I have a directory containing lot of files - txt and others.
I want to change extension those others file to txt
For now - i use this:
find . ! -name '*.txt' -type f -exec ls -f {} + > to_txt.txt
for i in ``cat to_txt.txt``; do
mv $i $i.txt && echo $i "File extension have been changed" || echo "Something went wrong"
done;
rm to_txt.txt
Script works fine, but i think it is clumsy
Is there any smarter and elegant way to do this?
Just use the -exec to perform the mv command:
find . ! -name '*.txt' -type f -exec mv {} {}.txt \;
# ^^^^^^^^^^^^
# here the magic
How does this work?
find . ! -name '*.txt' -type f is what you already had: it looks for those files whose name does not end with .txt.
Then, the key is the usage of -exec: there, we make use of {} that carries the value of every file that has been found. Since it acts as a variable, you can use it as so and perform commands. In this case, you want to do mv $file $file.txt, so this is what we do: mv {} {}.txt. To have it work, we finally have to add the \; part.
Related
So I just ran the following command to add a file extension to a bunch of files. I thought I would undo them one by one, but it turns out I need to undo them all at one time, how do I reverse this?
find . -name '*.targetFileType' -type f -exec mv '{}' '{}'.not \;
Before the file was: aFile.targetFileType
Now it is: aFile.targetFileType.not
I need to return it to aFile.targetFileType
I have managed to reverse with:
for f in $(find . -name '*.not' -type f); do mv ${f} $(echo ${f} | sed 's/.not//g'); done;
Any idea why this is not working? I checked many links and I can't figure it out why I think the syntax is correct.
I want to find the file maplist.txt.old and then rename it to maplist.txt in the same folder. I got no errors.
find ~ -type f -name csgo/maplist.txt.old -execdir mv csgo/maplist.txt.old maplist.txt \;
Lots of ways to handle this. Since you are looking in ~/csgo you can go directly to the directory in the find. The -execdir option will run the command in the directory. So without changing your example much:
find ~/csgo -type f -name maplist.txt.old -execdir mv maplist.txt.old maplist.txt \;
To automate this a bit further, you may want to handle this with a bash for loop, for example:
for file in $( find ~/csgo -type f -name maplist.txt.old ) ; do
mv $file $( echo $file | sed -e 's/\.old//' )
done
I want to rename a file present in several subdirectories using bash script.
my files are in folders:
./FolderA/ABCD/ABCD_Something.ctl
./FolderA/EFGH/EFGH_Something.ctl
./FolderA/WXYZ/WXYZ_Something.ctl
I want to rename all of the .ctl file with the same name (name.ctl).
I tried several command using mv or rename but didnt work.
Working from FolderA:
find . -name '*.ctl' -exec rename *.ctl name.ctl '{}' \;
or
for f in ./*/*.ctl; do mv "$f" "${f/*.ctl/name .ctl}"; done
or
for f in $(find . -type f -name '*.ctl'); do mv $f $(echo "$f" | sed 's/*.ctl/name.ctl/'); done
Can you help me using bash?
thanks
You can do this with one line with:
find . -name *.ctl -exec sh -c 'mv "$1" `dirname "$1"`/name.ctl' x {} \;
The x just allows the filename to be positional character 1 rather than 0 which (in my opinion) wrong to use as a parameter.
Try this:
find . -name '*.ctl' | while read f; do
dn=$(dirname "${f}")
# remove the echo after you sanity check the output
echo mv "${f}" "${dn}/name.ctl"
done
find should get all the files you want, dirname will get just the directory name, and mv will perform the rename. You can remove the quotes if you're sure that you'll never have spaces in the names.
i am a total noob, but i figured out this script for doing the following:
I have a folder called "unrar" in there are subfolders with unknown foldername with rar file inside.
Now i enter unknownsubfolder, find rar file and unrar it in unknownsubfolder.
After that i find the new file and rename it with the unknownsubfoldername. Now i grab the file and move it to ./unrar.
#!/bin/bash
cd /home/user/unrar/
for dir in /home/user/unrar/*;
do (cd "$dir" && find -name "*.rar" -execdir unrar e -r '{}' \;); done
echo "$(tput setaf 2)-> unrar done!$(tput sgr0)"
for dir in /home/user/unrar/*;
do (cd "$dir" && find -name "*.mkv" -exec mv '{}' "${PWD##*\/}.mkv" \;); done
for dir in /home/user/unrar/*;
do (cd "$dir" && find -name "*.mp4" -exec mv '{}' "${PWD##*\/}.mp4" \;); done
for dir in /home/user/unrar/*;
do (cd "$dir" && find -name "*.avi" -exec mv '{}' "${PWD##*\/}.avi" \;); done
cd /home/user/unrar
find -name "*.mkv" -exec mv '{}' /home/user/unrar \;
find -name "*.mp4" -exec mv '{}' /home/user/unrar \;
find -name "*.avi" -exec mv '{}' /home/user/unrar \;
This works fine with most files, but in some cases it doesn't
I want to find *.rar in DIR and unrar it. the newfile.(.mkv|.avi|.mp4) should be renamed to DIR(.mkv|.avi|.mp4) and moved to ./unrar
This is my filestructure.
./unrar/
- unknownsubfolder/
-file.rar
-file.r00
-....
- unknownsubfolder1/
- s01/
- file.rar
- file.r00
- ....
- s02/
- file.rar
- file.r00
- ....
- ....
If case1, unrar "/unknownsubfolder/file.rar" and get "x.mkv". the file is renamed from "x.mkv" to "unknwonsubfolder.mkv" and moved to "./unrar/unknownsubfolder.mkv"
(same with *.avi + *.mp4) ==perfekt
if case2, in my script unknownsubfolder/s01/file.rar will be unrard, but not renamed to s01.mkv insted to unknwonsubfolder1.mkv.
(if there are more like s02, s03, s04 ...) i always end up with one unknownsubfolder.mkv file in ./unrar) ==wrong output
So i guess i have 3 questions
How do i get the right DIRname for renaming the file? Or how do i enter unknownsubfolder/s01 ....?
Is there a way to exclude a word from the find? sometimes "unknownsubfolder" contains another folder+file called "sample(.mkv|.avi|.mp4)". I would like to exclude that, to prevent the original file to be overwritten with the sample file. happens sometimes.
I am sure i can combine some of the code,to make it even shorter. Could someone explain how? So how i combine the mkv,avi and mp4 in one line.
regards, wombat
(EDIT: for better understanding)
UPDATE:
I adjusted the solution to work with unrar. Since I did not had unrar installed previously, I used gunzip to construct the solution and then simply replaced it with unrar. The problem with this approach was that, by default, unrar extracts to the current working directory. Another difference is that the name of the extracted file can be completely different from the archive's name - it is not just a matter of different extensions. The original archive is also not deleted after extraction.
Here is the solution specifically tailored to work with unrar with respect to aforementioned behavior:
#!/bin/bash
path="$1"
omit="$2"
while read f;do
unrar e -r "${f}" "${f%/*}" > /dev/null
done < <(find "${path}" -type d -name "${omit}" -prune -o -type f -print)
while read f;do
new="${f%/*}"
new="${new##*/}"
mv "${f}" "${path}/${new}"
done < <(find "${path}" -type d -name "${omit}" -prune -o -type f -a \! -name '*.rar' -print )
You can save the script, e.g., as rename-script (do not forget to make it executable), and then call it like
./rename-script /path/to/unrar omitfolder
Notice, that inside the script there is no cd. You will have to at least provide the location of the unrar folder as first parameter, otherwise you will get an error. In case of OP this would be /home/user/unrar. The omitfolder is not a path, it is just the name of the folder that you want to omit. So in OP's case this would be sample.
./rename-script /home/user/unrar sample
As requested by OP in the comments, you can read about the bash read-builtin and process substitution in order to understand how the while-loop works and how it assigns the filenames returned by find to the variable f.
I'm trying to list the files in a directory that is given by the variable DIR. My code looks like this so far:
for i in `find $DIR -name "*.txt"
The variable DIR is already defined. I'm not sure what the syntax is here.
ls "${DIR}/*.txt"
or
find "${DIR}" -name "*.txt"
should do the trick. The first one only lists *.txt files in the directory itself, the second one also *.txt files in subdirectories.
I guess you want to execute a given action on all files with extension "txt" under $DIR and/or its subdirs. As usual there are different solutions.
This one:
$ for i in $(find "$DIR" -name \*.txt) ; do echo "Do something with ${i}" ; done
won't work if file path (either the file itself or one subdirectory) contains spaces.
But you can use this:
$ find "$DIR" -type f -name \*.txt | while read i ; do echo "Do something with ${i}" ; done
or this:
$ find "$DIR" -type f -name \*.txt -print0 | xargs -0 -I {} echo "Do something with {}"
or this:
$ find "$DIR" -type f -name \*.txt -exec echo "Do something with {}" \;
or... 100 additional solutions.
Not sure what you want.
find $DIR -name "*.txt" -print
will list all the files that end with .txt and are located in $DIR or its subdirectories. You can omit the -print as that is the default behaviour anyway.
If you have a simple thing you want to do with this file, you can use find's -exec function:
find $DIR -name "*.txt" -exec wc -l {} \;
Or you can use a loop:
for f in `find $DIR -name "*.txt"`; do
wc -l $f
mv $f /some/other/dir/
fi
note: as #mauro helpfully pointed out, this will not work if the DIR or the file names contain spaces.
Cheers