ElasticSearch comparative range results - elasticsearch

Question

Hi I would like to index objects that look like that
{
uuid: "123",
clauses: [{ order: 1, uuid: "345"},{ order: 2, uuid: "567"},{ order: 3, uuid: "789"}]
}
Is there a way to write a query that matches all the objects that contain
clauses with uuid: "345" and uuid: "789" but order of the second one is at most two bigger than first one?
So the above example would match but the next one wouldn't :
{
uuid: "999",
clauses: [{ order: 1, uuid: "345"},{ order: 2, uuid: "567"},{order: 3, uuid: "777"},{ order: 4, uuid: "789"}]
}
The reason is that order of "789" clause is 4 which is more than 2 bigger than "345" clause, which has order 1.
Any help is appreciated!
Thanks,
Michail

Answer 1

One way to achieve this involves using a script filter.
The script I'm using is the following:
def idxs = [];
for (int i = 0; i < doc['clauses.uuid'].values.size(); i++) {
if (matches.contains(doc['clauses.uuid'].values[i])){
idxs << i
}
};
def orders = idxs.collect{ doc['clauses.order'].values[it]};
return orders[1] - orders[0] <= 2
Basically, what I'm doing is first collection all indices of the clauses which contain a uuid in the matches array (i.e. 345 and 789).
Then, with the indices I got I gather all order values at those indices. And finally, I check that the second order minus the first order is not bigger than 2.
POST your_index/_search
{
"query": {
"bool": {
"filter": [
{
"term": {
"clauses.uuid": "345"
}
},
{
"term": {
"clauses.uuid": "789"
}
},
{
"script": {
"script": "def idxs = []; for (int i = 0; i < doc['clauses.uuid'].values.size(); i++) {if (matches.contains(doc['clauses.uuid'].values[i])){idxs << i}}; def orders = idxs.collect{doc['clauses.order'].values[it]}; return orders[1] - orders[0] <= 2",
"params": {
"matches": [
"345",
"789"
]
}
}
}
]
}
}
}
That will return only the first document and not the second.