Problems in parsing variable within body stored in database - laravel-5

I have an issue in parsing variable.
I have dynamic email template for all types of email like registration,activation and so on
Suppose i want to send feedback email and i have email template for feedback stored in database.
In database it is stored as Name:{{ $name }}
But when i sent email it is sending Name:{{ $name }} instead of actual name like Name:john
Following is my code:
$name = $request->get('name');
$address = $request->get('address');
$phone = $request->get('phone');
$emailaddress = $request->get('email_address');
$feedbacktext = $request->get`enter code here`('message');
Mail::send('lugmety.frontend.partials.contactUsEmail',
[ 'name' => $name,
],
function ($mail)
use ($address, $name,$phone,$emailaddress,$feedbacktext) {
$mail->to('anandshrestha57#gmail.com')->subject('FeedBack Form')->from($emailaddress,$name);
});
Here is my view which contains email template obtained from database.
<?php echo \App\EmailTemplate::where('slug','contact-us')->first()->body; ?>
Thanks for help.

private function parsed_content($email_template, array $args = array()){
$generated = \Blade::compileString($email_template);
ob_start() and extract($args, EXTR_SKIP);
try{
eval('?>'.$generated);
}catch (\Exception $e){
b_get_clean(); throw $e;
}
$content = ob_get_clean();
return $content;
}
And for parsing variable in email template stored in database:
$emailTemplate = EmailTemplate::where('slug','contact-us')->first();
$email_body = $this->parsed_content($emailTemplate, array(
'name' => $name,
'address' => $address,
'phone' => $phone,
'emailaddress' => $emailaddress,
'feedbacktext'=>$feedbacktext
));
$body = json_decode($email_body,true)['body'];
And for sending email:
Mail::send([],[],
function ($mail)
use ($body,$address, $name,$phone,$emailaddress,$feedbacktext) {
$mail->to('anandshrestha57#gmail.com')->subject('FeedBack Form')->from($emailaddress,$name)
->setBody($body,'text/html');
});
So no need of making every view. Source:#Is there any way to compile a blade template from a string?

Add a function in EmailTemplate Model
//$value is $EmailTemplate->body value
public function getBodyAttribute($value)
{
//get value name by request function
$name = request()->get('name');
//do your regex code to replace {{ name }} from $name in $value and update.....
//finaly return $value;
return $value;
}

Related

Undefined variable: image while update in laravel

public function update_room_detail(Request $request)
{
$request->validate([
'room_type' => 'required',
]);
if($images = $request->file('room_image'))
{
foreach($images as $item):
$var = date_create();
$time = date_format($var, 'YmdHis');
$imageName = $time.'-'.$item->getClientOriginalName();
$item->move(public_path().'/assets/images/room', $imageName);
$arr[] = $imageName;
endforeach;
$image = implode("|", $arr);
}
else
{
unset($image);
}
RoomDetail::where('id',$request->room_id)->update([
'room_type' => $request->room_type,
'room_image' => $image,
]);
Alert::success('Success', 'Rooms details updated!');
return redirect()->route('admin.manage-room');
}
In the above code I am trying to update image in database table. When I click on submit button then it show Undefined variable: image and when I use $image='' in else part instead of unset($image) then blank image name save. So, How can I solve this issue please help me? Please help me.
Thank You
As per the PHP documentation:
unset() destroys the specified variables.
What this means is that it doesn't empty the value of the specified variables, they are destroyed completely.
$foo = "bar";
// outputs bar
echo $foo;
unset($foo);
// results in Warning: Undefined variable $foo
echo $foo;
You've already discovered how to handle this:
when I use $image='' in else part instead of unset($image) then blank image name save
Fix:
Note : uses Storage library feel free to use any other.
public function update_room_detail(Request $request)
{
$request->validate([
'room_type' => 'required',
]);
$imageNames = array();
if ($request->hasFile('room_image')) {
$images = $request->file('room_image');
foreach ($images as $item) {
$var = date_create();
$time = date_format($var, 'YmdHis');
$imageName = $time . '-' . $item->getClientOriginalName() .".".$item->extension();
$item->storeAs('/public/room-images-path', $imageName);
array_push($imageNames, $imageName);
}
}
RoomDetail::where('id', $request->room_id)->update([
'room_type' => $request->room_type,
'room_image' => $imageNames,
]);
Alert::success('Success', 'Rooms details updated!');
return redirect()->route('admin.manage-room');
}

