What XPATH I need to extract the text inside SPAN that is preceded by a specific label inside a STRONG, both inside a P?
For example to extract website and email addresses from a page that looks like this:
<p>
<strong>Website:</strong>
<span>www.example.com</span>
</p>
<p>
<strong>Contact email:</strong>
<span>email#example.com</span>
</p>
This shall do:
//p/span[preceding::*[1][self::strong and . = 'Contact email:']]
Here, you are selecting all p/span elements with first preceding element strong, where label is Contact email:
Website:
//p/span[preceding::strong[1]/text()='Website:']
Email:
//p/span[preceding::strong[1]/text()='Contact email:']
It is also important to note that, by using preceding axes as shown in the other two answers, the XPath will mistakenly return span element that is formed like the following :
<strong>Website:</strong>
<p>
<span>www.example.com</span>
</p>
You can use preceding-sibling axes instead to avoid the mistake mentioned above :
//p/span[preceding-sibling::*[1][self::strong and . = 'Website:']]
preceding-sibling axes only consider elements that is located before context element (the span in this case), and is sibling (share the same parent) of the context element.
Related
Here is some sample HTML
<div class="something">
<p> This is a <b> Paragraph </b> with mixed elements
<p> Next paragraph....
</div>
what I tried was
//div[contains('#class','something')/text()
and
//div[contains('#class','something')/*/text()
and
//div[contains('#class','something')/p/text()
all of these seem to skip the 'b' tags and the 'a' tags.
Try " ".join(sel.xpath("//div[contains(#class,'something')]//text()").extract()) where sel is selector in your case may be response.
Use the XPath expression
//div[contains(#class,'something')]//text()
to get a concatenation of the text of all the text() nodes in the chosen div element.
Output:
This is a Paragraph with mixed elements
Next paragraph....
It depends on what and how you want to obtain. Anyway, there are couple of problems with what you tried:
You are missing closing bracket (]) after contains in the XPath expression.
#class should not be enclosed in (single) quotes when used inside contains.
If you want to get all the text of div element as one string, you might use
normalize-space(//div[contains(#class,'something')])
Given this XML, what XPath returns all elements whose prop attribute contains Foo (the first three nodes):
<bla>
<a prop="Foo1"/>
<a prop="Foo2"/>
<a prop="3Foo"/>
<a prop="Bar"/>
</bla>
//a[contains(#prop,'Foo')]
Works if I use this XML to get results back.
<bla>
<a prop="Foo1">a</a>
<a prop="Foo2">b</a>
<a prop="3Foo">c</a>
<a prop="Bar">a</a>
</bla>
Edit:
Another thing to note is that while the XPath above will return the correct answer for that particular xml, if you want to guarantee you only get the "a" elements in element "bla", you should as others have mentioned also use
/bla/a[contains(#prop,'Foo')]
This will search you all "a" elements in your entire xml document, regardless of being nested in a "blah" element
//a[contains(#prop,'Foo')]
I added this for the sake of thoroughness and in the spirit of stackoverflow. :)
This XPath will give you all nodes that have attributes containing 'Foo' regardless of node name or attribute name:
//attribute::*[contains(., 'Foo')]/..
Of course, if you're more interested in the contents of the attribute themselves, and not necessarily their parent node, just drop the /..
//attribute::*[contains(., 'Foo')]
descendant-or-self::*[contains(#prop,'Foo')]
Or:
/bla/a[contains(#prop,'Foo')]
Or:
/bla/a[position() <= 3]
Dissected:
descendant-or-self::
The Axis - search through every node underneath and the node itself. It is often better to say this than //. I have encountered some implementations where // means anywhere (decendant or self of the root node). The other use the default axis.
* or /bla/a
The Tag - a wildcard match, and /bla/a is an absolute path.
[contains(#prop,'Foo')] or [position() <= 3]
The condition within [ ]. #prop is shorthand for attribute::prop, as attribute is another search axis. Alternatively you can select the first 3 by using the position() function.
Have you tried something like:
//a[contains(#prop, "Foo")]
I've never used the contains function before but suspect that it should work as advertised...
John C is the closest, but XPath is case sensitive, so the correct XPath would be:
/bla/a[contains(#prop, 'Foo')]
If you also need to match the content of the link itself, use text():
//a[contains(#href,"/some_link")][text()="Click here"]
/bla/a[contains(#prop, "foo")]
try this:
//a[contains(#prop,'foo')]
that should work for any "a" tags in the document
For the code above...
