How to get sorted HashMap from TreeMap in Java - sorting

I would like to just sort my hashMap by key and need some help please. What I have so far:
Map<String, Map<String, String>> unsortedMapResult = new HashMap<String, Map<String, String>>();
unsortedMapResult.put("Delete Items", "Before items", "After items");
unsortedMapResult.put("Audit Items", "Before items", "After items");
Map<String, Map<String, String>> treeMapResult = new TreeMap<String,
Map<String, String>>(unsortedMapResult);
Map<String, Map<String, String>> finalResult = new HashMap<String, Map<String, String>>();
I am simply walking the TreeMap and copy contents to a new HashMap
Set<Entry<String, Map<String, String>>> entrySets = treeMapResult.entrySet();
for (Entry<String, Map<String, String>> ent : entrySets) {
finalResult.put(ent.getKey(), ent.getValue());
}
return finalResult;
The problem is finalResult now is NOT sorted and is exactly the same as my initial unsortedMapResult.
I would like to have it so that they are sorted as follow:
Audit Items, Before items, After items
Delete Items, Before items, After items

There is no such thing as a "sorted HashMap", so I'm afraid what you're asking for is simply not possible. As the documentation for HashMap says:
This class makes no guarantees as to the order of the map
Inserting elements in a particular order (which is what you're doing here) will do nothing to make them come out in the order you want, and neither will anything else -- other than using instead a collection (like TreeMap) that does respect some kind of ordering of the elements.

Related

Merging two collection in spring

I have two collections with the following payloads:
Collection-1 payload:-
{
name:"bucky",
email:"bucky#gmail.com"
}
collection-2 payload:-
{
score:"97",
subject:"Science"
}
I want to pass payload by merging collection-1 and 2,
Expected payload:-
{
"collection-1":{
name:"bucky",
email:"bucky#gmail.com"
},
"collection-2":{
score:"97",
subject:"Science"
}
}
How I can merge these two collections and generate the above-Expected payload?
Both collections have their respected DAO classes.
I was Doing Something like this :-
public Map<String,Object> getAllData{
Map<String, Object> result=new HashMap<>();
Map<String, Collection1> obj1=new HashMap<>();
Map<String, Collection2> obj2=new HashMap<>();
obj1=getData1();
obj2=getData2();
result.put("object-1",obj1);
result.put("object-2",obj1);
return result;
}

Convert a list of objects to a map of key and list of objects in java 8 [duplicate]

