My main.go file cannot see other files - go

I need some help understanding what is wrong with my file layout in a simple web application.
$GOPATH/src/example.com/myweb
I then have 2 files:
$GOPATH/src/example.com/myweb/main.go
$GOPATH/src/example.com/myweb/api.go
Both files have:
package main
The api.go file looks like:
package main
import (
"bytes"
"encoding/json"
"fmt"
"io"
"net/http"
"time"
)
type API struct {
URI string
Token string
Secret string
client *http.Client
}
...
My main.go file looks like:
package main
import (
"github.com/gorilla/mux"
"html/template"
"net/http"
)
var (
templates = template.Must(template.ParseFiles("views/home.html", "views/history.html", "views/incident.html"))
api = API{
URI: "http://localhost:3000",
Token: "abc",
Secret: "123",
}
)
func renderTemplate(w http.ResponseWriter, tmpl string, hp *HomePage) {
..
..
}
func WelcomeHandler(w http.ResponseWriter, r *http.Request) {
..
..
}
func main() {
r := mux.NewRouter()
r.HandleFunc("/", WelcomeHandler)
r.PathPrefix("/assets/").Handler(
http.StripPrefix("/assets/", http.FileServer(http.Dir("assets/"))))
http.ListenAndServe(":9000", r)
}
In the code I excluded, I basically use structs that are defined in my api.go file, and I get this error when doing:
go run main.go
# command-line-arguments
./main.go:16: undefined: API
./main.go:23: undefined: User
What exactly am I doing wrong here?
I tried changing the package name in api.go to myweb but that didn't help.
Am I suppose to use the package name myweb? Is just 1 file suppose to have main?

You're compiling only the main.go file. You should use:
go run main.go api.go
Or:
go run *.go
If you're writing a complex application, you might add everything to packages in subdirectories and have a single main.go file. For instance, etcd has an etcdmain subdirectory/package along with other subdirectories/packages. Something like:
/alarm
/auth
/cmd
/etcdmain
...
And the main.go file is simply:
package main
import "github.com/coreos/etcd/etcdmain"
func main() {
etcdmain.Main()
}

You are using golang workspace project, which is good for the structure for your application and it also standardize.
When we use the golang workspace, you can not run single go file. You need to call go build / go install.
Install
go install example.com/myweb
The command above will compile your main package on example.com/myweb. And the myweb executable binary will be placed on the GOPATH/bin. And you can run it manually.
Build
go build example.com/myweb
The command is similar to go install but the binary executable file will be placed on the current directory when you call the command, instead of on GOPATH/bin (unless your current directory is GOPATH/bin).
For more information please check this link.

Related

Go: import package from the same module in the same local directory

I want to create new package mycompany that will be published on Github at github.com/mycompany/mycompany-go (something similar to stripe-go or chargebee-go for example).
So I have created a folder ~/Desktop/mycompany-go on my MacOS. Then inside that folder I run go mod init github.com/mycompany/mycompany-go.
I have only these files in that local folder:
// go.mod
module github.com/mycompany/mycompany-go
go 1.19
// something.go
package mycompany
type Something struct {
Title string
}
// main.go
package main
import (
"github.com/mycompany/mycompany-go/mycompany"
)
func main() {
s := mycompany.Something {
Title: "Example",
}
}
However I get this error:
$ go run main.go
main.go:4:3: no required module provides package github.com/mycompany/mycompany-go/mycompany; to add it:
go get github.com/mycompany/mycompany-go/mycompany
I think that this is a wrong suggestion, because I need to use the local version, in the local folder, not get a remote version.
Basically I need to import a local package, from the same folder, from the same module.
What should I do? What's wrong with the above code?
You can't mix multiple packages in the same folder.
If you create a folder mycompany and put something.go inside it, that should fix the problem
The Go tool assumes one package per directory. Declare the package as main in something.go.
-- main.go --
package main
import "fmt"
func main() {
s := Something{
Title: "Example",
}
fmt.Println(s)
}
-- go.mod --
module github.com/mycompany/mycompany-go
go 1.19
-- something.go --
package main
type Something struct {
Title string
}
Runnable example: https://go.dev/play/p/kGBd5etzemK