Codeigniter-login with session

i am trying to do a login with sessions but it doesn't seem to be working because when i log in the session data on the view is not being displayed. once logged in it should read something like: 'Welcome Jon' but it doesn't. What could be the issue
controller fn
function login_user()
{
if(isset($_POST['login']))
{
$data = $this->Model_students->fetchUserData();
if(!empty($data))
{
var_dump($data);
foreach ($data as $key => $value) :
$user_id = $value->id;
$firstname = $value->firstname;
$lastname = $value->lastname;
$grade = $value->grade;
$email = $value->email;
$images = json_decode($value->userfile);
endforeach;
$user_info = array(
'id' => $user_id,
'firstname' => $firstname,
'lastname' => $lastname,
'grade' => $grade,
'email' => $email,
'images' => $images[0]->file_name,
'is_logged_in' => TRUE
);
$this->session->set_userdata($user_info);
redirect('Students/homepage');
}
else
{
$this->session->set_flashdata('error', 'Error! Invalid username or password');
redirect('Students/login_user');
}
}
else
{
$this->load->view('signup');
}
}
model
the join here is for a different table in the same db where the common row is id..not sure if the join is correct too
public function fetchUserData()
{
$this->db->select('users.*, user_images.*');
$this->db->from('users');
$this->db->join('user_images', 'users.id=user_images.user', 'inner');
$this->db->where('email', $this->input->post('email'));
$this->db->where('password', md5($this->input->post('password')));
$query = $this->db->get();
if($query->num_rows() == 1 ) :
foreach($query->result() as $row):
$data[] = $row;
endforeach;
return $data;
endif;
}
view the img scr here should display the user image based on what is saved on the db when he/she first registered
</head>
<body>
<h3>Welcome <?php $this->session->userdata('$firstname')?>.</h3>;
<img class ="img-circle" src="<?=base_url();?>uploads/users/<?=$this->session->userdata('userfile/file_name');?>" width="250" height="auto">
There's a typo in your views. where the session variable should be without the $ symbol.
<h3>Welcome <?php echo $this->session->userdata('firstname'); ?>.</h3>;
Also, check if the $user_info contains the expected data. Do a var_dump($user_info) and see just before creating the session.
there could be many issues with it.
1: your are passing a variable in the string which is not valid ( $this->session->userdata('$firstname') ) remove the $ from the first name;
2: there has to be a constructor in the controller so that the session could be called when ever the object is created;
hope it will solve your problem

Laravel 6 - validate unique, ignore on two conditions - same user and name. Also $this->id is null on update

I have the following rule so far.
$rules['name'] = [
'required',
'string',
'min:3',
'max:255',
Rule::unique('user_templates', 'name')->ignore($this->id),
];
Users can create records, but all his records must have a unique name (other users can have records with the same name). How can I do this? Also, $this->id on update is always null. What am I doing wrong?
Controller
public function update(UserTemplatesRequest $request, $slug)
{
try {
$model = UserTemplates::where('slug', XSS::clean($slug))
->firstOrFail();
} catch (ModelNotFoundException $err) {
return redirect()->action('UserTemplatesController#index');
}
$data = $request->validated();
if ($model->updateTemplate(XSS::clean($data, ['file']), $request)) {
$message = "There was an error, please try again";
$action = 'index';
$id = '';
} else {
$message = "Category Updated";
$action = 'edit';
$id = $model->id;
}
return redirect()->action("CategoriesController#{$action}", [$id])
->with('message', $message);
}
According to your Rule you can try and use a where clause to narrow it down to one user and not whole project like:
Rule::unique('user_templates', 'name')->where(function (Builder $query) {
return $query->where(
'user_id', '=', $this->user()->id;
})
user_id is the column inside your user_templates table that works as a foreign key with your users table.
About $this->id it should be $this->user()->id to retrieve your user id

