 lines, since you'll often see half of one line going off the screen while half of another line enters the screen. Draw some pictures to see exactly what I'm talking about
If I understand what you mean by making the lines "gradually" restart, you just have to restart them when their right side goes off the screen. In other words, when their x position is negative enough to be off the screen.
Putting it all together, it looks like this:
float[] linePositions = new float[9];
float lineWidth = 50;
float lineSpacing = 25;
float lineSpeed = 1;
void setup() {
size(600, 360);
for (int i = 0; i < linePositions.length; i++) {
linePositions[i] = (lineWidth+lineSpacing)*i;
}
}
void draw() {
background(51);
for (int i = 0; i < linePositions.length; i++) {
linePositions[i] -= lineSpeed;
rect(linePositions[i], 0, lineWidth, height);
if ( linePositions[i] < -(lineWidth+lineSpacing)) {
linePositions[i] = width;
}
}
}
So the code I'm writing is to output an array on the screen. The example I have been basing off my problem is here in which there are dots that are an equal distance from each other. If you're too lazy to click the link, this is the code:
float[][] distances;
float maxDistance;
int spacer;
void setup() {
size(640, 360);
maxDistance = dist(width/2, height/2, width, height);
distances = new float[width][height];
for (int y = 0; y < height; y++) {
for (int x = 0; x < width; x++) {
float distance = dist(width/2, height/2, x, y);
distances[x][y] = distance/maxDistance * 255;
}
}
spacer = 10;
noLoop(); // Run once and stop
}
void draw() {
background(0);
// This embedded loop skips over values in the arrays based on
// the spacer variable, so there are more values in the array
// than are drawn here. Change the value of the spacer variable
// to change the density of the points
for (int y = 0; y < height; y += spacer) {
for (int x = 0; x < width; x += spacer) {
stroke(distances[x][y]);
point(x + spacer/2, y + spacer/2);
}
}
}
What I have coded only returns a white window. This is that code:
float [] arrays = {1.0,2.0,3.0,4.0,5.0,6.0,7.0,8.0,9.0,10.0};;
int spacer=50;
PFont font;
int row;
int col;
void setup(){
size(640,360);
font = createFont("Arial",1);
textFont(font,50);
}
void draw(){
background(255,255,255);
for(int i = 0; i<col; i++){
for(int j=0;j<row;j++){
String myArray = nfp(arrays[i*col+j],1,2);
fill(0,0,0);
text(myArray, i+spacer/2, j+spacer/2);
}
}
}
I'm super new to processing, and stuff. Thanks ahead of time!
In your code, i don't see your col and row initializated.
You should do it in void setup()
Maybe that's the reason why you are not seeing anything on your window, because if this two variables has no value your two loops doesn't execute. In the example you provide, use width and height that are "system variables" that return the size of the window (640x360 in the example)
Also, watch out this:
float [] arrays = {1.0,2.0,3.0,4.0,5.0,6.0,7.0,8.0,9.0,10.0};; (two semicolons)
I'm fairly new to processing but I am having trouble shifting the z position on one of my line sets.
The x axis lines look as I need it to, but I am basically trying to bring up the Y set of lines so they arent just going downwards but are more linked up with the first set of lines. I hope I'm making sense, It's kind of hard to explain. Thanks!
Edit: Basically what Im trying to make is a tiled floor.
int grid = 80;
void setup() {
size (1024, 900, P3D);
}
void draw() {
int movement = mouseY-500;
background(0);
strokeWeight(2.5);
stroke(100, 255, 0, 60);
//floorx
for (int i = 0; i < width; i+=grid) {
line (i , height/2 , 0, i , height, 5000);
}
//floory
for (int i = 0; i < height; i+=grid) {
line (0, i + height/2, 0, width, i + height/2,0 );
}
}
I think that you want the grid to appear more geometrically correct. To achieve this you need different distances between the horizontal lines.
Try this in your floory part:
grid = 40;
//floory
for (int i = 0; i < height; i+=grid) {
line (0, i + height/2, 0, width, i + height/2, 0 );
grid += 20;
}
I'm using processing 2.1.
Any idea why my simple sketch is running slow on my (powerful) machine?
I'm simply drawing some quads in a grid, and when pressing the mouse I was trying to animate them (via Ani library), but the animation is sloppy and superslow....Any hint?
import de.looksgood.ani.*;
import de.looksgood.ani.easing.*;
int quadSize = 30;
int spacing = 10;
int numRows = 11;
int numColumns = 22;
float angleRotationIncrease = 3;
void setup () {
size (900, 600, P3D);
background (0);
fill (255);
stroke (255);
Ani.init(this);
frameRate (60);
}
void draw () {
text(frameRate,20,20);
// println (angleRotationIncrease);
background (0);
int posX = 0;
int posY = 0;
int angleRotation = 0;
float scaleFactor = 1;
float scaleFactorIncrease = -0.045;
for (int i=0; i<numRows; i++) {
for (int j=0; j<numColumns; j++) {
pushMatrix();
translate (posX + quadSize/2, posY + quadSize/2);
// println (radians(angleRotation));
rotate(radians(angleRotation));
if (scaleFactor > 0) {
rect (-quadSize/2 * scaleFactor, -quadSize/2* scaleFactor, quadSize* scaleFactor, quadSize* scaleFactor);
}
popMatrix ();
posX += (quadSize + spacing);
angleRotation += angleRotationIncrease;
scaleFactor += scaleFactorIncrease;
}
// for each new line, reset or change params
scaleFactorIncrease -= 0.002;
scaleFactor = 1;
angleRotation = 0;
posX = 0;
posY += (quadSize + spacing);
}
}
void mousePressed() {
Ani.to(this, 20, "angleRotationIncrease", -3);
}
Solved. it was a casting problem. Anglerotation is an int, so when subtracting the value I'm animating via Ani, it gets rounded
Because you are animating low range of values over very long period of time
Ani.to(this, 20, "angleRotationIncrease", -3);
Your range is [3,-3] and time is 20 seconds. Just try to decrease time and increase range an you will see more fluent animation on your powerful machine :) like this:
Ani.to(this, 2, "angleRotationIncrease", -30);
But at the end of animation is some kind of slowing what should be specified by default by Ani library so for more information read documentation here