I have a table in oracle with only 4 columns...
Memberid --- bigint
uuid --- String
insertdate --- date
updatedate --- date
I want to import those data in HIVE table using sqoop. I create corresponding HIVE table with
create EXTERNAL TABLE memberimport(memberid BIGINT,uuid varchar(36),insertdate timestamp,updatedate timestamp)LOCATION '/user/import/memberimport';
and sqoop command
sqoop import --connect jdbc:oracle:thin:#dbURL:1521/dbName --username ** --password *** --hive-import --table MEMBER --columns 'MEMBERID,UUID,INSERTDATE,UPDATEDATE' --map-column-hive MEMBERID=BIGINT,UUID=STRING,INSERTDATE=TIMESTAMP,UPDATEDATE=TIMESTAMP --hive-table memberimport -m 1
Its working properly and able to import data in HIVE table.
Now I want to update this table with incremental update with updatedate (last value today's date) so that I can get day to day update for that OLTP table into my HIVE table using sqoop.
For Incremental import I am using following sqoop command
sqoop import --hive-import --connect jdbc:oracle:thin:#dbURL:1521/dbName --username *** --password *** --table MEMBER --check-column UPDATEDATE --incremental append --columns 'MEMBERID,UUID,INSERTDATE,UPDATEDATE' --map-column-hive MEMBERID=BIGINT,UUID=STRING,INSERTDATE=TIMESTAMP,UPDATEDATE=TIMESTAMP --hive-table memberimport -m 1
But I am getting exception
"Append mode for hive imports is not yet supported. Please remove the parameter --append-mode"
When I remove the --hive-import it run properly but I did not found those new update in HIVE table that I have in OLTP table.
Am I doing anything wrong ?
Please suggest me how can I run incremental update with Oracle - Hive using sqoop.
Any help will be appropriated..
Thanks in Advance ...
Although i don't have resources to replicate your scenario exactly.
You might want to try building a sqoop job and test your use case.
sqoop job --create sqoop_job \
-- import \
--connect "jdbc:oracle://server:port/dbname" \
--username=(XXXX) \
--password=(YYYY) \
--table (TableName)\
--target-dir (Hive Directory corresponding to the table) \
--append \
--fields-terminated-by '(character)' \
--lines-terminated-by '\n' \
--check-column "(Column To Monitor Change)" \
--incremental append \
--last-value (last value of column being monitored) \
--outdir (log directory)
when you create a sqoop job, it takes care of --last-value for subsequent runs. Also here i have used the Hive table's data file as target for incremental update.
Hope this provides a helpful direction to proceed.
There is no direct way to achieve this in Sqoop. However you can use 4 Step Strategy.
Related
I am new to sqoop and hive . Please help me with understanding
The count of mysql and hive table are different
mysql is 51 rows (table has primary key and no duplicates ) ad hive is 38rows - first run itself
sqoop job --create mmod -- import --connect "jdbc:mysql://cxln2.c.thelab-240901.internal:3306/retail_db" --username sqoopuser --password-file
/tmp/.mysql-pass.txt --table mod --compression-codec org.apache.hadoop.io.compress.BZip2Codec --hive-import --hive-database encry --hive-table mod2 --h
ive-overwrite --check-column last_update_date --incremental lastmodified --merge-key id --last-value 0 --target-dir /user/user_name/append1sqo
pp
It is not creating target dir in given location , instead it creating in warehouse location
I am trying to schedule a sqoop incremental job , somehow I am doing mistake some where
command : above command
2.1 new rows are added with same date
2.2 delete and update on few rows
Output :
No new updates on given table .
It is not updating lastvalue in sqoop job
How to choose merge-key column in sqoop
Where condition in sqoop
--query "select * from reason where id>20 AND $CONDITIONS"
What is the use of $CONDITIONS and do we need to pass the variable in Linux
Is that possible to track rejected rows in sqoop job
Now my hive table with columns - id, name
and MySQL table - number, id, name
I want to map id (from hive) with number (from mysql), name (from hive) with id (from mysql).
I use the command :
sqoop export --hcatalog-database <my_db> --hcatalog-table <my_table> --columns "number,id" \
--connect jdbc:mysql://db...:3306/test \
--username <my_user> --password <my_passwd> --table <my_mysql_table>
However, it didn't work.
The same scenario liked this case can work fine [1]. The requirement can be fulfilled by locating the hive table on hdfs and using the following command to achieve.
sqoop export --export-dir /[hdfs_path] --columns "number,id" \
--connect jdbc:mysql://db...:3306/test \
--username <my_user> --password <my_passwd> --table <my_mysql_table>
Is there any solution can fulfill my scenario via Hcatalog?
reference :
[1]. Sqoop export from hive to oracle with different col names, number of columns and order of columns
I didn't used the hcatalog part of sqoop, but as is written in the manual, the next script should do the work:
sqoop export --hcatalog-database <my_db> --hcatalog-table <my_table> --map-column-hive "number,id" \
--connect jdbc:mysql://db...:3306/test \
--username <my_user> --password <my_passwd> --table <my_mysql_table>
This option: --map-column-hive when is used along with --hcatalog, does the work for hcatalog instead of hive.
Hope that this works for you.
