using find sort and wc -l in the one command - bash

Question

This is how find files using find and show the number of lines in each file
$ find ./ -type f -name "data*.csv" -exec wc -l {} +
380723 ./data_2016-07-07-10-41-13.csv
369869 ./data_2016-07-11-10-42-01.csv
363941 ./data_2016-07-08-10-41-50.csv
378981 ./data_2016-07-12-10-41-28.csv
1493514 total
how do I sort the results by file name? Below is my attempt, but it is not working.
$ find ./ -type f -name "data*.csv" -exec wc -l {} + | sort
1493514 total
363941 ./data_2016-07-08-10-41-50.csv
369869 ./data_2016-07-11-10-42-01.csv
378981 ./data_2016-07-12-10-41-28.csv
380723 ./data_2016-07-07-10-41-13.csv
$ find ./ -type f -name "data*.csv" | sort -exec wc -l {} +
sort: invalid option -- 'e'
Try `sort --help' for more information.
$ find ./ -type f -name "data*.csv" -exec sort | wc -l {} +
find: wc: {}missing argument to `-exec'
: No such file or directory
wc: +: No such file or directory
0 total
$
Can someone offer a solution and correct me so I understand it better?
EDIT1
from man sort
-k, --key=POS1[,POS2]
start a key at POS1 (origin 1), end it at POS2 (default end of line). See POS syntax below
POS is F[.C][OPTS], where F is the field number and C the character position in the field; both are origin 1. If neither -t nor -b is in effect, characters in a field are counted from the begin‐
ning of the preceding whitespace. OPTS is one or more single-letter ordering options, which override global ordering options for that key. If no key is given, use the entire line as the key.

Answer 1

Ismail's suggestion of using sort -k is correct. However, I'm often too lazy to learn (or relearn) how -k works, so here's a cheap solution:
find . -name 'data*.csv' -print0 | sort -z | xargs -0 wc -l
Edit: after some experimentation, I did figure out how -k works:
find . -name 'data*.csv' -exec wc -l {} + | sort -k 2