I want to translate a List of objects into a Map using Java 8's streams and lambdas.
This is how I would write it in Java 7 and below.
private Map<String, Choice> nameMap(List<Choice> choices) {
final Map<String, Choice> hashMap = new HashMap<>();
for (final Choice choice : choices) {
hashMap.put(choice.getName(), choice);
}
return hashMap;
}
I can accomplish this easily using Java 8 and Guava but I would like to know how to do this without Guava.
In Guava:
private Map<String, Choice> nameMap(List<Choice> choices) {
return Maps.uniqueIndex(choices, new Function<Choice, String>() {
#Override
public String apply(final Choice input) {
return input.getName();
}
});
}
And Guava with Java 8 lambdas.
private Map<String, Choice> nameMap(List<Choice> choices) {
return Maps.uniqueIndex(choices, Choice::getName);
}
Based on Collectors documentation it's as simple as:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(Choice::getName,
Function.identity()));
If your key is NOT guaranteed to be unique for all elements in the list, you should convert it to a Map<String, List<Choice>> instead of a Map<String, Choice>
Map<String, List<Choice>> result =
choices.stream().collect(Collectors.groupingBy(Choice::getName));
Use getName() as the key and Choice itself as the value of the map:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(Choice::getName, c -> c));
Most of the answers listed, miss a case when the list has duplicate items. In that case there answer will throw IllegalStateException. Refer the below code to handle list duplicates as well:
public Map<String, Choice> convertListToMap(List<Choice> choices) {
return choices.stream()
.collect(Collectors.toMap(Choice::getName, choice -> choice,
(oldValue, newValue) -> newValue));
}
Here's another one in case you don't want to use Collectors.toMap()
Map<String, Choice> result =
choices.stream().collect(HashMap<String, Choice>::new,
(m, c) -> m.put(c.getName(), c),
(m, u) -> {});
One more option in simple way
Map<String,Choice> map = new HashMap<>();
choices.forEach(e->map.put(e.getName(),e));
For example, if you want convert object fields to map:
Example object:
class Item{
private String code;
private String name;
public Item(String code, String name) {
this.code = code;
this.name = name;
}
//getters and setters
}
And operation convert List To Map:
List<Item> list = new ArrayList<>();
list.add(new Item("code1", "name1"));
list.add(new Item("code2", "name2"));
Map<String,String> map = list.stream()
.collect(Collectors.toMap(Item::getCode, Item::getName));
If you don't mind using 3rd party libraries, AOL's cyclops-react lib (disclosure I am a contributor) has extensions for all JDK Collection types, including List and Map.
ListX<Choices> choices;
Map<String, Choice> map = choices.toMap(c-> c.getName(),c->c);
You can create a Stream of the indices using an IntStream and then convert them to a Map :
Map<Integer,Item> map =
IntStream.range(0,items.size())
.boxed()
.collect(Collectors.toMap (i -> i, i -> items.get(i)));
I was trying to do this and found that, using the answers above, when using Functions.identity() for the key to the Map, then I had issues with using a local method like this::localMethodName to actually work because of typing issues.
Functions.identity() actually does something to the typing in this case so the method would only work by returning Object and accepting a param of Object
To solve this, I ended up ditching Functions.identity() and using s->s instead.
So my code, in my case to list all directories inside a directory, and for each one use the name of the directory as the key to the map and then call a method with the directory name and return a collection of items, looks like:
Map<String, Collection<ItemType>> items = Arrays.stream(itemFilesDir.listFiles(File::isDirectory))
.map(File::getName)
.collect(Collectors.toMap(s->s, this::retrieveBrandItems));
I will write how to convert list to map using generics and inversion of control. Just universal method!
Maybe we have list of Integers or list of objects. So the question is the following: what should be key of the map?
create interface
public interface KeyFinder<K, E> {
K getKey(E e);
}
now using inversion of control:
static <K, E> Map<K, E> listToMap(List<E> list, KeyFinder<K, E> finder) {
return list.stream().collect(Collectors.toMap(e -> finder.getKey(e) , e -> e));
}
For example, if we have objects of book , this class is to choose key for the map
public class BookKeyFinder implements KeyFinder<Long, Book> {
#Override
public Long getKey(Book e) {
return e.getPrice()
}
}
I use this syntax
Map<Integer, List<Choice>> choiceMap =
choices.stream().collect(Collectors.groupingBy(choice -> choice.getName()));
It's possible to use streams to do this. To remove the need to explicitly use Collectors, it's possible to import toMap statically (as recommended by Effective Java, third edition).
import static java.util.stream.Collectors.toMap;
private static Map<String, Choice> nameMap(List<Choice> choices) {
return choices.stream().collect(toMap(Choice::getName, it -> it));
}
Another possibility only present in comments yet:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(c -> c.getName(), c -> c)));
Useful if you want to use a parameter of a sub-object as Key:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(c -> c.getUser().getName(), c -> c)));
Map<String, Set<String>> collect = Arrays.asList(Locale.getAvailableLocales()).stream().collect(Collectors
.toMap(l -> l.getDisplayCountry(), l -> Collections.singleton(l.getDisplayLanguage())));
This can be done in 2 ways. Let person be the class we are going to use to demonstrate it.
public class Person {
private String name;
private int age;
public String getAge() {
return age;
}
}
Let persons be the list of Persons to be converted to the map
1.Using Simple foreach and a Lambda Expression on the List
Map<Integer,List<Person>> mapPersons = new HashMap<>();
persons.forEach(p->mapPersons.put(p.getAge(),p));
2.Using Collectors on Stream defined on the given List.
Map<Integer,List<Person>> mapPersons =
persons.stream().collect(Collectors.groupingBy(Person::getAge));
Here is solution by StreamEx
StreamEx.of(choices).toMap(Choice::getName, c -> c);
Map<String,Choice> map=list.stream().collect(Collectors.toMap(Choice::getName, s->s));
Even serves this purpose for me,
Map<String,Choice> map= list1.stream().collect(()-> new HashMap<String,Choice>(),
(r,s) -> r.put(s.getString(),s),(r,s) -> r.putAll(s));
If every new value for the same key name has to be overridden:
public Map < String, Choice > convertListToMap(List < Choice > choices) {
return choices.stream()
.collect(Collectors.toMap(Choice::getName,
Function.identity(),
(oldValue, newValue) - > newValue));
}
If all choices have to be grouped in a list for a name:
public Map < String, Choice > convertListToMap(List < Choice > choices) {
return choices.stream().collect(Collectors.groupingBy(Choice::getName));
}
List<V> choices; // your list
Map<K,V> result = choices.stream().collect(Collectors.toMap(choice::getKey(),choice));
//assuming class "V" has a method to get the key, this method must handle case of duplicates too and provide a unique key.
As an alternative to guava one can use kotlin-stdlib
private Map<String, Choice> nameMap(List<Choice> choices) {
return CollectionsKt.associateBy(choices, Choice::getName);
}
List<Integer> listA = new ArrayList<>();
listA.add(1);
listA.add(5);
listA.add(3);
listA.add(4);
System.out.println(listA.stream().collect(Collectors.toMap(x ->x, x->x)));
String array[] = {"ASDFASDFASDF","AA", "BBB", "CCCC", "DD", "EEDDDAD"};
List<String> list = Arrays.asList(array);
Map<Integer, String> map = list.stream()
.collect(Collectors.toMap(s -> s.length(), s -> s, (x, y) -> {
System.out.println("Dublicate key" + x);
return x;
},()-> new TreeMap<>((s1,s2)->s2.compareTo(s1))));
System.out.println(map);
Dublicate key AA
{12=ASDFASDFASDF, 7=EEDDDAD, 4=CCCC, 3=BBB, 2=AA}

