How to write email regular expression in Jmeter?
JMeter site has explanation on the syntax of regex, and JMeter has a RegEx tester. You can validate email in many ways. The most basic validation is this:
[A-Za-z0-9._%+-]+#[A-Za-z0-9.-]+\.[A-Za-z]{2,}
(it will check that # is present, the characters before and after # are limited to allowed characters, and domain extension is at least 2 characters long).
This expression catches most common emails, although it would fail for more advanced (but still valid) emails (e.g. emails with IPs, international domains, and so on)
I solved this problem by using the Regular expression extractor and beanshell post processor.
BeanShell sampler Code:-
emailAd = vars.get("email");
emailAddr = vars.get("EmailAddress");
//log.info(email); // if you want to log something to jmeter.log file
if(!emailAd.equals("0")) {
// Pass true if you want to append to existing file
// If you want to overwrite, then don't pass the second argument
f = new FileOutputStream("C:/Users/Errors.tsv", true);
p = new PrintStream(f);
this.interpreter.setOut(p);
print(emailAddr +"\t"+ emailAd );
f.close();}
Just use "(.+?)", it will work . Below is the example
<input type="email" value="madhu#gmail.com">
to extract email value just use regular expression as value="(.+?)"
Related
this works, but how can I ignore the quotation marks in the form of my token "token"
i don't want him to get the quotation marks
I would use Boundary Extractor
Put Left and Right Boundary as " and you will get the value
Allows the user to extract values from a server response using left and right boundaries. As a post-processor, this element will execute after each Sample request in its scope, testing the boundaries, extracting the requested values, generate the template string, and store the result into the given variable name
You need to provide the Template and specify the capturing group (in your case it will be 1)
More information:
JMeter: Regular Expressions
Using RegEx (Regular Expression Extractor) with JMeter
working in this way. maybe you will need it!
How to pass jmeter response data (ex: getting response 295 without any lable) to next http request url path/body. This 3 digits/4 digits number is dynamically generated for every run and this value i have to use it for next API calls. Since this value is not having any lable/attribute name not sure how to extract this value. Please suggest.
Regular Expression Configuration:
Reference Name: anything
Regular Expression: (.+)
Template: $1$
Match No.(O for Random): 1
The Reference name should be passed as the variable in the next HTTP request URL path/body.
Screenshot from Regex Test in View Results Tree.
If you need to extract a single numeric value, the relevant regular expression will be as simple as (\d+). See Perl 5 Regex Cheat sheet for quick reference.
If in future you will need a regular expression which return the whole response (including line breaks, special characters, whatever), as per How to Extract Data From Files With JMeter article it will be something like (?s)(^.*)
The Response data look like following within Script tag
var csrfParam =
"SKtEMgZtO0H8EYHkAZIQ4tcS5bC8jKrD=y2G5Of06jgHbkNdHNleFKiXoBMC62veD";
var securityTokenName = "SKtEMgZtO0H8EYHkAZIQ4tcS5bC8jKrD";
var securityTokenValue = "y2G5Of06jgHbkNdHNleFKiXoBMC62veD";
I'm using regular expression extractor as following:
Reference name : MYREF
Regular Expression : securityTokenName ="(.+?)" securityTokenValue="(.+?)"
Template : $1$$2$
I'm access this variable in next Jmeter request to build the URL:
${MYREF_g1}
${MYREF_g2}
Expecting to get MYREF_g1 =SKtEMgZtO0H8EYHkAZIQ4tcS5bC8jKrD
and MYREF_g2 =y2G5Of06jgHbkNdHNleFKiXoBMC62veD
But THIS is not working .
Any help would appreciated!
It looks like that you're misunderstanding what groups and templates are.
As per Using RegEx (Regular Expression Extractor) with JMeter
Template. The template used to create a string from the matches found.
This is an arbitrary string with special elements to refer to groups
within the regular expression. The syntax to refer to a group is:
'$1$' to refer to group 1, '$2$' to refer to group 2, etc. $0$ refers
to whatever the entire expression matches. So, if you have in response
word “economics” and search for regular expression “(ec)(onomics)” and
apply template $2$$1$ than in output variable you will receive
“onomicsec”.
So your RegEx should look like:
var securityTokenName = "(.+?)"; var securityTokenValue = "(.+?)";
So
securityTokenName will be stored in JMeter Variable MYREF_g1
securityTokenValue will be stored in JMeter Variable MYREF_g2
View Results Tree Listener has built-in RegExp Tester on ResponseData tab. You can also use Debug Sampler to see what variables have been set by your Regular Expression Extractor.
You need multiline regex match. Your regex will look like this
(?s)securityTokenName="(.+?)".*?securityTokenValue="(.+?)";
A sample test plan (it uses dummy sampler from jmeter plugins, if you don't have them it will faile) is here.
This post here discusses that simply having .*? will match multiple line, but apparently it did not work. This post wast the savior.
Details are from the jmeter documentation are here.
Please note that I have removed the spaces around = to simplify my sample. Please change the regex appropriately.
I'm trying to create a script that will take a URL out of a response and send it out again.
Using the regular expression extractor I've succeeded in taking the wanted URL, but it holds "&" so naturally when sending it out the request fails.
Example:
GET http://[ia-test01.inner-active.mobi:8080/simpleM2M/ClientUpdateStatus?cn=WS2006&v=2_1_0-iOS-2_0_3_7&ci=99999&s=3852719769860497476&cip=113-170-93-111&po=642&re=1<=0&cc=VN&acp=&pcp=]/
I'm trying to replace the "&" with a "&".
I've tried: ${__javaScript(${url}.replace("&","&"))}
But it did not work. I've tried the regex function as well- the same.
I'm not sure the IP field in the request supports the us e of functions.
I'm currently trying to use the beanshell post-processor. But I'm pretty sure there is a simpler solution I'm missing.
Not sure what you're trying to get by replacing & with & however will try to respond.
First of all: given multiple & instances you need to use replaceall function, not replace
Second: replace / replaceall functions take a RegEx as parameter, so you'll need to escape your &
If you're trying to substitute URL Path in realtime, you'll need Beanshell Pre Processor, not the Post Processor
Sample Beanshell Pre-Processor code
import java.net.URL;
URL myURL = sampler.getUrl();
String path = myURL.getPath();
String path_replaced = path.replaceAll("\\&", "&");
vars.put("NEW_PATH", path_replaced);
After that put ${NEW_PATH} to "Path:" section of your HTTP Request.
Hope this helps.
Solution with less code:
Install the Custom JMeter Functions plugin
Use the following syntax
${__strReplace(ImAGoodBoy,Good,Bad,replaceVar)}
‘ImAGoodBoy’ is a string in which replacement will take place
‘Good’ is a substring to be replaced
‘Bad’ is the replacement string
‘replaceVar’ is a variable to save result string
Refer this URL for more info!
Thank a lot. However, i see from a recent experience that to replace a character that is actually a RegExp special character, like \ " ( ) etc, you need to put 3 backslashes and not 1, not 2. This is weird.
so you write
var res = str.replaceAll("\\\\u003c", "<");
to replace \u003c with <
I have this regular expression:
name=\"javax.faces.FormSignature\" value="(.+?)"
that will extract the value I need to pass to a http request. My problem is, if this value happens to have a + or a = sign on it, Jmeter will replace them with a whitespace. That will fail my request.
Has anyone seen this before? I've tried with xpath extractor and the same thing happens.
If this shappens in next request that uses the RegExp extracted value then uncheck Encode checkbox in Parameters Table.
See Send Parameters With the Request: