zsh run script without sudo - bash

Question

I made a bash script helpme that contains help configurations tasks that I use daily.
I would like to use it everywhere (even in other machines) with simple running:
$ helpme
I made this for that:(MAC OS)
$ sudo chmod +x helpme
$ sudo mv helpme /usr/local/bin/helpme
If I use bash terminal works correctly but now I'm using oh-my-zsh terminal and it shows me this message:
usage: sudo -h | -K | -k | -L | -V
usage: sudo -v [-AknS] [-g groupname|#gid] [-p prompt] [-u user name|#uid]
usage: sudo -l[l] [-AknS] [-g groupname|#gid] [-p prompt] [-U username] [-u user name|#uid] [-g groupname|#gid] [command]
usage: sudo [-AbEHknPS] [-C fd] [-g groupname|#gid] [-p prompt] [-u user name|#uid] [-g groupname|#gid] [VAR=value] [-i|-s] [<command>]
usage: sudo -e [-AknS] [-C fd] [-g groupname|#gid] [-p prompt] [-u user name|#uid] file ...
If I run with sudo works, but I don't want to use sudo
$ sudo helpme
Edited:
This is an example:
#!/bin/bash
main(){
echo invalid option
}
if [[ "${BASH_SOURCE[0]}" = "${0}" ]]; then
main "$#"
fi
Any idea?