I am now learning to work with pivot tables: https://laravel.com/docs/4.2/eloquent#working-with-pivot-tables
I have WeeklyRoutine model. Each routine has several Activities. The assigned activities are attached in a pivot table activity_routine.
Relation defined in the WeeklyRoutine model:
return $this->belongsToMany('App\Models\Activity', 'activity_routine', 'routine_id', 'activity_id')->withPivot('done_at')->withTimestamps();
}
it looks like this:
// activity_routine pivot table (relevant columns only)
| id | activity_id | routine_id | done_at |
| 34 | 1 | 4 | 2016-04-23 09:27:27 | // *1
| 35 | 2 | 4 | null | // *2
*1 this activity is marked as done with the code below
*2 this activity is not yet done
what I have:
I can update the done_at field in the pivot table, thus making it marked as DONE for the given week (a weeklyroutine_id = 4 in the above code
public function make_an_activity_complete($routineid, $activityid) {
$date = new \DateTime;
$object = Routine::find($routineid)->activities()->updateExistingPivot($activityid, array('done_at' => $date));
return 'done!';
}
what I need
I want to UN-DO an activity. When it is already done, that is when the done_at is not null buc contains a date, make it null.
In other words I need to do the below switch of value, but the proper way:
$pivot = DB::table('activity_routine')->where('routine_id, $routineid)->where('activity_id, $activityid)->first();
if($pivot->done_at != null) {
$new_val = new \DateTime;
} else {
$new_val = null;
}
$object = Routine::find($routineid)->activities()->updateExistingPivot($activityid, array('done_at' => $new_val));
How to do it? I have no clue!
Thx.
Your approach seems fine to me. I would probably do it like this.
$routine = Routine::find($routineid);
$activity = $routine->activities()->find($activityid);
$done_at = is_null($activity->pivot->done_at) ? new \DateTime : null;
$routine->activities()->updateExistingPivot($activityid, compact('done_at'));
Related
I'm trying to get data from my pivot table.
clients table:
---|------
id | name
---|------
1 | John
---|------
2 | Steve
orders table:
---|------
id | description
---|------
1 | Mac
---|------
2 | Keyboard
---|------
3 | Printer
client_order (pivot)table:
id | client_id | order_id
---|-----------|------
1 | 1 1
---|-----------|------
2 | 1 | 2
---|-----------|------
3 | 2 | 3
Client.php
public function orders()
{
return $this->belongsToMany('App\Order','client_order');
}
Order.php
public function clients()
{
return $this->belongsToMany('App\Client','client_order');
}
Now, how can I retrieve data from pivot table? For example:
John | Mac, Keyboard (2 orders)
Steve| Printer (1 orders)
Thank you.
For client:
$client = Client::find(1); //or anyway you create the client
$client->orders; //it gives you a collection that you can get data
in a foreach loop
//for example
foreach($client->orders as $order){
echo $order->description;
}
For order:
$order = Order::find(1); //or anyway you create order
$order->clients; //it gives you a collection too
//for example
foreach($order->clients as $client){
echo $client->name;
}
This is for your new comment. First you select your users and then in a loop you can get the orders:
$clients = Client::all();
foreach($clients as $client){
echo $client->name." | ";
foreach($client->orders as $order){
echo $order->description;
}
echo "(".count($client->orders)." orders)";
}
You can achieve that using the relations as #Rouhollah Mazarei said, but you can also use the own pivot table to retrieve this information:
$clientsOrders = DB::table('client_order')->where('client_id', $clientId)->count()->get();
This will return to you how many orders this client made, you just need to inform his id.
I have a table of courses which will be free to access or an admin will need to click something to let users see the course.
The course table looks like this:
| id | title | invite_only |
|----|----------------|-------------|
| 1 | free course | 0 |
| 2 | private course | 1 |
Separate from this I have a course_user table, where initially users request access, then admins can approve or deny access:
| id | user_id | course_id | approved | declined |
|----|---------|-----------|----------|----------|
| 1 | 3 | 2 | 1 | 0 |
| 2 | 4 | 1 | 0 | 1 |
| 3 | 4 | 2 | 0 | 0 |
I'd like to index all the courses a user has access to:
class User extends model{
public function myCourses(){
$public = $this->publicCourses;
$invited = $this->invitedCourses;
return $public->merge($invited);
}
public function publicCourses(){
return $this
->hasMany('App\Course')
->where('invite_only', false);
}
public function invitedCourses(){
return $this
->belongsToMany("\App\Course")
->using('App\CourseUser')
->wherePivot('approved', 1);
}
}
How can I make the myCourses function return the results of both publicCourses and invitedCourses by doing only one database query? I'd like to merge the two query builder instances.
According to the doc, you can use union to merge query builders. But as far as I know, it does not work with relations. So maybe you should do it from within controller instead of model. This is an example based on what I understand from your example:
$q1 = App\Course::join('course_user', 'course_user.course_id', 'courses.id')
->join('users', 'users.id', 'course_user.user_id')
->where('courses.invite_only', 0)
->select('courses.*');
$q2 = App\Course::join('course_user', 'course_user.course_id', 'courses.id')
->join('users', 'users.id', 'course_user.user_id')
->where('courses.invite_only', 1)
->where('course_user.approvoed', 1)
->select('courses.*');
$myCourses = $q1->unionAll($q2)->get();
You can also refactor the code further by creating a join scope in App\Course.
I was able to make a much simpler query, and use Laravel's orWherePivot to extract the correct courses:
public function enrolledCourses()
{
return $this
->courses()
->where('invitation_only', false)
->orWherePivot('approved', true);
}
I have a table of items that contain info of the items. Plus, I have 3 other tables for some characteristics that could have more than one.
Follows an example:
table items
-----------------------
| id | price | stock |
-----------------------
| 1 | 19 | 99 |
-----------------------
table tallas
-----------------------------
| id | item_id| description |
-----------------------------
| 1 | 1 | large |
-----------------------------
table colors
-----------------------------
| id | item_id| description |
-----------------------------
| 1 | 1 | blue |
-----------------------------
table materials
-----------------------------
| id | item_id| description |
-----------------------------
| 1 | 1 | cotton |
-----------------------------
I want to know if there is a way where I can filter an item passing the item_id to the tallas relationship without using join (for example).
My model looks like this:
<?php
class Item extends Eloquent{
use Conner\Tagging\TaggableTrait;
public function tallas()
{
return $this->hasMany('Talla','item_id');
}
public function colores()
{
return $this->hasMany('Color','item_id');
}
public function materiales()
{
return $this->hasMany('Material','item_id');
}
public function imagenes()
{
return $this->hasMany('ItemImage','item_id');
}
}
And I have tried this:
$items = Item::with('imagenes')
->with(array('tallas' => function($query) use($dataFilter) {
$query->where('id','=',$dataFilter['filter-size']);
}));
But this return all the items and filter the tallas , using the example tables if i look for an item small it will return something like this.
[item]{
id:1,
price:19,
stock:99,
tallas:
[]...
colores:
[]...
materiales:
[]...
}
It should not return any item, any help?
EDITED
i forget to mention i'm using laravel 4.2
If I understand you question correctly I think you want whereHas e.g.
$items = Item::with('imagenes')
->whereHas('tallas', function ($query) use ($dataFilter) {
$query->where('id', '=', $dataFilter['filter-size']);
});
https://laravel.com/docs/4.2/eloquent#querying-relations
Hope this helps!
Piece of my database looks like database part
Categories use tree behavior.
How can i get a manufacturer's (Producers) Products for current Category?
I tried contain and matching, but i received duplicated data or Producers names without related Products.
EDIT:
$query = $this->Producers->find()->matching('Products.Categories',
function ($q) {
return $q->where(['Categories.id' => 18]);
}
);
Results:
Producent: Canon
-------------------------------------------
| ID | Name | Barcode |
-------------------------------------------
| 1 | EOS 1000D | |
-------------------------------------------
| 18 | Camera | |
-------------------------------------------
| 23 | 18 | |
-------------------------------------------
First row (id = 1) it's what i need.
Now i have to remove from results:
second row (id = 18) this is Category id from table Categories,
thrid row (id = 23) - from Products_Categories table.
Done. There is working query:
$query = $this->Producers->find()
->select(['Producers.id','Producers.name', 'Products.id', 'Products.name'])
->matching(
'Products.Categories', function ($q) use ($categoryId){
return $q->where(['Categories.id' => $categoryId]);
}
);
I use AJAX mechanism to set create or modify records in this table:
table:
id | item_type | item_id | creator_id | attitude
1 | exemplar | 3 | 33 | 1
2 | exemplar | 4 | 33 | 0
3 | exemplar | 3 | 35 | 1
In plain English: there are many exemplars to choose for one user. A given user can only set only one exemplar to value 1. In this particular case Exemplar #3 is active (attitude = 1). I want to set its "attitude" to 0 and in the same controller method where I have the below code.
The below code creates a new record for an exemplar which has never been chosen before, or changes the value of 'attitude column.
$user_id = Auth::user()->id;
$countatt = $exemplar->attitudes()->where('creator_id', $user_id)->first();
if (!$countatt)
{
$countatt = new Userattitude;
$countatt->creator_id = $user_id;
$countatt->item_type = 'exemplar';
$countatt->item_id = $exemplar_id;
}
$countatt->attitude = $value; // $value = 1
$countatt->save();
Problem to solve:
1. how, using the best practices, set all other records of the same user (creator_id) and exemplar_id to 0
My best guess isbe to put the below 4 lines before the code quoted above:
$oldactive= Exemplar::where('creator_id', $user_id)->where(exemplar_id, $exemplar_id)->first();
$zeroing_attitude= $oldactive->attitudes()->first();
$zeroing_attitude->attitude = 0;
$zeroing_attitude->save();
;
The above solution works only in case when there is only one exemplar with value of 'attitude' set to 1. But in the future I want to allow users to have multiple exemplars active. I am not familiar with Eloquent enough to rewrite the logic for multiple active Exemplars.
Sometimes there will be no active Exemplars set, which means that this collection would be empty
$oldactive= Exemplar::where('creator_id', $user_id)->where(exemplar_id, $exemplar_id)->first();
How should I skip executing the rest of the code in such case? By adding IF as below?
if($oldactive) {}
Thank you.
$oldactive= Exemplar::where('creator_id', $user_id)->where(exemplar_id,$exemplar_id)->first();
foreach($oldactive->attitudes() as $zeroing_attitude){
$zeroing_attitude->attitude = 0;
$zeroing_attitude->save();
}