Is there any way to set via property 'context-path' many mappings for a same Spring Boot MVC application? My goal is to avoid creating many 'Dispatcherservlet' for the uri mapping.
For example:
servlet.context-path =/, /context1, context2
You can create #Bean annotated method which returns ServletRegistrationBean , and add multiple mappings there. This is more preferable way, as Spring Boot encourage Java configuration rather than config files:
#Bean
public ServletRegistrationBean myServletRegistration()
{
String urlMapping1 = "/mySuperApp/service1/*";
String urlMapping2 = "/mySuperApp/service2/*";
ServletRegistrationBean registration = new ServletRegistrationBean(new MyBeautifulServlet(), urlMapping1, urlMapping2);
//registration.set... other properties may be here
return registration;
}
On application startup you'll be able to see in logs:
INFO | localhost | org.springframework.boot.web.servlet.ServletRegistrationBean | Mapping servlet: 'MyBeautifulServlet' to [/mySuperApp/service1/*, /mySuperApp/service2/*]
You only need a single Dispatcherservlet with a root context path set to what you want (could be / or mySuperApp).
By declaring multiple #RequestMaping, you will be able to serve different URI with the same DispatcherServlet.
Here is an example. Setting the DispatcherServlet to /mySuperApp with #RequestMapping("/service1") and #RequestMapping("/service2") would exposed the following endpoints :
/mySuperApp/service1
/mySuperApp/service2
Having multiple context for a single servlet is not part of the Servlet specification. A single servlet cannot serve from multiple context.
What you can do is map multiple values to your requesting mappings.
#RequestMapping({"/context1/service1}", {"/context2/service1}")
I don't see any other way around it.
You can use 'server.contextPath' property placeholder to set context path for the entire spring boot application. (e.g. server.contextPath=/live/path1)
Also, you can set class level context path that will be applied to all the methods e.g.:
#RestController
#RequestMapping(value = "/testResource", produces = MediaType.APPLICATION_JSON_VALUE)
public class TestResource{
#RequestMapping(method = RequestMethod.POST, value="/test", produces = MediaType.APPLICATION_JSON_VALUE)
public ResponseEntity<TestDto> save(#RequestBody TestDto testDto) {
...
With this structure, you can use /live/path1/testResource/test to execute save method.
None of the answers to this sort of question seem to mention that you'd normally solve this problem by configuring a reverse proxy in front of the application (eg nginx/apache httpd) to rewrite the request.
However if you must do it in the application then this method works (with Spring Boot 2.6.2 at least) : https://www.broadleafcommerce.com/blog/configuring-a-dynamic-context-path-in-spring-boot.
It describes creating a filter, putting it early in the filter chain and basically re-writing the URL (like a reverse proxy might) so that requests all go to the same place (ie the actual servlet.context-path).
I've found an alternative to using a filter described in https://www.broadleafcommerce.com/blog/configuring-a-dynamic-context-path-in-spring-boot that requires less code.
This uses RewriteValve (https://tomcat.apache.org/tomcat-9.0-doc/rewrite.html) to rewrite urls outside of the context path e.g. if the real context path is "context1" then it will map /context2/* to /context1/*
#Component
public class LegacyUrlWebServerFactoryCustomizer implements WebServerFactoryCustomizer<TomcatServletWebServerFactory> {
private static final List<String> LEGACY_PATHS = List.of("context2", "context3");
#Override
public void customize(TomcatServletWebServerFactory factory) {
RewriteValve rewrite = new RewriteValve() {
#Override
protected void initInternal() throws LifecycleException {
super.initInternal();
try {
String config = LEGACY_PATHS.stream() //
.map(p -> String.format("RewriteRule ^/%s(/.*)$ %s$1", p, factory.getContextPath())) //
.collect(Collectors.joining("\n"));
setConfiguration(config);
} catch (Exception e) {
throw new RuntimeException(e);
}
}
};
factory.addEngineValves(rewrite);
}
}
If you need to use HTTP redirects instead then there is a little bit more required (to avoid a NullPointerException in sendRedirect):
#Component
public class LegacyUrlWebServerFactoryCustomizer implements WebServerFactoryCustomizer<TomcatServletWebServerFactory> {
private static final List<String> LEGACY_PATHS = List.of("context2", "context3");
#Override
public void customize(TomcatServletWebServerFactory factory) {
RewriteValve rewrite = new RewriteValve() {
#Override
protected void initInternal() throws LifecycleException {
super.initInternal();
try {
String config = LEGACY_PATHS.stream() //
.map(p -> String.format("RewriteRule ^/%s(/.*)$ %s$1 R=permanent", p, factory.getContextPath())) //
.collect(Collectors.joining("\n"));
setConfiguration(config);
} catch (Exception e) {
throw new RuntimeException(e);
}
}
#Override
public void invoke(Request request, Response response) throws IOException, ServletException {
if (request.getContext() == null) {
String[] s = request.getRequestURI().split("/");
if (s.length > 1 && LEGACY_PATHS.contains(s[1])) {
request.getMappingData().context = new FailedContext();
}
}
super.invoke(request, response);
}
};
factory.addEngineValves(rewrite);
}
}
I use this approach:
import javax.servlet.ServletContext;
import javax.servlet.ServletRegistration;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.WebApplicationInitializer;
import org.springframework.web.context.ContextLoaderListener;
import org.springframework.web.context.support.AnnotationConfigWebApplicationContext;
import org.springframework.web.servlet.DispatcherServlet;
#Configuration
public class WebAppInitializer implements WebApplicationInitializer {
#Override
public void onStartup(ServletContext servletContext) {
AnnotationConfigWebApplicationContext rootContext = new AnnotationConfigWebApplicationContext();
rootContext.register(AppConfig.class);
rootContext.setServletContext(servletContext);
ServletRegistration.Dynamic dispatcher = servletContext.addServlet("dispatcher", new DispatcherServlet(rootContext));
dispatcher.setLoadOnStartup(1);
dispatcher.addMapping("/mapping1/*");
dispatcher.addMapping("/mapping2/*");
servletContext.addListener(new ContextLoaderListener(rootContext));
}
}
Related
Before a Spring boot application starts, I need to make a request for some credentials. I'm storing them in an object.