Codeigniter User's Data

Hi guys I have a User controller and User_model model. I want to be able to retrieve and display a logged in users email and phone number from the database to a view after the user is logged in. any idea how I could go about this would be appreciated and if codes could be written to demonstrate I would be very happy.
MODEL
public function login($username, $password){
//validation
$this->db->select('id, email, username');
$this->db->where('username', $username);
$this->db->where('password', $password);
$this->db->where('status', 1);
$result = $this->db->get('users');
if($result->num_rows() == 1){
return $result->row(0)->id;
} else {
return FALSE;
}
}
public function get_user($username){
$this->db->where('username', $username);
$query = $this->db->get('users');
return $query->result();
}
CONTROLLER:
public function login(){
$data['title'] = 'Login';
$this->form_validation-> set_rules('username', 'Username', 'required');
$this->form_validation-> set_rules('password', 'Password', 'required');
if($this->form_validation->run() === FALSE){
$this->load->view('templates/header');
$this->load->view('users/login', $data);
$this->load->view('templates/footer');
} else {
// fetching user
$username = $this->input->post('username');
//Encrypted password
$password = md5($this->input->post('password'));
//login user
$user_id = $this->user_model->login($username, $password);
if($user_id){
//creating session
$user_data = array(
'user_id' => $user_id,
'username' => $username,
'logged_in' => TRUE,
);
$this->session->set_userdata('user_data',$user_data);
// Set message to be sent
$this->session->set_flashdata('user_login', 'Welcome');
redirect('posts');
} else {
// Set message to be sent
$this->session->set_flashdata('login_fail', 'Login Failed');
redirect('users/login');
}
}
}
public function get_user()
{
if($this->session->userdata('logged_in')){
$username = $this->session->userdata('username');
$data['results'] = $this->user_model->get_user($username);
$this->load->view('templates/header');
$this->load->view('users/login', $data);
$this->load->view('templates/footer');
}
}
There is basic problem in your Controller
Session Data Problem: In your Controller you storing all array data in CodeIgniter Session:
the 'user_data' would work like array key, and all other array will be assign as keys data;
$this->session->set_userdata('user_data', $user_data);
and you retrieving/checking the session data by using $this->session->userdata('logged_in') and $this->session->userdata('username'), It's wrong my friend. You can get user data session by $this->session->userdata('user_data')['username'] or $this->session->userdata['user_data']['username'] ...
Because the session would be like;
Array
(
[__ci_last_regenerate] => 1499791562
// This is the array key 'user_data' where your array data stores
[user_data] => Array
(
[user_id] => 1
[username] => scott
[email] => scott.dimon#example.com
[phone_number] => 1234567890
[first_name] => Scott
[logged_in] => 1
)
)
So, you have to have use 'user_data' with session to get your data
One thing I would like to share with everyone, Always Read The Docs and manual Carefully. Believe me if you read before the start, your code would be more nicer and cleaner... Ha ha ha ha ha.. ;) :|
When you login if you set the users_id in session you can get the information like
Read manual also
https://www.codeigniter.com/user_guide/database/results.html#result-rows
https://www.codeigniter.com/user_guide/general/views.html#adding-dynamic-data-to-the-view
Make sure you autoload session, and database.
Examples ONLY below.
Filename: User_model.php
class User_model extends CI_Model {
public function get_user($id)
{
$this->db->where('user_id', $id);
$user_query = $this->db->get('yourtable');
return $user_query->row_array();
}
}
Filename: Dashboard.php
Controller
<?php
class Dashboard extends CI_Controller {
public function __construct()
{
parent::__construct();
if (!$this->session->userdata('user_id'))
{
redirect('logoutcontroller');
}
$this->load->model('user_model');
}
public function index()
{
$userdata = $this->user_model->get_user($this->session->userdata('user_id'));
/** You can use what you want example
$data['email'] = $userdata['email'];
**/
$data['username'] = $userdata['username'];
$this->load->view('some_view', $data);
}
}
View
<?php echo $username;?>
You can use session to carry the logged in user detail.
This is your model code:
//In your model
$query = $this->db
->select('id,email,phone')
->where(['username' => $username, 'password' => $password])
->where('status','1')
->get('users');
$user_data = $query->row_array();
if (!empty($user_data)) {
return $user_data;
} else {
return FALSE;
}
In side the controller where you get the user data if username & password is correct. Here you can put the user data on session:
//In Side Controller
$user_data = $this->user_model->login($username, $password);
if(isset($user_data) && !empty($user_data)){
// you can directly add the `$user_data` to the session as given billow.
// set user data in session
$this->session->set_userdata('user_data', $user_data);
Now after putting a data on session you can retrive it any where, on any view or in side morel, controller.
//retrive the user data in any view
//To echo in view Inside your view code.
<?php
$session_data = $this->session->userdata('user_data');
$user_email = $session_data['email'];
$user_phone = $session_data['phone'];
$user_id = $session_data['id'];
?>
<?= $user_phone ?> OR <?php echo $user_phone; ?>
<?= $user_email ?> OR <?php echo $user_email; ?>
On Your $this->load->view('users/login', $data); this view. Where the HTML & PHP code placed.
Example:
<html>
// Your View Page
</body>
<?php
$session_data = $this->session->userdata('user_data');
$user_email = $session_data['email'];
$user_phone = $session_data['phone'];
$user_id = $session_data['id'];
?>
<h1> Logged In User Email: <?= $user_email ?> </h1>
<h1> Logged In User Phone: <?= $user_phone ?> </h1>
<body>
</html>
Note: Once You save the user data inside the session then you don't need to pass that data to the view form controller. You just need to echo it where you need that.
You need to load session library first. like
$this->load->library('session');
Then after you can save your data into session like,
$newdata = array(
'username' => 'johndoe',
'email' => 'johndoe#some-site.com',
'logged_in' => TRUE
);
$this->session->set_userdata($newdata);
Then where ever you require at controller you can retrive session data like,
$data['session_data'] = $this->session->all_userdata();
and then pass to your view,
$this->load->view('data', $data);
and then access that data into your view with the key,
<?= $session_data['username']; ?>
I hope it helps,
Does this answer your question?
public function login($username, $password){
$db = $this->db;
//validation
$db->select('id, email, username');
$db->where('username', $username);
$db->where('password', $password);
$db->where('status', 1);
$result = $db->get('users')->row_array();
return empty($result['id']) ? false : $result['id'];
}
With a unique index on username you won't need to check the number of rows as it will be limited to 1.
if($user_id){
//creating session
$user_data = array(
'user_id' => $user_id,
'username' => $username,
'logged_in' => TRUE,
);
$this->session->set_userdata($user_data);
// Set message to be sent
$data['session_data'] = $this->session->all_userdata();
$this->session->set_flashdata('user_login', 'Welcome');
$this->load->view('posts', $data);
//redirect('posts');
}
else {
// Set message to be sent
$this->session->set_flashdata('login_fail', 'Login Failed');
redirect('users/login');
}
}
at the view,
<?php print_r($session_data); ?>
if you get your session data into print,
you can display it like,
<?= $session_data['user_id']; ?>
****Modal**
//user login**
function userlogin($data)
{
$condition = "username =" . "'" . $data['username'] . "' AND " . "password =" . "'" . $data['password'] . "' AND " . "status = '1'";
$this->db->select("*");
$this->db->from("user");
$this->db->where($condition);
$this->db->limit(1);
$query = $this->db->get();
if ($query->num_rows() == 1)
{
return $query->result();
}
else {
return false;
}
}
And in your Controller check
if($this->modal_name->login()==false)
{
//redirect user to login page
}
else
{
$data['details'] = $this->modal_name->login();
$this->load->view("post",$data);
}
View
foreach($details as $detail)
{
echo $detail->id;
echo $detail->username;
}

