insert id number only in sql - oracle

Question

I have a SQL Server table like this
+----+-----------+------------+
| id | acoount | date |
+----+-----------+------------+
| | John | 2/6/2016 |
| | John | 2/6/2016 |
| | John | 4/6/2016 |
| | John | 4/6/2016 |
| | Andi | 5/6/2016 |
| | Steve | 4/6/2016 |
+----+-----------+------------+
i want insert the id coloumn like this.
+-----------+-----------+------------+
| id | acoount | date |
+-----------+-----------+------------+
| 020616001 | John | 2/6/2016 |
| 020616002 | John | 2/6/2016 |
| 040616001 | John | 4/6/2016 |
| 040616002 | John | 4/6/2016 |
| 050616001 | Andi | 5/6/2016 |
| 040616003 | Steve | 4/6/2016 |
+-----------+-----------+------------+
I want to generate id number of the date provided like this. 02+06+16(from date)+001 = 020616001. if have same date, id + 1.
I have tried but still failed .
I want make it in oracle sql develop.
Someone help me.
Thanks.

Answer 1

Try the below SQL as per the given data, Its in SQL Server 2012....
select REPLACE(CONVERT(VARCHAR(10),convert(date,t.[date]), 101), '/', '')
+'00'+convert(varchar(2),row_number()over(partition by account,[date] order by t.[date])) as ID,
t.account,
t.date
from (values ('John','2/6/2016'),
('John','2/6/2016'),
('John','4/6/2016'),
('John','4/6/2016'),
('Andi','5/6/2016'),
('Steve','4/6/2016'))T(account,[date])

Answer 2

Update your table using statement .
update table set id= replace(CONVERT(VARCHAR(10),CONVERT(datetime ,date,103),3) ,'/', '') + Right('00'+convert(varchar(2),row_number()over(partition by account,[date] order by t.[date])) ,3)

Answer 3

MySql
i can give you the logic of 020616001 this part right now .......
for same id +1 i have to work on it....that i ll let u know after my work
insert into table_name(id)
select concat
(
if(length (day(current_date))>1,day(current_date),Concat(0,day(current_date))),
if(length (month(current_date))>1,month(current_date),Concat(0,month(current_date))),
(right(year(current_date),2)),'001'
)as id

Answer 4

you cannot convert your dates column to datetime type in normal way because it is dd/mm/yyyy.
Try this,
declare #t table(acoount varchar(50),dates varchar(20))
insert into #t values
('John','2/6/2016')
,('John','2/6/2016')
,('John','4/6/2016')
,('John','4/6/2016')
,('Andi','5/6/2016')
,('Steve','4/6/2016')
;With CTE as
(select * , SUBSTRING(dates,0,charindex('/',dates)) dd
,SUBSTRING(stuff(dates,1,charindex('/',dates),''),0, charindex('/',stuff(dates,1,charindex('/',dates),''))) MM
,right(dates,2) yy
from #t
)
,CTE1 as
(
select *
,ROW_NUMBER()over(partition by yy,mm,dd order by yy,mm,dd)rn from cte c
)
select *, REPLICATE('0',2-len(dd))+cast(dd as varchar(2))
+REPLICATE('0',2-len(MM))+cast(MM as varchar(2))
+yy+REPLICATE('0',3-len(rn))+cast(rn as varchar(2))
from cte1