Is there a way to register this object as a bean before all other beans so that I can inject them in a configuration class?
I've tried like below but it's throwing exceptions:
SpringBootApplication(exclude = {MongoAutoConfiguration.class,
SecurityAutoConfiguration.class, DataSourceAutoConfiguration.class})
public class BeanOnInitApplication {
public static void main(String[] args) {
System.out.println("Starting the app");
MongoCredentials creds = makeARequestToExternalServiceAndGetCredentials();
GenericApplicationContext appContext = (GenericApplicationContext) SpringApplication.run(BeanOnInitApplication.class, args);
appContext.registerBean("mongoCredentials", MongoCredentials.class, () -> creds, bdc -> bdc.setLazyInit(false));
}
}
And config class:
#Configuration
public class AppConfig {
#Autowired
MongoCredentials mongoCredentials;
#Bean(name = "mongoTemplate")
public MongoTemplate mt() {
String url = "mongodb://" + mongoCredentials.getUsername() + ":" + mongoCredentials.getPassword() + "#localhost:27017/admin";
MongoDatabaseFactory mdf = new SimpleMongoClientDatabaseFactory(url);
return new MongoTemplate(mdf);
}
}
If this is not a solution what are the alternatives? The scope is to register a critical bean before anything else.
Just make it an #Bean.
#Bean
public MongoCredentials mongoCredentials() {
return makeARequestToExternalServiceAndGetCredentials();
}
Don't handle exceptions in the makeARequestToExternalServiceAndGetCredentials and just let them bubble up. If the request then fails the application will simply fail to start. If you want to retry wrap the call with a Spring Retry RetryTemplate and you have everything you want.
Another option is, which would allow for using auto configuration for Mongo as you appear to be using Spring Boot. Is to create an EnvironmentPostProcessor which loads the properties and adds them to the environment.
public class MongoCredentialsPostProcessor implements EnvironmentPostProcessor {
public void postProcessEnvironment(ConfigurableEnvironment environment, SpringApplication application) {
MongoCredentials credentials = makeARequestToExternalServiceAndGetCredentials();
String url = "mongodb://" + mongoCredentials.getUsername() + ":" + mongoCredentials.getPassword() + "#localhost:27017/admin";
Map<String, Object> props = Map.of("spring.data.mongodb.uri", url);
MapPropertySource mps = new MapPropertySource("mongo-credentials", props):
}
}
Finally you could also modify your current code to do the same as the EnvironmentPostProcessor.
SpringBootApplication(exclude = {
SecurityAutoConfiguration.class, DataSourceAutoConfiguration.class})
public class BeanOnInitApplication {
public static void main(String[] args) {
System.out.println("Starting the app");
MongoCredentials creds = makeARequestToExternalServiceAndGetCredentials();
String url = "mongodb://" + mongoCredentials.getUsername() + ":" + mongoCredentials.getPassword() + "#localhost:27017/admin";
SpringApplicationBuilder sab = new SpringApplicationBuilder(BeanOnInitApplication.class);
sab.properties(Map.of("spring.data.mongodb.uri", url)).run(args);
}
}
With both the latter and the EnvironmentPostProcessor you should be able to use the mongo autoconfiguration (which will provide the MongoTemplate for you.
I am calling another microservice once my current microservice is up and ready using feign client in my current microservice built using Jhipster.
So my Feign Interface is
package com.persistent.integration.client;
import java.util.List;
import org.springframework.data.domain.Pageable;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RequestParam;
import com.persistent.integration.service.dto.DataPipelineDTO;
#AuthorizedFeignClient(name = "Integrationconfiguration")
public interface DataPipelinesResourceFeign {
#RequestMapping(value = "/api/data-pipelines", method = RequestMethod.GET)
List<DataPipelineDTO> getAllDataPipelines(#RequestParam(value = "pageable") Pageable pageable );
}
}
And I have implemented ApplicationRunner where I have called feign client method.