How do you map the output of a Spring stored procedure execute?

I am using Spring and stored procedures to retrieve data from a mySQL database. I have the stored procedure and parameters working OK but I'm having problems mapping the result set. At the moment I have some truly ugly code to get the values and I'm sure there has to be a better, cleaner and more elegant way. Can anyone guide me to a better solution?
After the stored procedure class, I have:
List<String> outList = new ArrayList<String>();
Map<String,Object> outMap = execute(parameters_map);
List list = (List) outMap.get("#result-set-1");
for (Object object : list) {
Map map2 = (Map) object;
list.add(map2.get("runname"));
}
return outList;
runname is the column from the database query.
Is there a better way to achieve this?
Example from spring docs using RowMapper:
public class JdbcActorDao implements ActorDao {
private SimpleJdbcCall procReadAllActors;
public void setDataSource(DataSource dataSource) {
JdbcTemplate jdbcTemplate = new JdbcTemplate(dataSource);
jdbcTemplate.setResultsMapCaseInsensitive(true);
this.procReadAllActors = new SimpleJdbcCall(jdbcTemplate)
.withProcedureName("read_all_actors")
.returningResultSet("actors",
BeanPropertyRowMapper.newInstance(Actor.class));
}
public List getActorsList() {
Map m = procReadAllActors.execute(new HashMap<String, Object>(0));
return (List) m.get("actors");
}
// ... additional methods
}
took a while to interpret the Spring docs but I finally got there.
My solution:
SimpleJdbcCall simpleJdbcCall = new SimpleJdbcCall(jdbcTemplate)
.withProcedureName("DistinctRunNames")
.withoutProcedureColumnMetaDataAccess();
simpleJdbcCall.addDeclaredParameter(new SqlParameter("environment", Types.VARCHAR));
simpleJdbcCall.addDeclaredParameter(new SqlParameter("username", Types.VARCHAR));
simpleJdbcCall.addDeclaredParameter(new SqlParameter("test_suite", Types.VARCHAR));
SqlParameterSource parameters = new MapSqlParameterSource().addValue("environment", environment)
.addValue("username", username).addValue("test_suite", testSuite);
Map map = simpleJdbcCall.returningResultSet("runnames", new ParameterizedRowMapper<RunNameBean>() {
public RunNameBean mapRow(ResultSet rs, int rowNum) throws SQLException {
RunNameBean runNameBean = new RunNameBean();
runNameBean.setName(rs.getString("runname"));
return runNameBean;
}
}).execute(parameters);
return (List) map.get("runnames");
Had problems with expected parameters versus actual, had to break up the simpleJdbcCall object. Maps the results into a list beautifully.
Thank you for answers, helped me to learn about Spring mapping.

