LESS has a great little feature called Space that allows mixins to append rules to existing properties. Really useful for transform() mixins, because you can append many transform rules to the same property, just by calling the mixin multiple times, eg.
Example:
.scale() {
transform+_: scale(2);
}
.rotate() {
transform+_: rotate(15deg);
}
.myclass {
.scale();
.rotate();
}
Outputs:
.myclass {
transform: scale(2) rotate(15deg);
}
I'm trying to get into SASS, but I don't understand how to achieve this with the available syntax. Whatever I do, the output only ever applies one of the transformations, not both. What is the best way to achieve this behaviour using SASS alone?
You can use variable arguments in a mixin like so:
#mixin transform($transforms...) {
transform: $transforms;
}
.myclass {
#include transform(scale(0.5) rotate(30deg));
}
this will output:
.myclass {
transform: scale(0.5) rotate(30deg);
}
You can see a working example here:
http://codepen.io/sonnyprince/pen/RaMzgb
A little more info:
Sometimes it makes sense for a mixin or function to take an unknown
number of arguments. For example, a mixin for creating box shadows
might take any number of shadows as arguments. For these situations,
Sass supports “variable arguments,” which are arguments at the end of
a mixin or function declaration that take all leftover arguments and
package them up as a list. These arguments look just like normal
arguments, but are followed by ....
http://sass-lang.com/documentation/file.SASS_REFERENCE.html#variable_arguments
Sass does not offer such a feature.
You can get reasonably close by using global variables. However, every single mixin you use, including ones provided by a 3rd party, will have to be modified to work this way.
// the setup
$append-property-vals: (); // global variable
$old-append-property-vals: (); // global variable
#mixin append-property($key, $val, $separator: comma) {
$old-val: map-get($append-property-vals, $key);
#if $old-val {
$append-property-vals: map-merge($append-property-vals, ($key: append($old-val, $val, $separator))) !global;
} #else {
$append-property-vals: map-merge($append-property-vals, ($key: $val)) !global;
}
}
#mixin append-properties {
// cache the original value
$old-append-property-vals: $append-property-vals !global;
#content;
// write out the saved up properties
#each $key, $val in $append-property-vals {
#{$key}: $val;
}
// restore the original value
$append-property-vals: $old-append-property-vals !global;
}
// modify the OP's provided mixins to work
#mixin scale {
// if the vals should be comma delimited, write `comma` instead of `space` for the 3rd argument
#include append-property(transform, scale(2), space);
}
#mixin rotate {
#include append-property(transform, rotate(15deg), space);
}
// call the mixins
.myclass {
#include append-properties {
#include scale;
#include rotate;
}
}
Output:
.myclass {
transform: scale(2) rotate(15deg);
}
Related
Let's say for instance we have the next sass partial file:
//_colors.scss
$foo: red;
And we "use" it on another file:
//test.scss
#use './colors'
.test{
color: colors.$foo;
}
All good, but what if I would like to use/get the value in a dynamic way within a mixin? something like:
//test.scss
#use './colors'
#mixin getColor($type){
color: colors[$type]; //JavaScript example, * don't actually work *.
or
color: #{colors.{$type}; * don't work neither *
//The above returns `color: colors.foo` instead of `color: red` on compilation.
or
color: colors.#{$type}; * doesn't work neither *
}
.test{
#include getColor(foo);
}
Is it possible? thanks for the help!
For a color, I really much prefer a function so it can be used on any property (color, background-color, border, box-shadow...)
I usually declare a string equivalent to variable names, then define them inside a map. Finally this map is accessible via a dedicated function.
Something like
//_colors.scss
#use 'sass:map';
$favoriteRed: "favoriteRed";
$favoriteYellow: "favoriteYellow";
$favoriteBlue: "favoriteBlue";
$MyColors: (
$favoriteRed: #c00,
favoriteYellow: #fc0,
$favoriteBlue: #0cf
);
#function my-color($tone: $favoriteRed) {
#if not map.has-key($MyColors, $tone) {
#error "unknown `#{$tone}` in MyColors.";
}
#else {
#return map.get($MyColors, $tone);
}
}
This _colors.scss generates no code at all, it can be imported anywhere at no cost.