#Component
public class ApplicationInitializer implements ApplicationRunner {
#Autowired
private DataPipelinesResourceFeign dataPipelinesResourceFeign;
#Autowired
private ActiveMQListener activeMqListener;
#Override
public void run(ApplicationArguments args) throws Exception {
// TODO Auto-generated method stub
Pageable pageable = PageRequest.of(0, 20);
try {
List <DataPipelineDTO> allStartedDataPipeLines = dataPipelinesResourceFeign.getAllDataPipelines(pageable); //.stream().filter(p->p.getState().equals(State.STARTED)).collect(Collectors.toList());
allStartedDataPipeLines.forEach(datapipe ->
{
try {
activeMqListener.consume(datapipe);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
});
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
But after running this, it gives below exception at dataPipelinesResourceFeign.getAllDataPipelines :
com.netflix.hystrix.exception.HystrixRuntimeException: DataPipelinesResourceFeign#getAllDataPipelines(Pageable) failed and no fallback available.
at com.netflix.hystrix.AbstractCommand$22.call(AbstractCommand.java:819)
at com.netflix.hystrix.AbstractCommand$22.call(AbstractCommand.java:804)
at rx.internal.operators.OperatorOnErrorResumeNextViaFunction$4.onError(OperatorOnErrorResumeNextViaFunction.java:140)
at rx.internal.operators.OnSubscribeDoOnEach$DoOnEachSubscriber.onError(OnSubscribeDoOnEach.java:87)
at rx.internal.operators.OnSubscribeDoOnEach$DoOnEachSubscriber.onError(OnSubscribeDoOnEach.java:87)
at com.netflix.hystrix.AbstractCommand$DeprecatedOnFallbackHookApplication$1.onError(AbstractCommand.java:1472)
Caused by: org.springframework.beans.factory.BeanCreationException:
Error creating bean with name 'scopedTarget.oauth2ClientContext':
Scope 'request' is not active for the current thread; consider
defining a scoped proxy for this bean if you intend to refer to it
from a singleton; nested exception is java.lang.IllegalStateException:
No thread-bound request found: Are you referring to request attributes
outside of an actual web request, or processing a request outside of
the originally receiving thread? If you are actually operating within
a web request and still receive this message, your code is probably
running outside of DispatcherServlet/DispatcherPortlet: In this case,
use RequestContextListener or RequestContextFilter to expose the
current request. at
org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(Abstrac>tBeanFactory.java:362)
at
org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractB>eanFactory.java:199)
at
org.springframework.aop.target.SimpleBeanTargetSource.getTarget(SimpleBeanTarge>tSource.java:35)
at
org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.>java:193)
at com.sun.proxy.$Proxy147.getAccessToken(Unknown Source) at
com.persistent.integration.security.oauth2.AuthorizationHeaderUtil.getAuthoriza>tionHeaderFromOAuth2Context(AuthorizationHeaderUtil.java:28)
at
com.persistent.integration.client.TokenRelayRequestInterceptor.apply(TokenRelay>RequestInterceptor.java:23)
at
feign.SynchronousMethodHandler.targetRequest(SynchronousMethodHandler.java:158)
at
feign.SynchronousMethodHandler.executeAndDecode(SynchronousMethodHandler.java:88)
at
feign.SynchronousMethodHandler.invoke(SynchronousMethodHandler.java:76)
at
feign.hystrix.HystrixInvocationHandler$1.run(HystrixInvocationHandler.java:108)
at com.netflix.hystrix.HystrixCommand$2.call(HystrixCommand.java:302)
at com.netflix.hystrix.HystrixCommand$2.call(HystrixCommand.java:298)
at
rx.internal.operators.OnSubscribeDefer.call(OnSubscribeDefer.java:46)
... 68 more Caused by: java.lang.IllegalStateException: No
thread-bound request found: Are you referring to request attributes
outside of an actual web request, or processing a request outside of
the originally receiving thread? If you are actually operating within
a web request and still receive this message, your code is probably
running outside of DispatcherServlet/DispatcherPortlet: In this case,
use RequestContextListener or RequestContextFilter to expose the
current request. at
org.springframework.web.context.request.RequestContextHolder.currentRequestAttr>ibutes(RequestContextHolder.java:131)
at
org.springframework.web.context.request.AbstractRequestAttributesScope.get(Abst>ractRequestAttributesScope.java:42)
at
org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(Abstrac>tBeanFactory.java:350)
many suggestions on internet were to add listerner RequestContextListener. But problem persisted even if I added listener in webConfigurer.java in onStartup method.
{
servletContext.addListener(RequestContextListener.class);
}
But of no use.
Any leads would be appreciated.
I found a workaround for this. I don't know why TokenRelayRequestIntercepton isn't working but you can use your own RequestInterceptor based on Spring's SecurityContext.