Gson: How do I deserialize an inner JSON object to a map if the property name is not fixed?

My client retrieves JSON content as below:
{
"table": "tablename",
"update": 1495104575669,
"rows": [
{"column5": 11, "column6": "yyy"},
{"column3": 22, "column4": "zzz"}
]
}
In rows array content, the key is not fixed. I want to retrieve the key and value and save into a Map using Gson 2.8.x.
How can I configure Gson to simply use to deserialize?
Here is my idea:
public class Dataset {
private String table;
private long update;
private List<Rows>> lists; <-- little confused here.
or private List<HashMap<String,Object> lists
Setter/Getter
}
public class Rows {
private HashMap<String, Object> map;
....
}
Dataset k = gson.fromJson(jsonStr, Dataset.class);
log.info(k.getRows().size()); <-- I got two null object
Thanks.
Gson does not support such a thing out of box. It would be nice, if you can make the property name fixed. If not, then you can have a few options that probably would help you.
Just rename the Dataset.lists field to Dataset.rows, if the property name is fixed, rows.
If the possible name set is known in advance, suggest Gson to pick alternative names using the #SerializedName.
If the possible name set is really unknown and may change in the future, you might want to try to make it fully dynamic using a custom TypeAdapter (streaming mode; requires less memory, but harder to use) or a custom JsonDeserializer (object mode; requires more memory to store intermediate tree views, but it's easy to use) registered with GsonBuilder.
For option #2, you can simply add the names of name alternatives:
#SerializedName(value = "lists", alternate = "rows")
final List<Map<String, Object>> lists;
For option #3, bind a downstream List<Map<String, Object>> type adapter trying to detect the name dynamically. Note that I omit the Rows class deserialization strategy for simplicity (and I believe you might want to remove the Rows class in favor of simple Map<String, Object> (another note: use Map, try not to specify collection implementations -- hash maps are unordered, but telling Gson you're going to deal with Map would let it to pick an ordered map like LinkedTreeMap (Gson internals) or LinkedHashMap that might be important for datasets)).
// Type tokens are immutable and can be declared constants
private static final TypeToken<String> stringTypeToken = new TypeToken<String>() {
};
private static final TypeToken<Long> longTypeToken = new TypeToken<Long>() {
};
private static final TypeToken<List<Map<String, Object>>> stringToObjectMapListTypeToken = new TypeToken<List<Map<String, Object>>>() {
};
private static final Gson gson = new GsonBuilder()
.registerTypeAdapterFactory(new TypeAdapterFactory() {
#Override
public <T> TypeAdapter<T> create(final Gson gson, final TypeToken<T> typeToken) {
if ( typeToken.getRawType() != Dataset.class ) {
return null;
}
// If the actual type token represents the Dataset class, then pick the bunch of downstream type adapters
final TypeAdapter<String> stringTypeAdapter = gson.getDelegateAdapter(this, stringTypeToken);
final TypeAdapter<Long> primitiveLongTypeAdapter = gson.getDelegateAdapter(this, longTypeToken);
final TypeAdapter<List<Map<String, Object>>> stringToObjectMapListTypeAdapter = stringToObjectMapListTypeToken);
// And compose the bunch into a single dataset type adapter
final TypeAdapter<Dataset> datasetTypeAdapter = new TypeAdapter<Dataset>() {
#Override
public void write(final JsonWriter out, final Dataset dataset) {
// Omitted for brevity
throw new UnsupportedOperationException();
}
#Override
public Dataset read(final JsonReader in)
throws IOException {
in.beginObject();
String table = null;
long update = 0;
List<Map<String, Object>> lists = null;
while ( in.hasNext() ) {
final String name = in.nextName();
switch ( name ) {
case "table":
table = stringTypeAdapter.read(in);
break;
case "update":
update = primitiveLongTypeAdapter.read(in);
break;
default:
lists = stringToObjectMapListTypeAdapter.read(in);
break;
}
}
in.endObject();
return new Dataset(table, update, lists);
}
}.nullSafe(); // Making the type adapter null-safe
#SuppressWarnings("unchecked")
final TypeAdapter<T> typeAdapter = (TypeAdapter<T>) datasetTypeAdapter;
return typeAdapter;
}
})
.create();
final Dataset dataset = gson.fromJson(jsonReader, Dataset.class);
System.out.println(dataset.lists);
The code above would print then:
[{column5=11.0, column6=yyy}, {column3=22.0, column4=zzz}]