Structuring local imports without GitHub in Golang

I'm building a simple app and after reading the doc on structuring go applications, I'm still confused.
I want this structure:
practice
models (packaged as models)
a
b
routers (packaged as routers)
a
b
app.go
Inside of app.go, I have the following:
package main
import (
"net/http"
// I have tried the following:
"practice/models/a"
"practice/models/b"
"practice/models"
"$GOPATH/practice/models/a"
"$GOPATH/practice/models/b"
"$GOPATH/practice/models"
...
)
func main() {
http.HandleFunc("/a", AHandler)
http.HandleFunc("/b", BHandler)
http.ListenAndServe(":8080", nil)
}
The A and B models look like this:
package models
import "net/http"
func AHandler(w http.ResponseWriter, r *http.Request) {
// code
}
Two questions:
What in the world is the right way to import these files? Do I really have to push them to github in order to be able to reference them? I understand the $GOPATH is the namespace for the entire go workspace on a local machine. My $GOPATH is set to include this directory.
Do I need to define a main method inside of these files? Can I just export a single function and have that be the handling function?
I have consulted the docs
See How to Write Go Code.
Use this directory structure:
- practice
- go.mod
- app.go
- models
- a.go
- b.go
- routers
- a.go
- b.go
where go.mod is created with the command go mod init practice where practice is the module path.
Import the packages as follows:
import (
"practice/routers"
"practice/models"
...
)
Use the imported packages like this:
func main() {
http.HandleFunc("/a", models.AHandler)
http.HandleFunc("/b", models.BHandler)
http.ListenAndServe(":8080", nil)
}
You do not need to push to github.com, even if you use github.com in the module path.
The main function in the main package is the entry point for the application. Do not define main functions in packages other than main.
What follows is the original answer based on GOPATH workspaces:
See How to Write Go Code.
Create your directory structure under $GOPATH/src.
$GOPATH
src
practice
models
routers
Import the packages as follows:
import (
"practice/routers"
"practice/models"
...
)
Use the imported packages like this:
func main() {
http.HandleFunc("/a", models.AHandler)
http.HandleFunc("/b", models.BHandler)
http.ListenAndServe(":8080", nil)
}
You do not need to push to github.com, even if you use 'github.com' in the file path.
The main function in the main package is the entry point for the application. Do not define main functions in packages other than main.
I think the other answer is out of date, you don't need to use GOPATH anymore.
Run:
go mod init yellow
Then create a file yellow.go:
package yellow
func Mix(s string) string {
return s + "Yellow"
}
Then create a file orange/orange.go:
package main
import "yellow"
func main() {
s := yellow.Mix("Red")
println(s)
}
Then build:
go build
https://golang.org/doc/code.html

is it possible to place test files in subfolder

When I have module and its test in the same directory it works ok.
- module1.go
- module1_test.go
But when number of files and test files grows it is hard to navigate through code.
Is it possible to place go tests to subfolder for cleaner code structure?
When I try to do it I got namespace error.
I placed file module1_test.go to folder ./test
- module1.go
- test/module1_test.go
Now I got error on testing:
test/module1_test.go:8: undefined: someFunc
My module1.go code:
package package1
func someFunc() {
}
My module1_test.go code:
package package1
import (
"testing"
)
func TestsomeFunc(t *testing.T) {
someFunc()
}
You can put the tests in another directory, but it is not common practice. Your tests will need to import the subject package and will not have access unexported methods in the subject package. This will work:
File $GOPATH/src/somepath/package1/module1.go
package package1
func SomeFunc() {
}
File $GOPATH/src/somepath/package1/test/module1_test.go
package test
import (
"testing"
"somepath/package1"
)
func TestSomeFunc(t *testing.T) {
package1.SomeFunc()
}
A couple of notes:
I changed SomeFunc to an exported method so that the test can access it.
The test imports the subject package "somepath/package1"

