questions for spring security config - spring

I`ve tried to config Spring Security.
This is my sucurity config.
#Override
protected void configure(HttpSecurity http) throws Exception {
// #formatter:off
http.authorizeRequests()
.antMatchers("/api/**", "/denied**").permitAll()
.anyRequest().denyAll()
.and()
.exceptionHandling().accessDeniedPage("/denied")
.and()
.csrf().disable();
// #formatter:on
}
When I access url "localhost:8080/admin", I expect "/denied" page.
But it shows default 403 page provided spring security.
Is there any problem my configuration?

Update:
Change .anyRequest().denyAll() to .anyRequest().authenticated()
#Override
protected void configure(HttpSecurity http) throws Exception {
// #formatter:off
http.authorizeRequests()
.antMatchers("/api/**", "/denied**").permitAll()
.anyRequest().authenticated()
.and()
.exceptionHandling().accessDeniedPage("/denied")
.and()
.csrf().disable();
// #formatter:on
}
If u need to use requiresSecure(), just add .requiresChannel().anyRequest().requiresSecure().and() after .and()

Related

How to throw user to a page other than /login if user is not authenticated in spring security

I wanted to throw users out on signup page instead of login page when they are not authenticated. One workaroud I did was to pass "/signup" in .loginPage() function in Security configuration of spring boot application.
But now I also need to put a .rememberMe() feature for login page. because of that I have to pass "/login" in .loginPage(). So that I can add .rememberMe() functionality.
To summarize, How can I throw non-authenticated users to /signup page as well as keeping the rememberMe functionality on login page?
#Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests()
.antMatchers("/game*/**").authenticated()
.antMatchers("/contest*/**").authenticated()
.antMatchers("/badges_awards").authenticated()
.antMatchers("/admin*/**").hasRole("ADMIN")
.and()
.formLogin()
.loginPage("/login")
.usernameParameter("emailAddress")
.passwordParameter("password")
.permitAll()
.and()
.rememberMe()
.key("remember-me")
.rememberMeParameter("remember-me")
.rememberMeCookieName("rememberlogin")
.and()
.logout()
.logoutUrl("/logout")
.logoutSuccessUrl("/")
.permitAll();
http.csrf().disable();
http.headers().frameOptions().disable();
}
Start your configuration like this to tell Spring Security that /signup URL does not need authentication and therefore won't be redirect to your login page :
http.authorizeRequests()
.antMatchers("/signup").permitAll()
try this
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests()
.antMatchers("/login.html").permitAll()
.antMatchers("/signup*/**").permitAll()
.and()
.formLogin()
.loginPage("/login")
.failureHandler(LoginAuthFailureHandler)
.and()
.exceptionHandling()
.accessDeniedPage("/signup.html");
}
#Component
public class LoginAuthFailureHandler extends SimpleUrlAuthenticationFailureHandler {
#Override
public void onAuthenticationFailure(HttpServletRequest request, HttpServletResponse response,
AuthenticationException exception) throws IOException, ServletException {
getRedirectStrategy().sendRedirect(request, response, "/signup.html");
}
}

Setting a DefaultAuthenticationEventPublisher in WebSecurityConfigurerAdapter for Spring Security 5

I've updated some of our services to Spring Security 5 from a SS 4 version where it had external support for OAuth2. I've been able to update our services for the most part.
Previously our WebSecurityConfigurerAdapter had the following configure function where we set an applicationEventPublisher on a OAuth2AuthenticationProcessingFilter so we can output logs messages about AuthenticationEvents.
But OAuth2AuthenticationProcessingFilter went away in SS5 because OAuth2 support is now directly supported.
Is their an easier way of setting the AuthenticationEventPublisher without creating my own filter and recreating the part of checking authentication to just have it done again by Spring?
#Override
protected void configure(HttpSecurity http) throws Exception {
http.sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS);
OAuth2AuthenticationProcessingFilter filter = new OAuth2AuthenticationProcessingFilter();
filter.setAuthenticationManager(authenticationManager);
filter.setStateless(true);
filter.setAuthenticationEventPublisher(
new DefaultAuthenticationEventPublisher(applicationEventPublisher));
filter.afterPropertiesSet();
http.csrf()
.disable()
.anonymous()
.disable()
.httpBasic()
.disable()
.logout()
.disable()
.formLogin()
.disable()
.addFilterBefore(filter, SessionManagementFilter.class)
.antMatcher("/actuator/**")
.authorizeRequests()
.antMatchers(HttpMethod.OPTIONS)
.permitAll()
.antMatchers("/actuator/**")
.access("#oauth2.hasScope('auditor')")
.anyRequest()
.authenticated()
.accessDecisionManager(accessDecisionManager);
}
#Bean
public ApplicationListener<AuditApplicationEvent> onEventListener() {
return (AuditApplicationEvent event) -> {
LoggingUtil loggingFormat = new LoggingUtil();
loggingFormat.setUser(event.getAuditEvent().getPrincipal());
loggingFormat.setEvent("Resource Authentication");
loggingFormat.setOutcome(event.getAuditEvent().getType());
loggingFormat.setMessage(
event.getAuditEvent().getData().containsKey("message")
? event.getAuditEvent().getData().get("message").toString()
: "");
String info = loggingFormat.toString();
logger.info(info);
};
}
For our SS 5 we have
protected void configure(HttpSecurity http) throws Exception {
http.sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS);
SessionManagementFilter as;
//TODO how do we setup the authenticationEventPublisher
//filter.setAuthenticationEventPublisher(
// new DefaultAuthenticationEventPublisher(applicationEventPublisher));
http.csrf()
.disable()
.anonymous()
.disable()
.httpBasic()
.disable()
.logout()
.disable()
.formLogin()
.disable()
// .addFilterBefore(filter, SessionManagementFilter.class)
.authorizeRequests()
.antMatchers(HttpMethod.OPTIONS)
.permitAll()
.antMatchers("/actuator/**").hasAuthority("SCOPE_auditor")
.anyRequest()
.authenticated()
.and()
.oauth2ResourceServer().jwt();
}

