I want to get 7 latest rows (in order from down to up), for the current week (Sunday to Saturday), for the current logged in user.
To do this, I used this one method:
Carbon::setWeekStartsAt(Carbon::SUNDAY);
Carbon::setWeekEndsAt(Carbon::SATURDAY);
$strikes = UserStrike::where('user_id', $user)->whereBetween('created_at', [Carbon::now()->startOfWeek(), Carbon::now()->endOfWeek()])->latest()->take(7)->get();
$strikes = $strikes->reverse(); //to order the list from DESC to ASC
But the problem with this method is that it doesn't get any missing days.
So if there are data like this for the current week (2020-05-12 is missing):
created_at: 2020-05-10
created_at: 2020-05-11
created_at: 2020-05-13
Then for that one day which is missing, there should be a null in array. Something like this:
$days = ["Sun", "Mon", null, "Wed"];
I'm having hard time to find a way to replace missing day with a null in array.
If anyone here can help me with this problem please leave your comment. Thank you in advance.
You can take data from DB and then create array by iterating on DateTimeInterval(). I don't know Laravel and Carbon well but it could be something like this:
Carbon::setWeekStartsAt(Carbon::SUNDAY);
Carbon::setWeekEndsAt(Carbon::SATURDAY);
$start = Carbon::now()->startOfWeek();
$end = Carbon::now()->endOfWeek();
$strikes = UserStrike::where('user_id', $user)
->whereBetween(
'created_at',
[$start, $end]
)
->latest()
->take(7)
->get();
$strikes = $strikes->reverse();
$timePeriod = new DatePeriod(
$start,
new DateInterval('P1D'),
$end
);
$days = [];
for ($i = 0; $i < count($timePeriod) $i++) {
$days[$i] = null;
foreach ($strikes as $strike) {
if ($strike->created_at->format('Y-m-d') == $timePeriod[$i]->format('Y-m-d') {
$days[$i] = $strike->created_at->format('Y-m-d');
break;
}
}
}
UseCase: Admin assigns tasks to People. Before we assign them we can see their tasks in a gantt chart. According to the task assign date and deadline, conflict days (overlap days) are generated between tasks.
I wrote this function to get overlapping dates between two dates. But now I need to get non overlapping days between two dates, below is the function I wrote.
$tasks = Assign_review_tasks::where('assigned_to', $employee)
->where('is_active', \Constants::$REVIEW_ACTIVE)
->whereNotNull('permit_id')->get();
$obj['task'] = count($tasks);
// count($tasks));
if (count($tasks) > 0) {
if (count($tasks) > 1) {
$start_one = $tasks[count($tasks) - 1]->start_date;
$end_one = $tasks[count($tasks) - 1]->end_date;
$end_two = $tasks[count($tasks) - 2]->end_date;
$start_two = $tasks[count($tasks) - 2]->start_date;
if ($start_one <= $end_two && $end_one >= $start_two) { //If the dates overlap
$obj['day'] = Carbon::parse(min($end_one, $end_two))->diff(Carbon::parse(max($start_two, $start_one)))->days + 1; //return how many days overlap
} else {
$obj['day'] = 0;
}
// $arr[] = $obj;
} else {
$obj['day'] = 0;
}
} else {
$obj['day'] = 0;
}
$arr[] = $obj;
start_date and end_date are taken from database,
I tried modifying it to,
(Carbon::parse((min($end_one, $end_two))->add(Carbon::parse(max($start_two, $start_one))))->days)->diff(Carbon::parse(min($end_one, $end_two))->diff(Carbon::parse(max($start_two, $start_one)))->days + 1);
But it didn't work, in simple terms this is what I want,
Non conflicting days = (end1-start1 + end2-start2)- Current overlapping days
I'm having trouble translate this expression . Could you help me? Thanks in advance
before trying to reimplement complex stuff I recommend you take a look at enhanced-period for Carbon
composer require cmixin/enhanced-period
CarbonPeriod::diff macro method is what I think you're looking for:
use Carbon\CarbonPeriod;
use Cmixin\EnhancedPeriod;
CarbonPeriod::mixin(EnhancedPeriod::class);
$a = CarbonPeriod::create('2018-01-01', '2018-01-31');
$b = CarbonPeriod::create('2018-02-10', '2018-02-20');
$c = CarbonPeriod::create('2018-02-11', '2018-03-31');
$current = CarbonPeriod::create('2018-01-20', '2018-03-15');
foreach ($current->diff($a, $b, $c) as $period) {
foreach ($period as $day) {
echo $day . "\n";
}
}
This will output all the days that are in $current but not in any of the other periods. (E.g. non-conflicting days)
I need to find the first working day of the month. Ideally it should be 01/MM/YYYY but the condition is that it should not be a Saturday or Sunday or a day from the List of Holidays.