First, define a RequestInterceptor :
public class MyRequestInterceptor implements RequestInterceptor {
public static final String AUTHORIZATION = "Authorization";
public static final String BEARER = "Bearer";
public MyRequestInterceptor() {
super();
}
#Override
public void apply(RequestTemplate template) {
// demander un token à keycloak et le joindre à la request
Optional<String> header = getAuthorizationHeader();
if (header.isPresent()) {
template.header(AUTHORIZATION, header.get());
}
}
public static Optional<String> getAuthorizationHeader() {
Authentication authentication = SecurityContextHolder.getContext().getAuthentication();
if (authentication != null && authentication.getDetails() != null && authentication.getDetails() instanceof OAuth2AuthenticationDetails) {
OAuth2AuthenticationDetails oAuth2AuthenticationDetails =
(OAuth2AuthenticationDetails) authentication.getDetails();
return Optional.of(String.format("%s %s", oAuth2AuthenticationDetails.getTokenType(),
oAuth2AuthenticationDetails.getTokenValue()));
} else {
return Optional.empty();
}
}
}
and then, declare a config class for your feign client using your RequestInterceptor, it should contains something like this :
#Bean(name = "myRequestInterceptor")
public RequestInterceptor getMyRequestInterceptor() throws IOException {
return new MyRequestInterceptor();
}
Your Feign client shoud look like this:
#FeignClient(name = "SERVICE_NAME", configuration = MyFeignConfiguration.class)
public interface MyRestClient {
I had the same issue with Feign Client running on startup using ApplicationRunner and I came up with following solution.
I defined my FeignClientsConfiguration with OAuth2FeignRequestInterceptor, which accepts predefined bean DefaultOAuth2ClientContext and OAuth2 configuration OAuth2ProtectedResourceDetails:
#Configuration
public class MyConfig extends FeignClientsConfiguration {
#Bean
public RequestInterceptor oauth2FeignRequestInterceptor( DefaultOAuth2ClientContext oAuth2ClientContext, MyOauth2Properties properties) {
return new OAuth2FeignRequestInterceptor(oAuth2ClientContext, resourceDetails(properties));
}
#Bean
public DefaultOAuth2ClientContext oAuth2ClientContext() {
return new DefaultOAuth2ClientContext();
}
private OAuth2ProtectedResourceDetails resourceDetails(MyOauth2Properties oauth2Properties) {
ResourceOwnerPasswordResourceDetails resourceDetails = new ResourceOwnerPasswordResourceDetails();
resourceDetails.setAccessTokenUri(oauth2Properties.getAccessTokenUri());
resourceDetails.setUsername(oauth2Properties.getUsername());
resourceDetails.setPassword(oauth2Properties.getPassword());
resourceDetails.setClientId(oauth2Properties.getClientId());
return resourceDetails;
}
}
Your feign client will look something like this:
#FeignClient(url = "http://localhost:8080/api/v1")
public interface FeignClient {
}
After all this, calling FeignClient from ApplicationRunner.run() works fine.
Spring Boot 2.2.6
I believe this is a simple question, but I couldn't find an answer or at least use the correct terms in the search.
I am setting up Angular2 and Springboot together. By default, Angular will use paths like localhost:8080\dashboard and localhost:8080\dashboard\detail.
I'd like to avoid using path as hashs, if possible. As Angular documentation states:
The router's provideRouter function sets the LocationStrategy to the PathLocationStrategy, making it the default strategy. We can switch to the HashLocationStrategy with an override during the bootstrapping process if we prefer it.
And then...
Almost all Angular 2 projects should use the default HTML 5 style. It produces URLs that are easier for users to understand. And it preserves the option to do server-side rendering later.
The issue is that when I try to access localhost:8080\dashboard, Spring will look for some controller mapping to this path, which it won't have.
Whitelabel Error Page
There was an unexpected error (type=Not Found, status=404).
No message available
I thought initially to make all my services to be under localhost:8080\api and all my static under localhost:8080\app. But how do I tell Spring to ignore requests to this app path?
Is there a better solution with either Angular2 or Boot?
In my Spring Boot applications (version 1 and 2), my static resources are at a single place :
src/main/resources/static
static being a folder recognized by Spring Boot to load static resources.
Then the idea is to customize the Spring MVC configuration.
The simpler way is using Spring Java configuration.
I implement WebMvcConfigurer to override addResourceHandlers().
I add in a single ResourceHandler to the current ResourceHandlerRegistry.
The handler is mapped on every request and I specify classpath:/static/ as resource location value (you may of course adding others if required).
I add a custom PathResourceResolver anonymous class to override getResource(String resourcePath, Resource location).
And the rule to return the resource is the following : if the resource exists and is readable (so it is a file), I return it. Otherwise, by default I return the index.html page. Which is the expected behavior to handle HTML 5 urls.
Spring Boot 1.X Application :
Extending org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter is the way. The class is an adapter of the WebMvcConfigurer interface
with empty methods allowing sub-classes to override only the methods they're interested in.
Here is the full code :
import java.io.IOException;
import org.springframework.context.annotation.Configuration;
import org.springframework.core.io.ClassPathResource;
import org.springframework.core.io.Resource;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter;
import org.springframework.web.servlet.resource.PathResourceResolver;
#Configuration
public class WebMvcConfig extends WebMvcConfigurerAdapter {
#Override
public void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler("/**/*")
.addResourceLocations("classpath:/static/")
.resourceChain(true)
.addResolver(new PathResourceResolver() {
#Override
protected Resource getResource(String resourcePath,
Resource location) throws IOException {
Resource requestedResource = location.createRelative(resourcePath);
return requestedResource.exists() && requestedResource.isReadable() ? requestedResource
: new ClassPathResource("/static/index.html");
}
});
}
}
Spring Boot 2.X Application :
org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter was deprecated.
