awk : trying to generate a query using awk - bash

Question

I'm trying to write an awk program to generate a sql query, using the output from a pipe command. The output of the command will be something like this
Service name: APP1
Service name: APP2
Service name: APP3
Service name: APP4
Service name: APP5
Service name: APP6
Service name: APP7
Service name: APP8
Service name: APP9
and the result I need is something like :
select 'APP1' x from dual union all
select 'APP2' from dual union all
select 'APP3' from dual union all
select 'APP4' from dual union all
select 'APP5' from dual union all
select 'APP6' from dual union all
select 'APP7' from dual union all
select 'APP8' from dual union all
select 'APP9' from dual
I need to get the string after the "Service Name:" string, put it between quotes, and place it into the select.
The first line must have the "x" after the string , and the last line must not contain the union all. There cannot be a space on the string. Since I don't have much experience with awk, so far I couldn't figure a way to do it.
I have this so far:
srvctl config service -db database | grep 'Service name' | awk 'BEGIN {FS = "[:]"}
{ gsub(/^[ \t]+|[ \t]+$/, "", $2)
if ( NR == 1 )
{
printf "'select\ \''" $2 "'\'\ x\ from\ dual\ union\ all\ '\n"
}
else
{
printf "'select\ \''" $2 "'\'\ from\ dual\ union\ all\ '\n"
}
}'
It will generate the following output:
select 'APP1' x from dual union all
select 'APP2' from dual union all
select 'APP3' from dual union all
select 'APP4' from dual union all
select 'APP5' from dual union all
select 'APP6' from dual union all
select 'APP7' from dual union all
select 'APP8' from dual union all
select 'APP9' from dual union all
Any help is appreciated
Thanks

Answer 1

Using awk you can do:
awk 'NR==1{printf "select \047%s\047 x from dual union all\n", $NF; next}
s{print s, "union all"}
{s=sprintf("select \047%s\047 from dual", $NF)} END{print s}' file
select 'APP1' x from dual union all
select 'APP2' from dual union all
select 'APP3' from dual union all
select 'APP4' from dual union all
select 'APP5' from dual union all
select 'APP6' from dual union all
select 'APP7' from dual union all
select 'APP8' from dual union all
select 'APP9' from dual

Answer 2

perhaps simpler this way
$ awk -v q="'" '{print "select " q$3q (NR==1?" x":"") " from dual union all"}' file |
sed '$s/\w* \w*$//'
select 'APP1' x from dual union all
select 'APP2' from dual union all
select 'APP3' from dual union all
select 'APP4' from dual union all
select 'APP5' from dual union all
select 'APP6' from dual union all
select 'APP7' from dual union all
select 'APP8' from dual union all
select 'APP9' from dual
or
$ awk -v q="'" -v x=" x" '{print "select " q$3q x " from dual union all"; x=""}' file |
sed '$s/\w* \w*$//'

Answer 3

$ awk 'BEGIN{x=" x"} NR>1{print prev " union all"; x=""} {prev="select \047" $NF "\047" x " from dual"} END{print prev}' file
select 'APP1' x from dual union all
select 'APP2' from dual union all
select 'APP3' from dual union all
select 'APP4' from dual union all
select 'APP5' from dual union all
select 'APP6' from dual union all
select 'APP7' from dual union all
select 'APP8' from dual union all
select 'APP9' from dual