Bash script echos but won't execute - bash

Question

I'm creating a simple bash script to remove all Bluetooth devices from my system. What it does is use bt-device -l to list the bluetooth devices, then grabs the MAC address in between the parens, then calls bt-device -r <MACAddress> to remove the device. I'm not that great at bash scripts but when I replace the bt-device call with echo, I get the correct output. When I put the command back in it says the device wasn't found. If I manually make the call it works (outputs "Done").
Sample output of the bt-device -l command:
Added Devices:
Samico BP (12:34:56:78:9a:bc)
SensorTag 2.0 (12:34:56:78:9a:bd)
And the script I'm using:
#!/usr/bin/env bash
bt-device -l | sed 1d |
while read x; do
bt-device -r $x | cut -d "(" -f2 | cut -d ")" -f1
done
When I run it, it runs the bt-device -r command but the output is Error: Device not found as if I'd typed the MAC address wrong. If I replace the bt-device call in the script with echo, I get the list of MAC addresses as expected.
Updated script working
#!/usr/bin/env bash
bt-device -l | sed 1d |
while read x; do
bt-device -r $(echo $x | cut -d "(" -f2 | cut -d ")" -f1)
done

Answer 1

The problem is that you're running cut -d "(" -f2 | cut -d ")" -f1 on the output of bt-device -r, instead of on its argument.
Instead, you should write something like this:
bt-device -l | sed 1d | cut -d "(" -f2 | cut -d ")" -f1 |
while read x; do
bt-device -r $x
done

Answer 2

You'd want to process $x prior to using it:
bt-device -l | sed 1d |
while read x; do
dev=$( echo "$x" | cut -d "(" -f2 | cut -d ")" -f1 )
bt-device -r "$dev"
done