How to check if the user entered the valid character in LC3 "Assembly Language"? For example, I want the entered characters between 0 through 9, or letters from A through F? Like if the user entered any other characters it will not be printed in the console.
Take a look at the ASCII table: http://www.asciitable.com
Once you get an input character from the console, check its value to see if it is in the range you're looking for. In other words, if you're checking for '0'-'9', you can check for a value between 0x30 and 0x39.
Related
In the past, we've used ZPL to create Code39 barcodes with a TAB character encoded in the middle using something similar to the following:
*USERNAME$IPASSWORD*
The $I in the middle gets translated to a TAB by the barcode scanners we use.
Now we have a need to do the same thing, but using Code128. With Code39, all the text needs to be uppercase (unless you're using Code39Extended, which supports lowercase letters). Because some of the data that is going to be encoded will be lowercase, we need to use Code128 B for most of the barcode, switching to Code128 A in the middle to encode the TAB character, then back to Code128 B for the final part.
Looking through the "ZPL II Programming Guide", it should be as easy as:
>:username>7{TAB}>6PA55w0rd
The >: at the beginning sets the subset to B, the >7 changes the subset to A, and the >6 changes the subset back to B. The problem I'm having (and haven't found a solution after almost a week of searching) is: How do I encode a TAB character using only text?
Use the ^FH (field hexidecimal encoding) command immediately prior to your field data. Based on your example:
^FH_^FD>:username>7_09>6PA55w0rd^FS
Where the underscore '_' is used as the escape character and 09 is the hex value for tab.
Also note that if the chosen escape character appears in the user name or password, you will need to escape it as well.
I tried what Mark Warren suggested, but unfortunately, it didn't work. It did, however, get me looking back through the ZPL II Programming Guide and I found the following, which I had overlooked before:
Code 128, Subsets A and C are programmed in pairs of digits, 00 to 99, in the field data string.
...
In Subset A, each pair of digits results in a single character being encoded in the bar code...
So, since 73 equates to a TAB in Subset A, I tried the following:
>:username>773>6PA55w0rd
And it worked!
Im trying to work out how to put an input mask on initials which will allow for initials that are two/three letters on.
I have tried entering >L?L< but this only allows three letter initials to be entered and not two letter initials.
Is there another symbol I should be using other than '?' that means that the user does not have to enter a character in that place?
I would suggest >LL?
> forces everything to uppercase
L is a required character
? is an optional character
I have created an ach file which, in a text editor looks exactly like a valid ach file. When I open it in an ACH viewer tool I get an error saying that the first character must be 1. I found this in the NACHA file specs 'Picture: This is the type of bit the ACH system is expecting to see. A 9 indicates a numeric value and an X indicates an
alphabetic value. If you put a letter in a PIC 9 position, the system will reject the field. If you see a number in parentheses
after the X or 9, that indicates the number of characters in that field. For example 9(10) means that field contains 10
numeric characters.'
The first position in the file is supposed to have content 1 in Picture format of size 1. I don't understand what do I need to do to fix this?
I finally downloaded a Hex file explorer and saw that the valid ACH file and my file both had different first characters. I found out that the ACH file needs the data in the ASCII format. All I had to do was when I populated the ACH file with data, I converted the data to ASCII before writing it.
I am writing some behavioural tests for code that interacts with a terminal and I need to assert behaviour on the sequence C-p C-q (ctrl-p ctrl-q). In order to do this, I need to write the raw characters to the PTY. I have a small mapping at the moment for things like C-d => 0x04, C-h => 0x08.
Is there somewhere I can get a basic mapping of human readable control sequences, mapped to raw byte sequences for xterm?
Take the ASCII value of the character (e.g., for ^H, take 72), and subtract 64. Thus, ^H is 8.
This works for any control character. Using it, you can discover that, for example, ^# is the NUL character and ^[ is ESC.
I am trying to print a Code 128 barcode on a label using the following the piece of ZPL with a Zebra ZP 450 printer:
^BY3^BCN,112,N^FO090,660^FD>;>89102100^FS
I'm expecting the barcode to scan as "9102100". However, when I scan the printed barcode, it reads as "910210" -- cutting off the final digit.
If I change the last digit, it is still cut off. But if I add more digits onto the end, e.g. "9102100357", the barcode correctly reads as "9102100357".
Why am I "losing" a digit in this particular case?
The >; inside of your ^FD block is telling the code 128 barcode to go into a subset (subset C in this case) which forces the data in the barcode to be numeric pairs (00 - 99). Any data that is not supplied in numeric pairs is ignored. If you put a letter in there, it will ignore that pair. In your case 9102100 has an odd number of numbers, so it ignores the last one. If for example, you add another 0, it will put all the letters in the barcode.
The ;> which puts the barcode in Subset C is not the default. Subset B or :> is the default which will allow any character to be encoded in the barcode. So you can replace the ;> with :>, or just remove the ;> entirely, and it will print out properly.
Check out the ^BC documentation in the ZPL programming manual for more information about Code 128 subsets and data validation
See pg 92 of the ZPL Programming Guide.
This issue may have been fixed in the firmware update, see below:
Example: This is an example with the mode parameter set to D*:
^XA
^PON
^LH0,0
^BY2,2.5,145
^FO218,343
^BCB,,Y,N,N,D
^FD(91)0005886>8(10)0000410549>8(99)05^FS
^XZ
D* — When trying to print the last Application Identifier with an odd number of characters, a problem
existed when printing EAN128 bar codes using Mode D. The problem was fixed in firmware version
V60.13.0.6."