I am new to Ruby.
I need to make this script work:
puts "Do you like cats?"
ask = gets
def ask(n)
if ask == yes
return "I do too"
end
if ask == no
return "Dogs are better"
end
end
puts "#{ask(n)}"
Error message is :
pracif.rb:15:in <main>': undefined local variable or methodn' for
main: Object (NameError)
Here's a script that would work for you :
puts "Do you like cats?"
answer = gets
def ask(n)
if n == 'yes'
return "I do too"
end
if n == 'no'
return "Dogs are better"
end
end
puts ask(answer.downcase.chomp)
Explaination
As the error said you were trying to pass in a variable n which was not defined
Secondly you have a method name ask same as variable name. I've renamed the variable to answer instead
Thirdly, enclose yes and no in quotes
And finally, since you are using gets a \n gets appended like yes\n so none of your conditions would match. So i've used chomp to remove \n. And also used downcase to make input case insensitive.
EDIT
As mentioned by #Jordan in the comments, there is no reason to use string interpolation for the puts statement. So it's enough to call the method directly.
There are a bunch of issues with your code. Try something more like:
def reply(response)
return 'I do too' if response == 'yes'
return 'Dogs are better' if response == 'no'
'Invalid response!'
end
puts 'Do you like cats?'
response = gets().chomp()
puts reply(response)
Pay attention to the variable names. If you keep them descriptive, it is easier to spot mistakes.
Your script has no n local variable defined that you are passing to your ask(n) method at the end.
Rename your ask variable that your script gets from user to answer for example and pass it to your ask method at the end like so:
Updated code to fix other problem I did not see in the first run.
puts "Do you like cats?"
answer = gets.chomp
def ask(n)
(n == 'yes') ? "I do too" : "Dogs are better"
end
puts "#{ask(answer)}"
Related
How do I put a message (string) for a specific answer (user input) and another message for another answer? For e.g.
puts "Did You Like My Program?"
feedback = gets
if feedback = "Yes"
puts "We're Glad!"
elsif feedback = "No"
puts "We Will Try To Improve!"
end
What should I change, add, or modify?
Your problem is that, when you compare, you have to use ==, not =.
When you input on command line, you always use Enter. It produces \n at the end of the string. So you need to remove it with chomp.
Also, to filter user input, I suggest this variant:
feedback = nil
until %w[y n].include?(feedback)
puts 'Did You Like My Program? Y/N'
feedback = gets.chomp.downcase
end
if feedback == 'y'
puts "We're Glad!"
else
puts "We Will Try To Improve!"
end
Brief explanation:
The code uses Array#include? and String#downcase.
%w[y n] is equal to ["y", "n"].
The until-loop executes the code while the condition is false.
if array.present?
puts "hello"
end
There is no else part to this.
How to write the above if condition using unless.
I'm asking this question because of this lint error:
Use a guard clause instead of wrapping the code inside a conditional expression
Regarding your comment:
I'm asking this question because of this lint error
Use a guard clause instead of wrapping the code inside a conditional expression
This means that instead of:
def foo(array)
if array.present?
puts "hello"
end
end
You are supposed to use:
def foo(array)
return unless array.present?
puts "hello"
end
See https://github.com/bbatsov/ruby-style-guide#no-nested-conditionals
If this is a Rails question (is it?), you can also use blank?:
def foo(array)
return if array.blank?
puts "hello"
end
There's no reason to.
Remember: unless is the inverse of if (or !if if you rather), and is only intended to make your code easier to read.
Using unless with your expression would be incredibly awkward, because you're now moving the actual body of work to an else statement...
unless array.present?
return
else
puts "hello"
end
...which doesn't make your code any easier to read if you had stuck with a negated if:
if !array.present?
return
else
puts "hello"
end
Don't use unless here. You lose readability in exchange for virtually nothing.
One-liner:
puts "hello" unless !array.present?
However, I would recommend:
puts "hello" if array.present?
unless array.present?
return
else
puts "hello"
end
OP requested one-liner modification:
Pseudocode:
something unless condition
Therefore:
puts "hello" unless !array.present?
So I've been messing around with Ruby for the first time after finishing the codecademy course up to "Object Oriented Programming, Part I" and I decided to start making a calculator. For some reason though, I get this error:
calc.rb:13:in `addition': undefined local variable or method `user_input' for main:Object (NameError)
from calc.rb:21:in `<main>'
I'm confused why it doesn't see my "user_input" array. Is it out of the scope of the method? Did I initialize it wrong?
Here's the code so you can see for yourself, it's obviously nothing sophisticated and it's not finished. I'm just trying to test for addition right now.
#!/usr/bin/env ruby
user_input = Array.new
puts "Would you like to [a]dd, [s]ubtract, [m]ultiply, or [d]ivide? "
type_of_math = gets.chomp
def addition
operator = :+
puts "Please enter the numbers you want to add (enter \"=\" to stop adding numbers): "
until gets.chomp == "="
user_input << gets.chomp.to_i
end
sum = user_input.inject(operator)
return sum
end
case type_of_math
when "a"
addition
when "s"
puts "Test for subtraction"
when "m"
puts "Test for multiplication"
when "d"
puts "Test for division"
else
puts "Wrong"
end
Consider this untested variation on your code. It's more idiomatic:
def addition
user_input = []
puts 'Please enter the numbers you want to add (enter "=" to stop adding numbers): '
loop do
input = gets.chomp
break if input == '='
user_input << input
end
user_input.map(&:to_i).inject(:+)
end
Notice that it puts user_input into the method. It also uses the normal [] direct assignment of an empty array to initialize it. Rather than chomp.to_i each value as it's entered it waits to do that until after the loop exits.
