Error when I tried create new maven module in IntellijIDE 15 - maven

I tried add new module to project in IntellijIDE 15 and I have error
Failed to create a Maven project
'C:/gitProjects/mayProj/pom.xml' already exists in VFS
And in my project create file moduleName.iml but in IDE not shows module folder and in project structure this module is shows.

When adding the module to an existing module that already has a POM, it is necessary to manually specify that the new module will be in a different directory. This is counter-intuitive, but I think the "Add Module" dialog was not built with maven specifically in mind.
What this means is when you are adding a module to an existing module with a POM, for example, an aggregator project, on the second page of the dialog, you need to manually copy and paste the "Module Name" onto the end of the "Content root" and "Module file locations".

When you create the module manually in the context root in module file location, you must define the module name.
eg. C:\Users\Desktop\Desktop\release\1.2.1-SNAPSHOT\payment\xxx-xxx-xxx

The problem is Intellij will be failing to create module folder for your module,
so you need to specify your content-root path and module-file-location.
just copy and paste your module name to content-root and module-file-location
module-name = learn-example
content-root = xxxx/zubs/learn-example
module-file-location = xxxx/zubs/learn-example

Error when I tried create new maven module in IntellijIDE on MacBook

Related

Build a go project with a different go.mod file [duplicate]

This question already has an answer here:
How to use an alternate go.mod file for local development?
(1 answer)
Closed 10 months ago.
I would like to know how can I build a go project using a different go.mod file. Suppose I want to build project A inside project B module using project B go.mod file without copying the files around. That means I want to use dependencies in Project B to build Project A.
Manual option
"Module files" refers to both go.mod and go.sum
Rename or move project A's module files to some temporary names / location
Copy project B's module files into project A
Edit the newly copied go.mod file in project A, and change the module name:
module github.com/x/b changes to module github.com/x/a
Build whatever you need to build in project A
Delete the active module files in project A
Restore the proper module files for project A that you renamed or moved in step 1
These steps could be automated with a shell script or batch file if you need to do it often.
With build command
Using the go help build command, we can see the build flag -modfile
-modfile file
in module aware mode, read (and possibly write) an alternate go.mod
file instead of the one in the module root directory. A file named
"go.mod" must still be present in order to determine the module root
directory, but it is not accessed. When -modfile is specified, an
alternate go.sum file is also used: its path is derived from the
-modfile flag by trimming the ".mod" extension and appending ".sum".
Using this, we can directly use an alternative set of module files to build things in project A.
First, the flag description indicates that it may write to the go.mod file, so it's probably still a good idea to create a copy of project B's module files to do this.
Second, using project B's module file is going to be a problem if: 1. project A and project B have a different module name declared in their module file, and 2. packages in project A import other packages in project A. The module name determines what the import path of packages in the module will be, so changing it could break imports.
So the best practice should still be to:
Make a copy of project B's module files
Change the module name in the copy
Then you can run the build command like this to build in project A:
go build -modfile path/to/projectb/go.mod
First, make a folder b somewhere. Then make a folder a inside b. Then make
b/b.go:
package b
const Something = 1
Then make b/a/a.go:
package a
import "b"
func something() int {
return b.Something
}
Then go back to b folder, and do go mod init b. Done.

Spring Boot how to add another resources folder in test folder

Is it possible to add another resources folder in test folder, which will also be on the classpath?
I need it because I don't want to add application-test.properties file in default resources folder because it belongs in test folder.
I tried to add folder manually but it does not work.
I soloved this problem, in Intellij IDEA by:
Right clicking on the project -> Projectu structure,
and I marked newlycreated folder as Resources file.
It is gradle project or maven? If you have gradle just add the line below to the build.gradle file:
ext {
resourcesDir = projectDir.path + "/other/resources"
}
where the /other/resources is your dedicated resource folder