List being:
ListOfHoliday
Name Day
Someday 01/01/2021
Someday 01/02/2021
Someday 31/03/2021
Someday 04/07/2021
Someday 25/12/2021
I was trying to use the below algo:
FWD = Text.concat(01, DateTime.CurrentMonthOfToday, DateTime.CurrentyearOfToday)
foreach(holiday in ListOfHoliday)
{
if (FWD == holiday)
{
DateTime.AddDays(ConvertTo.DateTime(FWD), 1)
if (ConvertTo.DateTime(FWD).DayOftheWeek == Saturday)
{
FWD=ConvertTo.Text(DateTime.AddDays(ConvertTo.DateTime(FWD), 2));
} else
{
if ((ConvertTo.DateTime(FWD).DayOftheWeek == Sunday))
{
FWD=ConvertTo.Text(DateTime.AddDays(ConvertTo.DateTime(FWD), 2));
}
}
}
}
But the result I get for the current month is 01/01/0001.
Here is the python code to find the first working day of a given month.
from datetime import datetime, timedelta
def working_day(temp,holid):
if temp.strftime('%A') == 'Saturday':
temp += timedelta(2)
return working_day(temp,holid)
elif temp.strftime('%A') == 'Sunday' or temp in holid:
temp += timedelta(1)
return working_day(temp,holid)
else:
return temp.strftime('%A')
date_format = "%d/%m/%Y"
holidays = ['01/01/2021','01/02/2021','31/03/2021','04/07/2021','25/12/2021']
holid = []
for day in holidays:
holid.append(datetime.strptime(day, date_format))
month = int(input('Enter the month')) # input should be 1,2,3....12
today ='01/'+str(month)+'/2021'
today = datetime.strptime(today, date_format)
print(working_day(today, holid))
output:
Enter the month 12
Wednesday
I use this part of the code (and also time trigger) to run script every 5 minutes on "working hours" but now I need some adjustments
function officeHours(){
var nowH=new Date().getHours();
var nowD=new Date().getDay();
Logger.log('day : '+nowD+' Hours : '+nowH)
if(nowH>17||nowH<8||nowD==6||nowD==0){return}
Browser.msgBox('time to work !');//normally your real function should begin here...
}
Reference: Working hours only trigger
But how be more specific? e.g. set working hours from 8:30 to 17:30 or another e.g. when shift (working hours) starts at one day and ends next day (from 22:30 at day one to 06:30 at next day)?
You can check if the current hour is between the shift hours as in this example.
function officeHours(startShift, endShift){
startShift = startShift || 23;
endShift = endShift || 7;
var currentHour = new Date().getHours();
if (startShift > endShift) {
if (currentHour >= startShift || currentHour <= endShift) {
// run the trigger function
}
} else {
if (currentHour >= startShift && currentHour <= endShift) {
// run the trigger function
}
}
}
I would like to display a time format like twitter and FB (Posted 3 hours ago, Posted 2 minutes ago and so on...)
I've tried this piece of code without success :
function format_interval($timestamp, $granularity = 2) {
$units = array('1 year|#count years' => 31536000, '1 week|#count weeks' => 604800, '1 day|#count days' => 86400, '1 hour|#count hours' => 3600, '1 min|#count min' => 60, '1 sec|#count sec' => 1);
$output = '';
foreach ($units as $key => $value) {
$key = explode('|', $key);
if ($timestamp >= $value) {
$floor = floor($timestamp / $value);
$output .= ($output ? ' ' : '') . ($floor == 1 ? $key[0] : str_replace('#count', $floor, $key[1]));
$timestamp %= $value;
$granularity--;
}
if ($granularity == 0) {
break;
}
}
I use this function with a callback into another function like : $this->format_interval(); and pass it to my View
My current format date is : 2012-07-26 09:31:pm and already stored in my DB
Any help will be very appreciated!
The Date Helper's timespan() method just does that:
The most common purpose for this function is to show how much time has elapsed from some point in time in the past to now.