Why the character ';' is added the end of request in OAuth2

There are Authorization Server(UAA) and Resource Server and Gateway applications that have been working correctly. The scenario for authentication is authorization_code. In the first time after authentication, the end of request is added ;jesessionid=[value], so its result is exception from HttpFirewall of Gateway application, because of having ';' in the request.
My question is that what is it and why jessionid is added the end of request? and how is it adaptable with HttpFirewall.
I have found a way around but I know it has some risks. It is like this:
#Bean
public HttpFirewall allowUrlEncodedSlashHttpFirwall() {
StrictHttpFirewall firewall = new StrictHttpFirewall();
firewall.setAllowSemicolon(true);
return firewall;
}
#Override
protected void configure(HttpSecurity http) throws Exception {
http
.csrf()
.disable()
.headers().cacheControl().disable()
.and()
.headers()
.cacheControl()
.disable()
.frameOptions()
.sameOrigin()
.and()
.httpBasic().disable()
.authorizeRequests()
.requestMatchers(EndpointRequest.toAnyEndpoint()).permitAll()
.requestMatchers(PathRequest.toStaticResources().atCommonLocations()).permitAll()
.mvcMatchers("/uaa/**", "/login**", "/favicon.ico", "/error**").permitAll()
.anyRequest().authenticated()
.and()
.logout()
.permitAll();
}
#Override
public void configure(WebSecurity web) throws Exception {
super.configure(web);
web.httpFirewall(allowUrlEncodedSlashHttpFirwall());
}
As above configuration, the ; is skipped but it is not right and it has some risks.
What is the correct way and config to solve this problem?