Instead of while loops, consider using loop do. They tend to be more easily seen when scanning code.
Also notice there's no return at the end of the method. Ruby automatically returns the last value seen.
I am trying to make a number guessing game in Ruby but the program exits after I type in yes when I want to play again. I tried using the catch and throw but it would not work. Could I please get some help.
Here is my code.
class Game
def Play
catch (:start) do
$a=rand(11)
puts ($a)
until $g==$a
puts "Guess the number between 0-10."
$g=gets.to_i
if $g>$a
puts "The number you guessed is too high."
elsif $g==$a
puts "Correct you won!!!"
puts "Would you like to play again?"
$s=gets()
if $s=="yes"
$c=true
end
if $c==true
throw (:start)
end
elsif $g<$a
puts "The number you guessed is too low."
end
end
end
end
end
Game.new.Play
Edit: Here's my new code after trying suggestions:
class Game
def Play
catch (:start) do
$a=rand(11)
puts ($a)
while $s=="yes"
until $g==$a
puts "Guess the number between 0-10."
$g=gets.chomp.to_i
if $g>$a
puts "The number you guessed is too high."
elsif $g==$a
puts "Correct you won!!!"
puts "Would you like to play again?"
$s=gets.chomp
if $s=="yes"
throw (:start)
end
elsif $g<$a
puts "The number you guessed is too low."
end
end
end
end
end
end
Game.new.Play
Your first problem is here:
$s=gets()
if $s=="yes"
$c=true
end
The gets method will read the next line including the new line character '\n', and you compare it to only "yes":
> gets
=> "yes\n"
The idiomatic way to fix this in Ruby is the chomp method:
> gets.chomp
=> "yes"
That said, your code has two other deficiencies.
You may come from a language such as PHP, Perl, or even just Bash scripting, but Ruby doesn't require the dollar sign before variables. Using a $ gives a variable global scope, which is likely not what you want. In fact, you almost never want a variable to have global scope.
Ruby uses three types of symbol prefixes to indicate scope - # for instance, ## for class, and $ for global. However the most common type of variable is just local which doesn't need any prefix, and what I would suggest for your code.
I have always been told that it is very bad practice to use exceptions for control structure. Your code would be better served with a while/break structure.
When you do gets(), it retrieves the full line with a '\n' in the end. You need to trim the new line character by using:
$g=gets.chomp.to_i
Same for other gets
Based on your updated code (where you fixed the newline problem shown by others), your new problem is that you have wrapped all your game inside while $s=="true". The very first time your code is run, $s is nil (it has never been set), and so you never get to play. If you used local variables instead of global variables (s instead of $s) this would have become more obvious, because the code would not even have run.
Here's one working way that I would re-write your game.
class Game
def play
keep_playing = true
while keep_playing
answer = rand(11) # Make a new answer each time
puts answer if $DEBUG # we don't normally let the user cheat
loop do # keep going until I break from the loop
puts "Guess the number between 0-10."
guess = gets.to_i # no need for chomp here
if guess>answer
puts "The number you guessed is too high."
elsif guess<answer
puts "The number you guessed is too low."
else
puts "Correct you won!!!",
"Would you like to play again?"
keep_playing = gets.chomp.downcase=="yes"
break
end
end
end
end
end
Game.new.play
I know this doesn't really answer your question about why your code isn't working, but after seeing the code you posted I just had to refactor it. Here you go:
class Game
def initialize
#answer = rand(11)
end
def play
loop do
guess = get_guess
display_feedback guess
break if guess == #answer
end
end
def self.play_loop
loop do
Game.new.play
break unless play_again?
end
end
private
def get_guess
puts "Guess the number between 0-10."
return gets.chomp.to_i
end
def display_feedback(guess)
if guess > #answer
puts "The number you guessed is too high."
elsif guess < #answer
puts "The number you guessed is too low."
elsif guess == #answer
puts "Correct you won!!!"
end
end
def self.play_again?
puts "Would you like to play again?"
return gets.chomp == "yes"
end
end
Game.play_loop
If i give input as 1 or 2, regardless of that program goes in default. Tried comparing input with "1" and 1 both. Same result.
My first Ruby program, plz excuse for naivety.
$choice
def getInfo
puts "Info"
end
def getMoreInfo
puts "MoreInfo"
end
def switch
if $choice == "1" #intentionally in ""
getInfo
elsif $choice == 2 #intentionally without ""
getMoreInfo
else
puts "default"
end
end
def callMainMenu
puts "Choose the operation:"
puts "[1] Get some Info"
puts "[2] Get some moreInfo"
$choice=gets
$choice.chomp
end
callMainMenu
switch
You need to use the destructive version of chomp if you're going to assign it like that.
$choice.chomp!
Or
$choice = $choice.chomp
In order to debug this, what I'd do is add puts $choice.inspect at the beginning of your switch method to see exactly what's in the variable. That said, I believe the problem here is that you're calling $choice.chomp instead of $choice.chomp!. The former will return the result, and the latter will change the variable in place.
When you change $choice.chomp to $choice.chomp! and get rid of the // (change those to #), then you'll have something working. Keep refining it , it is not perfect yet.
Use $choice.chomp!. chomp without ! does not alter $choice. It returns a new string. This a naming convention in Ruby.