Implementing directly WebMvcConfigurer is the way now as it is still an interface but it has now default methods (made possible by a Java 8 baseline) and can be implemented directly without the need for the adapter.
Here is the full code :
import java.io.IOException;
import org.springframework.context.annotation.Configuration;
import org.springframework.core.io.ClassPathResource;
import org.springframework.core.io.Resource;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurer;
import org.springframework.web.servlet.resource.PathResourceResolver;
#Configuration
public class WebMvcConfig implements WebMvcConfigurer {
#Override
public void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler("/**/*")
.addResourceLocations("classpath:/static/")
.resourceChain(true)
.addResolver(new PathResourceResolver() {
#Override
protected Resource getResource(String resourcePath,
Resource location) throws IOException {
Resource requestedResource = location.createRelative(resourcePath);
return requestedResource.exists() && requestedResource.isReadable() ? requestedResource
: new ClassPathResource("/static/index.html");
}
});
}
}
EDIT to address some comments :
For those that store their static resources at another location as src/main/resources/static, change the value of the var args parameter of addResourcesLocations() consequently.
For example if you have static resources both in static and in the public folder (no tried) :
registry.addResourceHandler("/**/*")
.addResourceLocations("classpath:/static/", "/public")
I have a solution for you, you can add a ViewController to forward requests to Angular from Spring boot.
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
#Controller
public class ViewController {
#RequestMapping({ "/bikes", "/milages", "/gallery", "/tracks", "/tracks/{id:\\w+}", "/location", "/about", "/tests","/tests/new","/tests/**","/questions","/answers" })
public String index() {
return "forward:/index.html";
}
}
here I have redirected all my angular2 ("/bikes", "/milages", "/gallery", "/tracks", "/tracks/{id:\w+}", "/location", "/about", "/tests","/tests/new","/tests/**","/questions","/answers") to my SPA
You can do the same for your preject and you can also redirect your 404 error page to the index page as a further step.
Enjoy!
You can forward all not found resources to your main page by providing custom ErrorViewResolver. All you need to do is to add this to your #Configuration class:
#Bean
ErrorViewResolver supportPathBasedLocationStrategyWithoutHashes() {
return new ErrorViewResolver() {
#Override
public ModelAndView resolveErrorView(HttpServletRequest request, HttpStatus status, Map<String, Object> model) {
return status == HttpStatus.NOT_FOUND
? new ModelAndView("index.html", Collections.<String, Object>emptyMap(), HttpStatus.OK)
: null;
}
};
}
You can forward everything not mapped to Angular using something like this:
#Controller
public class ForwardController {
#RequestMapping(value = "/**/{[path:[^\\.]*}")
public String redirect() {
// Forward to home page so that route is preserved.
return "forward:/";
}
}
Source: https://stackoverflow.com/a/44850886/3854385
My Spring Boot server for angular is also a gateway server with the API calls to /api to not have a login page in front of the angular pages, you can use something like.
import org.springframework.boot.autoconfigure.security.oauth2.client.EnableOAuth2Sso;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
import org.springframework.security.web.csrf.CookieCsrfTokenRepository;
/**
* This sets up basic authentication for the microservice, it is here to prevent
* massive screwups, many applications will require more secuity, some will require less
*/
#EnableOAuth2Sso
#Configuration
public class SecurityConfiguration extends WebSecurityConfigurerAdapter{
#Override
public void configure(HttpSecurity http) throws Exception {
http
.logout().logoutSuccessUrl("/").and()
.authorizeRequests()
.antMatchers("/api/**").authenticated()
.anyRequest().permitAll().and()
.csrf()
.csrfTokenRepository(CookieCsrfTokenRepository.withHttpOnlyFalse());
}
}
To make it more simple you can just implement ErrorPageRegistrar directly..
#Component
public class ErrorPageConfig implements ErrorPageRegistrar {
#Override
public void registerErrorPages(ErrorPageRegistry registry) {
registry.addErrorPages(new ErrorPage(HttpStatus.NOT_FOUND, "/"));
}
}
This would forward the requests to index.html.
#Controller
#RequestMapping("/")
public class MainPageController {
#ResponseStatus(HttpStatus.OK)
#RequestMapping({ "/" })
public String forward() {
return "forward:/";
}
}
I did it with a plain old filter:
public class PathLocationStrategyFilter implements Filter {
#Override
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain)
throws IOException, ServletException {
if(request instanceof HttpServletRequest) {
HttpServletRequest servletRequest = (HttpServletRequest) request;
String uri = servletRequest.getRequestURI();
String contextPath = servletRequest.getContextPath();
if(!uri.startsWith(contextPath + "/api") &&
!uri.startsWith(contextPath + "/assets") &&
!uri.equals(contextPath) &&
// only forward if there's no file extension (exclude *.js, *.css etc)
uri.matches("^([^.]+)$")) {
RequestDispatcher dispatcher = request.getRequestDispatcher("/");
dispatcher.forward(request, response);
return;
}
}
chain.doFilter(request, response);
}
}
Then in web.xml:
<web-app>
<filter>
<filter-name>PathLocationStrategyFilter</filter-name>
<filter-class>mypackage.PathLocationStrategyFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>PathLocationStrategyFilter</filter-name>
<url-pattern>*</url-pattern>
</filter-mapping>
</web-app>
These are the three steps you need to follow:
Implement your own TomcatEmbeddedServletContainerFactory bean and set up the RewriteValve
import org.springframework.boot.context.embedded.tomcat.TomcatEmbeddedServletContainerFactory;
...
import org.apache.catalina.valves.rewrite.RewriteValve;
...