Add local Gradle source module by absolute path

I want to add a subproject to my Gradle project. The project is located somewhere on my hard disk drive, for example:
/A/Path/to/a/ProjectA
/Another/Path/to/another/ProjectB
What I want to achieve is to use ProjectB as a source module within Project A. However, all my attempts to do this so far - either by adding include /Another/Path/to/another/ProjectB or by adding include ':ProjectB'; project(':ProjectB').projectDir = ... in settings.gradle - just failed. Apparently, Gradle is not able to find the project.
How can I add ProjectB as a dependency without moving it from it's location?
Using Gradle 3.4.1, the following works for me (full example here):
include 'app', 'common'
def MY_PATH = '/Users/johndoe/foo'
assert new File("$MY_PATH/random/path/common").exists()
project(':common').projectDir = new File("$MY_PATH/random/path/common")
Thanks for your responses.
Turns out I've made several mistakes:
Adding the project to the built was dependent on the value of an environment variable. I replaced that with a property within gradle.properties.
I tested this by running the settings.gradle usind IntelliJ. I mistakingly expected this to work, but it didn't
I did not add the project as a dependency to the build.gradle file of the parent project.
It works now. Thank you all again!

Gradle - Recursively include external project and its subprojects

I have a gradle project with many submodules named shared-library.
I have a project named service that depends on one of the modules of shared-library. e.g., it depends on :shared-library:module1. Normally, I get this dependency from maven.
Now I want to modify shared-library and test my changes using the dependent project. Instead of making a change to shared-library, building, deploying to maven, then rebuilding my service, I'd like to instead have service depend on the shared-library gradle project directly.
So I found out that you can point gradle to arbitrary project directories on the filesystem:
service/settings.gradle
include "shared-library"
project(":shared-library").projectDir = new File("/projects/shared-library")
But when I do this, the project is not aware of shared-library's submodules. I cannot do this:
service/build.gradle
compile(
project(":shared-library:module1"),
)
So I tried includeing them directly. :shared-library:module1 depends on :shared-library:module2 so I include that one as well:
service/settings.gradle
include "shared-library"
project(":shared-library").projectDir = new File("/projects/shared-library")
include "shared-library:module2"
include "shared-library:module1"
But now when I try to run this, it complains that :shared-library:module1 cannot locate a project named :module2. This is because its dependency is configured as such:
shared-library/module1/build.gradle
compile(
project(":module2")
)
But if I change that to an absolute project path, now shared-library cannot compile on its own:
shared-library/module1/build.gradle
compile(
project(":shared-library:module2")
)
tl;dr, it seems like there is a mismatch between the way service resolves the shared-library submodule names and how shared-library does it.
You're right. You can import an external project, or even external subprojects, and reference them in your main project, but as soon as you compile the external entities they fail to resolve with the expected names.
I found that you can rename the external projects in your main project so that they match the names of the external projects. That way your main project and the external projects use the same name.
Change your service/settings.gradle to:
include "shared-library"
project(":shared-library").projectDir = new File("/projects/shared-library")
include "shared-library:module2"
project('shared-library:module2').name = ':module2'
include "shared-library:module1"
project('shared-library:module1').name = ':module1'
Now in your project and external project refer to your modules always as :module1 and :module2. In service/build.gradle use:
compile(project(":module1"))

Dynamic file name in Maven archetype

I've problem with Maven. I tried to create archetype, but I don't now how to put source file to directory ${groupId}/${artifactId}. If I try to create project from this archetype, file is stored implicitly in ${groupId} directory. It seems Maven supposes, that group ID is a package name. But I'm using ${groupId}/${artifactId} as package name so I need have the source file stored in ${groupId}/${artifactId} directory. I have seen solution: to put the file into __artifactId__ directory. Double underscore should determine a variable. However it doesn't take any effect. Variable seems to be empty, but in package name inside source file is used succesfully.
Have enybody idea, which trick shall have been done when using double underscore in file name?
When you create a archetype of your project like so:
mvn archetype:create-from-project -Dinteractive
Set the package - in an explicit form to the root of the project.
Then you create a project of this archetype enter your root package ${groupId}.$ {artifactId} in explicit form. example:
mvn archetype: generate
-DarchetypeGroupId = com.test
-DarchetypeArtifactId = my_archetype
-DgroupId = com.test
-DartifactId = app
-Dpackage = com.test.app
-Dversion = 1.0-SNAPHOT
In this case, $ {groupId} = com.test, $ {artifactId} = app and target package = com.test.app

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