how to get data from database throught model using codeigniter with for each loop

http error occured while calling data from model using function
model
public function getProductCombo() {
$q = $this->db->get_where('products', array('type' => 'combo'));
if ($q->num_rows() > 0) {
foreach (($q->result()) as $row) {
$data[] = $row;
}
return $data;
}
}
controller
function sets() {
$this->sma->checkPermissions();
$this->load->helper('security');
$this->data['error'] = (validation_errors() ? validation_errors() :
$this->session->flashdata('error'));
// problem in this line also
$this->data['showcombo'] = $this->load->sales_model->getComboProduct();
$bc = array(array('link' => base_url(),
'page' => lang('home')),
array('link' => site_url('sales'),
'page' => lang('products')),
array('link' => '#', 'page' => "sets")
);
$meta = array('page_title' => "Add Sets", 'bc' => $bc);
$this->page_construct('sales/sets', $meta, $this->data);
}
First of all, No need to include the curly braces for $q->result
foreach ($q->result as $row)
{
$data[] = $row;
}
No need to use validation_errors in your php file.You can directly load your form page.Use validation_errors() in view page.
In your Controller, do this
if ($this->form_validation->run() == FALSE)
{
$this->load->view('myform');
}
Then in your formpage you can echo
<?php echo validation_errors(); ?>
change this line to
$this->data['showcombo'] = $this->load->sales_model->getComboProduct();
this
$this->data['showcombo'] = $this->load->sales_model->getProductCombo();
Because your
model name is
public function getProductCombo()
{
}
Firstly you load model in controller. And then called function, which you have defined in model..
$this->load->model('sales_model','sales'); // sales is alias name of model name
$this->data['showcombo'] = $this->sales->getComboProduct();

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