#Bean TomcatEmbeddedServletContainerFactory servletContainerFactory() {
TomcatEmbeddedServletContainerFactory factory = new TomcatEmbeddedServletContainerFactory();
factory.setPort(8080);
factory.addContextValves(new RewriteValve());
return factory;
}
Add a rewrite.conf file to the WEB-INF directory of your application and specify the rewrite rules. Here is an example rewrite.conf content, which I'm using in the angular application to take advantage of the angular's PathLocationStrategy (basicly I just redirect everything to the index.html as we just use spring boot to serve the static web content, otherwise you need to filter your controllers out in the RewriteCond rule):
RewriteCond %{REQUEST_URI} !^.*\.(bmp|css|gif|htc|html?|ico|jpe?g|js|pdf|png|swf|txt|xml|svg|eot|woff|woff2|ttf|map)$
RewriteRule ^(.*)$ /index.html [L]
Get rid of the useHash (or set it to false) from your routing declarations:
RouterModule.forRoot(routes)
or
RouterModule.forRoot(routes, {useHash: false})
forward all Angular routing with index.html. Including base href.
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
#Controller
public class ViewController {
#RequestMapping({ "jsa/customer","jsa/customer/{id}",})
public String index() {
return "forward:/index.html";
}
}
In my case jsa is base href.
in my opinion the best way is to separate the User Interface paths and API paths by adding a prefix to them and serve the UI app entrypoint (index.html) for every path that matches UI prefix:
step 1 - add a prefix for all your UI paths (for example /app/page1, /app/page2, /app/page3, /app/page2/section01 and so on).
step 2 - copy UI files (HTML, JS, CSS, ...) into /resources/static/
step 3 - serve index.html for every path that begins with /app/ by a controller like this:
#Controller
public class SPAController {
#RequestMapping(value = "/app/**", method = RequestMethod.GET)
public ResponseEntity<String> defaultPath() {
try {
// Jar
InputStream inputStream = this.getClass().getClassLoader().getResourceAsStream("/static/index.html");
// IDE
if (inputStream == null) {
inputStream = this.getClass().getResourceAsStream("/static/index.html");
}
String body = StreamUtils.copyToString(inputStream, Charset.defaultCharset());
return ResponseEntity.ok().contentType(MediaType.TEXT_HTML).body(body);
} catch (IOException e) {
e.printStackTrace();
return ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR).body("Error in redirecting to index");
}
}
#GetMapping(value = "/")
public String home(){
return "redirect:/app";
}
}
I created a filter using following annotations in a java web project created by spring-boot:
#Order(2)
#Component
#WebFilter(
filterName = "jwtFitler",
urlPatterns = "/*",
initParams = { #WebInitParam(name = "excludedPaths", value = "login, hello") }
)
However, the initParams are not working, excludedPaths and excludedUrls are always null. Could anyone help tell me why?
public class MyFilter implements Filter {
private String[] excludedUrls;
#Override
public void init(FilterConfig filterConfig) throws ServletException {
String excludedPaths = filterConfig.getInitParameter("excludedPaths");
System.out.println("excludedPaths:" + excludedPaths);
if(!StringUtils.isEmpty(excludedPaths))
excludedUrls = excludedPaths.split(",");
System.out.println("excludedUrls:" + excludedUrls);
}
//......
}
Due to your use of #Component, your Filter is being found as a plain Spring component. As a result, the #WebFilter configuration has no effect.
If you want Spring Boot to scan for Servlet components (#WebFilter, #WebListener and #WebServlet) you need to use #ServletComponentScan. Typically, that annotation is added to your main application class alongside #SpringBootApplication. With that in place, you should remove #Component from your Filter.
I believe this is a simple question, but I couldn't find an answer or at least use the correct terms in the search.
I am setting up Angular2 and Springboot together. By default, Angular will use paths like localhost:8080\dashboard and localhost:8080\dashboard\detail.
I'd like to avoid using path as hashs, if possible. As Angular documentation states:
The router's provideRouter function sets the LocationStrategy to the PathLocationStrategy, making it the default strategy. We can switch to the HashLocationStrategy with an override during the bootstrapping process if we prefer it.
And then...
Almost all Angular 2 projects should use the default HTML 5 style. It produces URLs that are easier for users to understand. And it preserves the option to do server-side rendering later.
The issue is that when I try to access localhost:8080\dashboard, Spring will look for some controller mapping to this path, which it won't have.
