I am trying to import BLOB(Image)data form oracle to Hive using below Sqoop command.
sqoop import --connect jdbc:oracle:thin:#host --username --password --m 3 --table tablename --hive-drop-import-delims --hive-table tablename --target-dir '' --split-by id;
But unsuccessful. Remember, BLOB Data stored in oracle database as Hexadecimal and we need to store this to Hive table as text or bianary.
What are the possible way to do that?
Sqoop does not know how to map blob datatype in oracle into Hive. So You need to specify --map-column-hive COLUMN_BLOB=binary
sqoop import --connect 'jdbc:oracle:thin:#host' --username $USER --password $Password --table $TABLE --hive-import --hive-table $HiveTable --map-column-hive COL_BLOB=binary --delete-target-dir --target-dir $TargetDir -m 1 -verbose
Related
I have to import data using sqoop, my source column names are having spaces in between them, so while I am adding it in --map-column-java parameter getting the error.
Sample Sqoop import:
sqoop import --connect jdbc-con --username "user1" --query "select * from table where \$CONDITIONS" --target-dir /target/path/ -m 1 --map-column-java data col1=String, data col2=String, data col3=String --as-avrodatafile
Column names:
data col1,
data col2,
data col3
Error:
19/03/07 07:31:55 DEBUG sqoop.Sqoop: Malformed mapping. Column mapping should be the form key=value[,key=value]*
java.lang.IllegalArgumentException: Malformed mapping. Column mapping should be the form key=value[,key=value]*
at org.apache.sqoop.SqoopOptions.parseColumnMapping(SqoopOptions.java:1355)
at org.apache.sqoop.SqoopOptions.setMapColumnJava(SqoopOptions.java:1375)
at org.apache.sqoop.tool.BaseSqoopTool.applyCodeGenOptions(BaseSqoopTool.java:1363)
at org.apache.sqoop.tool.ImportTool.applyOptions(ImportTool.java:1011)
at org.apache.sqoop.tool.SqoopTool.parseArguments(SqoopTool.java:435)
at org.apache.sqoop.Sqoop.run(Sqoop.java:135)
at org.apache.hadoop.util.ToolRunner.run(ToolRunner.java:70)
at org.apache.sqoop.Sqoop.runSqoop(Sqoop.java:183)
at org.apache.sqoop.Sqoop.runTool(Sqoop.java:234)
at org.apache.sqoop.Sqoop.runTool(Sqoop.java:243)
at org.apache.sqoop.Sqoop.main(Sqoop.java:252)
Malformed mapping. Column mapping should be the form key=value[,key=value]*
Able to resolve this issue:
1. Spaces issue:
sqoop import --connect jdbc-con --username "user1" --query "select * from table where \$CONDITIONS" --target-dir /target/path/ -m 1 --map-column-java "data col1=String, data col2=String, data col3=String" --as-avrodatafile
2. ERROR tool.ImportTool: Import failed: Cannot convert SQL type 2005:
3 columns in source are having 2005 and nvarchar added them in --map-column-java resolved this issue
3. org.apache.avro.file.DataFileWriter$AppendWriteException: org.apache.avro.UnresolvedUnionException: Not in union ["null","long"]: 1****
This is causing due to using * in select query, so modified sqoop query as:
sqoop import --connect jdbc-con --username "user1" --query "select [col1,data col2,data col3] from table where \$CONDITIONS" --target-dir /target/path/ -m 1 --map-column-java "data col1=String, data col2=String, data col3=String" --as-avrodatafile
Instead of using you can use this one method
I have used it and it works
here I am casting the columns to string so that timestamp could not change to int
keep note of that point It will help you to make your string properly
address = <localhost/server-ip-address/>
port = put your database port number
Sqoop is expecting the comma-separated list of mapping in form 'name of column'='new type'
columns-name = give your database column name of timestamp or date time to date
database-name = give your datbase name
database-user-name = put your user name
password = put your password
demo to understand the code properly
sqoop import --map-column-java "columns-name=String" --connect jdbc:postgresql://address:port/database-name --username user-name --password database-password --query "select * from demo where \$CONDITIONS;" -m 1 --target-dir /jdbc/star --as-parquetfile --enclosed-by '\"'
demo of code for single-column
sqoop import --map-column-java "date_of_birth=String" --connect jdbc:postgresql://192.168.0.1:1928/alpha --username postgres --password mysecretpass --query "select * from demo where \$CONDITIONS;" -m 1 --target-dir /jdbc/star --as-parquetfile --enclosed-by '\"'
demo of code for dealing with multiple columns
sqoop import --map-column-java "date_of_birth=String,create_date=String" --connect jdbc:postgresql://192.168.0.1:1928/alpha --username postgres --password mysecretpass --query "select * from demo where \$CONDITIONS;" -m 1 --target-dir /jdbc/star --as-parquetfile --enclosed-by '\"'
I want to import a table with date format from oracle database by Sqoop to Hive. I don't understand why imported fields in Hive are string and not timestamp (like Oracle). I prefer to do not use map-colum-hive because i want to do that automaticly for every date format for each table.