How to log out sucessfully

My login page is http://localhost:8080/nradmin/welcome
and my home page (after successful log in) is http://localhost:8080/nradmin/home
I'd like to log out and not anymore be able anymore to access any other page like the home page but only the welcome (login) page. If I type http://localhost:8080/nradmin/home on the browser after logout I continue to have access to the home page without logging in.
I've implemented the following methods overriden from the abstract class WebSecurityConfigurerAdapter:
#Override
protected void configure(HttpSecurity http) throws Exception { http
.authorizeRequests()
.antMatchers("/welcome").permitAll()
.antMatchers("/home", "/account/**", "/price/**").hasRole("ADMIN")
.antMatchers("/home", "/account/**", "/price/**").access("hasRole('ROLE_ADMIN')")
.anyRequest()
.authenticated()
.and()
.formLogin()
.loginPage("/welcome")
.defaultSuccessUrl("/home")
.and()
.logout()
.invalidateHttpSession(true)
.clearAuthentication(true)
.logoutSuccessUrl("/welcome")
.logoutUrl("/welcome")
.deleteCookies()
.permitAll()
.and()
.exceptionHandling()
.accessDeniedPage("/welcome")
.and()
.sessionManagement()
.sessionCreationPolicy(SessionCreationPolicy.IF_REQUIRED);
}
#Override
protected void configure(final AuthenticationManagerBuilder auth) throws Exception {
auth.inMemoryAuthentication() .withUser("username").password(passwordEncoder().encode("12345")).roles(LoginDataConstants.ROLE_ADMIN)
}
#Bean
public PasswordEncoder passwordEncoder() {
return new BCryptPasswordEncoder();
}
Does anyone have an idea how to do it?
I guess it may be due to having the same url in the methods logoutUrl and logoutSuccessUrl.
I suggest you to change logoutUrl to other path, for example just /logout and then try to perform the logout hitting that url. It should complete the logout task and the redirect to the logoutSuccessUrl, which is /welcome
Add CSRF
Reference from spring docs.
Will perform logout with the URL /logout is requested with any HTTP method
#Override protected void configure(HttpSecurity http) throws Exception {
http.
logout().logoutRequestMatcher(new AntPathRequestMatcher("/logout"));
}
}
You can also reference a good example on stack overflow using this same method here
When I had this issue I used this line
.logout().logoutRequestMatcher(new AntPathRequestMatcher("/logout")).logoutSuccessUrl("/login");
Where
.logoutSuccessUrl("/login") was the page the user will be redirected to.
You could re-factor your code to something like this
#Override
protected void configure(HttpSecurity http) throws Exception { http
.authorizeRequests()
.antMatchers("/welcome").permitAll()
.antMatchers("/home", "/account/**", "/price/**").hasRole("ADMIN")
.antMatchers("/home", "/account/**", "/price/**").access("hasRole('ROLE_ADMIN')")
.anyRequest()
.authenticated()
.and()
.formLogin()
.loginPage("/welcome")
.defaultSuccessUrl("/home")
.and()
.logout()
.and() // This section is re-factored.
.logout().logoutRequestMatcher(new AntPathRequestMatcher("/logout"))
.logoutSuccessUrl("/welcome").deleteCookies("JSESSIONID") //Or try .logoutSuccessUrl("/nradmin/welcome")
.invalidateHttpSession(true)
.permitAll()
.and()
.exceptionHandling()
.accessDeniedPage("/welcome")
.and()
.sessionManagement()
.sessio hinCreationPolicy(SessionCreationPolicy.IF_REQUIRED);
Update : This is a modified version. This is essentially what I use in my project except for this portion:
.and()
.exceptionHandling()
.accessDeniedPage("/welcome")
.and()
.sessionManagement()
.sessionCreationPolicy(SessionCreationPolicy.IF_REQUIRED);
So, I believe it should work; otherwise, I believe it may be a setup issue/configuration that resides somewhere else in your project. Please try the below example.
#Configuration
#EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
#Override
protected void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
.antMatchers("/nradmin/welcome", "/home", "/account/**", "/price/**").hasRole("ADMIN")
.anyRequest().permitAll()
.and()
.formLogin()
.loginPage("/nradmin/welcome")
.permitAll()
.and()
.logout().logoutRequestMatcher(new AntPathRequestMatcher("/logout"))
.logoutSuccessUrl("/nradmin/welcome").deleteCookies("JSESSIONID")
.invalidateHttpSession(true)
.permitAll()
.and()
.exceptionHandling()
.accessDeniedPage("/nradmin/welcome")
.and()
.sessionManagement()
.sessionCreationPolicy(SessionCreationPolicy.IF_REQUIRED);
}

Spring Security. Any request needs to be authorized and a special POST request needs an admin role. How to do this?

I want to secure my HATEOAS REST API build with Spring. All requests should need authorization and POST requests to "/rooms" should need the admin role. My WebSecurityConfigurerAdapter implementation code looks like this right now:
#Override
protected void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
// Todo: Make sure that all resources need to be authenticated and POST rooms needs ADMIN role
.anyRequest().authenticated()
.antMatchers(HttpMethod.POST, "/api/v1/rooms").hasRole("ADMIN")
.and()
.httpBasic()
.and()
.csrf().disable();
}
Right now all resources only need authentication if I put the "anyRequest().authenticated()" line before the "antMatchers..." line, but then the needed "ADMIN" role doesn't work or get applied and vice versa.
How am I to get both things working at the same time?
Kind Regards,
Florian
Securityconfiguration.java
#Override
protected void configure(HttpSecurity http) throws Exception {
http.httpBasic().and().authorizeRequests().antMatchers("/public/**")
.permitAll().antMatchers("/sa/**").hasAuthority("sa")
.antMatchers("/admin/**").hasAuthority("admin")
.and().logout()
.logoutRequestMatcher(new AntPathRequestMatcher("/logout"))
.logoutSuccessUrl("/index.html").and()
.addFilterAfter(new CsrfHeaderFilter(), CsrfFilter.class)
.csrf().disable();
}
And in the rest controller use..
#RequestMapping("/admin/adduser")
public void addUser(#RequestBody User user) {
authService.addUser(user);
}
The following code did it for me:
#Override
protected void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
.antMatchers(HttpMethod.POST, "/api/v1/rooms").hasRole("ADMIN")
.anyRequest().authenticated()
.and()
.httpBasic()
.and()
.csrf().disable();
}
}
Thank you for the response Pankaj.

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