Whitelabel Error Page
There was an unexpected error (type=Not Found, status=404).
No message available
I thought initially to make all my services to be under localhost:8080\api and all my static under localhost:8080\app. But how do I tell Spring to ignore requests to this app path?
Is there a better solution with either Angular2 or Boot?
In my Spring Boot applications (version 1 and 2), my static resources are at a single place :
src/main/resources/static
static being a folder recognized by Spring Boot to load static resources.
Then the idea is to customize the Spring MVC configuration.
The simpler way is using Spring Java configuration.
I implement WebMvcConfigurer to override addResourceHandlers().
I add in a single ResourceHandler to the current ResourceHandlerRegistry.
The handler is mapped on every request and I specify classpath:/static/ as resource location value (you may of course adding others if required).
I add a custom PathResourceResolver anonymous class to override getResource(String resourcePath, Resource location).
And the rule to return the resource is the following : if the resource exists and is readable (so it is a file), I return it. Otherwise, by default I return the index.html page. Which is the expected behavior to handle HTML 5 urls.
Spring Boot 1.X Application :
Extending org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter is the way. The class is an adapter of the WebMvcConfigurer interface
with empty methods allowing sub-classes to override only the methods they're interested in.
Here is the full code :
import java.io.IOException;
import org.springframework.context.annotation.Configuration;
import org.springframework.core.io.ClassPathResource;
import org.springframework.core.io.Resource;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter;
import org.springframework.web.servlet.resource.PathResourceResolver;
#Configuration
public class WebMvcConfig extends WebMvcConfigurerAdapter {
#Override
public void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler("/**/*")
.addResourceLocations("classpath:/static/")
.resourceChain(true)
.addResolver(new PathResourceResolver() {
#Override
protected Resource getResource(String resourcePath,
Resource location) throws IOException {
Resource requestedResource = location.createRelative(resourcePath);
return requestedResource.exists() && requestedResource.isReadable() ? requestedResource
: new ClassPathResource("/static/index.html");
}
});
}
}
Spring Boot 2.X Application :
org.springframework.web.servlet.config.annotation.WebMvcConfigurerAdapter was deprecated.
Implementing directly WebMvcConfigurer is the way now as it is still an interface but it has now default methods (made possible by a Java 8 baseline) and can be implemented directly without the need for the adapter.
Here is the full code :
import java.io.IOException;
import org.springframework.context.annotation.Configuration;
import org.springframework.core.io.ClassPathResource;
import org.springframework.core.io.Resource;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurer;
import org.springframework.web.servlet.resource.PathResourceResolver;
#Configuration
public class WebMvcConfig implements WebMvcConfigurer {
#Override
public void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler("/**/*")
.addResourceLocations("classpath:/static/")
.resourceChain(true)
.addResolver(new PathResourceResolver() {
#Override
protected Resource getResource(String resourcePath,
Resource location) throws IOException {
Resource requestedResource = location.createRelative(resourcePath);
return requestedResource.exists() && requestedResource.isReadable() ? requestedResource
: new ClassPathResource("/static/index.html");
}
});
}
}
EDIT to address some comments :
For those that store their static resources at another location as src/main/resources/static, change the value of the var args parameter of addResourcesLocations() consequently.
For example if you have static resources both in static and in the public folder (no tried) :
registry.addResourceHandler("/**/*")
.addResourceLocations("classpath:/static/", "/public")
I have a solution for you, you can add a ViewController to forward requests to Angular from Spring boot.
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
#Controller
public class ViewController {
#RequestMapping({ "/bikes", "/milages", "/gallery", "/tracks", "/tracks/{id:\\w+}", "/location", "/about", "/tests","/tests/new","/tests/**","/questions","/answers" })
public String index() {
return "forward:/index.html";
}
}
here I have redirected all my angular2 ("/bikes", "/milages", "/gallery", "/tracks", "/tracks/{id:\w+}", "/location", "/about", "/tests","/tests/new","/tests/**","/questions","/answers") to my SPA
You can do the same for your preject and you can also redirect your 404 error page to the index page as a further step.
Enjoy!
You can forward all not found resources to your main page by providing custom ErrorViewResolver. All you need to do is to add this to your #Configuration class:
#Bean
ErrorViewResolver supportPathBasedLocationStrategyWithoutHashes() {
return new ErrorViewResolver() {
#Override
public ModelAndView resolveErrorView(HttpServletRequest request, HttpStatus status, Map<String, Object> model) {
return status == HttpStatus.NOT_FOUND
? new ModelAndView("index.html", Collections.<String, Object>emptyMap(), HttpStatus.OK)
: null;
}
};
}
You can forward everything not mapped to Angular using something like this:
#Controller
public class ForwardController {
#RequestMapping(value = "/**/{[path:[^\\.]*}")
public String redirect() {
// Forward to home page so that route is preserved.
return "forward:/";
}
}
Source: https://stackoverflow.com/a/44850886/3854385
My Spring Boot server for angular is also a gateway server with the API calls to /api to not have a login page in front of the angular pages, you can use something like.
