GET_TIME in Oracle - oracle

Question

I have a code that is supposed to give me the compilation time for the procedure, but it only gets me 0 secs! Is the calculation wrong? Is there any other way?
create or replace PROCEDURE proc_time AS
v NUMBER := 1;
x NUMBER := 0;
counter number := 0;
summ NUMBER;
ex_start NUMBER;
ex_end NUMBER;
ex_time NUMBER;
BEGIN
ex_start := dbms_utility.get_time;
while counter <= 19
loop
counter := counter + 1;
summ := x+v;
x := v;
V := summ;
dbms_output.put_line('Fibonacci nr'||counter||': '||summ);
END loop;
ex_end := DBMS_UTILITY.GET_TIME;
ex_time := (ex_end-ex_start)/100;
DBMS_OUTPUT.PUT_LINE( 'Exekveringstid: ' || ex_time || ' sekunder.' );
END;
/

Answer 1

As explained in the above answer by Lalit. Your snippet runs too fast
to calculate the time difference. Try to increase the while loop with
some greater number and here you go !!!
CREATE OR REPLACE PROCEDURE proc_time
AS
v NUMBER := 1;
x NUMBER := 0;
counter NUMBER := 0;
summ NUMBER;
ex_start NUMBER;
ex_end NUMBER;
ex_time NUMBER;
BEGIN
ex_start := dbms_utility.get_time;
dbms_output.put_line('start time ==>'||NVL(ex_start,0));
WHILE counter <= 190000
LOOP
counter := counter + 1;
summ := x +v;
x := v;
V := summ;
-- dbms_output.put_line('Fibonacci nr'||counter||': '||summ);
END LOOP;
ex_end := DBMS_UTILITY.GET_TIME;
dbms_output.put_line('End time ==>'||ex_end);
ex_time := (ex_end-ex_start);
DBMS_OUTPUT.PUT_LINE( 'Exekveringstid: ' || ex_time || ' sekunder.' );
END;
set serveroutput on;
exec proc_time;
-------------------------------OUTPUT----------------------------------------
start time ==>1761607275
End time ==>1761607281
Exekveringstid: 6 sekunder.

Answer 2

As an alternative use the TIMESTAMP data type, this supports up to nanoseconds (provided your server supports it as well)
DECLARE
ex_start TIMESTAMP(9);
Duration INTERVAL DAY TO SECOND;
v NUMBER := 1;
x NUMBER := 0;
counter NUMBER := 0;
summ NUMBER;
BEGIN
ex_start := LOCALTIMESTAMP;
WHILE counter <= 10000 LOOP
counter := counter + 1;
summ := x +v;
x := v;
V := summ;
END LOOP;
Duration := LOCALTIMESTAMP - ex_start;
DBMS_OUTPUT.PUT_LINE ( EXTRACT(SECOND FROM Duration) /1000||' msec.');
END;

Answer 3

Perhaps, it is executing too quickly. You can try to increase the number of loops instead of 19 to something larger.
Also, it would give you the execution time, not the compilation time. The procedure is already compiled and stored in database. The time in the output is at run time, i.e. when you execute the procedure.
For example,
SQL> CREATE OR REPLACE PROCEDURE test_time
2 AS
3 l_start NUMBER;
4 l_loops NUMBER := 10000000;
5 l_number NUMBER := 0;
6 BEGIN
7 l_start := DBMS_UTILITY.get_time;
8 FOR i IN 1 .. l_loops
9 LOOP
10 l_number := l_number + i;
11 END LOOP;
12 DBMS_OUTPUT.put_line('time taken: ' || (DBMS_UTILITY.get_time - l_start) || ' hsecs');
13 END test_time;
14 /
Procedure created.
SQL> set serveroutput on
SQL> BEGIN
2 test_time;
3 END;
4 /
time taken: 101 hsecs
PL/SQL procedure successfully completed.
SQL>