Given a timestamp, it will show how much time has elapsed in this format:
1 Year, 10 Months, 2 Weeks, 5 Days, 10 Hours, 16 Minutes
So, in your example, all you need to do is convert your date to a timestamp and do something like this:
$post_date = '13436714242';
$now = time();
// will echo "2 hours ago" (at the time of this post)
echo timespan($post_date, $now) . ' ago';
Try something like this in a my_date_helper.php file (source: Codeigniter Forums):
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
if( ! function_exists('relative_time'))
{
function relative_time($datetime)
{
$CI =& get_instance();
$CI->lang->load('date');
if(!is_numeric($datetime))
{
$val = explode(" ",$datetime);
$date = explode("-",$val[0]);
$time = explode(":",$val[1]);
$datetime = mktime($time[0],$time[1],$time[2],$date[1],$date[2],$date[0]);
}
$difference = time() - $datetime;
$periods = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
$lengths = array("60","60","24","7","4.35","12","10");
if ($difference > 0)
{
$ending = $CI->lang->line('date_ago');
}
else
{
$difference = -$difference;
$ending = $CI->lang->line('date_to_go');
}
for($j = 0; $difference >= $lengths[$j]; $j++)
{
$difference /= $lengths[$j];
}
$difference = round($difference);
if($difference != 1)
{
$period = strtolower($CI->lang->line('date_'.$periods[$j].'s'));
} else {
$period = strtolower($CI->lang->line('date_'.$periods[$j]));
}
return "$difference $period $ending";
}
}
The format is a little different than the one you're using in your database (why do you mark times with pm/am rather than just use 24 hour times and convert for the frontend?). Either way, shouldn't take much work to get it working.
I had a function that solved this like this:
$int_diff = (time() - $int_time);
$str_this_year = date('Y-01-01', $int_time);
$str_weekday = t('time_weekday_'.strtolower(date('l', $int_time)));
$str_month = t('time_month_'.strtolower(date('F', $int_time)));
$arr_time_formats = array( '-90 seconds' => t('time_a_minute_at_most'),
'-45 minutes' => t('time_minutes_ago', ceil($int_diff / (60))),
'-70 minutes' => t('time_an_hour_at_most'),
'-8 hours' => t('time_hours_ago', ceil($int_diff / (60 * 60))),
'today' => t('time_hours_ago', ceil($int_diff / (60 * 60))),
'yesterday' => t('time_yesterday', date('H:i', $int_time)),
'-4 days' => t('time_week_ago', $str_weekday, date('H:i', $int_time)),
$str_this_year => t('time_date', date('j', $int_time), $str_month, date('H:i', $int_time)),
0 => t('time_date_year', date('j', $int_time), $str_month, date('Y', $int_time), date('H:i', $int_time)));
if ($boo_whole)
return $arr_time_formats[0];
foreach(array_keys($arr_time_formats) as $h)
if ($int_time >= strtotime($h))
return $arr_time_formats[$h];
Basicly t() is a function combined with $this->lang->line() and sprintf(). The idea here is to give keys that's runned through strtotime() till you reach the closest time, with 0 being the fallback.
This approach is really good since you can easy adjust the times with a nice overview. I could give more piece of the code, but it feels like doing too much of the work :) Basicly this is just the theory behind how you can do it.
<?php
$this->load->helper('date');
//client created date get from database
$date=$client_list->created_date;
// Declare timestamps
$last = new DateTime($date);
$now = new DateTime( date( 'Y-m-d h:i:s', time() )) ;
// Find difference
$interval = $last->diff($now);
// Store in variable to be used for calculation etc
$years = (int)$interval->format('%Y');
$months = (int)$interval->format('%m');
$days = (int)$interval->format('%d');
$hours = (int)$interval->format('%H');
$minutes = (int)$interval->format('%i');
// $now = date('Y-m-d H:i:s');
if($years > 0)
{
echo $years.' Years '.$months.' Months '.$days.' Days '. $hours.' Hours '.$minutes.' minutes ago.' ;
}
else if($months > 0)
{
echo $months.' Months '.$days.' Days '. $hours.' Hours '.$minutes.' minutes ago.' ;
}
else if($days > 0)
{
echo $days.' Days '.$hours.' Hours '.$minutes.' minutes ago.' ;
}
else if($hours > 0)
{
echo $hours.' Hours '.$minutes.' minutes ago.' ;
}
else
{
echo $minutes.' minutes ago.' ;
}
?>