Deserializing DynamoDBResults with gson fails

I have a specific use case where I store the results from my one table in DynamoDB to be stored in a serialized manner in another DynamoDB.
Now when I use gson to deserialize the data being retrieved,
I get this error:
java.lang.RuntimeException: Unable to invoke no-args constructor for class java.nio.ByteBuffer. Register an InstanceCreator with Gson for this type may fix this problem.
at com.google.gson.internal.ConstructorConstructor$12.construct(ConstructorConstructor.java:210)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$Adapter.read(ReflectiveTypeAdapterFactory.java:186)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$1.read(ReflectiveTypeAdapterFactory.java:103)
at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$Adapter.read(ReflectiveTypeAdapterFactory.java:196)
at com.google.gson.internal.bind.TypeAdapterRuntimeTypeWrapper.read(TypeAdapterRuntimeTypeWrapper.java:40)
at com.google.gson.internal.bind.MapTypeAdapterFactory$Adapter.read(MapTypeAdapterFactory.java:187)
at com.google.gson.internal.bind.MapTypeAdapterFactory$Adapter.read(MapTypeAdapterFactory.java:145)
at com.google.gson.Gson.fromJson(Gson.java:810)
at com.google.gson.Gson.fromJson(Gson.java:775)
My method looks like this:
public void store(MyCustomObject obj) {
String primaryKey = obj.getKey();
List<Map<String, AttributeValue>> results = AmazonDynamoDB.query(...).getItems();
Gson gson = new Gson();
List<String>records = results .stream()
.map(mappedResult-> gson.toJson(mappedResult))
.collect(Collectors.toList());
Map<String, AttributeValue> attributeMap = transformToAttributeMap(records);
PutItemRequest putItemRequest = new PutItemRequest().withItem(attributeMap);
AmazonDynamoDB.putItem(...);
}
The method to retrieve the records looks something like this:
public void retrieve(String id) {
QueryRequest...
Map<String, AttributeValue> records = DynamoDB.query(...).getItems();
List<String> serializedRecords = new ArrayList<>();
List<AttributeValue> values = records.get("key");
for( AttributeValue attributeValue: values) {
serializedRecords.add(attributeValue.getS());
}
Gson gson = new Gson();
Type recordType = new TypeToken<Map<String, AttributeValue>>() { }.getType();
List<Map<String, AttributeValue>> actualRecords = serializedRecords.stream()
.map(record-> gson.fromJson(record, recordType))
.collect(Collectors.toList());
}
What am I doing wrong?
The problem is AttributeValue class has a field java.nio.ByteBuffer with name b. Gson tries to deserialize the data into it, but there is no default constructor for ByteBuffer class. Therefore gson cannot deserialize b field.
An alternative solution is with the new DynamoDB usage of AWS SDK. Following example should work:
AmazonDynamoDBClient client = new AmazonDynamoDBClient(
new ProfileCredentialsProvider());
Item item = new DynamoDB(client).getTable("user").getItem("Id", "user1");
String json = item.toJSON();
Item deserialized = Item.fromJSON(json);
You should modify the credentials provider according to your setup.
Not exactly the best workaround/answer, but I was able to do this:
Item item = new Item().withJSON("document", jsonStr);
Map<String,AttributeValue> attributes = InternalUtils.toAttributeValues(item);
return attributes.get("document").getM();

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