Error in importing custom packages in Go Lang

I have created a library by the name libfastget which is in the src with my program as
src
|-libfastget
| |-libfastget.go
|
|-MainProgram
|-main.go
and the libfastget exports a funtion fastget as follows
package libfastget
import (
"fmt"
"io"
)
func fastget(urlPtr *string, nPtr *int, outFilePtr *string) download {
.....
return dl
}
When I use the library in my main program
package main
import (
"fmt"
"net/http"
"os"
"libfastget"
"path/filepath"
"strings"
"flag"
"time"
)
func uploadFunc(w http.ResponseWriter, r *http.Request) {
n:=libfastget.fastget(url,4,filename)
}
}
I get the following error upon trying to build with go build
# FServe
./main.go:94: cannot refer to unexported name libfastget.fastget
./main.go:94: undefined: libfastget.fastget
The strange thing is that the library file libfastget.a is present in the pkg folder.
you would need to make your function exportable with an uppercase for its name:
func Fastget(...
Used as:
n:=libfastget.Fastget(url,4,filename)
The spec mentions: "Exported identifiers":
An identifier may be exported to permit access to it from another package. An identifier is exported if both:
the first character of the identifier's name is a Unicode upper case letter (Unicode class "Lu"); and
the identifier is declared in the package block or it is a field name or method name.
All other identifiers are not exported.
to export a function into another package the function identifier must start with a capital letter.
I recently started learning GO Lang (2 days back)
And what I found was you need to setup a workspace folder to make the local packages import into other projects or main.go files. I'm using VS Code editor. Please correct me if Im wrong, but this setup works fine for me.
Inside your bash_profile OR .zshrc file add below lines, update the GOPATH as per your folder path.
export GOPATH=~/projects/GO_PROJECTS
export PATH=$PATH:$GOPATH/bin:$PATH
and this is my sayHello.go file, please note to be able to export a function the func name should start with a CapitalCase SayHello
package utils
import "fmt"
func SayHello() {
fmt.Println("Hello, Ajinkya")
}
and now I am able to import utils package into main.go file
package main
import (
"go_proj1/utils"
)
func main() {
utils.SayHello()
}
set the current directory as GOPATH
or you can use local import as follows
move your main.go to the ../ directory to the libfastget.go.
i mean the files looks like:
src
|-libfastget
| |-libfastget.go
|
|-main.go
import "./libfastget"