Then, in a specific style file:
//test.scss
#use './colors' as *;
//inside a mixin
#mixin special-hue-component($tone){
div.foo {
span.bar {
border-color: my-color($tone);
}
}
}
//or directly
.foobartest {
color: my-color($favoriteBlue);
}
I have a list of elements that need some gradient colors. But how can I make a simple mixin that simplifies the whole thing?
For example, in my css I'd like to be able to write:
button { #include linear(blue); }
and then scss would use my mixin and include my colors in my variables
$redTop: #F67777;
$redBottom: #E65050;
$blueTop: #77CFF6;
$blueBottom: #50B9E6;
#mixin linear($color) {
background-image: linear-gradient($colorTop, $colorBottom);
}
For this, you'd want to split the colours into a map.
$red: (
"top": #f00,
"bottom": #c00
);
#mixin linear($color) {
background-image: linear-gradient(map-get($color, "top"), map-get($color, "bottom"));
}
.red-bg {
#include linear($red);
}
I have the following SASS rules:
p {
margin: 0;
}
#include desktop() {
p {
margin: 0;
}
}
The mixin is like this:
#mixin desktop() {
#media screen and (min-width: 1200px) {
#content;
}
}
Elsewhere in the codebase there's a margin being set on desktop, hence in this case I need to explicitly remove it on the desktop breakpoint too, just having the first p selector rule doesn't cut it.
Is there a neat way to combine the selectors as it feels verbose having the same margin: 0 rule twice? I realise there's probably something more fundamentally wrong here with the inheritance, but that's outside the scope of the question. I don't want to use !important.
Many thanks.
Is there a neat way to combine the selectors? Sure there is… Just use another mixin:
#mixin para {
p {
margin: 0;
}
}
#include para;
#include desktop {
#include para;
}
You clearly already know how to use mixins, so I'm assuming your question is really about whether you can nest one mixin within another (yes), or whether you can include selectors within a mixin (yes).
How do I conditionally apply a mixin if --my-custom-var is present? For example:
.test {
#if var(--my-custom-var) {
#include someExampleMixin()
}
#if var(--another-custom-var) {
#include someExampleMixin()
}
}
I don't care what the value of the --my-custom-var is but just want to check its existence.
Sass has introduced the variable-exists() function already in alpha. Be aware that Sass can only check for Sass variables. Therefor if you'd really want to use CSS variables you need to define the content of your CSS variable inside a Sass variable, for example $sassVar: /* content */; --cssVar: $sassVar;. Be also aware that the #if statement must be inside a #mixin or a #function to work. I posted a working example below, but here is aslo my Codepen Example since Stack doesn't compile Sass.
Note:
I used "null" inside my $var which basically expresses that there
is no content within this variable, you can pass whatever you
want it won't affect the outcome unless you remove or change the actual
variable.
You can use multiple #if statements which I commented out in this example, but there should always follow an #else statement.
$var: null;
:root {
--someVar: $var;
}
#mixin checkForVariable {
#if variable-exists(var){
body {
background-color: red;
}
}
// #if variable-exists() {
// ...
// }
// #if variable-exists() {
// ...
// }
#else {
body {
background-color: blue;
}
}
}
#include checkForVariable;
I am trying to set global variables when a theme mixin is included since it seems much more straight-forward to use than this "themify" stuff I find from searching.
The idea is something like having a _themes.scss with
#mixin light-theme { $primary-color: #123456 !global; }
#mixin dark-theme { $primary-color: #654321 !global; }
body.light-theme { #include light-theme }
body.dark-theme { #include dark-theme }
The problem is it always uses the dark-theme value since it is declared last. Is what I am trying to do possible?