Replace multiple value of csv file - bash

Question

I have a csv file :
1,1,1,2
2,2,1,2
3,3,1,2
4,4,1,2
5,5,1,2
6,6,1,2
7,7,1,2
8,8,1,2
9,9,1,2
10,10,2,2
11,11,2,2
12,12,2,2
13,13,3,2
I want to replace each third value to this :
If 1; then 22
If 2; then 35
If 3; then 14
This is what I have made :
awk -F , -v OFS=, '{if ($3=="1") $3="22";if ($3=="2") $3="35";if ($3=="3") $3="14"} {print "\""$1"\""",""\""$2"\""",""\""$3"\""",""\""$4"\""}' /tmp/test.csv
It's work well on Debian but not on Ubuntu.
What is the problem ? Thanks you
[EDIT]
With the example I cited yesterday, it works , but not with this one :
cat -v test.csv
1,1,1,2
2,2,1,2
3,3,1,2
4,4,1,2
5,5,1,2
6,6,1,2
7,7,1,2
8,8,1,2
9,9,1,2
10,10,1,2
11,11,1,2
12,12,1,2
13,13,1,2
14,14,1,2
15,15,1,2
16,16,1,2
17,17,1,2
18,18,1,2
19,19,1,2
20,20,1,2
21,21,1,2
22,22,1,2
23,23,1,2
24,24,1,2
25,25,1,2
26,26,1,2
27,27,1,2
28,28,1,2
29,29,1,2
30,30,1,2
31,31,1,2
32,32,1,2
33,33,1,2
34,34,1,2
35,35,1,2
36,36,1,2
37,37,1,2
38,38,1,2
39,39,1,2
40,40,1,2
And now, the command return :
awk -F , -v OFS=, '{if ($3=="1") $3="2";if ($3=="2") $3="3";if ($3=="3") $3="5"} {print "\""$1"\""",""\""$2"\""",""\""$3"\""",""\""$4"\""}' toast.csv
"1","1","5","2"
"2","2","5","2"
"3","3","5","2"
"4","4","5","2"
"5","5","5","2"
"6","6","5","2"
"7","7","5","2"
"8","8","5","2"
"9","9","5","2"
"10","10","5","2"
"11","11","5","2"
"12","12","5","2"
"13","13","5","2"
"14","14","5","2"
"15","15","5","2"
"16","16","5","2"
"17","17","5","2"
"18","18","5","2"
"19","19","5","2"
"20","20","5","2"
"21","21","5","2"
"22","22","5","2"
"23","23","5","2"
"24","24","5","2"
"25","25","5","2"
"26","26","5","2"
"27","27","5","2"
"28","28","5","2"
"29","29","5","2"
"30","30","5","2"
"31","31","5","2"
"32","32","5","2"
"33","33","5","2"
"34","34","5","2"
"35","35","5","2"
"36","36","5","2"
"37","37","5","2"
"38","38","5","2"
"39","39","5","2"
"40","40","5","2"
All third values ​​are equal to 5 instead of 2. Same issue with this example on Debian.

Answer 1

None of the code you have posted will behave differently on any given machine vs any other machine. You saying that it did and posting the wrong code initially was a red herring, you just have buggy code, that's all.
The code you added in your latest edit says:
if ($3=="1") $3="2";if ($3=="2") $3="3";if ($3=="3") $3="5"
So let's say you start with a $3 in your input file that has value 1. Your first test/assignment is if ($3=="1") $3="2" so after that code executes $3 has value 2. Now your second test/assignment is if ($3=="2") $3="3" Well, $3 IS now 2 after your first code segment executes, so now it gets set to 3. And then your next test/assignment sets it to 5.
So given a $3 that is 1 you set $3 to 2, then you set it to 3 then you set it to 5 - net result is it's always 5. Throw in in some "else"s:
if ($3=="1") $3="2"; else if ($3=="2") $3="3"; else if ($3=="3") $3="5"
but at least change your script to avoid having to print each field individually:
awk -F, -v OFS='","' '{if ($3=="1") $3="2"; else if ($3=="2") $3="3"; else if ($3=="3") $3="5"} {print "\""$0"\""}' toast.csv
and consider using a more idiomatic approach:
$ cat file
9,9,1,2
10,10,2,2
13,13,3,2
$ awk -F, -v OFS='","' 'BEGIN{split("2,3,5",m)} {$3=m[$3]} {print "\""$0"\""}' file
"9","9","2","2"
"10","10","3","2"
"13","13","5","2"
The above assume your $3 is always one of the values you show/test for. If not there's easy tweaks.
In general to map one set of arbitrary numbers to another and allow for some input data that doesn't need to get mapped:
$ awk -F, -v OFS='","' 'BEGIN{split("1,2,3",a); split("2,3,5",b); for (i in a) m[a[i]]=b[i]} {$3=($3 in m ? m[$3] : $3)} {print "\""$0"\""}' file
"9","9","2","2"
"10","10","3","2"
"13","13","5","2"
or if you prefer:
$ awk -F, -v OFS='","' 'BEGIN{split("1,2,2,3,3,5",t); for (i=2;i in t;i+=2) m[t[i-1]]=t[i]} {$3=($3 in m ? m[$3] : $3)} {print "\""$0"\""}' file
"9","9","2","2"
"10","10","3","2"
"13","13","5","2"

Answer 2

It might be easier with sed:
sed 's/\([0-9]*,[0-9]*,\)1\(,[0-9]*\)/\122\2/' /tmp/test.csv
sed 's/\([0-9]*,[0-9]*,\)2\(,[0-9]*\)/\135\2/' /tmp/test.csv
sed 's/\([0-9]*,[0-9]*,\)3\(,[0-9]*\)/\114\2/' /tmp/test.csv
I believe that should do the trick and will most likely work on most sh/bash environments.
EDIT:
Note that this just prints out the actual replacements each command does, so you know what is going to happen before you actually change anything. You may want to first back up your file and then do inplace replacements with the -i flag:
$ cat /tmp/test.csv
1,1,1,2
2,2,1,2
3,3,1,2
4,4,1,2
5,5,1,2
6,6,1,2
7,7,1,2
8,8,1,2
9,9,1,2
10,10,2,2
11,11,2,2
12,12,2,2
13,13,3,2
$ cp /tmp/test.csv /tmp/test.csv.bak
$ sed -i 's/\([0-9]*,[0-9]*,\)1\(,[0-9]*\)/\122\2/' /tmp/test.csv
$ sed -i 's/\([0-9]*,[0-9]*,\)2\(,[0-9]*\)/\135\2/' /tmp/test.csv
$ sed -i 's/\([0-9]*,[0-9]*,\)3\(,[0-9]*\)/\114\2/' /tmp/test.csv
$ cat /tmp/test.csv
1,1,22,2
2,2,22,2
3,3,22,2
4,4,22,2
5,5,22,2
6,6,22,2
7,7,22,2
8,8,22,2
9,9,22,2
10,10,35,2
11,11,35,2
12,12,35,2
13,13,14,2