This is my Sqoop request :
sqoop import -D mapDateToTimestamp=true --direct --connect
jdbc:oracle:thin:#//$connection --username $username -password
$password -m 7 --table $table1 --hive-import --hive-overwrite
--hive-database $database1 --hive-table $table2 --where "$date>to_date('$dd/mm/yyyy hh:mm:ss','dd/mm/yyyy hh24:mi:ss')"
--null-string '\N' --null-non-string '\N' --target-dir $targetdirectory -- --schema $schema
I tried it with mapDateToTimestamp = True and oracle.jdbc.mapDateToTimestamp = True both, data are imported but data with date format are in string.
Do you have a solution ? suggestions ? advices ?
Thanks a lot !
I need some help with sqoop.
First of all, I'm sorry, my english isn't very good.
Using the folowing command:
sqoop import -D mapreduce.output.fileoutputformat.compress=false --num-mappers 1 --connection-manager "com.quest.oraoop.OraOopConnManager" --connect "jdbc:Oracle:thin:#(DESCRIPTION=(ADDRESS_LIST=(ADDRESS=(PROTOCOL=TCP)(HOST=myserver)(PORT=1534)))(CONNECT_DATA=(SERVICE_NAME=myservice)))" --username "rodrigo" --password pwd \
--query "SELECT column1, column2 from myTable where \$CONDITIONS" \
--null-string '' --null-non-string '' --fields-terminated-by '|' \
--lines-terminated-by '\n' --as-textfile --target-dir /data/rodrigo/myTable \
--hive-import --hive-partition-key yearmonthday --hive-partition-value '20180101' --hive-overwrite --verbose -P --m 1 --hive-table myTable
My table is already created, because I must create a solicitation for create a table in my hive database, so I can't create dinamically inside sqoop command.
I have permission to create the directory in hdfs.
When I remove the directory, sqoop logs an error saying that I have no create table permissions, and when I already create the diretory, it returns a FileAlreadyExistsException.
What can I do to solve that?
Thanks from Brazil.
I tried to (CDC)append new data of a table from Teradata database to HDFS path of already moved old data.
sqoop import --connect 'jdbc:teradata://xx.xx.xx.xx/database_name' --connection-manager org.apache.sqoop.teradata.TeradataConnManager --username dbc --password dbc --query "select * from database_name.table_name WHERE (1=0 OR \$CONDITIONS) tymstp>'2016-07-28 04:49:53.44'" --fields-terminated-by '\t' --lines-terminated-by '\n' --target-dir /hdfs/path -m 1 --append
From SQL server I imported and created a hive table using the below query.
sqoop import --connect 'jdbc:sqlserver://10.1.1.12;database=testdb' --username uname --password paswd --table demotable --hive-import --hive-table hivedb.demotable --create-hive-table --fields-terminated-by ','
Command was successful, imported the data and created a table with 10000 records.
I inserted 10 new records in SQL server and tried to append these 10 records into existing hive table using --where clause
sqoop import --connect 'jdbc:sqlserver://10.1.1.12;database=testdb' --username uname --password paswd --table demotable --where "ID > 10000" --hive-import -hive-table hivedb.demotable
But the sqoop job is getting failed with error
ERROR tool.ImportTool: Error during import: Import job failed!
