Magento ver. 1.7.0.2
In email templates facing one issue.
When I use
<a style="" href="{{store url=''}}">
it give me o/p like
<a style="" href="http://www.domain.com/index.php">
But I want like following
<a style="" href="http://www.domain.com">
Now If I add
<a href="{{store direct_url='service'}}">
It give me o/p like
<a href="http://www.domain.com/index.php/service">
But I want like following
<a href="http://www.domain.com/service">
Now If I add
<a href="{{store direct_url='service/contact'}}">
It give me o/p like (/index/index automatically appended)
<a href="http://www.domain.com/index.php/service/contact/index/index">
But I want like following
<a href="http://www.domain.com/service/contact">
And when I click on link it will navigate me to /service page not service/contact page.
Any idea what's this going on?
Following has done the job.
{{config path="web/unsecure/base_url"}}
<a href="{{config path="web/unsecure/base_url"}}service"
Related
having the following HTML (snippet grabbed from the web page I wanted to scrape):
<div class="ulListContainer">
<section class="stockUpdater">
<ul class="column4">
<li>
<img src="1.png" alt="">
<strong>
Buy*
</strong>
<strong>
Sell*
</strong>
</li>
<li>
<header>
$USD
</header>
<span class="">
20.90
</span>
<span class="">
23.15
</span>
</li>
</ul>
<ul>...</ul>
</section>
</div>
how do I get the 2nd li 1st span value using XPath? The result should be 20.90.
I have tried the following //div[#class="ulListContainer"]/section/ul[1]/li[2]/span[1] but I am not getting any values. I must said this is being used from a Google Sheet and using the function IMPORTXML (not sure what version of XPath it does uses) can I get some help?
Update
Apparently Google Sheets does not support such "complex" XPath expression since it seems to work fine:
Update 1
As requested I've shared the Google Sheet I am using to test this, here is the link
What you need is :
=IMPORTXML(A1;"//li[contains(text(),'USD')]/span[1]")
Removing section from your original XPath will work too :
=IMPORTXML(A1;"//div[#class='ulListContainer']/ul[1]/li[2]/span[1]")
Try this:
=IMPORTXML("URL","//span[1]")
Change URL to the actual website link/URL
I am trying to scrape a web page for NAME OF COMPANY and CITY AND STATE OF COMPANY shown below.
I have an xpath code snippet that identifies both text elements at the same time:
// span[starts-with(#class,"text-align")]/text()[2]
This xpath snippet pulls the first text value (COMPANY NAME). How do I get the second text element (CITY,STATE)?
A snip of the web page code looks like this:
<div>
<ul class="pv-top-card-v3--experience-list">
<li>
<a class="pv-top-card-v3--experience-list-item" href="#" data-control-name="position_see_more" data-ember-action="" data-ember-action-172="172">
<img src="https://media.licdn.com/dms/image/C4E0BAQFhA8h46hvabA/company-logo_100_100/0?e=1582761600&v=beta&t=VAeZqaGu3Lu6Ol_n5kiiI74FSRuSOZA1ggAI5qTVRjE" id="ember173" class="EntityPhoto-square-1 flex-shrink-zero ember-view">
<span id="ember174" class="text-align-left ml2 t-14 t-black t-bold full-width lt-line-clamp lt-line-clamp--multi-line ember-view" style="-webkit-line-clamp: 2"> THIS IS THE NAME OF A COMPANY
<!----></span>
</a>
</li>
<li>
<a class="pv-top-card-v3--experience-list-item" href="#" data-control-name="education_see_more" data-ember-action="" data-ember-action-176="176">
<img src="https://media.licdn.com/dms/image/C560BAQEr2uQX-x2EwQ/company-logo_100_100/0?e=1582761600&v=beta&t=aDbYLUDMvlS4DpwOLjOaQj3Dj60C_cYLC5UUvGoyld0" id="ember177" class="EntityPhoto-square-1 flex-shrink-zero ember-view">
<span id="ember178" class="text-align-left ml2 t-14 t-black t-bold full-width lt-line-clamp lt-line-clamp--multi-line ember-view" style="-webkit-line-clamp: 2"> THIS IS THE CITY AND STATE OF COMPANY
<!----></span>
</a>
</li>
</ul>
</div>
The xpath string is picking up the two span elements using class. I can't use the span id attributes because they are dynamic and change with each page (one page per company).
Can someone advise how I extract the desired text?
Thanks.
point to the li level.
//ul/li[2]/a/span[starts-with(#class,"text-align")]
I am trying to dynamically generate links for the content in my page by looping through a list but I get 'parsing errors'
I tried as mentioned in https://www.thymeleaf.org/doc/articles/standardurlsyntax.html:
<a th:href="#{/order/{id}/details(id=3,action='show_all')}">
Code:
<li th:each="param : ${paramList}">
<span th:text="${placeholder}">This is displaying the value of placeholder correctly</span>
<!-- The value I am trying to achieve is href="/member/team/ValueFromPlaceholderVariable?team=TeamName&page=PageName" -->
<a th:href="#{/member/team/{PlaceName}(PlaceName=${placeholder},team=${param.TeamName},page=${param.PageName})}">Page</a>
</li>
How can I generate the href link?
Remove the slash at the beginning
<a th:href="#{member/team/{PlaceName}(PlaceName=${placeholder},team=${param.TeamName},page=${param.PageName})}">Page</a>
Using Thymeleaf, how can I make an image act as a hyperlink?
The Thymeleaf Documentation says nothing about images and I tried using standard HTML for this issue but none of the below attempts made my image an active hyperlink.
<a th:href="#{/user/myUser}">
<img src="../../static/images/image.jpg" alt="logo"/>
</a>
<a href="https://www.w3schools.com">
<img src="../../static/images/image.jpg" alt="logo"/>
</a>
<a href="/oauth2/authorization/google">
<img alt="Google Login" title="Google login"
th:src="#{/images/login-with-google.png}" />
</a>
I am trying to ascertain how many pages are there for any search result on a site so that i can scrape data for all the pages using lxml and xpath.
There is a pagination tab with the following structure:
Page: 1 2 3 ... 7 next
the html content for the same being something like
<ul class="ulclass">
<li></li>
<li>
<span> You are on the first page</span>
"1"
</li>
<li>
<a href="link to second page">
<span></span>
"2"
</a>
</li>
<li>
</li>
...
<li>
<a href="link to last page">
<span></span>
"7"
</a>
</li>
My approach is to extract the page numbers 1,2,3,7 so that i can repeat the web scraping 7 times for every page 'cause otherwise it just scrapes the first result of the page.
I have written the following xpath, but it doesnot return correct page numbers.
xpath('//ul[#class="ulclass"]/li/a/text())
If I expand your example to form this,
<ul class="ulclass">
<li><span>You are on the first page</span>"1"</li>
<li><span></span>"2"</li>
<li><span></span>"3"</li>
<li><span></span>"4"</li>
<li><span></span>"5"</li>
<li><span></span>"6"</li>
<li><span></span>"7"</li>
</ul>
then using scrapy in Python I can get this:
>>> from scrapy.selector import Selector
>>> selector = Selector(text=open('temp.htm').read())
>>> selector.xpath('..//ul[#class="ulclass"]/li/a/text()').extract()
['"2"', '"3"', '"4"', '"5"', '"6"', '"7"']