//*[contains(#prop,'foo')]
suppose I have this structure:
<div class="a" attribute="foo">
<div class="b">
<span>Text Example</span>
</div>
</div>
In xpath, I would like to retrieve the value of the attribute "attribute" given I have the text inside: Text Example
If I use this xpath:
.//*[#class='a']//*[text()='Text Example']
It returns the element span, but I need the div.a, because I need to get the value of the attribute through Selenium WebDriver
Hey there are lot of ways by which you can figure it out.
So lets say Text Example is given, you can identify it using this text:-
//span[text()='Text Example']/../.. --> If you know its 2 level up
OR
//span[text()='Text Example']/ancestor::div[#class='a'] --> If you don't know how many level up this `div` is
Above 2 xpaths can be used if you only want to identify the element using Text Example, if you don't want to iterate through this text. There are simple ways to identify it directly:-
//div[#class='a']
From your question itself you have mentioned the answer for it
but I need the div.a,
try this
driver.findElement(By.cssSelector("div.a")).getAttribute("attribute");
use cssSelector for best result.
or else try the following xpath
//div[contains(#class, 'a')]
If you want attribute of div.a with it's descendant span which contains text something, try as below :-
driver.findElement(By.xpath("//div[#class = 'a' and descendant::span[text() = 'Text Example']]")).getAttribute("attribute");
Hope it helps..:)
I am trying to find a way to search for a string within nodes, but excluding ythe content of some subelements of those nodes. Plain and simple, I want to search for a string in paragraphs of a text, excluding the footnotes which are children elements of the paragraphs.
For example,
My document being:
<document>
<p n="1">My text starts here/</p>
<p n="2">Then it goes on there<footnote>It's not a very long text!</footnote></p>
</document>
When I'm searching for "text", I would like the Xpath / XQuery to retrieve the first p element, but not the second one (where "text" is contained only in the footnote subelement).
I have tried the contains() function, but it retrieves both p elements.
Any help would be much appreciated :)
I want to search for a string in
paragraphs of a text, excluding the
footnotes which are children elements
of the paragraphs
An XPath 1.0 - only solution:
Use:
//p//text()[not(ancestor::footnote) and contains(.,'text')]
Against the following XML document (obtained from yours but added p s within a footnote to make this more interesting):
<document>
<p n="1">My text starts here/</p>
<p n="2">Then it goes on there
<footnote>It's not a very long text!
<p>text</p>
</footnote>
</p>
</document>
this XPath expression selects exactly the wanted text node:
My text starts here/
//p[(.//text() except .//footnote//text())[contains(., 'text')]]
/document/p[text()[contains(., 'text')]] should do.
For the record, as a complement to the other answers, I've found this workaround that also seems to do the job:
//p[contains(child::text()|not(descendant::footnote), "text")]
I'd like to use Nokogiri to extract all nodes in an element that contain a specific attribute name.
e.g., I'd like to find the 2 nodes that contain the attribute "blah" in the document below.
#doc = Nokogiri::HTML::DocumentFragment.parse <<-EOHTML
<body>
<h1 blah="afadf">Three's Company</h1>
<div>A love triangle.</div>
<b blah="adfadf">test test test</b>
</body>
EOHTML
I found this suggestion (below) at this website: http://snippets.dzone.com/posts/show/7994, but it doesn't return the 2 nodes in the example above. It returns an empty array.
# get elements with attribute:
elements = #doc.xpath("//*[#*[blah]]")
Thoughts on how to do this?
Thanks!
I found this here
elements = #doc.xpath("//*[#*[blah]]")
This is not a useful XPath expression. It says to give you all elements that have attributes that have child elements named 'blah'. And since attributes can't have child elements, this XPath will never return anything.
The DZone snippet is confusing in that when they say
elements = #doc.xpath("//*[#*[attribute_name]]")
the inner square brackets are not literal... they're there to indicate that you put in the attribute name. Whereas the outer square brackets are literal. :-p
They also have an extra * in there, after the #.
What you want is
elements = #doc.xpath("//*[#blah]")
This will give you all the elements that have an attribute named 'blah'.
You can use CSS selectors:
elements = #doc.css "[blah]"