I am importing a set of tables from an Oracle database into Hive using sqoop import statement as follows:
sqoop import "-Dorg.apache.sqoop.splitter.allow_text_splitter=true" --connect CONNECTIONSTRING --table TABLENAME --username USERNAME --password PASSWORD --hive-import --hive-drop-import-delims --hive-overwrite --hive-table HIVE_TABLE_NAME1 --null-string '\N' --null-non-string '\N' -m 1
and i am using the following check column keyword in this sqoop statement for incremental loads:
--check-column COLUMN_NAME --incremental lastmodified --last-value HARDCODED_DATE
I tested this and it works great but I want to modify this so that it is dynamic and I dont have to hard code the date into the statement and I can just pass it as a parameter so that it checks the specified column and gets all the data after that date. I understand that the date has to be passed from a different file but I am not really sure what the structure of the file should be and how it would be referencing this sqoop statement. Any help or guidance would be greatly appreciated. Thank you in advance!
You can use sqoop job for the same.
Using sqoop job, you have to apply last-value as 0, it will import and update the data in the job so you only have to run sqoop-job --exec <> everytime, it will update the data without any hardcoded value.
sqoop job create <<job_name>> -- import "-Dorg.apache.sqoop.splitter.allow_text_splitter=true" --connect <<db_url>> --table <<db_name>> --username <<username>> --password <<password>> --hive-import --hive-drop-import-delims --hive-overwrite --hive-table <<hive_table>> --null-string '\N' --null-non-string '\N' -m 1 --incremental lastmodified --check-column timedate --last-value 0
sqoop job --exec <<job_name>>
For more details visit https://sqoop.apache.org/docs/1.4.6/SqoopUserGuide.html#_literal_sqoop_job_literal
I have imported data from sqoop to hive successfully. I have added an column in Oracle and again imported the particular column to hive using sqoop-import. But,it is appending to the first column data and remaining columns with null and no new column came in hive. Can anyone resolve the issue.
With out looking at your import statements, I am assuming that in your second import you are trying to append to the existing import but only importing new column using --columns and --append arguments. It will not work this way as it will append to the file at end of the file not at end of the each line.
you will need to overwrite the existing data in hdfs using --hive-overwrite; and alter hive table for adding additional column. OR just drop the hive table and use --create-hive-table in sqoop command.
so you import command should look like this:
sqoop --import \
--connect $CONNECTION_STR \
--username $USER \
--password $PASS \
--table $ORACLE_TABLE \
--hive-import \
--hive-overwrite \
--hive-table \
--hive-home $HIVE_HOME \
--hive-table $HIVE_TABLE
Change values to actual values of your environment
I am trying to import data from sql into a hive database. The goal is to update the changes in the oracle database to hive using sqoop import. The sqoop command is as follows:
sqoop import -D mapred.child.java.opts='\-Djava.security.egd=file:/dev/../dev/urandom'
--connect jdbc:oracle:thin:#(DESCRIPTION=(ADDRESS_LIST=(LOAD_BALANCE=ON)(FAILOVER=ON)(ADDRESS=(PROTOCOL=TCP)(HOST=)(PORT=1545))(ADDRESS=(PROTOCOL=TCP)(HOST=)(PORT=1545)))(CONNECT_DATA=(SERVICE_NAME=)(SERVER=DEDICATED)))'
--username abcde
--password 1234rgtds
--table Customer_Acc
--columns Name,ID,Address,Date_booking ,Last_update_date
-m 1
--target-dir /final/table
--hive-import
--hive-table tesupd
--map-column-hive Name,ID,Address,Date_booking
--null-string '\\N'
--null-non-string '\\N'
--hive-delims-replacement ' '
--incremental lastmodified
--check-column Last_update_date
--last-value "2009-12-31 12:14:28"
The final output should be the data greater than the last value, but in the above case it is appending the data instead of incrementally updating it.
I want the data to be updated rather than appended.
use --merge-key option in your sqoop-import command. This will replace the older records with the latest records.
Alternately you can use sqoop-merge command as well but it should be done in two steps. First sqoop-import without merge-key and then sqoop-merge
Try using --incremental append rather than --incremental last modified.
With --incremental append last-value of field mentioned is stored in sqoop metastore 'incremental.last.value' which keeps changing whenever the job is executed. Using --incremental append you do not have to update the last-value in your query but it is updated automatically.
By this your value will always be updated (in sqoop metastore) and there will not be any redundant data
Neither sqoop nor Hive can directly update the data in Hive using sqoop imports. Please follow the steps in the below link for row level updates.
http://hortonworks.com/blog/four-step-strategy-incremental-updates-hive/
So your data is mutable and you'd like to modify in HDFS the records which have been changed in your DB.
For this, you need to use the --incremental append flag. You also need to create a Sqoop job, because that will capture the most recent --last-value and serialize it back to the saved job.
You should create a Sqoop job which looks something like this.
sqoop job \
--create jobName \
-- \
import \
jdbc:oracle:thin:#hostname:port:sid \
--username user \
--password fileOnHDFS.password \
--table tableName \
--incremental lastmodified \
--check-column UPDATE_DATUM \
--last-value 1985.01.01 \
--merge-key ID \
More details can be found in the Sqoop User Guide (v1.4.6)