import org.springframework.boot.autoconfigure.security.oauth2.client.EnableOAuth2Sso;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
import org.springframework.security.web.csrf.CookieCsrfTokenRepository;
/**
* This sets up basic authentication for the microservice, it is here to prevent
* massive screwups, many applications will require more secuity, some will require less
*/
#EnableOAuth2Sso
#Configuration
public class SecurityConfiguration extends WebSecurityConfigurerAdapter{
#Override
public void configure(HttpSecurity http) throws Exception {
http
.logout().logoutSuccessUrl("/").and()
.authorizeRequests()
.antMatchers("/api/**").authenticated()
.anyRequest().permitAll().and()
.csrf()
.csrfTokenRepository(CookieCsrfTokenRepository.withHttpOnlyFalse());
}
}
To make it more simple you can just implement ErrorPageRegistrar directly..
#Component
public class ErrorPageConfig implements ErrorPageRegistrar {
#Override
public void registerErrorPages(ErrorPageRegistry registry) {
registry.addErrorPages(new ErrorPage(HttpStatus.NOT_FOUND, "/"));
}
}
This would forward the requests to index.html.
#Controller
#RequestMapping("/")
public class MainPageController {
#ResponseStatus(HttpStatus.OK)
#RequestMapping({ "/" })
public String forward() {
return "forward:/";
}
}
I did it with a plain old filter:
public class PathLocationStrategyFilter implements Filter {
#Override
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain)
throws IOException, ServletException {
if(request instanceof HttpServletRequest) {
HttpServletRequest servletRequest = (HttpServletRequest) request;
String uri = servletRequest.getRequestURI();
String contextPath = servletRequest.getContextPath();
if(!uri.startsWith(contextPath + "/api") &&
!uri.startsWith(contextPath + "/assets") &&
!uri.equals(contextPath) &&
// only forward if there's no file extension (exclude *.js, *.css etc)
uri.matches("^([^.]+)$")) {
RequestDispatcher dispatcher = request.getRequestDispatcher("/");
dispatcher.forward(request, response);
return;
}
}
chain.doFilter(request, response);
}
}
Then in web.xml:
<web-app>
<filter>
<filter-name>PathLocationStrategyFilter</filter-name>
<filter-class>mypackage.PathLocationStrategyFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>PathLocationStrategyFilter</filter-name>
<url-pattern>*</url-pattern>
</filter-mapping>
</web-app>
These are the three steps you need to follow:
Implement your own TomcatEmbeddedServletContainerFactory bean and set up the RewriteValve
import org.springframework.boot.context.embedded.tomcat.TomcatEmbeddedServletContainerFactory;
...
import org.apache.catalina.valves.rewrite.RewriteValve;
...
#Bean TomcatEmbeddedServletContainerFactory servletContainerFactory() {
TomcatEmbeddedServletContainerFactory factory = new TomcatEmbeddedServletContainerFactory();
factory.setPort(8080);
factory.addContextValves(new RewriteValve());
return factory;
}
Add a rewrite.conf file to the WEB-INF directory of your application and specify the rewrite rules. Here is an example rewrite.conf content, which I'm using in the angular application to take advantage of the angular's PathLocationStrategy (basicly I just redirect everything to the index.html as we just use spring boot to serve the static web content, otherwise you need to filter your controllers out in the RewriteCond rule):
RewriteCond %{REQUEST_URI} !^.*\.(bmp|css|gif|htc|html?|ico|jpe?g|js|pdf|png|swf|txt|xml|svg|eot|woff|woff2|ttf|map)$
RewriteRule ^(.*)$ /index.html [L]
Get rid of the useHash (or set it to false) from your routing declarations:
RouterModule.forRoot(routes)
or
RouterModule.forRoot(routes, {useHash: false})
forward all Angular routing with index.html. Including base href.
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
#Controller
public class ViewController {
#RequestMapping({ "jsa/customer","jsa/customer/{id}",})
public String index() {
return "forward:/index.html";
}
}
In my case jsa is base href.
in my opinion the best way is to separate the User Interface paths and API paths by adding a prefix to them and serve the UI app entrypoint (index.html) for every path that matches UI prefix:
step 1 - add a prefix for all your UI paths (for example /app/page1, /app/page2, /app/page3, /app/page2/section01 and so on).
step 2 - copy UI files (HTML, JS, CSS, ...) into /resources/static/
step 3 - serve index.html for every path that begins with /app/ by a controller like this:
#Controller
public class SPAController {
#RequestMapping(value = "/app/**", method = RequestMethod.GET)
public ResponseEntity<String> defaultPath() {
try {
// Jar
InputStream inputStream = this.getClass().getClassLoader().getResourceAsStream("/static/index.html");
// IDE
if (inputStream == null) {
inputStream = this.getClass().getResourceAsStream("/static/index.html");
}
String body = StreamUtils.copyToString(inputStream, Charset.defaultCharset());
return ResponseEntity.ok().contentType(MediaType.TEXT_HTML).body(body);
} catch (IOException e) {
e.printStackTrace();
return ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR).body("Error in redirecting to index");
}
}
#GetMapping(value = "/")
public String home(){
return "redirect:/app";
}
}