Where am I going wrong? any other alternatives to insert into table using sqoop.
EDIT:
After slightly changing the above command I am able to append the new rows.
sqoop import --connect 'jdbc:sqlserver://10.1.1.12;database=testdb' --username uname --password paswd --table demotable --where "ID > 10000" --hive-import -hive-table hivedb.demotable --fields-terminated-by ',' -m 1
Though it resolves the mentioned problem, I can't insert the modified rows. Is there any way to insert the modified rows without using
--incremental lastmodified parameter.
in order to append rows to hive table, use the same query you have been using before, just remove the --hive-overwrite.
I will share the 2 queries that I used to import in hive, one for overwriting and one for append, you can use the same for importing:
To OVERWRITE the previous records
sqoop import -Dmapreduce.job.queuename=default --connect jdbc:teradata://database_connection_string/DATABASE=database_name,TMODE=ANSI,LOGMECH=LDAP --username z****** --password ******* --query "select * from ****** where \$CONDITIONS" --split-by "HASHBUCKET(HASHROW(key to split)) MOD 4" --num-mappers 4 --hive-table hive_table_name --boundary-query "select 0, 3 from dbc.dbcinfo" --target-dir directory_name --delete-target-dir --hive-import --hive-overwrite --driver com.teradata.jdbc.TeraDriver
TO APPEND to the previous records
sqoop import -Dmapreduce.job.queuename=default --connect jdbc:teradata://connection_string/DATABASE=db_name,TMODE=ANSI,LOGMECH=LDAP --username ****** --password ******--query "select * from **** where \$CONDITIONS" --split-by "HASHBUCKET(HASHROW(key to split)) MOD 4" --num-mappers 4 --hive-import --hive-table guestblock.prodrptgstrgtn --boundary-query "select 0, 3 from dbc.dbcinfo" --target-dir directory_name --delete-target-dir --driver com.teradata.jdbc.TeraDriver
Note that I am using 4 mappers, you can use more as well.
I am not sure if you can give direct --append option in sqoop with --hive-import option. Its still not available atleast in version 1.4.
The default behavior is append when --hive-overwrite and --create-hive-table is missing. (atleast in this context.
I go with nakulchawla09's answer. Though remind yourself to keep the --split-by option . This will ensure the split names in hive data store is appropriately created. otherwise you will not like the default naming. You can ignore this comment in case you don't care for the backstage hive warehouse naming and backstage data store. When i tried with the below command
Before the append
beeline:hive2> select count(*) from geolocation;
+-------+--+
| _c0 |
+-------+--+
| 8000 |
+-------+--+
file in hive warehouse before the append
-rwxrwxrwx 1 root hdfs 479218 2018-10-12 11:03 /apps/hive/warehouse/geolocation/part-m-00000
sqoop command for appending additional 8k records again
sqoop import --connect jdbc:mysql://localhost/RAWDATA --table geolocation --username root --password hadoop --target-dir /rawdata --hive-import --driver com.mysql.jdbc.Driver --m 1 --delete-target-dir
it created the below files. You can see the file name is not great because did not give a split by option or split hash (can be datetime or date).
-rwxrwxrwx 1 root hdfs 479218 2018-10-12 11:03 /apps/hive/warehouse/geolocation/part-m-00000
-rwxrwxrwx 1 root hdfs 479218 2018-10-12 11:10 /apps/hive/warehouse/geolocation/part-m-00000_copy_1
hive records appended now
beeline:hive2> select count(*) from geolocation;
+-------+--+
| _c0 |
+-------+--+
| 16000 |
+-------+--+
We can use this command:
sqoop import --connect 'jdbc:sqlserver://10.1.1.12;database=testdb' --username uname --password paswd --query 'select * from demotable where ID > 10000' --hive-import --hive-table hivedb.demotable --target-dir demotable_data
Use --append option and -m 1 so it will be like below :
sqoop import --connect 'jdbc:sqlserver://10.1.1.12;database=testdb' --username uname --password paswd --table demotable --hive-import --hive-table hivedb.demotable --append -m 1