How to call function from another file in Go

I want to call function from another file in Go. Can any one help?
test1.go
package main
func main() {
demo()
}
test2.go
package main
import "fmt"
func main() {
}
func demo() {
fmt.Println("HI")
}
How to call demo in test2 from test1?
You can't have more than one main in your package.
More generally, you can't have more than one function with a given name in a package.
Remove the main in test2.go and compile the application. The demo function will be visible from test1.go.
Go Lang by default builds/runs only the mentioned file. To Link all files you need to specify the name of all files while running.
Run either of below two commands:
$go run test1.go test2.go. //order of file doesn't matter
$go run *.go
You should do similar thing, if you want to build them.
I was looking for the same thing. To answer your question "How to call demo in test2 from test1?", here is the way I did it. Run this code with go run test1.go command. Change the current_folder to folder where test1.go is.
test1.go
package main
import (
L "./lib"
)
func main() {
L.Demo()
}
lib\test2.go
Put test2.go file in subfolder lib
package lib
import "fmt"
// This func must be Exported, Capitalized, and comment added.
func Demo() {
fmt.Println("HI")
}
A functional, objective, simple quick example:
main.go
package main
import "pathToProject/controllers"
func main() {
controllers.Test()
}
control.go
package controllers
func Test() {
// Do Something
}
Don't ever forget: Visible External Functions, Variables and Methods starts with Capital Letter.
i.e:
func test() {
// I am not Visible outside the file
}
func Test() {
// I am VISIBLE OUTSIDE the FILE
}
If you just run go run test1.go and that file has a reference to a function in another file within the same package, it will error because you didn't tell Go to run the whole package, you told it to only run that one file.
You can tell go to run as a whole package by grouping the files as a package in the run commaned in several ways. Here are some examples (if your terminal is in the directory of your package):
go run ./
OR
go run test1.go test2.go
OR
go run *.go
You can expect the same behavior using the build command, and after running the executable created will run as a grouped package, where the files know about eachothers functions, etc. Example:
go build ./
OR
go build test1.go test2.go
OR
go build *.go
And then afterward simply calling the executable from the command line will give you a similar output to using the run command when you ran all the files together as a whole package. Ex:
./test1
Or whatever your executable filename happens to be called when it was created.
Folder Structure
duplicate
|
|--duplicate_main.go
|
|--countLines.go
|
|--abc.txt
duplicate_main.go
package main
import (
"fmt"
"os"
)
func main() {
counts := make(map[string]int)
files := os.Args[1:]
if len(files) == 0 {
countLines(os.Stdin, counts)
} else {
for _, arg := range files {
f, err := os.Open(arg)
if err != nil {
fmt.Fprintf(os.Stderr, "dup2: %v\n", err)
continue
}
countLines(f, counts)
f.Close()
}
}
for line, n := range counts {
if n > 1 {
fmt.Printf("%d\t%s\n", n, line)
}
}
}
countLines.go
package main
import (
"bufio"
"os"
)
func countLines(f *os.File, counts map[string]int) {
input := bufio.NewScanner(f)
for input.Scan() {
counts[input.Text()]++
}
}
go run ch1_dup2.go countLines.go abc.txt
go run *.go abc.txt
go build ./
go build ch1_dup2.go countLines.go
go build *.go
You can import functions from another file by declaring the other file as a module. Keep both the files in the same project folder.
The first file test1.go should look like this:
package main
func main() {
demo()
}
From the second file remove the main function because only one main function can exist in a package. The second file, test2.go should look like below:
package main
import "fmt"
func demo() {
fmt.Println("HI")
}
Now from any terminal with the project directory set as the working directory run the command:
go mod init myproject.
This would create a file called go.mod in the project directory. The contents of this mod file might look like the below:
module myproject
go 1.16
Now from the terminal simply run the command go run .! The demo function would be executed from the first file as desired !!
as a stupid person who didn't find out what is going on with go module
should say :
create your main.go
in the same directory write this in your terminal
go mod init "your module name"
create a new directory and go inside it
create a new .go file and write the directory's name as package name
write any function you want ; just notice your function must starts with capital letter
back to main.go and
import "your module name / the name of your new directory"
finally what you need is writing the name of package and your function name after it
"the name of your new dirctory" + . + YourFunction()
and write this in terminal
go run .
you can write go run main.go instead.
sometimes you don't want to create a directory and want to create new .go file in the same directory, in this situation you need to be aware of, it doesn't matter to start your function with capital letter or not and you should run all .go files
go run *.go
because
go run main.go
doesn't work.
Let me try.
Firstly
at the root directory, you can run go mod init mymodule (note: mymodule is just an example name, changes it to what you use)
and maybe you need to run go mod tidy after that.
Folder structure will be like this
.
├── go.mod
├── calculator
│ └── calculator.go
└── main.go
for ./calculator/calculator.go
package calculator
func Sum(a, b int) int {
return a + b
}
Secondly
you can import calculator package and used function Sum (note that function will have Capitalize naming) in main.go like this
for ./main.go
package main
import (
"fmt"
"mymodule/calculator"
)
func main() {
result := calculator.Sum(1, 2)
fmt.Println(result)
}
After that
you can run this command at root directory.
go run main.go
Result will return 3 at console.
Bonus: for ./go.mod
module mymodule
go 1.19
ps. This is my first answer ever. I hope this help.

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